Column and Footing Design23-11-04.xls

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    Braced Column Design

    Column Identification: C1 Steel strength:

    60,000 psi

    Column case No. 1 Concrete strength: 4,000 psi

    Column height (c/c: 14 ft Concrete !odulus: ",644 #si

    $eam Spacing (c/c: %4 ft Concrete strength: 4,000 psi

    $eam &idth: 4' in Concrete !odulus: ",644 #si

    $eam depth: 1% in

    ead load )i*e load +actored load

    -ial load : %"0 1" 616.1 #ips

    !oment !%: % 10' 1'6.4 ft#ips

    !oment !1: % 100 16.% ft#ips

    Coulmn dimension: 1' in Clear co*er: 1. in

    Si2e of 3ies No. " Si2e of main ar No. 10

    5: 0.%

    u/g: 1.0 #si !u/gh: 0."' #si

    +rom column interaction diagram, 0.0%

    Step 2 Braced or Unbraced Frame

    7esults of +irstorder anal8sis: 7esults of Secondorder anal8sis: Increase

    !u1: 10 ft#ips !u1: 110 ft#ips 4.69

    Step 1 Design as Short Column (Assuming no slenderness effect):

    ρ:

    Criterion ased on  Δ anal8sis

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    u 0 t ps u 0 t ps 69

     &ith #;1, #lu/r: %'.'

    Ig/l: 1,6"1,'41 in#ips

    t top of the column,

    No. of top columns: 1 Column height (c/c: 14 ft

    No. of eams: %   2.17

    t ottom of the column,No. of columns: 1 Column height (c/c: 14 ft

    No. of eams: %   2.17

    +rom alignment chart,

    =ffecti*e length factor #, 0.'

    Slenderness ratio #lu/r: %.1"

    ith refined calculation! Slenderness must be considered in design

    Step " #inimum #oment #u2min$

    !inimum eccentricit8, emin: 1.14 in

    !inimum !oment !u%min: '." ft#ips

    #inimum moment does not control

    Cm: 0.6

    ?d: 0.%

    =I ' "' %10 i % #i

    ψtop:

    ψtop:

    Step % Cm! βd! &'! and (c$

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    Braced Column Design

    Column Identification: C1 Steel strength:

    60,000 psi

    Column case No. 1 Concrete strength: 4,000 psi

    Column height (c/c: %% ft Concrete !odulus: ",644 #si

    $eam Spacing (c/c: %% ft Concrete strength: 4,000 psi

    $eam &idth: %4 in Concrete !odulus: ",644 #si

    $eam depth: 1' in

    ead load )i*e load +actored load

    -ial load : 1" " "%. #ips

    !oment !%: 61 41 1.1 ft#ips

    !oment !1: 41 % 10"." ft#ips

    Coulmn dimension: 16 in Clear co*er: 1. in

    Si2e of 3ies No. " Si2e of main ar No. 11

    5: 0.6'

    u/g: 1."' #si !u/gh: 0.4 #si

    +rom column interaction diagram, 0.0%'

    Step 2 Braced or Unbraced Frame

    7esults of +irstorder anal8sis: 7esults of Secondorder anal8sis: Increase

    !u1: 10 ft#ips !u1: 110 ft#ips 4.69

    Step 1 Design as Short Column (Assuming no slenderness effect):

    ρ:

    Criterion ased on  Δ anal8sis

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    Column height lu: %0. ft

     &ith #;1, #lu/r: 1.%

    Ig/lc: 1","1,""1 in#ips  ,, , ,

    t top of the column,

    No. of columns: 1 Column height (c/c: 1% ft

    No. of eams: 1   1.33t ottom of the column,

    No. of columns: 1 Column height (c/c: 1% ft. .

    +rom alignment chart,

    =ffecti*e length factor #, 0.'

    Slenderness ratio #lu/r: 41.00ith refined calculation! Slenderness must be considered in design

    Step " #inimum #oment #u2min$

    !inimum eccentricit8, emin: 1.0' in

    !inimum !oment !u%min: "1.4 ft#ips

    #inimum moment does not control

    Cm: 0.'

    ?d 0

    ψtop:

    Step % Cm! βd! &'! and (c$

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    Design of Column Bracket

    Crushing strength of concrete 2.5 si!ield "trength of "teel #$ si

    %idth of Column &' inch

    ength of r*cet &2 inch

    +ccentricit,- e ' inch

    "erice lo*d /*ctored o*d

    ie lo*d &5 25.5

    0e*d o*d ' &&.21#.

