Chapter11 Lecture Notes 1

23
Chemical Reaction Engineering (S1.2012) Fogler Chapter 11 External Diffusion Effects on Heterogeneous Reactions Gia Hung Pham

Transcript of Chapter11 Lecture Notes 1

Page 1: Chapter11 Lecture Notes 1

Chemical Reaction Engineering

(S1.2012)Fogler Chapter 11

External Diffusion Effects on Heterogeneous Reactions

Gia Hung Pham

Page 2: Chapter11 Lecture Notes 1

Catalysis reactor types

1. Two phase reactor

- Fixed bed reactor

- Fluidized bed reactor

2. Three phase reactor

- Slurry reactor

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Fixed bed reactor

Lit.: Jens Hagen; Industrial Catalysis A Practical Approach; Wiley-VCH; 1999

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Fluidised bed reactor

Gas

Gas

Solid catalyst

Reactor

Cyclone

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Compare: Fixed bed and Fluidised bed reactor

1. Catalyst pellet size

Fixed bed reactor : large (Heat and mass transfer will influence the rate and product selectivity)

Fluidised bed reactor: small

2. Catalyst weight

Fixed bed reactor requires much more catalyst than fluidised bed reactor.

3. Temperature control

Fixed bed reactor: bad, non-isothermal operation and hot spots ruin the catalyst.

Fluidised bed reactor: very good (rapid mixing of solid)

4. Pressure drop

Fixed bed reactor: high

Fluidised bed reactor: low

5. Catalyst deactivation - regeneration

Fixed bed reactor: less advantages (not suitable)

Fluidised bed reactor: more advantages

6. Scale-up

Fixed bed reactor: easy

Fluidised bed reactor: difficult

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Three phase reactor

Lit.: Jens Hagen; Industrial Catalysis A Practical Approach; Wiley-VCH; 1999

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Notes: reaction rate units

smmolCkdt

dN

Vr A

AA

3/1

sgmolCkdt

dN

wr catA

AA /

1 ''

smmolCkdt

dN

Sr A

AA

2'''' /1

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Chapter 11: External diffusion effects on heterogeneous reaction

Effective reaction rate constant

Two steps involve in the reaction (External mass transfer and surface reaction )

Catalyst pellet

1

4Gas

Boundary layer

δ

CAb

CAs

A

P

4

1

P

Reaction first-order

A P

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External mass transfer

Fick’s law

with

- kc : Mass transfer coefficient (m/s)

- DAB : Diffusion coefficient (m2/s) (is a function of T and P)

- δ : Boundary layer thickness (m) (is unknown, depends on fluid velocity, particle diameter, viscosity, density, temperature….)

- JAZ: average molar flux from the bulk fluid to the surface (mol/m2.s)

AsAbcA

ABAz CCkdz

dCDJ

AB

c

Dk

Concentration

Positional coordinate

Gasδ Cat

CAb

CAs

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Mass transfer rate

Surface reaction rate (first order reaction)

Determination of CAs

At steady state rMT = rs

)( AsAbcMTAZ CCkrJ

AsrS Ckr

AsrAsAbc CkCCk )(

rc

AbcAs

kk

CkC

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Derive the effective reaction rate

keff

Rate limiting1. Mass transfer is faster than surface reaction rate

kc » kr we have kc + kr ≈ kc

keff = kr

2. Surface reaction is faster than mass transfer kr » kc we have kc + kr ≈ kr

keff = kc

Ab

rc

rceffA C

kk

kkr

,

,

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Determination of kc by using correlation equation

Sherwood number

Flow over a sphere

Reynolds and Schmidt number

u : fluid flow velocity (m/s)

l : characteristic length (particle diameter) (m)

ν : kinematic viscosity (m2/s)

kc increases with increasing fluid velocity. (Why ?)

AB

c

D

lkSh

3/12/1Re6.02 ScSh

ABDSc

luRe

Frossling correlation

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From Sherwood number and Frossling correlation equation

3/12/1Re6.02 ScD

lk

AB

c

l

D

D

luk AB

AB

c

3/12/1

6.02

Fluid velocity affects kc

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Effect of fluid velocity on the effective reaction rate

reff

u

With mass transfer effect

Without mass transfer effect

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Example: Rapid reaction on a catalyst surface

Determine the effective rate of reaction per unit surface area of catalyst.

l = dp = 1 cm

CAs = 0 mol/L

CAb = 1 mol/L

u = 0.1 m/s

ν = 0.5x10-6 m2/s

Catalyst pellet

1

4

Fluid

Boundary layer

δ

CAb

CAs

A

PP

Reaction first-order

A P

DAB = 10-10 m2/s

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Solution

AsAbcMT CCkr

7.460Re6.02 3/12/1 ScD

dkSh

AB

pc

2000105.0

1.0()01.0(Re

126

1

sm

msmud p

500010

1051210

127

sm

sm

DSc

AB

161210

1061.401.0

7.46010

msm

sm

d

ShDk

p

ABc

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CAb = 103 mol/m3

rMT = 4.61x10-6 m/s x (103 – 0) mol/m3 = 4.61x10-3 mol/m2s

This is the effective reaction rate.

smmolr effA

23''

, /106.4

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Mass transfer-limited reaction in packed bed

Reaction A + B P

At steady state

z z+∆z

Mass balance for this slice

of the catalyst bed

0''

\\ zAarFF ccAzzAzzAz

Molar rate in

Molar rate out

Molar rate of accumulation

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0''

\\ zAarFF ccAzzAzzAz

Rate of generation of A per unit

Catalytic surface area (mol/s.m2)

External surface area of catalyst per volume of

catalyst bed (m2/m3)

Pd

16

Particle diameter (m)

Porosity of the bed (-)

Cross-sectional area of tube (m2)

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Dividing the above equation by Ac∆z and ∆z →0

δ

flow in tube: JAz<<BAz

01 ''

cA

Az

c

ardz

dF

A

cAzAzAzcAz ABJWAF

Molar flux of A (mol/m2s)

Molecular diffusive flux (mol/m2s)

Flux of A resulting from

Bulk flow (mol/m2s)

cAAzcAzcAz AUCBAWAF

superficial velocity (m/s) = constant

Cat

SurfaceCA

CAs

)(''

AsAcArA CCkWr

= 0

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AccA Cak

dz

dCU

z

U

ak

C

C cc

A

A exp0

Axial concentration profile in the reactor

CA/CA0

1

z

Integrating with the limit, at z =0, CA = CA0

0

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Determine the reactor length L necessary to achieve a conversion X

At z = L

z

U

akCkr cc

AcA exp0

''

Reaction rate along the length of the reactor

0

0

A

ALA

C

CCX

LU

ak

X

cc1

1ln

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In class exercise

Tubular fixed bed reactor with spherical catalyst

External mass transfer control

Calculate final conversion X of the reaction A P

Additional information:

- Catalyst bed length L = 2 m

- Catalyst bed diameter dR = 6 cm

- Bed porosity φ = 0.5

- Catalyst sphere diameter dp = 3 mm

- Superficial gas velocity U = 3 m/s

- Sherwood number Sh = 60

- Diffusion coefficient DAB = 10-7 m2/s

Solution

- Reorganise the equation

- Calculate kc

- Calculate ac (specific surface area)

- Calculate kc ac L / U

- Calculate X