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Share       Paper Type : Whole-TestpaperPosted By : JaicUpdated Date : Dec 28, 2012Cisco Whole-Testpaper placement paper Question and answersCisco recruitment process and aptitude test experiencesCISCO PLACEMENT PAPER    CAUTION: There is a -ve marking of +1 & -1 u dont mark blindly.Mark theanswer if u know exactly.cutoff will be 25 marks out of 60.So becareful.There r 2 sections in CISCO section 1: Aptitude 20 marks (10 aptitude,10analogy,oppositewords etc)) section 2:comp sc (data structue , c, theory of computation,networks,operating systems)I collected upto 20 questions; In this setion questions exact numbers I have forgotten.So this will be useful to the style of the problem only.  SECTION 1:   1: A man went to market with some money.With that money he can buy 15 pencils or 25 pens.He kept 15% of that money for bus fare and with rest of the money he purchased 5 pencils,and 'x' pens.How many pens he purchased? 2:A man climbing a wall.For every 4 steps go up he will slipdown 2 steps.If he takes 12 min to 3 steps.how much time it takes to climb 48meters and one step=2meters. 3: Two trains with lengths x and y ,and speeds u and v.Approaching each other how much time it takes to takes for faster train to cross othertrain?In this question I don't remember the x,y,u,v.U can find formula in Aggarwal's quantitative aptitude book 4: there was some question on ages that was easy SECTION 2:

Great

1. main()   { fork();     fork();     fork();     printf("hello");   }How many times it will print hello? 2: char A[5,6] How many bytes it requires? 3:Bridges are used in which layer? 4.Bigendian meansa)lower byte stored in lower addressb)lower byte stored in higher addressone of these is correct.u can verify in Any micro processor book. 5: #define mmx 10+10   printf"%d",mmx*mmx); 6: main()   { j=0      for(i=0;i<10;i++)      {  j+=i; }   }what is the value of i & j at the end of the loopans: 10,46 7: Regular expression with 2 consecutive 1's and all string of 0's and 1's 8: dead lock conditions 1 question 9: selective repeat widow size of sender & receiver 1 question. 10;Balanced trees 1 question

1     What is the probability of getting at least one six in a single throw of three unbiased dice?

(1) 1 / 6(2) 125 / 216(3) 1 / 36(4) 81 / 216(5) 91 / 216

Correct choice is (5) and Correct Answer is 91 / 216Explanatory AnswerEvery die has got six sides. Each of the sides is numbered from 1 to 6.When a single unbiased die is thrown you can have six possible outcomes. When two dice are thrown simultaneously, the total number of outcomes will be 6 * 6 = 36Similarly, when three dice are thrown simultaneously, the total number of outcomes will be 6*6*6=216.We need to find out the number of cases in which at least one of the facing sides shows 6.At least one means - either one dice or two dice or all three.

Case 1: Let us take the easiest case first - all three dice showing '6' - There is only one such possibility.

Case 2: The number of cases in which two of the dice show 6 and one of them is a different number.

For eg an event like 6 6 5 will be one of the outcomes for case 2.

As two of the dice show '6' , it can happen in only one way. The third die shows a different number, a number other than 6, and it can be any of the 5 other numbers. Therefore, there will 5 possible options i.e. (1, 6, 6), (2, 6, 6), (3, 6, 6), (4, 6, 6), (5, 6, 6).

However, each of these possibilities can have three different arrangements depending upon where the third different digit appears. For example take (1, 6, 6) case - it will have three options (1, 6, 6), (6, 1, 6), (6, 6, 1). 

Therefore, the total number of events in which 2 of the dice will show '6' and one will show a different number = 5*3 = 15 cases.

Case 3: When only one of the die shows '6' and the other two show numbers other than '6'.

The die showing '6' has only one option. The other two dice can have any of the '5' options. Therefore, the total number of possibilities = 1*5*5 = 25.

However, the die showing '6' can either be the first die or the second die or the third die. 

Therefore, there are a total of 25 * 3 = 75 possibilities.

Total possible outcomes where at least one die shows '6' = Case 1 + Case 2 + Case 3 = 1 + 15 +75 = 91.

