Class XI BIO Group - Synthesis Bikaner€¦ · The OMR Sheet is kept inside the Test Booklet. When...

Student Name :...................................................................... Roll No. :.................................................

Date : 15/01/2017 Time: 3.00 hrs. Max Marks: 180×4=720

INSTRUCTIONS funsZ'k

1. Immediately fill in the particulars on this page of theTest Booklet with Blue/Black Ball Point Pen.

2. The OMR Sheet is kept inside the Test Booklet. Whenyou are directed to open the Test Booklet, take outthe OMR Sheet and fill in the particulars carefully.

3. The test is of 3.00 hours duration.4. The Test Booklet consists of 180 questions. The

maximum marks are 720.5. There are three sections in the question paper A,

B, C consisting of Physics, Chemistry , Botany &Zoology having 45 questions in each section ofequal weightage. Each question is allotted 4 (four)marks for correct response.

6. Candidates will be awarded marks as stated above ininstruction 5 for correct response of each question.1/4 (one forth) marks will be deducted for indicatingincorrect response of each question. No deductionfrom the total score will be made if no response isindicated for an item in the OMR sheet.

7. There is only one correct response for each question.Filling up more than one response in each questionwill be treated as wrong response and marks forwrong response will be deducted accordingly as perinstruction 6 above.

8. Use Blue/Black Ball Point Pen only for writingparticulars/marking responses on OMR Sheet.

9. No candidate is allowed to carry any textual material,

printed or written bits of papers, pager, mobile phone,

any electronic device etc. inside the examination room.

10. Rough work is to be done on the space provided forthis purpose in the Test Booklet only.

11. On completion of the test, the candidate must handover the OMR Sheet to the Invigilator on duty in theRoom. However, the candidates are allowed to takeaway this Test Booklet with them.

1. ijh{kk iqfLrdk ds bl i"B ij vko';d fooj.k uhys] dkys ckWyIokbaV isu ls rRdky HkjsaA

2. mŸkj i= (OMR) bl ijh{kk iqfLrdk ds vUnj j[kk gSA tcvkidks ijh{kk iqfLrdk [kksyus dks dgk tk,] rks mŸkj i=fudky dj lko/kkuhiwoZd fooj.k HkjsaA

3. ijh{kk dh vof/k 3.00 ?kaVs gSA4. bl ijh{kk iqfLrdk esa 180 iz'u gSA vf/kdre vad 720 gSA

5. bl ijh{kk iqfLrdk esa rhu Hkkx A, B, C gSa] ftuds izR;sd Hkkxesa HkkSfrd foKku] jlk;u foKku] ouLifr foKku rFkktho foKku ds 45 iz'u gSa vkSj lHkh iz'uksa ds vad leku gSAizR;sd iz'u ds lgh mŸkj ds fy, 4 (pkj) vad fu/kkZfjr fd;sx;s gSaA

6. vH;fFkZ;ksa dks izR;sd lgh mŸkj ds fy, mijksDr funsZ'ku la[;k5 ds vuqlkj ekDlZ fn;s tk;saxsA izR;sd iz'u ds xyr mŸkj dsfy;s 1/4 oka Hkkx dkV fy;k tk;sxkA ;fn mŸkj esa fdlh iz'udk mŸkj ugh fn;k x;k gks rks dqy izkIrkad ls dksbZ dVkSrh ughdh tk;sxhA

7. izR;sd iz'u dk dsoy ,d gh lgh mŸkj gSA ,d ls vf/kd mŸkj

nsus ij mls xyr mŸkj ekuk tk;sxk vkSj mijksDr funsZ'k 6

ds vuqlkj vad dkV fy;s tk;saxsA

8. mŸkj iqfLrdk esa dsoy uhys@dkys isu dk gh iz;ksx djsaA

9. ijh{kkFkhZ }kjk ijh{kk d{k@gkWy esa izos'k dkMZ ds vykok fdlhHkh izdkj dh ikB~; lkexzh] eqfnzr ;k gLrfyf[kr] dkxt dhifpZ;k¡] istj] eksckby] Qksu ;k fdlh Hkh izdkj ds bysDVªkWfudmidj.kksa ;k fdlh vU; izdkj dh lkexzh dks ys tkus ;kmi;ksx djus dh vuqefr ugha gSA

10. jQ dk;Z ijh{kk iqfLRkdk esa dsoy fu/kkZfjr txg ij dhft,A11. ijh{kk lekIr gksus ij] ijh{kkFkhZ d{k@gkWy NksM+us ls iwoZ mŸkj

i= d{k fujh{kd dks vo'; lkSai nsaA ijh{kkFkhZ vius lkFk blijh{kk iqfLrdk dks ys tk ldrs gSaA

ClassXI

BIOGroup

"Gyan Tower" Plot No. 1,2 , Near Shivbari Circle, Old Shivbari Road, Bikaner (0151-2206735, 2233735, Mob : 80030948 - 91/92/93,)

Class : XI Page - 2

1. The energy (E), angular momentum (L) anduniversal gravitational constant (G) are chosen asfundamental quantities. The dimension of universalgravitational constant in the dimensional formulaof Planck's constant (h) is :(1) 0 (2) –1(3) 5/3 (4) 1

2. In the relation, z/kP e?? ??

?? , where P is pressure, z

is distance, k is Boltzmann's constant and istemperature. The dimensional formula for is :

(1) 0 2 0M L T? ?? ? (2) 2M L T? ?? ?

(3) 0 1M L T?? ?? ? (4) 0 2 1M L T?? ?? ?

3. A

and B

are two vectors given by ˆ ˆA 2i 3j? ?

and ˆ ˆB i j? ?

. The magnitude of the component

of A

along B

is :

(1) 52

(2) 32

(3) 72

(4) 12

4. A particle located at x=0 at time t=0, starts movingalong the positive, x-direction with a velocity 'v'

that varies as v x? ? . The displacement of the

particle varies with time as :(1) t1/2 (2) t3

(3) t2 (4) t

5. A particle moves with velocity ? ?ˆ ˆv K yi xj? ?

,

where K is constant. The general equation for itspath is :(1) y2=x2+constant (2) y=x2+constant(3) y2=x+constant (4) xy=constant

6. From an elevated point P, a stone is projectedvertically upwards. When the stone reaches adistance h below P, its velocity is double of its velocityat a height h above P. The greatest height attainedby the stone from the point of projection P is :

(1) 3

h5

(2) 5

h3

(3) 7

h5

(4) 5

h7

1. ÅtkZ (E), dks.kh; laosx (L) rFkk lkoZf=d xq:Rokd"kZ.kfu;rkad (G) dks ewy jkf'k;k¡ ysus ij Iykad fu;rkad (h)ds foeh; lw= esa xq:Rokd"kZ.k fu;rakd dh foek;sa gksxh :

(1) 0 (2) –1(3) 5/3 (4) 1

2. lEcU/k z/kP e?? ??

?? , tgk¡ P nkc, z nwjh, k cksYVteku

fu;rkad rFkk rkieku gS] esa dh foek;sa gksxh :

(1) 0 2 0M L T? ?? ? (2) 2M L T? ?? ?

(3) 0 1M L T?? ?? ? (4) 0 2 1M L T?? ?? ?

3. A

rFkk B

nks lfn'k ˆ ˆA 2i 3j? ?

rFkk ˆ ˆB i j? ?

}kjk

fn;s tkrs gSA A

ds B

ds vuqfn'k ?kVd dk ifjek.k gksxk:

(1) 5

2(2)

3

2(3)

7

2(4)

1

2

4. ,d d.k x=0 ij le; t=0 ij fLFkr gS rFkk ;g/kukRed x-v{k fn'kk esa osx 'v' ls bl izdkj pyrk gS fd

v x? ? . d.k dk foLFkkiu le; ds lkis{k fdl izdkjifjofrZr gksxk :(1) t1/2 (2) t3

(3) t2 (4) t

5. ,d d.k osx ? ?ˆ ˆv K yi xj? ?

ls xfr djrk gS, tgk¡ K

fu;rkad gSA d.k ds iFk dh lehdj.k gksxh :

(1) y2=x2+fu;krad (2) y=x2+fu;krad(3) y2=x+fu;krad (4) xy=fu;krad

6. fdlh iRFkj dks Å¡pkbZ ij fLFkr fcUnq P ls bl izdkjÅ/okZ/kj Åij dh vksj iz{ksfir fd;k tkrk gS fd fcUnq Pls h Å¡pkbZ uhps bldk osx, h Å¡pkbZ ij blds osx dknksxquk gSA fcUnq P ls iRFkj }kj izkir dh xbZ vf/kdreÅ¡pkbZ gksxh :

(1) 3

h5

(2) 5

h3

(3) 7

h5

(4) 5

h7


Class : XI Page - 3

7. A particle is placed at the origin and a force F=Kx isacting on it, where K is a positive constant. If U(0)=0,the graph of U(x) versus x will be : (where U is thepotential energy function)

(1) (2)

(3) (4)

8. A string of negligible mass going over a clampedpulley of mass 'm' supports a block of mass M asshown in the figure. The force on the pulley by theclamp is given by :

(1) 2 Mg

(2) 2 mg

(3) ? ?2 2M m m g? ?? ?? ?? ?

(4) ? ?2 2M m M g? ?? ?? ?? ?

9. A block of mass 2 kg is free to move along the x-axis. It is at rest and from t=0 onwards it is subjectedto a time-dependent force F(t) in the x-direction.The force F(t) varies with 't' as shown in the figure.The kinetic energy of the block after 4.5 seconds,is :

(1) 4.50 J(2) 7.50 J(3) 5.06 J(4) 14.06 J

7. ,d d.k ewy fcUnq ij fLFkr gS rFkk bl ij ,d cyF=Kx dk;Z dj jgk gS tgk¡ K /kukRed fu;rkad gSA ;fnU(0)=0 gks rks U(x) rFkk x ds e/; dk vkjs[k gksxk :(tgk¡ U fLFkfrt ÅtkZ dk Qyu gS )

(1) (2)

(3) (4)

8. ux.; nzO;eku dh ,d Mksjh dk ,d fljk nhokj ls tqM+k gSrFkk nwljk fljk nzO;eku 'm' okyh ,d tM+ f?kjuh ls gksrkgqvk nzO;eku M ds ,d CykWd ls fp=kuqlkj tqM+k gSA f?kjuhDysEi ls tqM+h gSA DysEi }kjk f?kjuh ij vkjksfir cy gksxk

(1) 2 Mg

(2) 2 mg

(3) ? ?2 2M m m g? ?? ?? ?? ?

(4) ? ?2 2M m M g? ?? ?? ?? ?

9. nzO;eku 2 kg dk ,d CykWd x-v{k ds vuqfn'k xfr djusgsrq Lora= gSA ;g t=0 ij fojkekoLFkk eas fLFkr gS] rFkkblds i'pkr~ bl ij ,d le; vkfJr cy F(t) /kukRedx-fn'kk eas dk;Z djrk gSA fp= esa cy F(t) dk le; 't' dslkFk vkjs[k fn[kk;k x;k gSA 4.5 lSds.M i'pkr~ CykWddh xfrt ÅtkZ gksxh :(1) 4.50 J(2) 7.50 J(3) 5.06 J(4) 14.06 J


Class : XI Page - 4

10. A space-craft of mass 100 kg breaks into two, whenits velocity is 104 ms–1. After the break, a mass of10 kg of the space-craft is left stationary. Thevelocity of the remaining part is :

(1) 103 ms–1 (2) 11.11×103 ms–1

(3) 11.11×102 ms–1 (4) 104 ms–1

11. A mass 10 kg moving with a speed 10 cm/s on asmooth horizontal surface hits a spring as shown infigure. Work done by the spring force on the massis :

(1) 0.05 J (2) –0.05 J(3) –0.1 J (4) 0.1 J

12. Potential energy of a 1 kg particle free to move

along X-axis is given by ? ?4 2x x

V x joule4 2

? ?? ?? ?? ?

Total mechanical energy of the particle is 2 joule.Then the maximum speed in m/s is :

(1) 2 (2) 3

2(3) 2 (4)

1

2

13. An ideal spring with spring constant k is hung fromthe ceiling and a block of mass M is attached to itslower end. The mass is released with the springinitially unstretched. Then, the maximum extensionin the spring is :

(1) 4Mgk

(2) 2Mgk

(3) Mgk

(4) Mg2k

14. The centre of mass of a non-uniform rod of lengthL whose mass per unit length varies as

2k xL?? ? where k is a constant and x is the

distance of any point from one end is :

(1) 3

L4

(2) 1

L4

(3) kL

(4) 3kL

10. nzO;eku 100 kg dk ,d varfj{k ;ku nks VqdM+ksa eas VwVtkrk gS rFkk bl le; bldk osx 104 ms–1 gSA VwVus dsrqjar i'pkr~ 10 kg nzO;eku okyk vUrfj{k ;ku dk VqdM+kfojkekoLFkk izkIr djrk gSA vUrfj{k ;ku ds 'ks"k Hkkx dkosx gksxk :(1) 103 ms–1 (2) 11.11×103 ms–1

(3) 11.11×102 ms–1 (4) 104 ms–1

11. nzO;eku 10 kg dk ,d CykWd {kSfrt ?k"kZ.k jfgr /kjkryij 10 cm/s dh pky ls pyrk gqvk ,d fLizax ls fp=kuqlkjVdjkrk gSA bl nzO;eku ij fLiazx cy }kjk fd;k x;kdk;Z gksxk :

(1) 0.05 J (2) –0.05 J(3) –0.1 J (4) 0.1 J

12. nzO;eku 1 kg dk ,d d.k X-v{k ds vuqfn'k xfr djusgsrq Lora= gSA bldh fLFkfrt ÅtkZ dk Qyu

? ?4 2x x

V x joule4 2

? ?? ?? ?? ?

}kjk fn;k tkrk gSA

;fn bldh dqy ;kaf=d ÅtkZ 2 joule gS] rks bldhvf/kdre pky m/s esa gksxh :

(1) 2 (2) 32

(3) 2 (4) 12

13. cy fu;arkad k okyh ,d vkn'kZ fLizax dk ,d fljk Nrls tqM+k gS rFkk nwljs fljs ij ,d nzO;eku M dk CykWdyVdk gSA izkjEHk esa fLiazx esa dksbZ f[kapko ugha gS vkSjnzO;eku dks eqDr fd;k tkrk gSA fLiazx esa vf/kdre izlkjgksxk :

(1) 4Mgk

(2) 2Mgk

(3) Mgk

(4) Mg2k

14. yEckbZ L rFkk vleku vuqizLFk dkV {ks=Qy okyh NM+

dh izfr ,dkad yEckbZ dk nzO;eku 2k x

L?? ? gS tgk¡ k

,d fu;rkad gS vkSj x fdlh fcUnq dh ,d fljs ls nwjh gSAbldk nzO;eku dsUnz gksxk :

(1) 3

L4

(2) 1

L4

(3) kL

(4) 3kL


Class : XI Page - 5

15. A particle of mass 'm' is projected from ground withan initial speed u0 at an angle with horizontal. Atthe highest point of its trajectory, it makes acomplete inelastic collision with another identicalparticle, which was thrown vertically upward fromthe ground with the same initial speed u0. The anglethat the composite system makes with thehorizontal immediately after the collision is :

(1) 4?

(2) 4? ? ?

(3) 4? ? ? (4)

2?

16. The kinetic energy T of a particle of mass 'm' movingin a circle of radius 'r' varies with the distance traced,S as T=KS2. The tangential acceleration of theparticle is :

(1) 2KS

m(2)

2KSm

(3) 3KS

3m(4)

22KSr

17. Four point masses, each of value m, are placed atthe corners of a square ABCD of side . The momentof inertia of this sytem about an axis passing throughA and parallel to BD is :

(1) 3 m2 (2) m2 (3) 2 m2 (4) 3 m2

18. An equilateral prism of mass 'm' rests on a roughhorizontal surface with coefficient of friction . Ahorizontal force F is applied on the prism as shownin the figure. If the coefficient of friction is sufficientlyhigh so that the prism does not slide beforetoppling, then the minimum force required to topplethe prism is :

(1) mg

3(2)

mg4

(3) mg

3

?(4)

mg4

?

15. nzO;eku 'm' ds ,d d.k dks /kjkry ls izkjfEHkd pky u0

ls {kSfrt ls dks.k ij iz{ksfir fd;k tkrk gSA vius iFkds mPpre fcUnq ij ;g leku nzO;eku ds ,d ,sls d.kls iw.kZr;k vizR;kLFk VDdj djrk gS ftls /kjkry lsÅ/okZ/kj Åij dh vksj u0 pky ls iz{ksfir fd;k x;k gSAVDdj ds i'pkr~ nksuksa d.kksa ds fudk; dh xfr {kSfrt lsfdruk dks.k cuk;sxh :

(1) 4?

(2) 4? ? ?

(3) 4? ? ? (4)

2?

