CHAPTER III FREE VIBRATION OF SINGLE DEGREES OF FREEDOM ...
Transcript of CHAPTER III FREE VIBRATION OF SINGLE DEGREES OF FREEDOM ...
CHAPTER β IIIFREE VIBRATION OF SINGLE
DEGREES OF FREEDOM systems
Outlines
Free Vibration of an Undamped Translational System
Free Vibration of an Undamped Torsional System
Free Vibration with Viscous Damping (Translational and Torsional system)
Free Vibration with Coulomb Damping (Translational and Torsional system)
Free Vibration with Hysteretic Damping
Free vibration occurs because there is an initial disturbance to the
system.
The initial disturbance is referred to as an initial condition, which
can be either a displacement of the mass, an initial velocity of the
mass, or both.
Frequency of the system is determined by the mass and spring
constant of the system, initial conditions do not affect the vibration
frequency of an undamped system, therefore it is called the natural
frequency.
Vibration amplitude and the phase angle are also determined by
initial conditions. Theoretically, an undamped free vibration system
will vibrate forever once it is started.
Free Vibration of an Undamped Translational System
A system is said to undergo free vibration when it oscillates only
under an initial disturbance with no external forces acting afterward.
Some examples are the oscillations of the pendulum of a
grandfather clock, the vertical oscillatory motion felt by a bicyclist
after hitting a road bump, and the motion of a child on a swing after
an initial push.
Single-degree-of-freedom (SDOF) system is a system whose motion is
defined just by a single independent co-ordinate (or function) e.g. x which
is a function of time.
SDOF systems are often used as a very crude approximation for a
generally much more complex system.
Figure shows a spring-mass system that represents the simplest possible
vibratory system. It is called a single-degree-of-freedom system,
since one coordinate (x) is sufficient to specify the position of the mass at
any time. There is no external force applied to the mass; hence the motion
resulting from an initial disturbance will be free vibration.
Fig: A spring-mass system in horizontal position
The aim of developing a SDOF mathematical model is to use it in
order to find the position π₯(π‘) of the moving mass m at any instant
of time, also often velocity αΆπ₯(π‘) and acceleration α·π₯(π‘).
Question: How can we drive the equation of motion for this system?
The equation of motion can be derived using:
Newton's 2nd law of motion
DβAlembert's Principle
The principle of virtual displacement
The principle of conservation of energy
Using Newton's 2nd law of motion
βπΉ = ππ,βπ π₯ = π αΊ
Thus, παΊ + ππ₯ = 0 is the equation of motion.
Using DβAlembert's principle states that
βthe sum of all active and reactive forces minus the inertia force
gives the virtual state of equilibrium known as dynamic equilibrium
state.β
βπΉ βπ α·π₯ = 0
βππ₯ βπ α·π₯ = 0
π αΆπ₯ + ππ₯ = 0 is the equation of motion.
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Using Principle of Virtual Displacements
βIf a system that is in equilibrium under the action of a set of forces
is subjected to a virtual displacement, then the total virtual work
done by the forces will be zero.β
Consider spring-mass system as shown in figure, the virtual work done
by each force can be computed as:
xxmW
xkxW
i
S
)( force inertia by the done work Virtual
)( force spring by the done work Virtual
0 xkxxxm
0 kxxm
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Since the virtual displacement can have an arbitrary value, πΏπ₯ β 0,
equation above gives the equation of motion of the spring-mass
system as
When the total virtual work done by all the forces is set equal to zero,
we obtain
Using Principle of conservation of energy
A system is said to be conservative if no energy is lost due to
friction or energy-dissipating non elastic members.
If no work is done on a conservative system by external forces
(other than gravity or other potential forces)
Then the total energy of the system remains constant. Since the
energy of a vibrating system is partly potential and partly kinetic,
the sum of these two energies remains constant.
The kinetic energy T is stored in the mass by virtue of its velocity,
and the potential energy U is stored in the spring by virtue of its
elastic deformation.
Thus the principle of conservation of energy can be
expressed as:
The kinetic and potential energies are given by:
and
Substitute these equations in to the above equation,
Thus, the equation of motion can be:
0)(
constant
UTdt
d
UT
2
2
1xmT
2
2
1kxU
0 kxxm
Response of un damped free vibration
Force acting on the mass due to the spring is β ππ₯.
For the above differential equation we have three possible solutions.
x = π΄π ππ , π₯ = π΄ sinππ‘, π₯ = π΅ cosππ‘
Also any combination of these solution can be a solution, the most
general form of solution for this equation will be:
The most general form of solution for this equation will be
Where, Οn = Ξ€πΎ π, is the natural frequency
A1 and A2 are constants, which can be determined from the
initial conditions of the system.
Thus the solution of the equation subject to the initial conditions is
given by
tAtAtx nn sincos)( 21
02
01
)0(
)0(
xAtx
xAtx
n
tx
txtx n
n
n
sincos)( 00
The above equation is harmonic function of time.