Therefore, the required probability = 91/216

Alternate approach:

Find the number of cases in which none of the digits show a '6'. 

i.e. all three dice show a number other than '6', 5 * 5 *5 = 125 cases. 

Total possible outcomes when three dice are thrown = 216.

The number of outcomes in which at least one die shows a '6' = Total possible outcomes when three dice are thrown - Number of outcomes in which none of them show '6'.

= 216 - 125 = 91.

The required probability = 91/216

2     When two dice are thrown simultaneously, what is the probability that the sum of the two numbers that turn up is less than 11? 

(1) 5 / 6 (2) 11 / 12(3) 1 / 6 (4) 1 / 12Correct Answer - (2)Solution:

Instead of finding the probability of this event directly, we will find the probability of the non-occurrence of this event and subtract it from 1 to get the required probability.

Combination whose sum of 12 is (6,6)

Combinations whose sum of 11 is (5,6), (6,5).

Therefore, there are totally 3 occurrences out of 36 occurrences that satisfy the given condition.

Probability whose sum of two numbers is greater than or equal to 11 = 3 / 36 = 1 / 12.

Hence probability whose sum of two numbers is lesser than 11 = 1 - 1 / 12 = 11 / 12.

3     The average monthly salary of 12 workers and 3 managers in a factory was Rs. 600. When one of the manager whose salary was Rs. 720, was replaced with a new manager, then the average salary of the team went down to 580. What is the salary of the new manager? Rs 570Rs 420Rs 690Rs 640Rs 610Correct Answer - Rs 420. Choice (2)

Explanatory Answer

The total salary amount = 15 * 600 = 9000

The salary of the exiting manager = 720.

Therefore, the salary of 12 workers and the remaining 2 managers = 9000 - 720 = 8280

When a new manager joins, the new average salary drops to Rs.580 for the total team of 15 of them. 

The total salary for the 15 people i.e., 12 workers, 2 old managers and 1 new manager = 580 *15 = 8700

Therefore, the salary of the new manager is 9000 - 8700 = 300 less than that of the old manager who left the company, which is equal to 720 - 300 = 420.

An alternative method of doing the problem is as follows:

The average salary dropped by Rs.20 for 15 of them. Therefore, the overall salary has dropped by 15*20 = 300.

Therefore, the new manager's salary should be Rs.300 less than that of the old manager = 720 - 300 = 420.

Correct answer choice (2) 

4     If the letters of the word CHASM are rearranged to form 5 letter words such that none of the word repeat and the results arranged in ascending order as in a dictionary what is the rank of the word CHASM?

(1) 24(2) 31(3) 32(4) 30Correct Answer - (3)Solution:

The 5 letter word can be rearranged in 5! Ways = 120 without any of the letters repeating.

The first 24 of these words will start with A.

Then the 25th word will start will CA _ _ _. The remaining 3 letters can be rearranged in 3! Ways = 6. i.e. 6 words exist that start with CA.

The next word starts with CH and then A, i.e., CHA _ _. The first of the words will be CHAMS. The next word will be CHASM.

Therefore, the rank of CHASM will be 24 + 6 + 2 = 32.

5     The time in a clock is 20 minute past 2. Find the angle between the hands of the clock.(1) 60 degrees(2) 120 degrees(3) 45 degrees(4) 50 degreesCorrect choice (4). Correct Answer - 50 degreesSolution:

Time is 2:20. Position of the hands: Hour hand at 2 (nearly).Minute hand at 4Angle between 2 and 4 is 60 degrees [(360/12) * (4-2)]Angle made by the hour hand in 20 minutes is 10 degrees, since it turns through ½ degrees in a minute.Therefore, angle between the hands is 60 degrees - 10 degrees = 50 degrees

6    .A 12% stock yielding 10% is quoted at:

A.Rs. 83.33B.Rs. 110C.Rs. 112D.Rs. 120Answer: Option DExplanation:To earn Rs. 10, money invested = Rs. 100.To earn Rs. 12, money invested = Rs.100x 12= Rs. 120.10 Market value of Rs. 100 stock = Rs. 120

7 A and B take part in 100 m race. A runs at 5 kmph. A gives B a start of 8 m and still beats him by 8 seconds. The speed of B is:

A.5.15 kmphB.4.14 kmphC.4.25 kmphD4.4 kmphAnswer: Option BExplanation:

8 100 oranges are bought at the rate of Rs. 350 and sold at the rate of Rs. 48 per dozen. The percentage of profit or loss is:

9    What was the day of the week on 28th May, 2006?A.ThursdayB.FridayC.SaturdayD.SundayAnswer: Option DExplanation:28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)Odd days in 1600 years = 0Odd days in 400 years = 05 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2)  6 odd daysJan. Feb. March April May (31 + 28 + 31 + 30 + 28 ) = 148 days148 days = (21 weeks + 1 day)  1 odd day.Total number of odd days = (0 + 0 + 6 + 1) = 7  0 odd day.Given day is Sunday.

10 The H.C.F. of two numbers is 11 and their L.C.M. is 7700. If one of the numbers is 275, then the other is:

A.279B.283C.308D.318Answer: Option COther number =11 x 7700 = 308.275

11     How many digits will be there to the right of the decimal point in the product of 95.75 and .02554 ?

A.5B.6C.7D.None of theseAnswer: Option BExplanation:Sum of decimal places = 7.Since the last digit to the extreme right will be zero (since 5 x 4 = 20), so there will be 6 significant digits to the right of the decimal point.

12  One pipe can fill a tank three times as fast as another pipe. If together the two pipes can fill the tank in 36 minutes, then the slower pipe alone will be able to fill the tank in:A.81 min.B.108 min.C.144 min.D.192 min.Answer: Option CExplanation:Let the slower pipe alone fill the tank in x minutes.

13    A man purchased a cow for Rs. 3000 and sold it the same day for Rs. 3600, allowing the buyer a credit of 2 years. If the rate of interest be 10% per annum, then the man has a gain of:A 0%B.5%C.7.5%D.10%Answer: Option AExplanation:C.P. = Rs. 3000.

S.P. = Rs.

3600 x 100

= Rs. 3000.100 + (10 x 2)Gain = 0%.

14     Find out the wrong number in the series.

6, 12, 48, 100, 384, 768, 3072

A.768B.384C.100D.48E.12Answer: Option CExplanation:

Each even term of the series is obtained by multiplying the previous term by 2.2nd term = (1st term) x 2 = 6 x 2 = 124th term = (3rd term) x 2 = 48 x 2 = 96.6th term = (5th term) x 2 = 384 x 2 =768. 4th term should be 96 instead of 100

15     David gets on the elevator at the 11th floor of a building and rides up at the rate of 57 floors per minute. At the same time, Albert gets on an elevator at the 51st floor of the same building and rides down at the rate of 63 floors per minute. If they continue travelling at these rates, then at which floor will their paths cross ?A.19B.28C.30D.37Answer: Option C 

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Next Papers Cisco Placement-Paper-Candidate-Experien...

CISCO PAPER PATTERN ON 17th AUGUST AT COCHIN

Hi friends, 

Cisco visit my campus (CUSAT,cochin) on 17-08.

Cisco selected 4 students out of 24 who selected out of 500 after written exam.

I didn't get selected. cutoff was high.(44/50).

So you should score high to clear the test. I don't more about technical question, but according to my friend who selected,

you must have a sound knowledge of basics. because they search for best talent. so be confident abot your fundamentals. you can get...

Pattern:Test was conducted by Cisco. time allocated was one hour & total no. of questions were 50.there was no negative marking.

Papers contains aptitude, digital electronic,microprocessor,c(pointer),os,data structure,networking.

questions were not so easy. aptitude was relatively easier sections among those.tech were tougher.

exa: aptitude sections consists of probality,ven diagram,relative velocity(train),men & work,series sum,etc..

os-semaphore

ds-binary tree,stack...

mp-memory based i/o,...

de-simplification(AB+BC+AC).,flip flop,.

electonics-diode,rectifier,

By, Sanjay Kumar.Found the similar paper in recruitment ? :

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Previous Papers Next Papers Cisco/Placement-Paper-Aptitude-Numerical... Cisco Placement-Paper-Whole-Testpaper-32...