16. nzO;eku 'm' ds ,d d.k dh xfrt ÅtkZ T, tc ;g f=T;k'r' ds oÙk ij ?kwe jgk gS] nwjh S ds lkis{k T=KS2 }kjkifjofrZr gksrh gSA d.k dk Li'kZ js[kh; Roj.k gksxk :

(1) 2KS

m(2)

2KSm

(3) 3KS

3m(4)

22KSr

17. nzO;eku m ds pkj fcUnq d.kksa dks oxZ ABCD ds izR;sddksus ij j[kk x;k gS ftldh Hkqtk gSA bl fudk; dkfcUnq A ls xqtjus okyh rFkk BD ds lekUrj v{k dslkis{k tM+Ro vk?kw.kZ gksxk :

(1) 3 m2 (2) m2 (3) 2 m2 (4) 3 m2

18. nzO;eku 'm' dk ,d leckgq fizTe ?k"kZ.k xq.kkad okys{kSfrt /kjkry ij fLFkr gSA bl fizTe ij fp=kuqlkj ,d{kSfrt cy F vkjksfir fd;k tkrk gSA ;fn ?k"kZ.k xq.kkaddk eku fcuk fQlys fizTe dks iyVus gsrq i;kZIr gS] rksfizTe dks iyVus gsrq vko';d U;wure cy gksxk :

(1) mg

3(2)

mg4

(3) mg

3

?(4)

mg4

?


Class : XI Page - 6

19. A solid sphere is rolling without slipping on ahorizontal surface. The ratio of its rotational kineticenergy to its translational kinetic energy is :(1) 2/9 (2) 2/7(3) 2/5 (4) 7/2

20. A system of binary stars of masses mA and mB aremoving in circular orbits of radii rA and rB

respectively. If TA and TB are the time periods ofmasses mA and mB respectively, then :

(1)

3/2

A A

B B

T rT r

? ?? ? ?? ?

(2) TA > TB (if rA > rB)

(3) TA > TB (if mA > mB) (4) TA = TB

21. Maximum height reached by a rocket firedperpendicular to the surface of the earth with aspeed equal to 50% of the escape velocity fromearth surface is :

(1) R2

(2) 16R

9(3)

R3

(4) R8

22. A point mass 'm' and a thin uniform rod of mass Mand length are located along a straight line asshown in figure. What is the poential energy ofgravitational interaction of this sytem ?

(1) GMm a

n 1? ?? ?? ?? ?

(2)

GMmn 1

a? ?? ?? ?? ?

(3) GMm a

1? ?? ?? ?? ? (4) ? ?

GMma / 2

??

23. Two planets have radii r1 and r2 and densities d1

and d2 respectively. The ratio of the accelerationdue to gravity on them will be :

(1) 1 2 2 1r d : r d

(2) 1 1 2 2r d : r d

(3) 2 21 1 2 2r d : r d

(4) 2 21 1 2 2r d : r d

19. ,d Bksl xksyk fdlh {kSfrt /kjkry ij fcuk fQlysyq<+d jgk gSA bldh ?kw.kZu xfrt ÅtkZ rFkk LFkkukUrj.kxfrt ÅtkZvksa dk vuqikr gksxk :(1) 2/9 (2) 2/7(3) 2/5 (4) 7/2

20. f}rkjk fudk; ds nks rkjksa ds nzO;eku mA rFkk mB gS] tksØe'k% oÙkkdkj d{kkvksa ftudh f=T;k;sa rA rFkk rB gS] esapDdj yxk jgs gSA ;fn buds vkorZdky Øe'k% TA , TB

gksa rks :

(1)

3/2

A A

B B

T rT r

? ?? ? ?? ?

(2) TA > TB (;fn rA > rB)

(3) TA > TB (;fn mA > mB) (4) TA = TB

21. iFoh /kjkry ls Å/okZ/kj Åij dh vksj iyk;u osx ds50% osx ls iz{ksfir fd;s x;s jkWdsV }kjk izkIr vf/kdreÅ¡pkbZ gksxh :

(1) R2

(2) 16R

9(3)

R3

(4) R8

22. fcUnq nzO;eku 'm' rFkk nzO;eku M vkSj yEckbZ okyh ,diryh NM+ fp=kuqlkj ,d gh js[kk ij O;ofLFkr gSA blfudk; dh xq:Rokd"kZ.k fLFkfrt ÅtkZ gksxh ?

(1) GMm a

n 1? ?? ?? ?? ?

(2)

GMmn 1

a? ?? ?? ?? ?

(3) GMm a

1? ?? ?? ?? ? (4) ? ?

GMma / 2

??

23. nks xzgksa dh f=T;k;sa r1 rFkk r2 ,oe~ Øe'k% ?kuRo d1 rFkkd2 gSA bu xzgksa ij xq:Rokd"kZ.k Roj.kksa dk vuqikr gksxk:

(1) 1 2 2 1r d : r d

(2) 1 1 2 2r d : r d

(3) 2 21 1 2 2r d : r d

(4) 2 21 1 2 2r d : r d


Class : XI Page - 7

24. Four particles, each of mass m, are placed at thefour corners of a square of side 'a'. Force exertedby this system on another particles of mass 'm'placed at the midpoint of a side of square is :

(1) 2

2

16Gm

5 5a(2)

2

2

16Gm5 3 a

(3) 2

2

16Gm5a (4) zero

25. A thin uniform annular disc of mass M has outerradius 4R and inner radius 3R. The work requiredto take a unit mass from point P on its axis to infinityis :

(1) ? ?2GM4 2 5

7R? (2) ? ?2GM

4 2 57R

? ?

(3) GM4R

(4) ? ?2GM2 1

5R?

26. Gravitational potential on the surface of earth is V.Gravitational potential at the centre of earth is then

(1) V (2) 3

V2

(3) 2

V3

(4) zero

27. An inverted (bell) lying at the bottom of a lake 47.6m deep has 50 cm3 of air trapped in it. The bell isbrought to the surface of the lake. The volume ofthe trapped air will be (atmospheric pressure =70cm of Hg and density of Hg = 13.6 g/cm3)(1) 350 cm3 (2) 300 cm3

(3) 250 cm3 (4) 22 cm3

24. pkj d.k, izR;sd nzO;eku m fdlh oxZ ds ,d&,d dksusij j[ks x;s gS ftldh Hkqtk 'a' gSA bl fudk; }kjknzO;eku 'm' ds ml d.k ij vkjksfir cy D;k gksxk ftlsfdlh ,d Hkqtk ds e/; fcUnq ij j[kk x;k gS :

(1) 2

2

16Gm

5 5a(2)

2

2

16Gm5 3 a

(3) 2

2

16Gm5a (4) 'kwU;

25. ,d iryh [kks[kyh oy; dk nzO;eku M rFkk ckgjh vksjHkhrjh f=T;k;sa Øe'k% 4R rFkk 3R gSA bldh v{k ijfLFkr fcUnq P ls fdlh ,dkad nzO;eku dks vuUr rdHkstus gsrq vko';d dk;Z gksxk :

(1) ? ?2GM4 2 5

7R? (2) ? ?2GM

4 2 57R

? ?

(3) GM4R

(4) ? ?2GM2 1

5R?

26. iFoh /kjkry ij xq:Rokd"kZ.k fOkHko V gSA iFoh ds dsUnzij xq:Rokd"kZ.k foHko gksxk

(1) V (2) 3

V2

(3) 2

V3

(4) 'kwU;

27. fdlh 47.6 m xgjh >hy dh ryh esa 50 cm3 vk;ru okyh,d ?k.Vh mYVh j[kh gSA bl ?k.Vh dks >hy dh lrg rdyk;k tkrk gSA >hy dh lrg ij bl ?k.Vh esa fufgr ok;q dkvk;ru D;k gks tk;sxk (ok;qe.Myh; nkc = ikjs ds 70 cmLrEHk ds nkc ds cjkcj rFkk ikjs dk ?kuRo = 13.6 g/cm3 )(1) 350 cm3 (2) 300 cm3

(3) 250 cm3 (4) 22 cm3


Class : XI Page - 8

28. Water is filled up to a height 'h' in a beaker of radiusR as shown in the figure. The density of water is ,the surface tension of water is T and theatmospheric presssure is P0. Consider a verticalsection ABCD of the water column through adiameter of the beaker. The force on water on oneside of this section by water on the other side ofthis section has magnitude

(1) 202P Rh R gh 2RT? ? ? ?

(2) 202P Rh R gh 2RT? ? ?

(3) 2 20P R R gh 2RT? ? ? ?

(4) 2 20P R R gh 2RT? ? ? ?

29. A liquid is kept in a vertical cylindrical vessel which isrotated along its axis. The liquid rises at the sides. Ifthe radius of vessel is 'r' and the speed of revolutionis 'n' rotation/sec, find the difference in height ofliquid at the centre of vessel and its sides

(1) 2 2 22 n r

hg

?? (2) 2 2 24 n r

hg

??

(3) 2 22 n r

hg

?? (4) 2 24 n r

hg

??

30. A spherical liquid drop of radius R is divided intoeight equals droplets. If surface tenstion T, thenwork done in the process will be :

(1) 22 R T? (2) 23 R T?(3) 24 R T? (4) 22 RT?

28. f=T;k R okys ,d chdj esa h Å¡pkbZ rd ikuh fp=kuqlkjHkj k t kr k gSA i kuh d k ?kuRo gS rFkk i"B ruko T gS ,oaok;qe.Myh; nkc P0 gSA bl chdj ds O;kl ds vuqfn'k,d m/okZ/kj LraHk ABCD dh ty ds Hkhrj dYiuk djsaAbl LrEHk ds ,d vksj fLFkr ty }kjk nwljh vksj fLFkrty ij vkjksfir cy dk ifjek.k gksxk

(1) 202P Rh R gh 2RT? ? ? ?

(2) 202P Rh R gh 2RT? ? ?

(3) 2 20P R R gh 2RT? ? ? ?

(4) 2 20P R R gh 2RT? ? ? ?

29. fdlh nzo dks Å/okZ/kj csyukdkj ik= esa Hkjk x;k gS rFkk;g ik= viuh v{k ds ifjr ?kw.kZu dj jgk gSA nzo fdukjksaij Åij p<+ tkrk gSA ik= dh f=T;k 'r' gS rFkk ?kw.kZudh pky 'n' [email protected] gS, ik= eas dsUnz ij rFkkfdukjksa ij nzo dh Å¡pkbZ eas vUrj gksxk

(1) 2 2 22 n r

hg

?? (2) 2 2 24 n r

hg

??

(3) 2 22 n r

hg

?? (4) 2 24 n r

hg

??

30. f=T;k R okyh ,d xksykdkj nzo cwan vkB NksVh cwanksa esa VwVtkrh gSA ;fn nzo dk i"B ruko T gS, rks bl izØe esafd;k x;k dk;Z gksxk :(1) 22 R T? (2) 23 R T?(3) 24 R T? (4) 22 RT?

mailto:[email protected]


Class : XI Page - 9

31. A beam of metal supported at the two ends is loadedat the centre. The depression at the centre isproportional to :(1) Y2 (2) Y (3) 1/Y (4) 1/Y2

32. A rod of length L is hinged from one end. It isbrought to a horizontal position and released. Theangular velocity of the rod when it is in verticalposition is :

(1) 2g / L (2) 3g / L

(3) g / 2L (4) g / L

33. If a solid sphere, a disc and a hollow sphere areallowed to roll down an incline plane from the sameheight :(1) hollow sphere will reach the bottom first(2) disc will reach the bottom first(3) sphere will reach ther bottom first(4) all will reach the bottom at the same time

34. In a two-particle system with particle masses m1

and m2, the first particle is pushed towards thecentre of mass through a distanced 'd', the distancethrough which second particle must be moved tokeep centre of mass at the same position is :

(1) 1

2

m dm (2) d

(3) ? ?1

1 2

m dm m? (4)

? ?1 2m m dm?

35. A small sphere A of radius 'r' rolls without slippinginside a large hemispherical bowl of radius R as shownin figure. If the sphere starts from rest at the toppoint of the hemisphere find the normal forceexerted by the small sphere on the hemispherewhen it is at the bottom B of the hemisphere :

(1) 17

mg7

(2) 2

mg5

(3) 5

mg7

(4) 7

mg5

31. /kkrq dh fdlh che dks nks fljksa ls tM+ fd;k tkrk gS rFkkblds chp esa Hkkj yVdk;k tkrk gSA dsUnzh; Hkkx esamRiUu >qdko lekuqikrh gksxk :(1) Y2 (2) Y (3) 1/Y (4) 1/Y2

32. fdlh ,d fljs ls fdyfdr dh xbZ ,d L yEckbZ dh NM+dks {kSfrt voLFkk ls eqDr fd;k tkrk gSA ftl le; NM+Å/okZ/kj gksxh bldk dks.kh; osx gksxk :

(1) 2g / L (2) 3g / L

(3) g / 2L (4) g / L

33. ,d Bksl xksyk] ,d pdrh rFkk ,d [kks[kys xksys dksfdlh urry ds 'kh"kZ ls eqDr fd;k tkrk gS :

(1) vk/kkj ij lcls igys [kks[kyk xksyk igq¡psxk(2) vk/kkj ij lcls igys pdrh igq¡psxh(3) vk/kkj ij lcls igys Bksl xksyk igq¡psxk(4) rhuksa oLrq,sa vk/kkj ij ,dlkFk igq¡psxh

34. fdlh f}&d.k fudk; esa d.kksa ds nzO;eku m1 rFkk m2

gSA izFke d.k dks nzO;eku dsUnz dh rjQ 'd' nwjh /kdsyktkrk gSA nwljs d.k dks fdruh nwjh rd /kdsyk tk;s rkfdnzO;eku dsUnz dh fLFkfr ogh jgs :

(1) 1

2

m dm (2) d

(3) ? ?1

1 2

m dm m? (4)

? ?1 2m m dm?

35. r f=T;k dk ,d NksVk xksyk A fdlh cM+s v)Zxksys dsHkhrj fcuk fQlys yq<+d jgk gSA v)Zxksys dh f=T;k RgSA ;fn NksVk xksyk v)Zxksys ds 'kh"kZ fcUnq ls yq<+dukvkjEHk djs rks v)Zxksys ds vk/kkj fcUnq B ij igq¡pus ijblds }kjk v)Zxksys ij vkjksfir vfHkyEc izfrfØ;k cygksxk :

(1) 17

mg7

(2) 2

mg5

(3) 5

mg7

(4) 7

mg5


Class : XI Page - 10

36. A bullet loses 1n

of its speed as it passes through a

plank. Number of such planks required to stop thebullet are :

(1) n (2) 2n

2n 1?

(3) n

n 1? (4) n n?

37. A 2kg block slides on a horizontal floor with a speedof 4 m/s. It strikes an uncompressed spring andcompresses it till the block is motionless. The kineticfriction force is 15 N and spring constant is 10,000N/m. The spring compresses by :(1) 5.5 cm (2) 2.5 cm(3) 11.0 cm (4) 8.5 cm

38. Two particles are projected simultaneously fromtwo points O and O' such that d is the horizontaldistance 'h' is the vertical distance between themas shown in the figure. They are projected at thesame inclination to the horizontal with the samevelocity v. The time after which their separationbecomes minimum is :

(1) d

v cos ? (2) 2d

v cos ?

(3) d

2v cos ? (4) dv

36. fdlh r[rs eas ls xqtjus ij ,d xksyh dh pky dk 1n

Hkkx

[kpZ gks tkrk gSA xksyh dks jksdus gsrq ,sls fdrus rRoksa dhvko';drk iM+sxh :

(1) n (2) 2n

2n 1?

(3) n

n 1? (4) n n?

37. nzO;eku 2kg dk ,d CykWd fdlh {kSfrt /kjkry ij4 m/s dh pky ls fQly jgk gSA ;g fdlh fLizax lsVdjkrk gS rFkk bls rc rd laihfM+r djrk gS tc rd dhxfr :d uk tk;sA xfrd ?k"kZ.k 15 N rFkk fLiazx dkfu;rakd 10,000 N/m gS] rks fLiazx esa laihM+u gksxk :(1) 5.5 cm (2) 2.5 cm(3) 11.0 cm (4) 8.5 cm

38. nks d.kksa dks ,dlkFk fcUnqvksa O rFkk O' ls bl izdkjiz{ksfir fd;k tkrk gS fd d {kSfrt gS rFkk 'h' muds e/;fp=kuql kj Å /okZ/kj nwj h gSA mUgsa {kSfr t l s l eku d ks. k ij leku osx v ls iz{ksfir fd;k tkrk gSA fdrus le;i'pkr~ muds e/; nwjh U;wure gksxh :

(1) d

v cos ? (2) 2d

v cos ?

(3) d

2v cos ? (4) dv



39. Given in the figure are two blocks A and B of weight20 N and 100 N, respectively. These are beingpressed against a wall by a force F as shown. If thecoefficient of friction between the blocks is 0.1 andbetween block B and the wall is 0.15, the firctionalforce applied by the wall on block B is :

F A B

(1) 120 N (2) 150 N(3) 100 N (4) 80 N

40. A particle of mass 'm' moving in the x-direction withspeed 2v is hit by another particle of mass 2mmoving in the y-direction with speed v. If the collisionis perfectly inelastic, the percentage loss in theenergy during the collision is close to :(1) 56% (2) 62%(3) 44% (4) 50%

41. From a solid sphere of mass M and radius R a cubeof maximum possible volume is cut. Moment ofinertia of cube about an axis passing through itscentre and perpendicular to one of its faces is :

(1) 24MR

9 3?(2)

24MR

3 3?

