Chemical Equilibrium

Intro: Many chemical reactions go to

completion (where all reactants are consumed to form product)

This unit deals with reactions that do not completely convert all reactants to products.

Chemical Equilibrium A state where the rate of the forward chemical

reaction is equal to the rate of the reverse chemical reaction

Double arrows show that a system is at equilibrium

Characteristics of a system at equilibrium1. Reversible reaction must be possible2. There is a dynamic state of balance

between both the forward and backward reaction

3. There is no change in concentration of reactants or products once chemical equilibrium is reached

4. There is no bulk change in properties of the system (ex: no colour or pressure change)

Characteristics cont.5. It is a closed system (no heat or

matter in or out)6. The temperature of the system

remains constant7. It can be reached from either direction8. Any change to the system at

equilibrium can be reversed if restored back to original equilibrium conditions.

Examples at Equilibrium Water evaporating and condensing in a

jar with lid. Any solution at the saturation point. A bottle of unopened pop, carbon

dioxide is in equilibrium in solution and air above pop.

Walking the wrong way on an escalator.

Equilibrium System Simulation With a partner, take two graduated cylinders

and fill them with a random amount of water (not full).

Record the volume of water in each cylinder. Take straws and place one into each of the

cylinders, wet your finger and place it on the top of the straw.

Transfer the water trapped in the straw to the other cylinder (do not spill).

Record new volume in each cylinder. Repeat until the volumes are unchanged for

three trials. Plot a graph of volume vs trials

AnalysisHow were you able to tell when your system established equilibrium?Would the system be described as an open or closed system?How does this simulation model a dynamic equilibrium system?

Homework

Read Section 7.1 Page 428 #1,2

Changing the temperature affects the rates of forward and reverse reactions differently because they have different activation energies

Kc = expressed in terms of molar concentration (mol/L)

Calculating KcN2 + 3Cl2 <--> 2NCl3

Temp remains constant in 5 L flask.Equilbrium was reached and the following was

found: 0.007 mol N2 , 0.0022 mol Cl2 and 0.95 mol of NCl3. Calculate the Kc for this reaction.

Find molar concentration of everything (mol/L)

Use equilibrium expression based on chemical equation

Answer1. [N2] = 0.007 mol / 5 L = 0.0014 M

[Cl2] = 0.0022 mol / 5 L = .00044 M[NCl3] = 0.95 mol / 5 L = 0.19 M

2. Kc = [NCl3]2= [0.19]2

[N2][Cl2]3[0.0014][0.00044]3

= 3.0 x 10 11

CH4 (g) + 2 O2 (g) CO2 (g) + 2 H2O (g)

1. Write an expression for Keq

2. Calculate K at a given temperature if [CH4] = 0.020 M, [O2] = 0.042 M, [CO2] = 0.012 M, and [H2O] = 0.030 M at equilibrium. (include units)

K eq = 0.306 Time to practice…

Practice: Read section 7.2 Pg 431 #1-3 Pg 436 #2,3

The value of K The value or magnitude of K tells us the

extent to which reactants have been converted into products.

Remember in the ratio for K, the concentration of products divided by the concentration of reactants.

A small value for K means that very little of the reactants were converted into products before equilibrium was reached.

This is stated as “reactants are favoured”. A large value of K means that most of the

reactants were converted into products before equilibrium was reached.

This is stated as “products are favoured”.

The Magnitude of Equilibrium ConstantsIf K >1, then products dominate at equilibrium

and equilibrium lies to the right.If K <1, then reactants dominate at equilibrium

and the equilibrium lies to the left.

If K = 1 neither reactants nor products are favoured. The value of

K does not indicate how long it takes for equilibrium to be reached. The value of K varies with temperature and that’s why its usually mentioned with K

2NO2 (g) <--> N2O4 (g) Four experiments

were performed. The initial

concentrations of the two chemicals were

different in each experiment and the concentration of each gas was measured once the system reached equilibrium.

At Equ ilibrium

Exp # [NO2] [N2O4]

1 0.104 1.19

2 0.048 0.254

3 0.136 2.04

4 0.202 4.48

Calculate Using the data on the previous page,

calculate the K for each experiment.

What did you find?

Homework