The starting location of an array is 1000. If the array[1..5/...4] is stored in row major order, what is the location of element[4][3]. Each work occupies 4 bytes. If the number of leaves in a binary tree are N, then the total number of internal nodes........(Assume complete binary tree)ANS: N-1The locality of reference means.............If two ausigned 8 bit numbers are multiplied what is the memory space required...............The vector address of RST 7.5 is ............ANS: 003C (multiply 7.5 by 8 and convert to hex int b = 0xAA;b>>4;printf("%x",b);What is the output of the above program.... 1.       struct s1 { struct { struct {int x;}s2}s3}y;How to access x? ANS: y.s3.s2.x 2.       Why there is no recursion in Fortran?ANS: There is no dynamic allocation 3.       What is the worst case complexity of Quick sort?ANS: O(n^2) 4.       Quick sort uses..............Ans: Divide and conquer 5.        In a sequential search, the time it takes to search through n elements is 6.       What is the size of the array declared as double * X[5]ANS: 5* sizeof (double *)

 7.       A binary search tree is given and asked to write the preorder traversal result. 8.       If size of the physical memory is 2^32-1, then the size of virtual memory...... 9.        S-> A0B A-> BB|0 B-> AA|1 How many strings of length 5 are possible with the above productions?? 10.   (3*4096+15*256+3*16+3). How many 1's are there in the binary representation of the result.ANS: 10 11.    In memory mapped I/O how I/O is accessed.............ANS: Just like a memory location (Means, I/O devices can be accessed using the instructions like mov A,M etc...) 12.    What is the use of ALE in 8085.......ANS: To latch the lower byte of the address. 13.    If the logical memory of 8 X 1024 is mapped into 32 frames, then the number of bits for the logical address ......ANS: 13 14.   Context free grammar is useful for...ANS: If-then structures. 15.   In ternary number representation, numbers are represented as 0,1,-1. Here -1 is represented as - (1 bar). Then how is 352/9 represented...... 16.   There are processors which take 4,1,8,1 machine cycles respectively. If these are executed in round robin fashion with a time quantum of 4, what is the time it take for process 4 to complete....ANS: 9 17.   The minimum frequency of operation is specified for every processor because...... 18.   In memory mapped I/O, what will happen if a device is identified with a 16 bit address and enabled by memory related control signals..... 19.   The reason for preferring CMOS over NMOS is....Ans: Low power consumption. 20.   Two binary numbers A,B are given and asked to find out A-B. 21.   Each character is represented by 7 bits, 1 bit is used to represent error bit and another bit for parity. If total number of bits transmitted is 1200bits, then number of symbols that can be transmitted....... 22.   One question about the setassociativity of cache.. 23.   Write the postfix form of the following expression...A+[[(B+C)+(D+E)*F]/G] 24.   What is the function of the linker...... 25.   void f(int y) {  struct s *ptr;

  ptr = malloc (sizeof (struct)+ 99*sizeof(int)); } struct s{  int i;  float p;  };when free(ptr) is executed, then what will happen?? system concepts:1.       int a[5,6]how much memory will be allocated2.       char p[6];char *d[10];ans:d=(char*)p3.       using LFU algorithm,how many page faults will occur of the pages r1,2,1,3,4.ans:1,44.       in which layer the bridges r used.a)data link layerb)session layerc)physical layerd)network layer 5.       #define d 10+10main(){ printf("%d",d*d);}6.       in a complete binary tree if the number of levels r 4 then the number ofnodes will be,7.       if we delete a node from a balanced binary tree,how can we retain theproperties of balanced binary tree.ans: by rotation at the nodes.8.       in a k-way search tree with N keys, the number of node/no. of leaves=9.       s->A0BA->BB|1B->AA|0how many string can be constructed with length 5.10.   in which of the following regular expression the srting containsatleast 2 concetive 1's.ans:(0+10)*||(0+1)*11.   int i,j=1;for(i=0;i<10;i++);{j=j+1;}printf("%d %d",i,j);ans:10 11 12.   static char *i;i=malloc(sizeof(char));find the error;ans:malloc returns void 13.   virtual memory address capacity depends on-- 