(3) 2MR

32 2?(4)

2MR

16 2?42. What is the minimum energy required to launch a

satellite of mass 'm' from the surface of a planet ofmass M and radius R in a circular orbit at an altitudeof 2R ?

(1) GmM2R

(2) GmM3R

(3) 5GmM

6R(4)

2GmM3R

39. fp= esa nks CykWd A rFkk B n'kkZ;s x;s gS ftuds Hkkj Øe'k%20 N rFkk 100 N gSA bUgsa fdlh Å/okZ/kj nhokj ij ,d{kSfrt cy F }kjk fp=kuqlkj nck;k tkrk gSA ;fn nksuksaCykWdksa ds e/; ?k"kZ.k xq.kkad 0.1 rFkk CykWd B vkSj nhokjds e/; ?k"kZ.k xq.kkad 0.15 gks, rks nhokj }kjk CykWd B ijvkjksfir ?k"kZ.k cy gksxk :

F A B

(1) 120 N (2) 150 N(3) 100 N (4) 80 N

40. nzO;eku 'm' dk ,d d.k x-fn'kk esa pky 2v ls pyrk gqvk,sls d.k ls Vdjkrk gS ftldk nzO;eku 2m gS rFkk ;g y-fn'kk eas pky v ls py jgk gSA ;fn ;g VDdj iw.kZr;kvizR;kLFk gS] rks VDdj esa gqbZ izfr'kr ÅtkZ gkfu gksxh :(1) 56% (2) 62%(3) 44% (4) 50%

41. nzO;eku M rFkk f=T;k R okys ,d Bksl xksys esa lsvf/kdre laHko vk;ru dk ?ku dkV fy;k x;k gSA bl?ku ds ,d Qyd ds yEcor~ rFkk blds dsUnz ls xqtjusokyh v{k ds ijr ?ku dk tM+Ro vk?kwZ.k gksxk :

(1) 24MR

9 3?(2)

24MR

3 3?

(3) 2MR

32 2?(4)

2MR

16 2?42. nzO;eku m ds ,d mixzg dks nzO;eku M rFkk f=T;k R

okys xzg dh lrg ls 2R Å¡pkbZ ij fLFkr oÙkkdkj d{kkesa LFkkfir djus gsrq vko';d U;wure ÅtkZ gksxh ?

(1) GmM2R

(2) GmM3R

(3) 5GmM

6R(4)

2GmM3R



43. The length of a metal wire is L1 when the tension isT1 and L2 when the tension is T2. The unstretchedlength of the wire is :

(1) 1 2L L2?

(2) 1 2L L

(3) 2 1 1 2

2 1

T L T LT T

?? (4)

2 1 1 2

2 1

T L T LT T

??

44. The lower end of a glass capillary tube is dipped inwater. Water rises to a height of 8 cm. The tube isthen broken at a height of 6 cm. The height ofwater column and angle of contact will be :

(1) 1 36m,sin

4? (2) 1 3

6m,cos4

?

(3) 1 14m,sin

2? (4) 1 3

4m,cos4

?

45. An open glass tube is immersed in mercury in sucha way that a length of 8 cm extends above themercury level. The open end of the tube is thenclosed and sealed and the tube is raised verticallyup by additinal 46 cm. What will be length of the aircolumn above mercury in the tube now ?(Atmospheric pressure = 76 cm of Hg)(1) 6 cm (2) 16 cm(3) 22 cm (4) 38 cm

46. 2.8 gm of N2 gas at 300 K and 20 atm was allowedto expand isothermally and irreverssibly at a constantexternal pressure of 1 atm unitl the pressure of gasreaches 1 atm. Calculate work done by the system:(1) –237.04 Joule (2) –240.83 Joule(3) +240.83 Joule (4) –1083.83 Joule

47. Which is correct order of stability

(1) 2 2Be CN O NO? ? ?? ? ?

(2) 2 2O NO CN Be? ? ?? ? ?

(3) 2 2Be O CN NO? ? ?? ? ?

(4) 2 2NO O Be CN? ? ?? ? ?

48. In which hybridization dx2–y2 orbital involve :(1) sp3d (2) dsp3

(3) sp3d3 (4) dsp2

43. fdlh /kkfRod rkj dh yEckbZ L1 gS tcfd bl ijvkjksfir ruko T1 gS rFkk yEckbZ L2 gS tc vkjksfir rukoT2 gSA rkj dh ewy yEckbZ gksxh :

(1) 1 2L L2?

(2) 1 2L L

(3) 2 1 1 2

2 1

T L T LT T

?? (4)

2 1 1 2

2 1

T L T LT T

??

44. fdlh dk¡p dh ds'kuyh ds fupys fljs dks ty esa Mqcks;kx;k gSA blesa ty 8 cm rd dh Å¡pkbZ rd p<+rk gSAvc bl uyh dks 6 cm dh Å¡pkbZ ls rksM+ fn;k tkrk gSAvc blesa ty LrEHk dh Å¡pkbZ rFkk lEidZ dks.k gksaxsa :

(1) 1 36m,sin

4? (2) 1 3

6m,cos4

?

(3) 1 14m,sin

2? (4) 1 3

4m,cos4

?

45. fdlh [kqyh dk¡p dh ufydk dks ikjs esa bl izdkj Mqcks;ktkrk gS fd 8 cm dh Å¡pkbZ dh ufydk dk Hkkx ikjs lsckgj jgrk gSA bl ufydk ds [kqys fljs dks can dj lhydj fn;k tkrk gS rFkk bl ufydk dks vkSj 46 cm dhÅ¡pkbZ rd mBk;k tkrk gSA vc bl ufydk esa ikjs dsÅij ok;q LrEHk dh yEckbZ gksxh ? (ok;qe.Myh; nkc =ikjs ds 76 cm LrEHk dk nkc)(1) 6 cm (2) 16 cm(3) 22 cm (4) 38 cm

46. 20 atm nkc o 300 K rki ij 2.8 xzke ukbVªkstu xSl dslerkih; vuqRØe.kh; izlkj esa fd;k x;k dk;Z Kkrdhft, tc rd vfUre nkc 1 atm rd u igq¡p tk, :(Pext. = 1 atm)(1) –237.04 twy (2) –240.83 twy(3) +240.83 twy (4) –1083.83 twy

47. LFkkf;Ro dk lgh Øe gS

(1) 2 2Be CN O NO? ? ?? ? ?

(2) 2 2O NO CN Be? ? ?? ? ?

(3) 2 2Be O CN NO? ? ?? ? ?

(4) 2 2NO O Be CN? ? ?? ? ?

48. dkSuls ladj.k esa dx2–y2 d{kd lfEefyr gksrk gS :(1) sp3d (2) dsp3

(3) sp3d3 (4) dsp2



49. The energies of the electron in a hydrogen like ionare given byEn = –(2.18 × 10–18) Z2 2

1n

, where n is principalquantum number and Z is the atomic number ofthe element. The ionisation energy (in kJ mol–1) ofthe Li2+ ion is :(1) 1.18 × 103 (2) 118 × 103

(3) 0.118 × 103 (4)11.8 × 103

50. For following species SiO2, BH3, graphite, the correctorder of hybridization are respectively(1) SP, SP2, SP2 (2) SP3, SP2, SP2

(3) SP3, SP3, SP2 (4) SP, SP2, SP3

51. The density of 3M NaCl solution is 1.25 gm/ml.Calculate its molality ?(1) 2.79 mole/litre (2) 1.83 mole/kg(3) 1.83 mole/litre (4) 2.79 mole/kg

52. The strength of 10 volume solution of hydrogenperoxide is –(1) 3.036 gm/litre (2) 10 gm/litre(3) 30.36 gm/litre (4) 56.08 gm/litre

53. In terms of polar character which one of thefollowing order is correct

(1) 3 2 2NH H O HF H S? ? ?

(2) 2 3 2H S NH H O HF? ? ?

(3) 2 3 2H O NH H S HF? ? ?

(4) 2 3 2HF H O NH H S? ? ?

54. An element, X has the following isotopiccomposition:200X : 90% 199X : 8.0% 202X : 2.0%The weighted average atomic mass of thenaturally-occurring element X is closest to(1) 201 amu (2) 202 amu(3) 199 amu (4) 200 amu

55. Specific heat of metal is 0.23 and its chloridecontains 87% of chlorine. What is the exact atomicweight of the metal ?(1) 62 (2) 54(3) 24 (4) 26.52

49. gkbMªkstu tSls vk;u esa bysDVªkWu dh ÅtkZ fuEufyf[krlw= }kjk nh tkrh gSEn = –(2.18 × 10–18) Z2 2

1n

, tgk¡ n eq[; Dok.Vela[;k rFkk Z rRo dk ijek.kq Øekad gSA rks Li2+ vk;u dhvk;uu ÅtkZ kJ mol–1 esa gksxh

(1) 1.18 × 103 (2) 118 × 103

(3) 0.118 × 103 (4)11.8 × 103

50. fuEufyf[kr iztkfr;ksa SiO2, BH3, xzsQkbV ds fy;s

ladj.k Øe'k% gS(1) SP, SP2, SP2 (2) SP3, SP2, SP2

(3) SP3, SP3, SP2 (4) SP, SP2, SP3

51. 3M, NaCl foy;u dk ?kuRo 1.25 gm/ml. gS rks bldheksyyrk Kkr dhft, ?(1) 2.79 mole/litre (2) 1.83 mole/kg(3) 1.83 mole/litre (4) 2.79 mole/kg

52. 10 vk;ru] H2O2 foy;u dk lkeF;Z gS –(1) 3.036 gm/litre (2) 10 gm/litre(3) 30.36 gm/litre (4) 56.08 gm/litre

53. /kzqoh; xq.kkas ds vk/kkj ij dkSulk ,d Øe lgh gS

(1) 3 2 2NH H O HF H S? ? ?

(2) 2 3 2H S NH H O HF? ? ?

(3) 2 3 2H O NH H S HF? ? ?

(4) 2 3 2HF H O NH H S? ? ?

54. ,d rRo X ds leLFkkfudksa dk laxBu fuEufyf[kr gS:

200X : 90% 199X : 8.0% 202X : 2.0%izkÑfrd :i ls ik;s tkus okys rRo X dk vkSlr ijek.kqHkkj gS(1) 201 amu (2) 202 amu(3) 199 amu (4) 200 amu

55. /kkrq dh fof'k"V Å"ek 0.23 rFkk bldk DyksjkbM 87%Dyksjhu j[krk gS rks /kkrq dk ijek.kq Hkkj gSA

(1) 62 (2) 54(3) 24 (4) 26.52



56. The crystalline salt 2 4 2Na SO xH O? on heating loses

55.9% of its weight. The formula of crystalline saltis

(1) 2 4 2Na SO 5H O? (2) 2 4 2Na SO 7H O?

(3) 2 4 2Na SO 2H O? (4) 2 4 2Na SO 10H O?

57. 50 cm3 of 0.04 M K2Cr2O7 in acidic medium oxidizesa sample of H2S gas to sulphur. Volume of 0.03 MKMnO4 required to oxidize the same amount of H2Sgas to sulphur, in acidic medium is(1) 60 cm3 (2) 80 cm3

(3) 90 cm3 (4) 120 cm3

58. Calcualte S involved in conversion 1 gm of ice at0° to liquid water. If H fusion of ice = 6.006 kJ/mole :

(1) 225 JK (2) 22 JK

(3) 1.22 JK (4) None of these

59. Predict the period, group and block of the elementfrom the following electronic configuration :[Xe] 4f15d16s26p0

(1) 7th period, III B group and d-block(2) 6th period, II A group and s-block(3) 6th period, III B group and p-block(4) 6th period, III B group and f-block

60. At which of the four condition, the density of N2 willbe maximum :(1) STP (2) 273K and 2 atm(3) 546K and 1 atm (4) 546 K and 2 atm

61. 11 mL of N10

, NaOH and 10 ml of N11

, HCl are mixed

together. Calculate the pH of resulting solution :

(1) 2.04 (2) 11.01(3) 11.96 (4) 6.91

62. Which is a electron precise hydride –(1) NH3 (2) SiH4

(3) BH3 (4) HF63. The ONO angle is maximum in :

(1) NO3– (2) NO2

+

(3) N2O4 (4) NO2

56. ,d fØLVyh; yo.k 2 4 2Na SO xH O? xeZ djus ij vius

Hkkj dk 55.9% Hkkj [kks nsrk gSA rks bl fØLVyh; yo.kdk lw= gS

(1) 2 4 2Na SO 5H O? (2) 2 4 2Na SO 7H O?

(3) 2 4 2Na SO 2H O? (4) 2 4 2Na SO 10H O?

57. 50 cm3 ds 0.04 M K2Cr2O7 vEyh; ek/;e esa H2S xSldks lYQj esa vkWDlhÑr dj nsrk gSA rks H2S xSl dhleku ek=k dks lYQj esa vkWDlhÑr djus ds fy, 0.03M KMnO4 ds fdrus vk;ru dh vko';drk gksxh(1) 60 cm3 (2) 80 cm3

(3) 90 cm3 (4) 120 cm3

58. 0º C ij 1 xzke cQZ ikuh esa cnyrh gS rks bldh ,UVªkWihesa ifjorZu (S) Kkr djks (;fn cQZ ds fy, H

xyu =

6.006 kJ/mole)

(1) 225 JK (2) 22 JK

(3) 1.22 JK (4) buesa ls dksbZ ugha

59. v/kksfyf[kr bysDVªkWfud foU;kl ds vk/kkj ij rRo dsfy, vkorZ] lewg o CykWd gksxk : [Xe] 4f15d16s26p0

(1) 7th vkorZ , III B lewg rFkk d-CykWd

(2) 6th vkorZ, II A lewg rFkk s-CykWd

(3) 6th vkorZ, III B lewg rFkk p-CykWd

(4) 6th vkorZ, III B lewg rFkk f-CykWd60. fuEufyf[kr dkSulh fLFkfr esa N2 ds fy, ?kuRo vf/kdre

gksxk :(1) STP (2) 273K and 2 atm(3) 546K and 1 atm (4) 546 K and 2 atm

61.N10

, NaOH ds 11 ml o N11

, HCl ds 10 ml dks fefJr

djrs gS rks ifj.kkeh foy;u dh pH gksxh :(1) 2.04 (2) 11.01(3) 11.96 (4) 6.91

62. fuEu esa ls dkSulk ,d bysDVªkWu ifj'kq) gkbMªkbM gS –(1) NH3 (2) SiH4

(3) BH3 (4) HF63. fdlesa ONO ca/k dks.k vf/kdre gS :

(1) NO3– (2) NO2

+

(3) N2O4 (4) NO2



64. 13.8 gm of N2O4 was placed in one litre flask at 400

K, N2O4(g) 2NO2(g), the total pressure at

equilibrium was 9.15 atm. Calculate Kc atequilibrium?

(1) 85.87 mol.litre–1 (2) 25.88 mol.litre–1

(3) 2.61 mol.litre–1 (4) None of these65. For the reactions,

(i) H2(g) + Cl2(g) = 2HCl(g) + x kJ(ii) H2(g) + Cl2(g) = 2HCl(l) + y kJWhich one of the following statements is correct ?(1) x > y (2) x < y(3) x – y = 0 (4) x = y

66. Which is not correct for compressiblity factor (Z):(1) The deviation from ideal behaviour of gases can

be measured in terms of Z(2) Z is the ratio of actual molar volume of a gas to

the ideal gas molar volume at same temperature& pressure

(3) If Z >1, than the gas show the positive deviationgenerally at low pressure from ideal gasbehaviour and the gas will be more compressiblethan ideal gas

(4) If Z < 1, than the gas show the negativedeviation generally at low pressure from idealgas behaviour and the gas will be highlycompressible than ideal gas

67. Permanent hardness of water can not be removedby the following method(1) Ion – exchange method(2) Calgon's method(3) Clark's method(4) Synthetic resin method

68. For complete combustion of ethanol :

C2H5OH(l) +3O2(g) 2 22CO (g) 3H O( ) l

The amount of heat produced as measured in bombcalorimeter, is 1364.47 kJ mol–1 at 25ºC. Assumingideality, the enthalpy of combustion, CH for thereaction will be : (R = 8.314 J K–1 mol–1)(1) –1460.50 kJ mol–1 (2) –1350.50 kJ mol–1

(3) –1366.95 kJ mol–1 (4) –1361.95 kJ mol–1

64. N2O4(g) 2NO2(g)

N2O4 xSl ds 13.8 xzke dks 400 K rki ij 1 yhVj¶ykLd esa ysus ij lkE;koLFkk ij 9.15 atm dqy nkcizkIr gksrk gS rks bl vfHkfØ;k ds fy, lkE;koLFkk ij Kc

Kkr dhft, ?(1) 85.87 mol.litre–1 (2) 25.88 mol.litre–1

(3) 2.61 mol.litre–1 (4) None of these65. vfHkfØ;kvksa ds fy,

(i) H2(g) + Cl2(g) = 2HCl(g) + x kJ(ii) H2(g) + Cl2(g) = 2HCl(l) + y kJfuEu esa ls dkSulk dFku lR; gS(1) x > y (2) x < y(3) x – y = 0 (4) x = y

66. laihM+rk xq.kkad (Z) ds fy;s lgh ugha gS :(1) xSlksa dk vkn'kZ O;ogkj ls fopyu Z ds :i esa ekik

tk ldrk gSA(2) Z ,d xSl dk okLrfod eksyj vk;ru rFkk vkn'kZ

xSl eksyj vk;ru dk leku rki o nkc ij vuqikrgSA

(3) ;fn Z >1, rc xSl lkekU;r;k de nkc ij vkn'kZxSl O;ogkj ls /kukRed fopyu n'kkZrh gS rFkk xSlvkn'kZ xSl dh rqyuk eas vf/kd laihM~; gSA

(4) ;fn Z < 1, rc xSl lkekU;r;k de nkc ij vkn'kZxSl O;ogkj ls _.kkRed fopyu n'kkZrh gS rFkk xSlvkn'kZ xSl dh rqyuk eas vR;f/kd laihM~; gSA

67. ikuh dh LFkkbZ dBksjrk fuEu esa ls dkSulh fof/k }kjk ughgVk ldrs gSa&(1) vk;u – fofue; fof/k(2) dSYxksu fof/k(3) DykdZ fof/k(4) flaFksfVd jsftu fof/k

68. bFksukWy ds iw.kZ ngu ds fy, :

C2H5OH(l) +3O2(g) 2 22CO (g) 3H O( ) l

eqDr gqbZ ÅtkZ dk eku ckWEc dSyksjh ehVj esa 25ºC rkiij 1364.47 kJ mol–1 gSA rks bl vfHkfØ;k ds fy, ngudh ,UFkSYih CH dk eku gksxk(R = 8.314 J K–1 mol–1)(1) –1460.50 kJ mol–1 (2) –1350.50 kJ mol–1

(3) –1366.95 kJ mol–1 (4) –1361.95 kJ mol–1



69. For the process :

H2O(l) 2H O(g)

at T = 100º C and 1 atmospheric pressure, thecorrect choice is :(1) Ssystem > 0 and Ssurroundings > 0(2) Ssystem > 0 and Ssurroundings < 0(3) Ssystem < 0 and Ssurroundings > 0(4) Ssystem < 0 and Ssurroundings < 0

70. For the reaction N2(g) + O2(g) 2NO(g), the

equilibrium constant is K1. The equilibrium constantis K2 for the reaction 2NO(g) + O2(g) 2NO2(g)What is K for the reaction

2 2 2

1NO (g) N (g) O (g) ?