    3ori4ont*l force

    .1

    omin*l "he*r "trength #.'

    &$.'

    effectie 0e6th of r*cet- d 5.7

    8ot*l 0e6th of r*cet- h #.9

    "lo6e 75.$ $.'5r*cet 0e6th *t outside- h& 5.&

    $.5d 2.

    8ot*l "he*r friction steel- Af $.#

    ending ;oment to uired- Af &.1

     Addition*l steel Are*- An $.2

     As ? Af@An &.7

    $.#$$$&5'1;inimum "teel re>uirement $.&&&&&&&

    No of #6 bars 3

    Close hoo6 "teel Ah $ 2&'7521'&

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    Design of Column Bracket

    Crushing strength of concrete 5 6si

    !ield "trength of "teel #$ 6si

    %idth of Column &2

    ength of r*cet '

    +ccentricit,- e 5.5

    "erice lo*d /*ctored o*d

    ie lo*d 5& '&.#

    0e*d o*d 25 1$.$&&&.#

    3ori4ont*l force

    22.1

    omin*l "he*r "trength 9.$

    .2

    effectie 0e6th of r*cet- d &5.5

    8ot*l 0e6th of r*cet- h &.$

    "lo6e 75.$ $.'5r*cet 0e6th *t outside- h& 9.$

    $.5d .'

    8ot*l "he*r friction steel- Af &.'

    ending ;oment to uired- Af $.'

     Addition*l steel Are*- An $.5

     As ? Af@An &.1

    &.'275&72'#;inimum "teel re>uirement $.#2

    No of #6 bars 4

    Close hoo6 "teel Ah $ ##72'5&71

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    Com

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    +t Ent

    (4)*!+" i6s

    3+4!' i6s )*3!3" i6s

    9.29 ft

    363,!'

    (3464!) ()4"*!*+

    V*lues *re in inches *nd i6s.

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    0esign of "tri6 /ooting P*d

    Concrete "trength   1 si Concrete Coer 1 in

    "teel !ield "terngth 7$ si 0e6th of /ooting 1 ft

    "*fe e*ring C*6cit, & tonssft %idth of

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    %u &7.#1

    0ist*nce %u "he*r o*d

    free end $ &1.2 $

     A #.5 &1.2 '5.' &15.&'

    #.5 &1.2 79.1' &15.&' 2#.5 &1.2 2&7.#2 259.59

    2#.5 &1.2 77.9 259.59

    C 7#.5 &1.2 2&9.$1 12&.77

    7#.5 &1.2 &$2.7& 12&.77

    0 ##.5 &1.2 &.59 121.79

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    + '#.5 &1.2 &$2.& 12&.77

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    / &$#.5 &1.2 77.## 259.59

    &$#.5 &1.2 2&7.91 259.59G &2#.5 &1.2 79.$ &15.&'

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    $ear Diagram

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    0esign of "tri6 /ooting e*m

    Concrete "trength 2.5 si Concrete Coer 1"teel !ield "terngth 7$ si %idth of /ooting 99

    "*fe e*ring C*6cit, $.5 tonssft %idth of

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    "tri6 #

    einforcements for ositi5e

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    72 19 &12 '&.15 91#.2 #.#2 .$ 9 H'

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    72 19 &12 &$2$.5 &227# '.'## 9.71 &2 H'

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    72 19 &12 &&$&. &122$.7 9.5'7 &$.2&

    einforcements for Negati5e

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    Design of Footing

    Footing Identification = C1Input Data:

    fy = 50 ksi

    f'c = 4 ksi

    Col. side,b = 18 in

    S.Load, SL = 400 k

    F.Load, FL = 61.5 k #VALUE!

    !.Ca"acity,!C = 5 ksf

    #o$ dee" %& = 5 ft

    Footing $idt&, = (.5 ft )*y+ (.56

    Footing -e"t&,- = .5 in )*y+ .5

    /nte* !a* sed = 8 23s = 0.(

    SOLUTION:

    /ffectie !ea*ing Ca"acity

    e = !.C. 0.15 7 & = 4.5 ksf

    3*ea 9 sides of Footing:

    3 = S.L.; e = (1.4 s. ft

    (.56 ft

    Facto*ed Soil ini?? -e"t& of Footing !ased on

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    f@c; ksi

    c; in

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    his condition corres6onds to c ? M *nd e ? $.

    i6s 7I-8 deduction for concrete olume dis6l*ced

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