14.   main(){ int i=1;fork();fork();fork();printf("%d",i);}how many times i will be printedans:8 15.   question on threads 16.   int i=0xaachar *p;p=(char *)i;p=p>>4;printf("%x",p);ans:0x000000a; 17.   union{ char *p;int i;char b;}main(){--p=(char*)malloc(8*sizeof(char));}what is the size of union? 18.   enum{sunday=-1,monday,...saturday}printf("%d %d",sizeof(wednesday),wednesday); 19.   struct x{struct{struct{char ch;} x;}};ans:definition wrong 20.   struct *s;s=(struct *)malloc(10*sizeof(struct)+90*sizeof(int));free(s);ans:total memory deallocated 21.   one alogrithm is given:ans:10395 22.   func(){ int x=1;if(x=1)x=1000;elsex=10;

return x;}what is the return value?ans:1000It has taken 1 hr 15 min to complete the techinal round And in hr its simple no qs for me they will explain abt the company 

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CISCO PAPER ON 26th AUGUST  

1. Find perimeter of a trapezium with 3 sides given and distance between  parallel sides given.

2. A triangle ABC is given, a line DE is paralel to base side and that  cuts the triangle. The ratio of area

of triangle to the area of  trapezium .given DE/BC=3/5.

3. Four concentric circles are given. The radius of 1st circle is x.next  is 2x,then 3x and 4x. given that

area b/w 2nd and 1st is A and 4th  and 3rd circles being B.find ratio of A to B

4. What is the Difference between the perimeteres of two concentric circles is 66. Find  the difference

between radius

answer 10.5

5. 3/p=6,3/q=15. Find p-q

Cisco Technical questions

6. #define clrscr() 100

 main()

   {

   clrscr();

   printf(?%d?,clrscr());

  }  

7. which of the followin is used for avoiding network congestion

bufferin 

cachin 

Great

sourcequench

all of de above

8. main()

 {

  int a;

  printf(?%d?,scanf(%d,&a));

}

wats o/p of this pgm. What will b printed

ans :0

9. main()

  {

   printf(?as?); 

   printf(?\bhi?); 

   printf(?is\n?);

  }  wat will b printed.

10. main()

  {

   unsigned short a=-1;

   unsigned char b=a;

   printf(?%d %d ?,a,b);

  }

  wat is o/p of the program

a. 65535 -1

b. 65535 65535

c. -1 -1 

11. arrays base address is 1000?.array is a[5][4]..then wat is de 

correct address of a[4][3]?

ans:1056

12. one packet is 64bytes..no of pkts send is 16000..then total no of  bytes send is 

ans 1024000

13. #define maxval 5  (programming / computer science engineering technical questions)

int main (void)

  {

   int i=1;

   if(i-maxval)

    {

     printf(?inside?);

     }

else

   {

    printf(?out?); 

   }

find o/p???

14. #define a 3+3

#define b 11-3

main()

{

  printf(?%d?,a*b);

}

wat is o/p?????

15. A question in which segment address is given. logical address is 800. Base addresses also

given. You have 2 find physical address

16. There was a question on processor speed in nanocycles. Then it performs a instruction in x

cycles. like this..

17. main()

 {

  int *i;

  int s=(int *)malloc(10*sizeof(int));

  for (i=0;i<10;i++)

   {

     printf(?%d?,i*i)

   }

whats the output?

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Paper Type : Interview-Tech InterviewPosted By : WaseemUpdated Date : Aug 10, 2010

Cisco Interview-Tech Interview placement paper Question and answersCisco recruitment process and aptitude test experiences

The written test had two parts. 

20 questions from aptitude and 30 technical

No negative marking.

Aptitude was quite a lot tricky.

Technical was Electronics + CS.

Three C programs

1) main(){int const a=100;int *p;p=&a;(*p)++;printf("%d%d",a,*p);}Ans: 101 101

2) More questions between simple ones.

Two Network questions

ARP is used for?

End to End delievery is responsibility of which layer?

Good

One computer architecture.

If virtual address is[0,514] then if page table contains an entry (032) then physical address is:Ans append binary form of 32 with binary form of 514

Floating point representation: Simple one

If 23 bits are used for IEEE representation then whats the range of normalized nos. which can be represented?

One semaphores.

I'm from CS background. So don't remember much electronics question.