2

(1) 1 2

1K K (2)

1 2

12K K

(3) 1 2

14K K (4)

1/2

1 2

1K K

71. The electronic configuration of superoxide ion is :(1) 1s2 < *1s2 < 2s2 < *2s2 < 2pz

2

< 2px2 = 2py

2 < *2px2 = *2py

1

(2) 1s2 < *1s2 < 2s2 < *2s2 < 2px2

= 2py2 < 2pz

2 < *2px2 = *2py

2

(3) 1s2 < *1s2 < 2s2 < *2s2 < 2px2

= 2py2 < 2pz

2 < *2px2 = *2py

2

(4) None of these72. The mass of an electron is 9.1 × 10–31 kg. If its

kinetic energy is 3 × 10–25 J, calculate its wavelength :(1) 8967 Å (2) 8967 nm(3) 89670 nm (4) 1 & 3 both

73. For the reaction PCl5(g) PCl3(g) + Cl2(g),

when 2 litre Ne gas is added at constant pressure,the reaction will be proceed in which direction :

(1) forward direction (2) backward direction(3) unchanged (4) any direction

69. izØe ds fy;s :

H2O(l) 2H O(g)

rki T = 100º C rFkk 1 atm nkc ij lgh dFku gS :

(1) Ssystem > 0 and Ssurroundings > 0(2) Ssystem > 0 and Ssurroundings < 0(3) Ssystem < 0 and Ssurroundings > 0(4) Ssystem < 0 and Ssurroundings < 0

70. vfHkfØ;k N2(g) + O2(g) 2NO(g), ds fy;s

lkE; koLF k k fL F kj k ad K1 g SA v fH k fØ;k2NO(g) + O2(g) 2NO2 ds fy;s lkE;koLFkkfLFkjkad K2 gS rks fuEufyf[kr vfHkfØ;k ds fy;s K dk eku

gksxk : 2 2 2

1NO (g) N (g) O (g) ?

2

(1) 1 2

1K K (2)

1 2

12K K

(3) 1 2

14K K (4)

1/2

1 2

1K K

71. lqijvkWDlkbM vk;u dk bysDVªkWfud foU;kl gS :(1) 1s2 < *1s2 < 2s2 < *2s2 < 2pz

2

< 2px2 = 2py

2 < *2px2 = *2py

1

(2) 1s2 < *1s2 < 2s2 < *2s2 < 2px2

= 2py2 < 2pz

2 < *2px2 = *2py

2

(3) 1s2 < *1s2 < 2s2 < *2s2 < 2px2

= 2py2 < 2pz

2 < *2px2 = *2py

2

(4) buesa ls dksbZ ugha72. ,d bysDVªkWu dk nzO;eku 9.1 × 10–31 kg. gS ;fn bldh

xfrt ÅtkZ 3 × 10–25 twy gS rks bldh rjaxnS/;Z gksxh :(1) 8967 Å (2) 8967 nm(3) 89670 nm (4) 1 & 3 both

73. fuEu vfHkfØ;k ds fy,

PCl5(g) PCl3(g) + Cl2(g), fu;r nkc ij tc

2 yhVj fu;kWu xSl feykrs gS rks vfHkfØ;k dkSulh fn'kkesa lEiUu gksxh :(1) vxz fn'kk esa (2) i'p fn'kk esa(3) vifjofrZr (4) fdlh Hkh fn'kk esa



74. An aqueous solution of H2SO4 is 13% by mass andits density is 1.09 gm/ml. Calculate the normality(N)of the solution :(1) 1.4 (2) 2.8(3) 5.16 (4) 10.32

75. Solution of 0.1 M NH4OH and 0.1 M NH4Cl has pH9.25. Then pKb of NH4OH is :(1) 9.25 (2) 4.75(3) 3.75 (4) 8.25

76. What is the mole fraction of solute in 1m aq. solution(m = molality)(1) 0.177 (2) 0.0177(3) 1.770 (4) 0.0354

77. How many electron can fit in the orbital for whichn = 2, l = 1(1) 10 (2) 6(3) 2 (4) 14

78. Which is a kinetic gas equation :

(1) PV = 13

mNV2 rms (2) PV = nRT

(3) K.E. = 32

RT (4) PV = 3 RT2 NA

79. Which is correct order of IInd ionisation potential ofthe following elements : Si, S, P, Cl(1) Si < Cl < P < S (2) Si > P > Cl > S(3) Si < P < Cl < S (4) Si < S < P < Cl

80. The oxidation state of each S in sodiumtetrathionate ion are :(1) +2, +4, +2, +2(2) +3, +2, +2, +3(3) +5, 0, 0, +5

(4) +102

, +102

, +102

, +102

81. How many moles of KMnO4 are required to oxidizedone mole of KI in alkaline medium(1) 2/3 (2) 3(3) 1.5 (4) 2

82. Calculate the momentum of a moving particlewhose wavelength is 1nm ?(1) 6.62 × 10–25m/sec. (2) 3.32 × 10–34m/sec(3) 0 (4) 6.62 × 10–25 kg.m/sec

74. H2SO4 ds 13% Hkkj ls tyh; foy;u dk ?kuRo1.09 gm/ml gS rks bl foy;u dh ukWeZyrk Kkr dhft,:(1) 1.4 (2) 2.8(3) 5.16 (4) 10.32

75. 0.1 M NH4OH rFkk 0.1 M NH4Cl ds foy;u dh pH9.25 gS rks NH4OH dk pKb gksxk :(1) 9.25 (2) 4.75(3) 3.75 (4) 8.25

76. 1 m tyh; foy;u esa mifLFkr foy; ds eksy izHkkt gS(m = eksyyrk)(1) 0.177 (2) 0.0177(3) 1.770 (4) 0.0354

77. d{kd ftlds fy, n = 2, l = 1 gS esa fdrus vf/kdrebysDVªkWu Hkjs tk ldrs gS&(1) 10 (2) 6(3) 2 (4) 14

78. dkSulh lehdj.k xfrd xSl lehdj.k gS –

(1) PV = 13

mNV2 rms (2) PV = nRT

(3) K.E. = 32

RT (4) PV = 3 RT2 NA

79. fuEu Lih'kht ds fy, f}rh; vk;uu foHko dk lgh ØegS Si, S, P, Cl(1) Si < Cl < P < S (2) Si > P > Cl > S(3) Si < P < Cl < S (4) Si < S < P < Cl

80. lksfM;e VsVªkFkk;ksusV vk;u esa izR;sd lYQj dh vkWDlhdj.kvoLFkk gS :(1) +2, +4, +2, +2(2) +3, +2, +2, +3(3) +5, 0, 0, +5

(4) +102

, +102

, +102

, +102

81. {kkjh; ek/;e esa 1 eksy KI dks vkWDlhÑr djus gsrq fdruseksy KMnO4 dh vko';drk gksxh%(1) 2/3 (2) 3(3) 1.5 (4) 2

82. ,d xfr'khy d.k dk laosx Kkr dhft, ftldhrjaxnS/;Z 1nm gS ?(1) 6.62 × 10–25m/sec. (2) 3.32 × 10–34m/sec(3) 0 (4) 6.62 × 10–25 kg.m/sec



83. Which is not a redox reaction :

(1) 2KClO3(s) 2KCl(s) + 3O2(g)

(2) CH4(g) + 2O2(g) CO2(g) + 2H2O(g)

(3) CaCO3(s) CaO(s) + CO2(g)

(4) 2NaH(s) 2Na(s) + H2(g)

84. If pressure of a gas contained in a closed vessel is

increased by 0.4% when heated by 1°C. The initial

temperature must be :(1) 250°C (2) 250K(3) 2500 K (4) 25°C

85. Which is correct for Rydberg constant of H–atom

(1) 2 2 4

H 3

2 m eR

Ch

(2) RH = 1.09 × 107 m–

(3) RH = 109667.581 cm(4) All of these

86. Calculate the solubility of Na2SO4[Ksp] in C

concentration of Na2CO3 solution :

(1) S' = 2

KspC

(2) S' = 2

Ksp4C

(3) S' = KspC

(4) S' = 3

Ksp8C

87. Compare relative stability of following resonatingstructure :

(1) a > b > c (2) b > a > c(3) b > c > a (4) a > c > b

88. Which formula represent the plaster of paris(1) 2CaSO4.H2O (2) CaSO4.2H2O(3) Na6S6O18 (4) 1/2 CaSO4.H2O

83. fuEu esa ls dkSulh ,d jsMkWDl vfHkfØ;k ugha gS :

(1) 2KClO3(s) 2KCl(s) + 3O2(g)

(2) CH4(g) + 2O2(g) CO2(g) + 2H2O(g)

(3) CaCO3(s) CaO(s) + CO2(g)

(4) 2NaH(s) 2Na(s) + H2(g)

84. ,d can ik= esa ,d xSl dks 1ºC ls xeZ djus ij ;fn nkc

0.4% ls c<+ tkrk gS rks izkjafHkd rki gksxk :

(1) 250°C (2) 250K(3) 2500 K (4) 25°C

85. gkbMªkstu ijek.kq ds fjMcxZ fu;rkad ds fy, lgh gS

(1) 2 2 4

H 3

2 m eR

Ch

(2) RH = 1.09 × 107 m–

(3) RH = 109667.581 cm

(4) mijksDr lHkh

86. Na2SO4[Ksp] dh C lkanzrk okys Na2CO3 foy;u esa

foys;rk gksxh :

(1) S' = 2

KspC

(2) S' = 2

Ksp4C

(3) S' = KspC

(4) S' = 3

Ksp8C

87. fuEu vuquknh lajpuk dh rqyukRed LFkkf;Ro dk ØegS :

(1) a > b > c (2) b > a > c(3) b > c > a (4) a > c > b

88. IykLVj vkWQ isfjl dk lw= gS(1) 2CaSO4.H2O (2) CaSO4.2H2O(3) Na6S6O18 (4) 1/2 CaSO4.H2O



89. A gas absorb 200 J of heat and expand against theconstant external pressure of 1.5 atm. The initialand final volume of gas is 0.5 litre and 1.0 litre.Calculate the change in internal energy ?(1) 200.75 Joule (2) 199.75 Joule(3) 124.025 Joule (4) None of these

90. MO2 is a superoxide, than M is not may be –(1) Na (2) K(3) Rb (4) Cs

91. The deep-sea vents lodge microbes that surviveon energy produced by metaboilizing inorganicmolecules like sulphur compounds. They are :

(1) Chemo-organotrophs(2) Photo-organotrophs(3) Chemo-lithotrophs(4) Photo-lithotrophs

92. Recognise the following flow diagram and the findcorrect option according to taxonomic hierarchy :

Petunia

Angiosperm

(1) ‘a’ is comparable to muscidae while ‘b’ is at thesame level as that of primata

(2) ‘c’ includes all the angiosperms having twocotyledons in their seeds

(3) For wheat ‘a’ is poaceae ‘b’ is poales and c ismonocotyledonae

(4) All of the above are correct statement93. Botanical gardens and zoological parks have :

(1) Collection of endemic living species only(2) Collection of exotic living species only(3) Collection of endemic and exotic living species

(4) Collection of only local plants and animals

89. ,d xSl 1.5 atm fu;r ckg~; nkc ij 200 J Å"ekvo'kksf"kr dj 0.5 yhVj vk;ru ls 1.0 yhVj rd izlkfjrgksrh gS rks bldh vkUrfjd ÅtkZ esa ifjorZu Kkr dhft, ?

(1) 200.75 Joule (2) 199.75 Joule(3) 124.025 Joule (4) None of these

90. MO2 ,d lqij vkWDlkbM gS rks M ugha gks ldrk –(1) Na (2) K(3) Rb (4) Cs

91. xgjs leqnzksa dh [kkM+h esa ik;s tkus okys lw{e tho vdkcZfudrRoksa tSls lYQj ;kSfxdksa ds mikip;u ls mRiUu ÅtkZij fuHkZj jgrs gSA vr% os gS :

(1) jlk;u vkWxsZuksVªkWQ(2) izdk'k vkWxsZuksVªkWQ(3) jlk;u fyFkksVªkWQ(4) izdk'k fyFkksVªkWQ

92. fuEufyf[kr izokg fp= dks igpkfu;s rFkk ofxZdh inkuqØeds vuqlkj lgh fodYi pqfu;s

Petunia

Angiosperm

(1) ‘a’ dh rqyuk E;wlhMh ls dh tk ldrh gS tcfd ‘b’izkbesVk ds leku Lrj dk gS

(2) ‘c’ esa lHkh vorchth lfEefyr gS ftuds chtksa esa nkschti= gksrs gS

(3) xsagq¡ ds fy;s ‘a’ iks,lh ] ‘b’ iks,yl~ rFkk 'c' ,dchti=hgS

(4) mijksDr lHkh dFku lgh gS93. cksVsfudy xkMZu rFkk twykWftdy ikdZ esa:

(1) dsoy thfor LFkkfud tkfr;ksa dk laxzg.k gksrk gSA(2) dsoy thfor fons'kt tkfr;ksa dk laxzg.k gksrk gSA(3) thfor LFkkfud rFkk fons'kt tkfr;ksa dk laxzg.k

gksrk gSA(4) dsoy LFkkfud ikniksa rFkk izkf.k;ksa dk laxzg.k gksrk

gSA



94. Following is a schematic diagram of evolution ofplants :

Unicellularalgae 1

2

3

4

5

6

7

Mosses

Ferns

Grasses

Trees

If 1 represents multicellularity :3 represents diploidy and 5 represents vesselsthen 2, 4, 6 and 7 can be

(1) Haploidy, conducting tissues, vessels, tracheids(2) Gametophyte, treacheids, atacto-stele, eustele(3) Haploidy, tracheids, atacto-stele eustele(4) Gametophyte, dictyostele, atacto-stele, eu-stele

95. Members of phycomycetes are found in :i. Aquatic habitatsii. On decaying woodiii. Moist and damp placesiv. As obligate parasites on plantsChoose from the following options(1) None of the above(2) i and iv(3) ii and iii(4) All of the above

96. Choose the incorrect match :(1) Cladistics - Origin from a

common ancestor(2) Cytotaxonomy - Chromosome

number andstructure

(3) Numerical taxonomy- Mathematical toolsand computer

(4) Chemotaxonomy - Chromosomenumber

97. A pathogen which can not be culturedin artificialmedium is(1) Protozoan (2) Virus(3) Bacterium (4) Fungus

94. fuEukafdr ikni mf}dkl dk vkjs[kh fp= gS :

Unicellularalgae 1

2

3

4

5

6

7

Mosses

Ferns

Grasses

Trees

;fn 1 cgqdksf'kdrk dks n'kkZrk gS :3 f}xqf.krk dks vkSj 5 okfgdkvksa dks rc 2, 4, 6 vksj7 gks ldrs gS

(1) vxqf.krk] laoguh Ård] okfgdk,] okfguhdk,(2) ;qXedksnfHkn~] okfguhdk,] fodZ.kjEHkh]] lqjEHkh(3) vxqf.krk] okfguhdk,] fodZ.kjEHkh] lqjEHkh(4) ;qXedksn~fHkn] fMfDV;ksLVhy] fodZ.kjEHkh] lqjEHkh

