coeficient g
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Transcript of coeficient g
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7/30/2019 coeficient g
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The general factor of thermal insulation G
This factor of thermal insulation reflects the sum of all thermal loss troughall the building envelope elements for a thermal difference of 1 Kelvin () plus the lossesbecause of ventilation and air infiltration.
GGN
The minimal values GN are given in the following table:
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Where:V represents the inside volume of the building V[m3] ;Rm - represents the average corrected thermal resistance of the building element,
[m2K/W];
;1
==
j
j
j
med
m
R
AUR
[W/m3K];
A The area of the element with the specific main thermal resistance Rm;A[m2];
n represents the ventilation rate (the number of volume changes per hour.n=0,7; 0,8; 0,9 [h-1] according to the degree of win exposure of the building);
The temperature correction factor
;)()(
ei
ui
TTTT
=
Ti=+20CTe represents the external temperature and it is in function of the zone.Tu= +5C;
Tu represents the temperature for indoor un-wormed spaces;
A
l
RRU +=
=
)(11 ;
where:
represents the linear coefficient of temperature losses trough thermal bridges anddepends on the constructive detail of the linear thermal bridge.l- represents the length of the linear thermal bridge where the specific measure the heat
losses (lis determined for one floor and than multiplied with the nr. of similar floors).
F th j t th i th ifi th l b id th t b i l d d i th
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3Vertical joint between envelope wall andinternal shear wall near an opening
1=0.0362=0.20
4Vertical joint between end shear wall andinternal shear wall.
=0.035
5 Horizontal joint at the roof.
1=0.145
2=0.168
6 Current floor horizontal joint.1=0.112=0.10
7 Current floor with balcony horizontal joint.1=0.212=0.20
8 Horizontal joint at the wall base.1=0.152=0.20
9Horizontal joint between internal wall andfloor over basement floor.
=0.029
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The steps to follow in order to determine the general factor of thermal insulation Gare:
1. Elaboration of the building plans and the characteristic cross (vertical) section throughthe building with the specification of the heated spaces perimeter;
2. Estimation of all the specific areas for the elements from the perimeter (envelope) ofthe building.
3. Calculation of the building envelope area and ( A=Aj) the building heated volume (V);4. Evaluation of the indoor unheated temperatures (Tu) by the equations of thermal
balance (for the case of in the project Tu=+5 C) ;5. Estimation of temperature correction factor j;6. Computation of the corrected thermal resistance of the building elements from the eq:
jj A
l
RRU
+=
=
)(11
7. Calculation of the mean thermal resistance of the building elements ;)/(.
=
jj
j
jm RA
AR ;
8. Estimation of the ventilation rate n in the project will consider n=0,7. . . 0,9;9. Assessment of the expression
jjm
j
R
A
,
;
10.Estimation of nR
A
VG
m
+
= 34.0
1 ;
11.Calculation of (A/V) and the resultant GN;
12.Comparison between G and GN
Recommendation:
For a simple and a better conduction of the estimation procedure we recommendorganizing the data and the results in tables, and we suggest some models for the tables
to use in the evaluation process.
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Linearheat loss
Linear bridgelength
AreaThermalresist.
Correctedthermalresist.
Meanthermalresist.
Temp.Correct.factor
Specificpower
Bridge
Detail
l *l A R (*l) R' Rm' (A )Rm'
Currentnum
ber
BuildingElem
ent
_W
m*Km
WK
mm*K
WWK
m*KW
m*KW
1 2 3 4 5 6=4*5 7 8 9=611=1/(1/8+7/
9)12=7/(7/9) 13 14=7*13/12
10,065
0,2844,8
3,588
15,456
2
4
6
1 External Wall
5
586,08
3,39
(arithmeticmean of R)
(R1+R2+R3)/3
1
52
Floor over thebasement
8
(R1+R)/2
3 Roof 5 1
4 Windows & Doors 9 1
Need for G . . . . . . . . . .