95. QkbdksekbflVht ds lnL; ik, tkrs gSa %i. tyh; vkokl esaii. lM+h&xyh ydM+h ijiii. ue rFkk vknZz LFkkuksa ijiv. ikniksa ij vofodYih ijthoh dh rjg lsfuEufyf[kr fodYiksa esa ls p;u dhft,(1) mi;qZDr esa dksbZ ugha(2) i rFkk iv(3) ii rFkk iii(4) mi;qZDr lHkh

96. vlR; feyku dk p;u dhft;s :(1) DysMfLVd - leku iwoZtksa }kjk

mRifÙk(2) dksf'kdh; oxhZdh - xq.klw= dh la[;k rFkk

lajpuk

(3) la[;kRed oxhZdh - xf.krh; midj.k rFkkdEI;wVj

(4) jlk;u oxhZdh - xq.klw= la[;k

97. ,d jksxtud ftls Ñf=e ek/;e esa laof/kZr ugha fd;ktk ldrk] og gS(1) izksVkstksvk (2) ok;jl(3) thok.kq (4) dod



98. A few events that occur in the lytic cycle of a virus(bacteriophage) are listed :

i. Host cell transcribes and translates phageproteins.

ii. Host DNA is digested.iii. New phage DNA is formed.iv. Phage enzyme causes the cell to lyse.v. Phage particles are released.The correct order in which these events occur is:(1) iv, ii, iii, i, v (2) ii, iii, i, iv, v(3) v, iv, ii, iii, i (4) i, ii, iii, iv, v

99. Diatomaceous earth used in polishing, filtration ofoils and syrups due to its :(1) Slimy nature (2) Gritty nature(3) Dusty nature (4) Hard nature

100. Which arrangements of the organisms representsa rank ordering (bassed on size/importance) fromdominat gametophyte on the left to dominantsporophyte on the right :(1) Polysiphonia, Cycas, Equisetum(2) Seleginella, Zostera, Riccia(3) Funaria, Dryopteris, Pinus(4) Pinus, Selaginella, Marchantia

101. Select the wrong statement :(1) First plants to form embryo were bryophytes(2) First plants to have sporangia were

pteridophytes(3) Gymnosperms were first to have seed habit

(4) All three are wrong102. The type of life-cycle in which there is no free-living

sporophytes and the dominant, photosyntheticphase in such plants is the free-living gametophyte.We are talking about :(1) Haplontic life cycle shown in Volvox and some

species of Chlamydomonas(2) Diplontic life cycle as shown in seed-bearing

plants(3) Haplo-diplontic life cycle as shown in bryophytes

and pteridophytes(4) Haplo-diplontic life cycle as shown in fucus

98. ok;jl ¼thok.kqHkksth½ ds y;u pØ dh dqN ?kVuk, uhpsnh xbZ gS :

i. ijiks"kh dksf'kdk vuqysf[kr gksrh gS vkSj HkksthizksVhu dk vuqoknu gksrk gSA

ii. ijiks"kh DNA dk ikpu gksrk gSAiii. u;k Hkksth DNA curk gSAiv. Hkksth ,Utkbe dksf'kdk dks xykrk gSAv. Hkksth d.k eqDr gksrs gSAbu ?kVukvksa dk lgh Øe gS :(1) iv, ii, iii, i, v (2) ii, iii, i, iv, v(3) v, iv, ii, iii, i (4) i, ii, iii, iv, v

99. Mkb,Veh enk dk mi;ksx ikWfy'k djus] rsyksa rFkk fljids fuL;anu esa fuEu ds dkj.k gksrk gS :(1) 'ys"keh izÑfr (2) d.ke; izÑfr(3) /kqye; izÑfr (4) dBksj izÑfr

100. thoks dh dkSulh O;oLFkk cka;s izHkkoh ;qXedksn~fHkn~ ls nka;sizHkkoh chtk.kqn~fHkn~ dh vksj (vkdkj@egRo ds vk/kkj ij)lgh Øe iznf'kZr djrs gS :

(1) ikWyhlkbQksfu;k, lkbdl, bfDolhVe(2) flysftusyk, tkWLVsjk, fjfDl;k(3) ¶;wusfj;k, Mªk;ksIVsfjl, ikbul(4) ikbul, flysftusyk, ekjdsfU'k;k

101. xyr dFku dk p;u dhft;s :(1) Hkwz.k cukus okys izFke ikni czk;ksQkbV~l Fks(2) chtk.kq/kkuh j[kus okys izFke ikni VsfjMksQkbV~l Fks

(3) loZizFke chth; LoHkko dh mRifr vukorchth;ksa esagqbZ

(4) lHkh rhuksa xyr gS102. ,d ikni ds thoupØ esa eqDrthoh chtk.kqn~fHkn~ ugha gS

rFkk bl ikni dh izHkkoh izdk'k la'ys"kh voLFkk eqDrthoh;qXedksn~fHkn gSA ge ckr dj jgs gS :

(1) okWyokWDl rFkk DysekbMkseksukl dh dqN tkfr;ka esavxqf.krd thoupØ dh

(2) cht/kkjh ikniksa esa n'kkZ;s tkus okyk f}xq.khrdthoupØ dh

(3) czk;ksQkbVk rFkk VsfjMksQkbVk esa n'kkZ;s tkuk okykvxqf.krd&f}xqf.krd thou pØ

(4) ¶;wdl esa n'kkZ;s tkuk okyk vxqf.krd&f}xqf.krdthou pØ



103. Agarophytes are agar yielding red algae. This agar

used in medicines, ice creams but chiefly in culture

medium to make them semisolid, is obtained from

:

(1) Gelidium and Gracilaria

(2) Fucus and Sargassum

(3) Geelidium and Fucus

(4) Gracilaria and Sargassum

104. Amphibians of plant kingdom are not characterised

by :

(1) Sporic meiosis

(2) Vascular tissue

(3) Alternation of generation

(4) Presence of chlorophyll

105. While taking a stroll in the garden, you happen to

see a tall fern plant. The correct description of this

plant will be :

(1) It is a gametophyte that will produce gametes

by mitosis

(2) It is a sporophyte with haploid number of

chromosomes in each cell

(3) It is a gametophyte with haploid number of

chromosomes in each cell

(4) It is a sporophyte that will produce spores by

meiosis

106. Select the incorrect statement about

Gymnoperms:-

(1) Ovules are orthotropus and unitegmic

(2) Endosperm is a gametophytic tissue

(3) Possess an independent gametophyte

generation

(4) They are a bridge between pteridophytes and

angiosperms.

103. ,sxsjksQkbV~l vxkj nsus okys yky 'kSoky gSA bl vxkj

dk mi;ksx vkS"k/kh ] vkblØhe o eq[; :i ls lao/kZu ek/

;e dks v)ZBksl cukus esa fd;k tkrk gSA ;g fuEu ls izkIr

gksrs gS :

(1) ftysfM;e rFkk xzslhysfj;k

(2) ¶;wdl rFkk lkxsZle

(3) ftysfM;e rFkk ¶;wdl

(4) xzslhysfj;k rFkk lkxsZle

104. ikni txr ds mHk;pj dk fuEu y{k.k ugha gS :

(1) chtk.kqd v)Zlw=h foHkktu

(2) laogu ÅÙkd

(3) ih<+h ,dkUrj.k

(4) DyksjksfQy dh mifLFkfr

105. cxhps esa ?kqers le; vkius ,d QuZ dk yEck ikS/kk ns[kkA

bl ikni dk lgh o.kZu gksxk :

(1) ;g ,d ;qXedksn~fHkn gS tks fd lelw=h foHkktu }kjk

;qXed mRiUu djrk gSA

(2) ;g ,d chtk.kqfHkn gS ftldh izR;sd dksf'kdk esa

vxqf.kr xq.klw= gksrs gSA

(3) ;g ,d ;qXedksn~fHkn gS ftldh izR;sd dksf'kdk esa

vxqf.kr xq.klw= gksrs gSA

(4) ;g ,d chtk.kqfHkn gS tks fd v/kZlw=h foHkktu }kjk

chtk.kq mRiUu djrk gSA

106. ftEuksLieZ ds lanHkZ esa vlR; dFku dk p;u dhft,&

(1) chtk.M _tq o ,d v/;koj.kh;

(2) Hkzw.kiks"k ;qXedksn~fHkn~ mÙkd gSA

(3) LorU= ;qXedksn~fHkn ih<h ik;h tkrh gSA

(4) ;s VsfjMksQkbV~l o ,fUt;ksLiZl ds chp lsrq gSA



107. The first few leaves after the cotyledons in theseedling of Acacia are pinnately compound but thepetioles of the upper compound leaves are flattenedand they bear few pinnae. The adult plant has onlyparallel veined leaf like flattened petioles but withoutany pinnae. These observation lead us to theconclusion that :(1) The leaves in the adult plant are reduced to

phyllode while the seedling leaves are unreduced(2) The green parallel veined structures in the adult

plant are phylloclades(3) The plant exhibits heterophylly; bearing simple

leaves in the adult plant and compound leavesin the seedling

(4) The adult plant leaves are a case of reversionwhere they become simple like cotyledons

108. Parts of two plants were observed, Structure Adeveloped aerically and produces roots when comesin contact with the soil. Structure B developes fromunderground part of the stem, grows obliquelybecomes aerial and produces roots on its lowersurface. Identify, respectively the structures of Aand B(1) Sucker, Stolon(2) Stolon, Runner(3) Stolon, Sucker(4) Runner, Stolon

109. Accompanying diagram is a longitudinal section ofa tender plant part. This plant part must be:

(1) Root(2) Stem(3) Inflorescence(4) Midrib of a leaf

107. vdsf'k;k ds uoksn~fHkn~ eas chti=ksa ds ckn dh igyh dqNifÙk;k¡ fiPNkdkj la;qDr gksrh gS ysfdu Åijh la;qDrifÙk;ksa dk i.kZoar piVk gksrk gS vkSj dqN i=d j[krk gSAO;Ld ikS/kk dsoy lekarj f'kjkfoU;kl ;qDr iÙkh ds lekupiVs i.kZo`ar j[krk gS ysfdu fcuk i=d dsA ;g izs{k.k gesafuEu fu"d"kZ ij igqapkrk gS :

(1) O;Ld ikS/ks esa ifÙk;k¡ fQYyksM eas gzkflr gks tkrh gStcfd uoksn~fHkn eas ifÙk;k¡ gzkflr ugha gksrh gSA

(2) O;Ld ikS/ks eas gjh lekarj f'kjk&foU;kl okyh lajpuk;asfQyksDySMl gSA

(3) ikS/kk fo"kei.kZrk n'kkZrk gS; O;Ld ikS/ks esa ljy ifÙk;k¡gksrh gS tcfd uoksn~fHkn eas la;qDr ifÙk;k¡ gksrh gSA

(4) O;Ld ikS/ks dh ifÙk;k¡ O;qRØeu dh ?kVuk gS tgk¡ oschti=ksa dh Hkk¡fr lk/kkj.k gks tkrh gSA

108. nks ikS/kksa ds Hkkxksa dk izs{k.k fd;k x;k] lajpuk A ok;oh;fodflr gksrh gS vkSj tc feV~Vh ds lEidZ eas vkrh gS rcewy mRikfnr djrh gSA lajpuk B rus ds Hkqfexr Hkkx lsfodflr gksrh gS] fr;Zd c<+rh gS vkSj ok;oh; gks tkrhgS rFkk bldh fupyh lrg ls ewy mRiUu gksrh gSA lajpukA vkSj B Øe'k% gS

(1) ldj, LVksyksu(2) LVksyksu, juj(3) LVksyksu, ldj(4) juj, LVksyksu

109. fn;k x;k fp= ikni ds ,d r:.k Hkkx dk yEcor~ dkVdks iznf'kZr djrk gS ;g ikni Hkkx vo'; gh gksxk :

(1) eqy(2) LrEHk(3) iq"iØe(4) i.kZ dh e/; fljk



110. Which of the following statements is correct withreference to the accompanying floral diagram?

(1) There is adhesion between corolla andandroecium.

(2) Calyx as well as corolla have imbricateaestivation.

(3) The flower is bracteate.

(4) Placentation is parietal.

111. Gossipium shows following group of characters :

(1) Alternate phyllotaxy, diadelphous,palmateleaves

(2) Monodelphous,alternate phyllotaxy,simpleleaves, reticulate veination

(3) Monodelphous,reticulate venation, compoundleaves

(4) Superior ovary,monodelphous,palmatecompound leaves

112. K C A(5) 1+2+(2) (9)+1 1G+ is the floral formula of the

family :

(1) Lupin

(2) Cicer

(3) Soyabean

(4) All of these

110. fuEu fn;s x;s rF;ksa esa ls dkSulk rF; fn;s x;s iq"ih;fp= ds lanHkZ esa lR; gS ?

(1) ;gka nyiqat rFkk iqeax ds e/; vklatu gSA

(2) ckg~;nyiqat o nyiqat nksuksa esa gh dksjNknh foU;klgS

(3) iq"i lgi=h gS

(4) fHkfÙk; chtk.MkU;kl gS

111. xkWlhih;e esa fuEufyf[kr xq.k ik;s tkrs gS :

(1) ,dkUrfjr i.kZ foU;kl, f}la?kh, gLrkdkj ifÙk;k¡

(2) ,dla?kh,,dkUrfjr i.kZ foU;kl, ljy ifÙk;k¡,tkfydkor f'kjkfoU;kl

(3) ,dla?kh, tkfydkor f'kjkfoU;kl, la;qDr i.kZ

(4) Å/oorhZ v.Mk'k;, ,dla?kh, gLrkdkj la;qDr i.kZ

112. K C A(5) 1+2+(2) (9)+1 1G+ fdl dqy dk iq"ih; lw= gS :

(1) Y;wfiu

(2) lkblj

(3) lks;kchu

(4) mijksDr lHkh



113. Match the following columns :Column - I Column - II

A. Food 1. AlliumB. Spices 2. BrinjalC. Medicine 3. BeanD. Fumigatory 4. ChiliE. Ornamental 5. Atropa

6. Mulaithi7. Nicotiana8. Petunia9. Tulip

Code :A B C D E

(1) 1,2 3,4 5,6 7 9(2) 1,2,3 4 5,6 7 8,9(3) 1,2,3 4,5 6 7 8,9(4) 1 2 3,4 5,6 7,8

114. Which of the following statements are the functionsof a medullary ray in plants ?(i) Storage of food(ii) Secondary growth(iii) Transmission of water and food(iv) Seat of origin of inter-fascicular cambium(1) (i), (ii) and (iii)(2) (i), (iii) and (iv)(3) (ii), (iii) and (iv)(4) Only (i) and (iii)

115. Bicollateral conjoint vascular bundles have :(1) Xylem and phloem which are arranged in an

alternative manner on different radii(2) Xylem and phloem which are situated at the

different radius and it has two groups of phloemalong the two sides of xylem (inside andoutside)

(3) Xylem and phloem in same radius but it hasonly one group of phloem outside the xylem

(4) Xylem and phloem in same radius but it hastwo group phloem of both side of xylem

113. fuEu LrEHkksa dk feyku dhft;s :LrEHk - I LrEHk - II

A. Hkkstu 1. ,yh;eB. elkys 2. cSaxuC. nokbZ;k¡ 3. QyhD. /kqeziku 4. fepZE. ltkoVh 5. ,Vªksik

6. eqySBh7. fudksfV;kuk8. ihVwfu;k9. V~;wfyi

dwV :A B C D E

(1) 1,2 3,4 5,6 7 9(2) 1,2,3 4 5,6 7 8,9(3) 1,2,3 4,5 6 7 8,9(4) 1 2 3,4 5,6 7,8

114. fuEu esa ls dkSulk rF; ikni esa eTtk fdj.kksa ds dk;Z dkscrkrk gS ?(i) Hkkstu dk laxzg.k(ii) f}rh;d of)(iii) ty o [kkn~; inkFkZ dk LFkkukUrj.k(iv) vUrj laoguh; ,/kk ds mn~Hko dk LFkku(1) (i), (ii) rFkk (iii)(2) (i), (iii) rFkk (iv)(3) (ii), (iii) rFkk (iv)(4) Only (i) rFkk (iii)

115. f}laik'ohZd ] la;qDr laogu iwy esa ik;s tkrs gS :(1) tk;ye rFkk ¶yks;e tks fd fHkUu fHkUu f=T;kvksa ij

,dkUrj Øe esa ik;s tkrs gS(2) tk;ye o ¶yks;e tks fd vleku f=T;k ij fLFkr

gksrs gS rFkk buesa nks lewg ¶yks;e] tk;ye ds nksuksarjQ ckgj rFkk vUnj mifLFkr gksrs gS

(3) tk;ye rFkk ¶yks;e tks leku f=T;k ij ysfdublesa ¶yks;e dk dsoy ,d lewg tk;ye ds ckgjmifLFkr gksrk gSA

(4) tk;ye rFkk ¶yks;e leku f=T;k ij ysfdu tk;yeds nksuksa vksj ¶yks;e ds nks lewg ik;s tkrs gS



116. You marked two ink spots along the height at thebase of a coconut tree and also at the top of thetree.When you examine the spots year when thetree has grown taller,you will see

(1) The two spots at the top have grown more apartthan the two spots at the bottom

(2) The top two spots have grown less apart thanthe bottom two spots

(3) Both sets of spots have grown apart to the sameextent

(4) Both sets of spots remain un-altered117. I. During secondary growth, a complete ring is

formed by intra vascular cambiumII. Interfascicular cambium originates from

medullary ray cellsIII. Vascular cambium form xylem on the inside and

phloem on the outside due to differential actionof hormones

Select the correct combination of option :(1) I and II are correct(2) II and III are correct(3) I and III are correct(4) I, II and III are correct

118. Consider a hypothetical situation where a cell Q withpressure potential of 0.05 units filled solely with wateris surrounded by four cells A, B, C and D. Thepressure and solute potentials (p and s) of therespective cells are tabulated below :

Water from which of the cells is likely to enter thecell Q ?

A B C D

? P 0 0.3 0.23 –0.23

? S –0.23 –0.23 –0.23 –0.23

(1) A (2) B(3) C (4) D

116. tc ukfj;y ds o{k ij yEckbZ esa blds vk/kkj rFkk 'kh"kZij nksuks gh LFkkuksa ij L;kgh ds nks fcUnqvksa dks yxkrs gSrFkk lky ds ckn bu fcUnqvksa dk fujh{k.k djrs gS tcfdo{k yEck gks tkrk gS rc vki ns[krs gks fd :

(1) 'kh"kZ ij ik;s tkus okys nks fcUnq vk/kkj ij ik;s tkusokyss nks fcUnqvksa dh rqyuk esa vf/kd of) djrs gS

(2) 'kh"kZ ds nks fcUnqvksa vk/kkj ds nks fcUnqvksa dh rqyuk esade of) djrs gSA

(3) nksuksa gh LFkku ij fcUnq leku izlkj esa of) djrs gS

(4) nksuksa fcUnqvksa ds ;qXe leku fLFkfr ij jgrs gS117. I. f}rh;d of) ds nkSjku vUr% laoguh; ,/kk ds }kjk

,d laiw.kZ oy; curh gSII. vUrjlaoguiwyh; ,/kk eTtk fdj.kksa dh dksf'kdkvksa

}kjk curh gSIII. laoguh; ,/kk }kjk vUnj dh rjQ tk;ye rFkk

ckgj dh rjQ ¶yks;e curk gS tks fd gkWeksZu dhfHkUukRed fØ;kvksa ds dkj.k mRiUu gksrs gS

fodYiksa esa ls lgh la;kstuksa dk p;u dhft;s(1) I rFkk II lgh gS(2) II rFkk III lgh gS(3) I rFkk III lgh gS(4) I, II rFkk III lgh gS

118. ,d dkYifud fLFkfr ds ckjs esa fopkj djrs gS tgka ,ddksf'kdk Q ftldk nkc foHko 0.05 bdkbZ gS ftldkspkjksa vksj ls pkj dksf'kdkvksa A, B, C rFkk D }kjk ?ksj j[kkgSA bu dksf'kdkvksa dk nkc rFkk foys; foHko (p rFkks) nh xbZ rkfydk esa Øekuqlkj gS :fuEu ds vk/kkj ij dkSulh dksf'kdk }kjk Q dksf'kdk esaty izos'k djsxk ?

A B C D

? P 0 0.3 0.23 –0.23

? S –0.23 –0.23 –0.23 –0.23

(1) A (2) B(3) C (4) D



119. Two plants X and Y are showing association withfungus to form mycorrhizae. The table belowindicates the details observed in roots of plants Xand Y.

Sr.No Details Plant X Plant Y

1 Growth of fungal hyphae into the cortex of root

2 Fungal hyphae invading apoplast

X

3 Fungal hyphae forming arbusules (branched structures)

X

4 Root hair X

Plant X and Y can respectivcly be :(1) X : oak plant with ectomycorrhizae, Y : maize

plant with endomycorrhizae.(2) X : oak plant with endomycorrhizae, Y : maize

plant with ectomycorrhizae(3) X : oak plant with ectomycorrhizae, Y : maize

plant with both endomycorrhizae andectomycorrhizae

(4) X : oak plant with both endomycorrhizae andectomycorrhizae, Y : maize plant withectomycorrhizaed

120. Column I lists some principles pretaining tophysiology of of plants. Column II lists the namesof scientists, who proposed the idea. Match thetwo columns. Identify the correct choice from thecodes given options :

Column - I Column - IIA. Pressure flow 1. EMP

hypothesisB. C4 cycle 2. Dixon and jollyC. Pulling theory 3. Munch

of ascent of sapD. Glycolysis 4. Hatch and Slack

Codes : A B C D(1) 4 3 2 1(2) 3 4 1 2(3) 4 3 1 2(4) 3 4 2 1

119. nks ikni X rFkk Y dod ds lkFk lgla;kstu iznf'kZr djdod eqy cukrs gSA nh xbZ rkfydk esa ikni X rFkk Y dhewyksa dk izs{k.k bafxr gS-

Ø- la- fooj.k ikni X ikni Y1 eqy ds oYdqV esa dod

rUrqvksa dh of)

2 dod rUrq ,iksIykLV dks

vfrØfer djrs gS

X

3 dod rUrq vR;f/kd 'kkf[kr lajpuk fufeZr djrs gS

X

4 ewy jkse X

ikni X rFkk Y Øekuqlkj gks ldrs gS :(1) X : vksd ikni ckg~; dodeqy ds lkFk, Y : eDdk

ikni vUr% dodeqy ds lkFk(2) X : vksd ikni vUr% dodeqy ds lkFk, Y : eDdk

ikni ckg~; dodeqy ds lkFk(3) X : vksd ikni ckg~; dodeqy ds lkFk , Y : eDdk

ikni vUr% dodeqy rFkk ckg~; dodeqy nksuksa dslkFk

(4) X : vksd ikni vUr% dodeqy rFkk ckg~; dodeqynksuksa ds lkFk, Y : eDdk ikni ckg~; dodeqy dslkFk

120. dkWye I esa ikniksa esa dkf;Zdh ls lacaf/kr dqN fl)kUrksa dhlwph nh x;h gSA dkWye II esa mUk fopkjksa dks izLrqr djusokys oSKkfudksa ds uke dh lwph nh xbZ gSA nksuksa dkWye dkfeyku dhft;s rFkk fn;s x;s fodYiksa esa dwVksa ij vk/kkfjrigpku dj lgh dk p;u dhft;s

dkWye - I dkWye - IIA. nkc izokg 1. bZ-,e-ih

ifjdYiukB. C4 pØ 2. fMDlu rFkk tkWyhC. jlkjksg.k dk f[kapko 3. eaqp

fl)kUrD. XykbdksykbZfll 4. gsp rFkk Lysd

Codes : A B C D(1) 4 3 2 1(2) 3 4 1 2(3) 4 3 1 2(4) 3 4 2 1



121. The diagram depicts the mechanism of opening ofstomata. Identify X and Y.

x

Cl–K+

2H+

Cl–

K+

CO2Starch

GUARD CELL

H+

Vacuole

(1) PEP and Malate (2) Malate and PEP(3) Pyruvate and NAD (4) NAD and Pyruvate

122. Nitrogen is required mainly by which of the followingpart of the plants :I. Meristematic tissuesII. Differentiating tissuesIII. Apical tissuesIV. Metabolically active cellChoose the correct option :(1) Only II (2) Only I(3) I and II (4) I and IV

123. Fill in the blank (A - E) and choose the correctoption accordingly :I. Sulphur deficiency may causes ....A.... of the

leavesII. .....B..... is involved in the maintenance of the

turgidity of cellsIII. .....C.... is an important constitutent of proteins

involved in the transfer of electrons likeferrodoxin and cytochromes

IV. Deficiency may cause ....D.... and ....E..... ofthe leaves

(1) A - molting, B - Potassium, C - phosphorous,D - necrosis, E - yellowing

(2) A - yellowing , B - phosphorous, C - iron,D -molting, E - necrosis

(3) A - yellowing , B - potassium, C - iron,D - molting, E - necrosis

(4) A - necrosis, B - iron, C - potassium, D - molting,E - yellowing

121. fn;k x;k fp= jU/kz ds [kqyus dh fØ;kfof/k dk vuqekuyxkrk gSA ;gka X rFkk Y dh igpku dhft,

x

Cl–K+

2H+

Cl–

K+

CO2Starch

GUARD CELL

H+

Vacuole

(1) PEP rFkk esysV (2) esysV rFkk PEP(3) ikb:osV rFkk NAD (4) NAD rFkk ikb:osV

122. fuEu fn;s x;s ikni ds Hkkxksa esa ls fdldks eq[;r%ukbVªkstu dh vko';drk gksrh gS :I. foHkT;ksrdh; mÙkdII. foHksfnr gksrs gq, mÙkdIII. 'kh"kZLFk mÙkdIV. mikip;h :i ls lfØ; dksf'kdk;salgh fodYi dk p;u dhft;s :(1) dsoy II (2) dsoy I(3) I rFkk II (4) I rFkk IV

123. (A - E) rd fjDr LFkkuksa dh iwfrZ dhft;s rFkk mldsvuqlkj lgh fodYi dk p;u dhft;s :I. lYQj dh vi;kZIrrk i.kZ esa ....A.... mRiUu djrh gS

II. .....B..... dksf'kdk dh LQhfFkrk dks fu;fer djus esaiz;qDr gksrk gS

III. .....C.... ,d izksVhu dk egRiw.kZ ?kVd gS tks fdQsjsMkWDlhu rFkk lk;VksØkWe esa bysDVªkWu LFkkukUrj.kds fy;s iz;qDr gksrk gS

IV. vi;kZIrrk ds dkj.k i.kZ esa ....D....rFkk ....E.....mRiUu gksrs gS

(1) A - eksfYVax, B - ikWVsf'k;e, C - QkWLQksjl, D - usØksfll,E - ihykiu

(2) A - ihykiu, B - QkWLQksjl, C - ykSg, D - eksfYVax,E - usØksfll

(3) A - ihykiu, B - ikWVsf'k;e, C - ykSg, D - eksfYVax,E - usØksfll

(4) A - usØksfll, B - ykSg, C - ikWVsf'k;e , D - eksfYVax,E - ihykiu



124. Which of the following diagram correctly depictsN2 - cycle

(1)

(2)

(3)

(4)

125. Choose the correct statement for distribution ofchloroplast in palisade tissue on the basis of light

intensity :

SIDE VIEW

UPPERSURFACE

VIEW

LIGHT LIGHT

A B

124. fn;s x;s fp= esa ls dkSulk ukbVªkstu pØ dks lgh iznf'kZrdj ldrk gS

(1)

(2)

(3)

(4)

125. izdk'kh; rhozrk ds vk/kkj ij [kEHk mÙkd esa gfjryod ds

forj.k ds fy;s lR; dFku dk p;u dhft;s :

SIDE VIEW

UPPERSURFACE

VIEW

LIGHT LIGHT

A B



(1) Diagram A shows arrangement of chloroplastduring strong light intensity

(2) Diagram B shows arrangement of chloroplastduring weak light intensity

(3) In diagram A the chloroplast align themselfalong the tangential wall in moderate light

(4) In diagram B the chloroplast align themself invertical position along the lateral wall in weaklight intensity

126. Find out the wrong statement :(1) CAM plants open their stomata at night and

close during day time(2) Splitting of water takes place in the chloroplast

membrane(3) PS–I is found in stromal as well as granal

thalakoids(4) Current availability of CO2 levels is limting to

the C3 plants127. Given below are the graphs showing the absorption

spectra of photosynthetic pigments, out of whichone is showing the action spectrum of

photosynthesis :

(A) (B) (C) (D) (1) Chlorophyll a Carotenoids Action

spectrum Chlorophyll b

(2) Chlorophyll a Action spectrum

Carotenoids Chlorophyll b

(3) Chlorophyll b Carotenoids Chlorophyll a Action spectrum

(4) Carotenoids Chlorophyll b Action spectrum

Chlorophyll a

128. If photosynthesizing green algae (oxygenic

photosynthesis) are provided with CO2 labelled withan isotope of oxygen (18O that is, "heavy" butnot radioactive), later analysis will show that all ofthe following compounds produced by the algaecontain the 18O label except :(1) PGA (2) RuBP(3) Glucose (4) O2

(1) fp= A rhoz izdk'kh; rhozrk ij gfjryod ds forj.kdks n'kkZrk gS

(2) fp= B de izdk'kh; rhozrk ij gfjryod ds forj.kdks n'kkZrk gS

(3) fp= A esa e/;e izdk'k esa gfjryod Lo;a dks Li'kZjs[kh;fHkfÙk dh vksj O;fLFkr j[krs gS

(4) fp= B esa de izdk'kh; rhozrk ij gfjryod Lo;a dksm/okZ/kj fLFkfr esa ik'ohZ; fHkfÙk dh vksj O;ofLFkrj[krs gS

126. fuEu esa xyr dFku gS :(1) CAM ikni vius jU/kz jkf= eas [kksyrs gS rFkk fnu ds

le; can djrs gSA(2) ty dk fo?kVu gfjryod dh f>Yyh esa gksrk gSA

(3) PS–I LVªksek rFkk xzsuk FkkbysdkWbM nksuksa esa ik;k tkrkgSA

(4) orZeku esa miyC/k CO2 dk Lrj C3 ikniksa ds fy,lhekdkjh gSA

127. uhps fn;s x;s xzkQ izdk'k la'ys"kh o.kZd ds vo'kks"k.kLisDVªk dks n'kkZrs gaSA buesa ls ,d izdk'k la'ys"k.k dklfØ; LisDVªe gS :

(A) (B) (C) (D) (1) DyksjksfQy a dsjsVhukWbM~l fØ;kRed

LiSDVªe DyksjksfQy b

(2) DyksjksfQy a fØ;kRed LiSDVªe

dsjsVhukWbM~l DyksjksfQy b

(3) DyksjksfQy b dSjsVhukWbM~l DyksjksfQy a fØ;kRed LiSDVªe

(4) dsjsVhukWbM~l DyksjksfQy b fØ;kRed LiSDVªe

DyksjksfQy a

128. ;fn vkWDlhtsfud izdk'k la'ys"k.k djus okys izdk'k la'ys"kh

gjs 'kSoky dks vkblksVkWi vkWDlhtu ukekafdr CO2 nh xbZ(18O Hkkjh gS, ysfdu jsfM;kslfØ; ugha gS), rFkk blds ckndk fo'ys"k.k n'kkZrk gS fd 'kSoky }kjk mRikfnr lHkh;kSfxd esa 18O gksxk] fuEufyf[kr ds vykok :

(1) PGA (2) RuBP(3) XywdkWt (4) O2



129. Plasticity in plant growth means that :(1) Plant roots are extensible(2) Plant growth is dependent on the environment(3) Stems can extend(4) None of the above

130. Match the column :Column - I Column - II

A. Complex - I i. Cytochrome bc1

complexB. Complex - II i i. Succinate

dehydrogenaseC. Complex - III i i i. Cytochrome - c -

oxidaseD. Complex - IV iv. NADH -

dehydrogenase(1) A - ii, B - iv, C - iii, D - i(2) A - i, B - iv, C - ii, D - iii(3) A - iv, B - ii, C - i, D - iii(4) A - iv, B - ii, C - iii, D - i

131. Which of the following reactions correctly depictsstep involved in respiration ?

(1) Glucose + O Pyruvate Lactate2 ? ?

ADP ATP

NADH NAD–

(2) Glucose Pyruvate Lactate? ?

ADP ATP

ADP ATP

(3) Glucose + O Pyruvate Alcohol + CO2 2? ?

ADP ATPADP ATP


ADP ATP

NAD+ NADH

129. ikni of) esa lq?kV~;rk dk vFkZ gS(1) ikni dh tM+as foLrkj djus okyh gksrh gSaA(2) ikni of) i;kZoj.k ij fuHkZj djrh gSA(3) LraHk c<+ ldrk gSA(4) mi;qZDr esa dksbZ ugha

130. LrEHk dk feyku dhft, :Column - I Column - II

A. lfEeJ - I i. lkbVksØkse bc1

dkWEiysDlB. lfEeJ - II i i. lfDlusV

fgMgkbMªksftustC. lfEeJ - III i i i. lkbVksØkse - c -

vkWDlhMstD. lfEeJ - IV iv. NADH -

fMgkbMªksftust(1) A - ii, B - iv, C - iii, D - i(2) A - i, B - iv, C - ii, D - iii(3) A - iv, B - ii, C - i, D - iii(4) A - iv, B - ii, C - iii, D - i

131. fuEu esa ls dkSulh vfHkfØ;k 'olu esa fufgr inksa dk lghvuqeku yxkrh gS ?

(1) Glucose + O Pyruvate Lactate2 ? ?

ADP ATP

NADH NAD–


ADP ATP

ADP ATP

(3) Glucose + O Pyruvate Alcohol + CO2 2? ?

ADP ATPADP ATP


ADP ATP

NAD+ NADH



132. The following schematic diagram depicts the energyacquiring process in:

(1) bacterium (2) mitochondrion(3) chloroplast (4) (a) and (b)

133. Three hormones X, Y, Z show the followingproperties :

Hormone

SeedllingGrowth

ApicalDominance

LeafAbscission

Site ofProduction

X

Y

Promotescell divisionand expansion

Embryo,young leaves,root and shoot apices

Promotescellexpansion

Inhibitslateralbuds

InhibitsAbscission

Embryo, young leaves, shootapical meristem

Promotescellexpansion

Promoteslateralbuds

InhibitsAbsicission

RootsZ

The correct sequence of hormones is -(1) X-Gibberellin, Y-Cytokinin, Z-Auxin(2) X-Gibberllin, Y-Auxin, Z-Cytokinin(3) X-Auxin, Y-Cytokinin, Z-Gibberellin(4) X-Auxin, Y-Gibberellin, Z-Cytokinin

134. I. More female flowers in cucumberII. -amylase production in barley grainIII. Acceleration of fruit ripening in tomatoIV. Delayed sprouting in potato tubersFrom the given effects find, out the effects ofethylene and choose the correct option accordingly(1) I and II (2) I and III(3) II and IV (4) III and IV

132. fn;k x;k vkjs[kh fp= fdlesa ÅtkZ ds izkfIr dh fØ;kfof/k dk vuqeku yxkrk gS :

(1) cSDVhfj;e (2) ekbVksdkWfUMª;ksu(3) gfjryod (4) (1) rFkk (2)

133. rhu gkeksZUl X, Y, Z fuEu y{k.k iznf'kZr djrk gS :

gkWeksZUl uokssn~fHkn~of) 'kh"kZ izHkkfork i.kZ foyxumRiknu dk

LFkyX dksf'kdk

foHkktu rFkk

nh?khZdj.k dks mRizsfjr djuk

Hkwz.k] r:.k i.kZ] eqy

rFkk izjksg 'kh"kZ

Y dksf'kdk nh?khZdj.k dks

mRizsfjr djuk

ik'oZdfydk dk fujks/ku

foyxu dk fujks/ku

Hkwz.k] r:.k i.kZ] izjksg

'kh"kZ foHkT;kssrd

Z dksf'kdk nh?khZdj.k dks

mRizsfjr djuk

ik'oZdfydk dks mRizsfjr

djuk

foyxu dk fujks/ku

eqy

gkWeksZUl dk lgh vuqØe gS -(1) X-ftczsfyu, Y-lkbVksdk;fuu, Z-vkWfDlu(2) X-ftczsfyu, Y-vkWfDlu, Z-lkbVksdk;fuu(3) X-vkWfDlu, Y-lkbVksdk;fuu, Z-ftczsfyu(4) X-vkWfDlu, Y-ftczsfyu, Z-lkbVksdk;fuu

134. I. dqdqEcj esa vf/kd eknk iq"iII. tkS ds nkuksa esa -,ekbyst dk mRiknuIII. VekVj esa Qy ifjiDou dks Rofjr djukIV. vkyw ds danksa esa vadqj.k esa nsjh gksukmijksDr fn;s x;s izHkkoksa esa ls bFkkbyhu ds izHkko dks[kkstdj mlds vuqlkj lgh fodYi dk p;u dhft;s(1) I rFkk II (2) I rFkk III(3) II rFkk IV (4) III rFkk IV



135. Match the following columns :Column - I Column - II

A. Human urine 1. CytokininB. Gibberella fujikuroi 2. AuxinC. Herring fish DNA 3. EthyleneD. Fruit Ripening 4. ABAE. Aged leaves of plants 5. GA

Codes : A B C D E(1) 1 2 3 4 5(2) 2 5 1 3 4(3) 2 5 1 4 3(4) 5 2 4 3 1

136. Identify A, B, C and D :

A

B

D

C

A B C D

1 Ectoderm Endoderm Coelom Mesoderm

2 Epidermis Lumen Coelom Mesoderm

3 Ectoderm Lumen Coelom Mesoderm

4 Ectoderm Coelom Mesoderm Lumen

137. Which of the following guards the opening ofhepatopancreatic duct into the duodenum :(1) Pyloric sphincter (2) Sphincter of Oddi(3) Semilunar valve (4) Ileocaecal valve

138. Microtubule depolymerizing drug such as colchicineis expected to :(1) inhibit spindle formation during mitosis(2) inhibit cytokinesis(3) allow mitosis beyond metaphase(4) induce formation of multiple contractile rings.

135. fuEufyf[kr LrEHkksa dks lqesfyr dhft;s :LrEHk - I LrEHk - II

A. ekuo ew= 1. lkbVksdkbfuuB. ftCcjsyk ¶;qthdksjkb 2. vkWDlhuC. gsafjax eNyh dk DNA 3. ,FkhyhuD. Qy ifjiDou 4. ABAE. ikni dh o) i.kZ 5. GA

dwV : A B C D E(1) 1 2 3 4 5(2) 2 5 1 3 4(3) 2 5 1 4 3(4) 5 2 4 3 1

136. A, B, C rFkk D dks igpkfu;s

A

B

D

C

A B C D

1 ,DVksMeZ ,.MksMeZ lhykse ehtksMeZ

2 ,ihMfeZl Y;qfeu lhykse ehtksMeZ

3 ,DVksMeZ Y;qfeu lhykse ehtksMeZ

4 ,DVksMeZ lhykse ehtksMeZ Y;qfeu

137. fuEufyf[kr esa ls dkSu lh lajpuk ;Ñr&vXuk'; okfguhds xzg.kh esa [kqyus okys ja/kz dh ns[kHkky djrh gS \(1) tBjfuxZe vojksf/kuh (2) vkMkbZ dks vojksf/kuh(3) v/kZpanzkdkj dikV (4) f=dka= dikV

138. ekbØksV~;wCywl fola?kuu vkS"kf/k dksfYplhu dk dk;Z gSaA

(1) lelw=h foHkktu esa rdqZrarq fuekZ.k dks jksduk(2) dksf'kdk æO; foHkktu jksduk(3) lelw=h foHkktu esVkQst ls ijs djuk(4) xq.kkRed ladqpu'khy pØksa ds fuekZ.k dks izsfjr djuk

(multiple contractile rings)



139. Identify the stage :

(1) Metaphase

(2) Metaphase-I

(3) Metaphase-II

(4) Anaphase - II140. Villi and microvilli are present in which of the

following organs :(1) Oesophagus (2) Stomach(3) Small intestine (4) Large instestine

141. Which of the following are correct ?i. Spones : Cellular level of organizationii. Cnidaria : Tissue organ level of organizationiii. Platyhelminthes : Organ level of organizationiv. Annelids, Arthropods, Molluses, Echinodermsand Chodrates : Organ system level of organization.(1) All are correct except (ii)(2) (ii) and (iv) are correct(3) (ii) and (iii) are correct(4) (i) and (ii) are correct

142. Which of the following characters belongs to sameclass :A. 6-15 gill slits, operculum, myxineB. Aircavity, warm blooded, flying foxC. Sinus venosus, four chambered heart,

crocodilusD. Star shape, water vescular system, fertilisation

internal(1) A, B (2) B, C, D(3) Only B (4) None of these

143. Of which the body is made up of 33 somites :(1) Leech (2) Earthworm(3) Tapeworm (4) Slug

144. Identify the wrong statement :(1) Tendon connect skeletal muscle with bones(2) Ligaments connect bones with bones(3) Adipose tissue store protein(4) Matrix of cartilage posseses chondrin protein

145. EC 5.2.1.2 represents :(1) Enzyme hydrolyse the reactant(2) Enzyme oxidise the reactant(3) Enzyme isomerise the reactant(4) Enzyme reduces the reactant

139. fuEu voLFkk dks igpkfu;s :

(1) e/;koLFkk

(2) e/;koLFkk -I

(3) e/;koLFkk -II

(4) i'pkoLFkk - II140. buesa ls dkSu&ls vaxksa esa vadqj o lw{ekadqj ekStwn gksrs gS\

(1) xzluh (2) vkek'k;(3) NksVh vk¡r (4) cMh vk¡r

141. fuEu esa ls dkSulk lgh gS \i. Liat : dksf'kdh; Lrj dk laxBuii. fuMsfj;k : ÅÙkd vax Lrj dk laxBuiii. IysVhgsfYeUFkht : vax Lrj dk laxBuiv. ,usfyMk] vkFkksZiksMk] eksyLdk] bdkbuksMesZVk] dksMsZVk: vax ra= Lrj dk laxBu(1) (ii) dks NksM+ dj lHkh lgh gSA(2) (ii) o (iv) lgh gSA(3) (ii) o (iii) lgh gSA(4) (i) o (ii) lgh gSA

142. fuEu esa ls dkSuls y{k.k ,d gh oxZ ls lEcfU/kr gS :A. 6-15 Dykse njkjsa, izPNn, feDlkbuB. ok;qxqgk, lerkih, ¶ykbax QkWDlC. f'kjk dksVj, pkj d{kh; ân;, exjePN

D. rkjs dh vkÑfr, ty laogu ra=, cká fu"kspu

(1) A, B (2) B, C, D(3) dsoy B (4) dksbZ ugha

143. fdldk 'kjhj 33 nsg[k.Mksa (Somites) dk cuk gksrk gS :(1) tkSad (2) dsapqvk(3) QhrkÑfe (4) Lyx

144. xyr dFku dks igpkus :(1) d.Mjk dadkfy; is'kh dks vfLFk;ksa ls tksM+rh gS(2) Luk;w vfLFk;ksa dks vfLFk;ksa ls tksM+rh gS(3) ,fMiksl mÙkd izksVhu laxzfgr djrs gS(4) mikfLFk dh vk|k=h esa dkWfUMªu izksVhu gksrk gS

145. EC 5.2.1.2 iznf'kZr djrk gS :(1) ,atkbe vfHkdkjd v.kq dk ty vi?kVu djrk gS(2) ,atkbe vfHkdkjd v.kq dks vkWDlhÑr djrk gS(3) ,atkbe vfHkdkjd v.kq dk leko;ohdj.k djrk gS(4) ,atkbe vfHkdkjd v.kq dk vip;u djrk gS



146. Apocrine secretion of gland means :(1) Entire contents of cells is discharged with the

destruction of the cell(2) When the product is discharged the cell remains

intact(3) When part of apical cytoplasm is lost(4) None of the above

147. The mouth part of a cockroach are said to be :(1) Absorbing type(2) Biting and absorbing type(3) Biting and chewing type(4) Biting and sucking type

148. The four sketches (A, B, C and D) gives below,represent four different types of animal tissues.Which one of these is correctly identified in theoptions given, along with its correct location andfunction :

(A) (C)

(B) (D)

Tissue Location Function (1) (A) Smooth

muscle tissue Heart Heart

contraction (2) (B) Columnar

epithelium Nephron Secretion and

absorption (3) (C) Glandular

epithelium Intestine Secretion

(4) (D) Collagen fibres

Cartilage Attach skeletal muscles to

bones

146. xzafFk;ksa ds viL=koh L=ko.k ls rkRi;Z gS :(1) dksf'kdk ds u"V gksus ij lEiw.kZ dksf'kdk ds ?kVd

fu"dkflr gks tkrs gS(2) tc mRikn fu"dkflr gksrk gS rks dksf'kdk ;Fkkor

jgrh gS(3) 'kh"kZLFk dksf'dk nzO; dk Hkkx [kks tkrk gS(4) mijksDr esa ls dksbZ ugha

147. dkWdjksp ds eq[kkax fdl izdkj ds gksrs gS :(1) vo'kks"kh izdkj ds(2) dkVus o vo'kks"kh izdkj ds(3) dkVus o pckus izdkj ds(4) dkVus o pw"k.k izdkj ds

148. uhps fn;s x,a pkj fp=ks (A, B, C rFkk D) esa] pkj izdkjds izk.kh Ård fn[kk, x, gS] buesas ls fdl ,d dks uhpsfn;s x, fodYiksa esa ls lgh igpkuk x;k ,ao mlds ik;stkus dk LFkku rFkk dk;Z Hkh lgh fn;s x, gS :

(A) (C)

(B) (D)

Ård ik;s tkus dk LFkku

dk;Z

(1) (A) fpduh is’ kh Ård

ân; ân; ladqpu

(2) (B) LrEHkkdkj midyk

usÝkWu L=ko.k ,oa vo’ kks"k.k

(3) (C) xzafFky midyk vka= L=ko.k (4) (D) dkSyStsu js'ks mikfLFk dadkyh; isf'k;ks a

dks gfì;ksa ds lkFk tksM+rs gSaA



149. When two flagella in a cell are dissimilar it is called :(1) Isokont (2) Heterokont(3) Akont (4) Anisogamy

150. Nucleoid is :(1) A single inactive nucleus having double stranded

DNA and proteins(2) A group of chromosomes associated with

proteins(3) A nucleus without nuclear membrane and

nucleolus or genetic material of prokaryotes(4) A chromosome associated with proteins

151. The quaternary structure of a protein :(1) Consists of 4 subunits-hence the same

quaternary(2) Is unrelated to the function of the protein(3) Both (1) and (2)(4) Depends on the 1° structure of subunits

152. Which one out of following is not lipid :

(1) R –C–O—CH2

CH –O–C–R2 3

CH –O–C–R2 1

O

O

O

(2) R –C–O—CH2

CH –O–P–O–CH –CH2 2 2

CH –O–C–R2 1

O

O

O

OHCH3

CH3

CH3

N

(3)

HO

(4)

COOH

H—C—NH2

CH —OH2

149. tc dksf'kdk ds nks ¶ysftyk vleku gks rks dgykrsgSa &(1) vkblksdksUV (2) gsVjksdksUV(3) ,dksUV (4) ,uvkblksxSeh

150. U;wfDyvksbM gksrk gSa %(1) ,d fuf"Ø; dsUnzd ftlesa nksgjk dq.Mfyr DNA o izksVhu gksrk gSa(2) izksVhu ls lEcfU/kr xq.klw=ksa dk leqg(3) ukfHkd ftlesa ukfHkdh; f>Yyh o U;wfDy;ksyl ugha gksrk vFkok izksdSfj;ksV dk vkuqoakf'kd inkFkZ(4) ,d Øksekslkse tks izksVhu ls lacaf/kr jgrk gSa

151. izksVhu dh prqFkZd lajpuk :(1) pkj mi bZdkb;ksa ls cuh gksrh gS vr% prqFkZd lajpuk

dgykrh gSA(2) izksVhu ds dk;Z ls lEcfU/kr ugha gksrh gSA(3) (1) rFkk (2) nksuks(4) mi bZdkb;ksa dh 1° lajpuk ij fuHkZj djrh gSA

152. fuEu esa ls dkSulk fyfiM ugha gS :

(1) R –C–O—CH2

CH –O–C–R2 3

CH –O–C–R2 1

O

O

O

(2) R –C–O—CH2

CH –O–P–O–CH –CH2 2 2

CH –O–C–R2 1

O

O

O

OHCH3

CH3

CH3

N

(3)

HO

(4)

COOH

H—C—NH2

CH —OH2



153. Cell organelle specialised in forming acrosome partof sperm is :(1) Mitochondrion (2) Centriole(3) Peroxisome (4) Golgi apparatus

154. Choose the correct option :

A

B

(1) A–Activation energy without enzyme –reactionis exothermic

(2) A–Activation energy with enzyme–reaction isendothermic

(3) B–Activation energy with enzyme–reactionis endothermic

(4) B–Activation energy without enzyme–reactionis exothermic

155. Identify the flow of blood in A, B, C and D :

A B

CD

A B C D

1 Postirio r Anterio r Down Up

2 Anterio r Down Up Postirio r

3 Up Postirio r Anterio r Down

4 Postirio r Down Up Anterio r

153. dkSulk dksf'kdkax fo'ks"k :i ls 'kqØk.kq ds ,Økslkse Hkkxdks cukrk gS %(1) ekbVksdkWf.Mª;k (2) lsUVªh;ksy(3) ijvkWDlhlkse (4) xkWYth midj.k

154. lgh fodYi dk p;u djsa :

A

B

(1) A–,Utkbe ds fcuk lfØ;.k ÅtkZ rFkk vfHkfØ;kÅ"ek{ksih

(2) A–,Utkbe ds lkFk lfØ;.k ÅtkZ rFkk vfHkfØ;kÅ"ek'kks"kh

(3) B–,Utkbe ds lkFk lfØ;.k ÅtkZ rFkk vfHkfØ;kÅ"ek'kks"kh

(4) B–,Utkbe ds fcuk lfØ;.k ÅtkZ rFkk vfHkfØ;kÅ"ek{ksih

155. A, B, C rFkk D esa jDr izokg dh fn'kk igpkfu;s :

A B

CD

A B C D

1 i hN s v kx s uhp s Åij

2 vkx s uhp s Åij i hN s

3 Åij i hN s v kx s uhp s

4 i hN s uhp s Åij v kx s



156. izk.kh lsY;qykst dks D;ksa ugh ipk ikrs :(1) bles dbZ gkbMªkstu ca/k gksrs gS tks mi bdkb;ksa dks

ck/ksa j[krs gSA(2) lsY;qykst dh mi bdkb;ksa dks tksMus okys ca/k vR;f/kd

etcwr gksrs gSA(3) tarqvks esa mi bdkb;ksa ds e/; fLFkr ca/kks dks rksMus

gsrq mi;ZqDr ,atkbe ugh gksrs gSA(4) lsY;qykst vikP; dkbfVu dk cuk gksrk gSA

157. ,d U;wfDy;ksVkbM cuk gksrk gS%(1) I;wfju] ikbjhfeMhu o QkWLQsV dk(2) I;wfju] 'kdZjk o QkWLQsV dk(3) ukbVªkstu {kkj] 'kdZjk o QkWLQsV dk(4) ikbjhfeMhu] 'kdZjk o QkWLQsV dk

158. ;ksfu] xzkluky rFkk ew=ekxZ esa fdl izdkj dk mrd ik;ktkrk gS :(1) i{ekfHkdh; midyk(2) LrEHkkdkj midyk(3) ljy 'kYdh midyk(4) Lrfjr 'kYdh midyk

159. fuEu esa ls dkSulk L=koh mRikn ds fy, lgh Øe gS

(1) vUrj iznZO;h tkfydk iqfV~VdkxkWYthdkW;dk lei{k {ks= xkWYthdkW; dk foi{k {ks=iqfV~Vdk IykTek f>Yyh

(2) [kqjnjh vUrj iznZO;h tkfydk iqfV~Vdkykblkslkse ukfHkdh; f>Yyh IykTek f>Yyh

(3) vUrj iznZO;h tkfydk iqfV~VdkxkWYth dkW;dk foi{k { k s= xkWYthdk W; dk lei{k{ks=iqfV~Vdk IykTek f>Yyh

(4) ykblkslksevUrj iznZO;h tkfydk xkWYthdkW;iqfV~Vdkdksf'kdk f>Yyh

160. tUrq dk og lewg tgk¡ o;Ld vfodflr fdUrq ykokZv f/kd fod fl r gksr s gSa :(1) ,XusFkk(2) V~;wuhdsV~l(3) ,EQhfc;u(4) flQsyksdkWMsZV~l

156. Why animals cannot digest cellulose :(1) There are many hydrogen bonds holding the

subunits together(2) The bonds holding cellulose subunits together

are extremely strong(3) They do not have the proper enzyme to break

the bonds between subunits(4) Cellulose is made up of indigestible chitin

157. A nucleotide is formed of :(1) Purine, pyrimidine and phosphate(2) Purine, sugar and phosphate(3) Nitrogen base, sugar and phosphate(4) Pyrimidine, sugar and phosphate

158. Vagina, oesophagus and urethra contain which typeof tissue :(1) Ciliated epithelium(2) Columnar epithelium(3) Simple squamous epithelium(4) Stratified squamous epithelium

159. Which of the following is the correct sequence/route of the secretory product ?(1) ERVesiclesCis region of GB Transans

region of GB Vesicles Plasma membrane

(2) RERGBLysosome Nuclear membraneane

Plasma membrane(3) ERVesicles Trans region of GBCis

region of GB Vesicles Plasma membrane

(4) Lysosome ER GB Vesicles Celllmembrane

160. The animal group, where the adults aredegenerated but larvae are well developed, is :(1) Agnatha(2) Tunicates(3) Amphibians(4) Cephalo chordates



161. Which one is correct :(1) Notochord is a mesodermally derived rod like

structure formed on the dorsal side inembryonic development in all vertibrate animals

(2) Notochord is a mesodermally derived rod likestructure formed on the dorsal side inembryonic development in all animals

(3) Porifera to Echinodermata are non- chordates(4) 2 and 3

162. The main difference between the living and non livingis :(1) In the growth(2) In the size(3) In the movement(4) In the presence of protoplasm

163. Male and female cockroaches can be distinguishedexternally through :(1) Anal styles in Male(2) Anal cerci in female(3) Anal style and Antennae in females(4) Both 2 and 3

164. Cytoplasm of one cell is connected with otherthrough :(1) Cytoplasmic strands (2) Plasmodesmata(3) Torus (4) Pit membrane

165. Go through the section of view of chloroplastshowing the different parts and tell in which partdark reaction occur :

(1) B - Thylakoid(2) A - Stroma(3) D - Stroma(4) C - Stroma lamella

161. dkSulk ,d dFku lR; gS :(1) uksVksdkWMZ fetksMeZ ls O;qRiu ,d NM tSlh lajpuk gS]

tks lHkh d'ks:d tUrqvksa ds Hkzw.kh; fodkl ds nkSjkui"B lrg ij curh gS

(2) uksVksdkWMZ ] mn~Hko esa ehtksMeZy gksrk gS rFkk lHkhthoks es ikbZ tkrh gS

(3) ikWjhQsjk ls bdkbuksMesZVk rd vd'ks:dh gksrs gSa(4) 2 vksj 3

162. thfor vkSj vthfor esa izeq[k vUrj gS

(1) of) esa (2) ifjek.k esa

(3) xfr esa (4) izksVksIykTe dh mifLFkfr esa163. uj rFkk eknk dkWdjksp esa cká :i ls vUrj fd;k tk ldrk

gS%(1) uj esa xqnk 'kwd ls(2) eknk esa ,uy ldkZbZ ls(3) eknk esa ,uy LVkby rFkk Ükafxdkvksa ls(4) nksuksa 2 o 3

164. ,d dksf'kdk dk thonzO; nwljh dksf'kdk ds thonzO; lsfdlds }kjk tqM+k jgrk gS(1) lkbVksIykfTed LVsªUM (2) IykTeksMsLesVk(3) Vksjl (4) xrZ f>Yyh

165. DyksjksIykLV ds dkV fuEu Hkkxksa dks n'kkZ;k gS rFkk fdlHkkx esa vizdkf'kd vfHkfØ;k gksrh gS &

(1) B - Fkk;ysdkWbM(2) A - LVªksek(3) D - LVªksek(4) C - LVªksek ysfeyh



166. fuEu esa ls le cgqyd gS :(1) LVkpZ , lsY;wykst, Xykbdkstu rFkk bU;wfyu(2) bU;wfyu] dkbfVu] isfDVu(3) lsY;wykst , bU;wfyu, ikWyhisIVkbM(4) izksVhu , fyfiM rFkk ikWyhlSdsjkbM

167. lelw=h foHkktu ds fy, lgh dFku pqusA(1) VhyksQst esa ØksesfVM+ foifjr /kzqoksa dh vkSj xfr djuk

izkjEHk djrs gSaa(2) Golgi vkSj ER izksQst ds var rd fn[kkbZ nsrs gSaA

(3) Øksekslkse rdqZ e/;ka'k dh rjQ xfr djrs gSaA vkSjbDosVj Plate ij Metaphase voLFkk esa bDB~Bs gkstkrs gSaA

(4) ,ukQst voLFkk esa ØksesfVM+ vyx gks tkrs gSa ijUrqdksf'kdk ds dsUnz esa jgrs gSa

168. fd;kTesVk curs gSa%(1) letkr xq.klw=ks ds dqN Hkkx ds chp Økflax vkWoj

(2) vletkr xq.klw=ks ds dqN Hkkx ds chp Økflax vkWoj

(3) leku rFkk vleku xq.klw=ksa ds }hxq.ku ds nkSjku

(4) xq.klw=ks ds dqN Hkkx dh {kfr

169. lkekU; dksf'kdh; fØ;k,a tSls çksVhu la'ys"k.k vkfnçkFkfed :i ls fdlds nkSjku gksrh gS %(1) baVjQst(2) ,ukQst(3) esVkQst(4) çksQst

170. fuEu esa ls dkSulk lgh lqesfyr gS :

(1) piVs Ñfe vf/kdka'k ckáijthoh

(2) lfjliZ vf/kdka'k LFkyh;

(3) Y;wflQj yksdLV

(4) fuMksCykLV VhuksQksjk

166. Which one is homopolymer :(1) Starch, Cellulose, Glycogen and inulin(2) Inulin, Chitin, Pectin(3) Cellulose, Inulin, Polypeptide(4) Protein, Lipid and polysaccharide

167. Select the correct option with respect to mitosis :(1) Chromatids start moving towards opposite

poles in telophase(2) Golgi complex and endoplasmic reticulum are

still visible at the end of prophase(3) Chromosomes move to the spindle equator and

get aligned along equatorial plate in metaphase

(4) Chromatids separate but remains in the centreof the cell in anaphase

168. Chiasmata are formed due to(1) Crossing over of some part between

homologous chromosomes(2) Crossing over of some part between non-

homologous chromosomes(3) Dupl ication of homologous and non-

homologous chromosomes(4) Loss of some part of chromosomes

169. Normal cellular activities, such as protein synthesisoccur primarily during :(1) Interphase(2) Anaphase(3) Metaphase(4) Prophase

170. Which of the following correctly match :

(1) Flat worms Mostly ectoperasites(2) Reptiles Mostly terristrial(3) Luccifer Locust(4) Cnidoblast Ctenophora



171. Recognise the figure and find out the correctmatching

(1) a-ovary, b-oviduct, c-vagina, d-collaterial gland(2) b-ovary, a-oviduct, d-vagina, c-collaterial gland(3) c-ovary, d-oviduct, b-vagina, a-collaterial gland(4) d-ovary, c-oviduct, a-vagina, b-collaterial gland

172. Which of the followign correctly shows a pair ofhomologous chromosomers at the start of meiosis?

(1) (2)

(3) (4)

173. Without exception, all birds are :

(1) Omnivorous

(2) Have feathers and fly

(3) Form nests and care their young one

(4) Have calcareous shelled egg

171. fp= dks igpkudj lgh fodYi dk p;u djsa

(1) a-v.Mk'k;, b-v.Mokfguh, c-;ksfu, d-laikf'oZd xzafFk(2) b-v.Mk'k;, a-v.Mokfguh, d-;ksfu, c-laikf'oZd xzafFk(3) c-v.Mk'k;, d-v.Mokfguh, b-;ksfu, a-laikf'oZd xzafFk(4) d-v.Mk'k;, c-v.Mokfguh, a-;ksfu, b-laikf'oZd xzafFk

172. fuEu esa ls dkSulk izkjfEHkd v/kZlw=h foHkktu ds laHkkxhxq.klw=ksa ds ;qXeksa dks iznf'kZr djrk gS

(1) (2)

(3) (4)

173. fcuk fdlh viokn ds i{kh gksrs gS :

(1) lokZgkjh

(2) ia[k mifLFkr ,oa mM+us okys

(3) ?kkslys cukuk ,oa iSrd laj{k.k

(4) v.Mksa ij dSYdsfj;l dop ik;k tkrk gS



174. Identify A, B, C and D

A

B

C

D

A B C D 1 Stensons

duct Submendibular gland

Parotid gland Whartons duct

2 Stensons duct

Parotid gland Submendibular gland

Whartons duct

3 Whartons duct

Parotid gland Submendibular gland

Stensons duct

4 Parotid gland

Submendibular gland

Stensons duct Whartons duct

175. If the pancreating duct of a healthy dog is blockedan hour after it had its food, which one of thefollowing functions of the pancreas will not beaffected-(1) Carbohydrate digestion(2) Neutralization of chyme(3) Break down of protein(4) Maintenance of normal blood sugar level

176. A phosphoglyceride is always made up of :(1) a saturated or unsaturated fatty acid esterified

to a phosphate group which is also attachedto a glycerol molecule

(2) only a saturated fatty acid esterified to a glycerolmolecule to which a phosphate group is alsoattached

(3) only a unsaturated fatty acid esterified to aglycerol molecule to which a phosphate groupis also attached

(4) a saturated or unsaturated fatty acid esterifiedto a glycerol molecule to which a phosphategroup is also attached

174. A, B, C rFkk D dks igpkfu;s

A

B

C

D

A B C D 1 LVsUlUl

ufydk v/kksguq ykj xzafFk

d.kZewy ykj xzafFk

okjVUl ufydk

2 LVsUlUl ufydk

d.kZewy ykj xzafFk

v/kksguq ykj xzafFk

okjVUl ufydk

3 okjVUl ufydk

d.kZewy ykj xzafFk

v/kksguq ykj xzafFk

LVsUlUl ufydk

4 d.kZewy ykj xzafFk

v/kksguq ykj xzafFk

LVsUlUl ufydk okjVUl ufydk

175. ;fn ,d LoLFk 'oku dks Hkkstu nsus ds i'pkr~ mldhvXU;k'k; ufydk dks ,d ?k.Vs ds fy;s cUn dj fn;ktk;s rks vXU;k'k; dk fuEu esa ls dkSulk dk;Z ÁHkkforugha gksxk &

` (1) dkcksZgkbMªsV ikpu(2) dkbe dk mnklhuhdj.k(3) ÁksVhu dk VwVuk(4) lkekU; jDr 'kdZjk Lrj esa fu;eu

176. QkLQksfXyljkWbM lnSo cus gksrs gSa(1) QWkLQsV lewg ls ,LVjhÑr ,d larIr ;k vlarIr

olk vEy ftlls ,d fXyljkWy v.kq Hkh la;ksftr jgrk gSA

(2) fxyljkWy v.kq ls ,LVjhÑr ,d larIr olk vEyftlls QWkLQsV lewg Hkh la;ksftr jgrk gSA

(3) fXyljkWy v.kq ls ,LVjhÑr ,d vlarIr olk vEyftlls QWkLQsV lewg Hkh la;ksftr jgrk gSA

(4) fXyljkWy v.kq ls ,LVjhÑr ,d larIr ;k vlarIrolk vEy ftlls QkLQsV lewg Hkh la;ksftr jgrkgSA



177. Which one of the following pairs is not correctlymatched :(1) Vitamin B12 – Pernicious anaemia(2) Vitamin B6 – Loss of appetite(3) Vitamin B1 – Beri-beri(4) Vitamin B3 – Pellagra

178. Component of blood responsible for producingantibodies is :(1) Thrombocytes (2) Monocytes(3) Erythrocytes (4) Lymphocytes

179. Where do certain symbiotic microorganismsnormally occur in human body :(1) Oral lining and tongue surface(2) Vermiform appendix and rectum(3) Duodenum(4) Caecum

180. As per following diagram which cross match isincorrect :

D

(1) A - External muscularis(2) B - Submucosa(3) C - Mucosa(4) D - Circular muscularis

177. fuEu esa ls dkSu & lk tksM+k lqesfyr ughsa gS

(1) foVkfeu B12 & fouk'kdkjh jDrkYirk(2) foVkfeu B6 & Hkw[k dh deh(3) foVkfeu B1 & csjh & csjh(4) foVkfeu B3 & isysxzk

178. :f/kj dk og ?kVd tks ,aUVhckWfMt ¼izfrj{kh½ dks mRiUudjrk gS %(1) FkzksEckslkbV~l (2) eksukslkbV~l(3) bfjFkzkslkbV~l (4) fyEQkslkbV~l

179. ekuo 'kjhj esa dgka dqN lgthoh lw{e thok.kqvksa lkekU;:i ls ik;s tkrs gSa\(1) ekSf[kd vLrj vkSj thHk dh lrg(2) ,isf.MDl vkSj eyk'k;(3) xzg.kh(4) lhde

180. fuEu fp=kuqlkj dkSulk lqesy lgh ugha gS

D

(1) A - cká is'khLrj(2) B - v/k%'ysf"edk(3) C - 'ysf"edk(4) D - orZqy is'khLrj



ANSWER KEY (XI NEET)

Q. 1 2 3 4 5 6 7 8 9 10 11 12 13Ans. 1 1 1 3 1 2 1 4 3 2 2 2 2Q. 14 15 16 17 18 19 20 21 22 23 24 25 26Ans. 1 1 2 1 1 3 4 3 2 2 1 1 2Q. 27 28 29 30 31 32 33 34 35 36 37 38 39Ans. 2 2 1 3 3 2 3 1 1 2 1 3 1Q. 40 41 42 43 44 45Ans. 1 1 3 3 2 2Q. 46 47 48 49 50 51 52 53 54 55 56 57 58Ans. 1 3 4 4 3 4 3 2 4 4 4 2 3Q. 59 60 61 62 63 64 65 66 67 68 69 70 71Ans. 4 2 3 2 2 3 2 3 3 3 2 4 1Q. 72 73 74 75 76 77 78 79 80 81 82 83 84Ans. 1 1 2 2 2 2 1 3 3 4 4 3 2Q. 85 86 87 88 89 90Ans. 2 2 2 1 3 1Q. 91 92 93 94 95 96 97 98 99 100 101 102 103Ans. 3 4 3 3 4 4 2 2 2 3 3 1 1Q. 104 105 106 107 108 109 110 111 112 113 114 115 116Ans. 2 4 3 1 3 1 1 2 4 2 3 4 1Q. 117 118 119 120 121 122 123 124 125 126 127 128 129Ans. 2 2 1 4 1 4 3 1 3 2 2 4 2Q. 130 131 132 133 134 135Ans. 3 4 4 2 2 2Q. 136 137 138 139 140 141 142 143 144 145 146 147 148Ans. 3 2 1 3 3 1 4 1 3 3 3 3 3Q. 149 150 151 152 153 154 155 156 157 158 159 160 161Ans. 2 3 4 4 4 2 2 3 3 4 1 2 1Q. 162 163 164 165 166 167 168 169 170 171 172 173 174Ans. 4 1 2 3 1 3 1 1 2 1 4 4 2Q. 175 176 177 178 179 180Ans. 4 4 2 4 4 1

Note : - B means Bonus

Class XI BIO Group - Synthesis Bikaner€¦ · The OMR Sheet is kept inside the Test Booklet. When...

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Transcript of Class XI BIO Group - Synthesis Bikaner€¦ · The OMR Sheet is kept inside the Test Booklet. When...