The amplitude and phase angle can be:
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If initial displacement (π₯0) is zero,
tx
tx
tx n
n
n
n
sin
2cos)( 00
If initial velocity ( αΆπ₯0) is zero,
txtx ncos)( 0
Free Vibration of an Undamped Torsional System
l
GIM t
0
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From the theory of torsion of circular shafts, we have the relation:
Shear modulus
Polar moment of
inertia of cross
section of shaft
Length shaftTorque
32
4
0
dI
18
l
Gd
l
GIMk t
t32
4
0
Polar Moment of Inertia:
Torsional Spring Constant:
Equation of Motion:
00 tkJ
2/1
0
J
ktn
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Applying Newtonβs Second Law of Motion,
Thus, the natural circular frequency:
The period and frequency of vibration in cycles per second are:
2/1
0
2/1
0
2
1
2
J
kf
k
J
tn
t
n
Note the following aspects of this system:
g
WDDhJ
832
44
0
20
1) If the cross section of the shaft supporting the disc is not circular,
an appropriate torsional spring constant is to be used.
2) The polar mass moment of inertia of a disc is given by:
3) An important application: in a mechanical clock
where Ο is the mass density
h is the thickness
D is the diameter
W is the weight of the disc
General solution can be obtained:
tAtAt nn sincos)( 21
00 )0()0( and )0(
tdt
dtt
21
where A1 and A2 can be determined from the initial conditions. If
The constants A1 and A2 can be found:
nA
A
/02
01
Equation above can also represent a simple harmonic motion.
RESPONSE OF DAMPED FREE VIBRATION
A single degree of freedom system consists of a mass, a spring, and a damper if
the system is modeled as a damped system.
The spring is modeled as a linear spring, which provides a restoring force.
The damper is modeled as a viscous damper, which provides a damping force
proportional to a relative displacement and acting in the direction against a
velocity vector.
If there is a driving force acting on the mass, the system vibrates under the
driving force, which is called forced vibration.
Otherwise, the system may vibrate under initial displacement and/or initial
velocity, which is called free vibration.
Physically, there is no vibrating system that vibrates forever, that means there isalways some kind of damping in the system that dissipates energy.
For mathematical simplicity, the damping is modeled as viscous damping.
Depending on the magnitude of damping, a damped system can be underdamped,critically damped or overdamped.
The critical damping coefficient is determined by the system's mass and springconstant.
Under critical damping, the damping ratio is unity. Critical damping separates nooscillatory motion from oscillatory motion.
When the damping ratio is greater than 1, which is called overdamping, thesystem does not oscillate. For a damping ratio less than 1, which is calledunderdamping, the system oscillates with decaying magnitude, as shown in thefigure below.
For most physical system, damping ratios are less than 1. Actually, most physicalsystems have damping ratio less than 0.1. With damping in the free vibrationsystem, the mass always restores its equilibrium position even it is disturbed. Thegreater the damping, the less time it takes to restore its equilibrium position. So inmost cases, adequate damping is desireable.
Free Vibration with Viscous Damping
The viscous damping force F is proportional to the velocity αΊ
or v can be expressed by
πΉ = βπ αΆπ₯
where c is the damping constant or coefficient of viscous
damping and the negative sign indicates that the damping force is
opposite to the direction of velocity
Contd.,The equation of motion is then
Newton's second law
βπΉ = ππ
π α·π₯ = βπ αΆπ₯ β ππ₯
π α·π₯ + π αΆπ₯ + ππ₯ = 0
We assume that solution in the form of
π₯ π‘ = πΆππ π‘
Insert this equation into the previous equation
ππ 2 + ππ + π = 0
Then the roots are
π 1,2 =βπΒ± π2β4ππ
2π=
βπ
2πΒ± (
π
2π)2β
π
π
Contd.,
The roots gives the two solutions
The most general solution in the combination of these solutions
π₯1 π‘ = πΆ1ππ 1π‘ and π₯2 π‘ = πΆ2π
π 2π‘
π₯ π‘ = πΆ1ππ 1π‘ + πΆ2π
π 2π‘
= πΆ1π βπ
2π+
π
2π
2β
π
ππ‘ + πΆ2π β
π
2π+
π
2π
2β
π
ππ‘
Where, πΆ1 and πΆ1 are arbitrary constants to be find from initial conditions.
Critical damping constant and damping ratio:
The critical damping is defined as the value of the damping constant πΆπΆfor which the radical in Equation becomes zero.
ππ2π
2
βπ
π= 0
ππ = 2π ΰ΅π π = 2 ππ = 2πππ
Contd.,For any damped system the damping ratio is defined as the ratio
of damping constant to critical damping constant.
ΞΆ = ΰ΅π ππWe can write
π
2π=
π
ππ.ππ2π
= ΞΆππ
And hence
π 1,2 = πΆ1πβπ+ π2β1 πππ‘ + πΆ2π
βπβ π2β1 πππ‘
Contd.,
Comparison of motions with different types of damping
Logarithmic Decrement
The logarithmic decrement represents the rate at which the
amplitude of a free-damped vibration decreases.
It is defined as the natural logarithm of the ratio of any two
successive amplitudes.
Let t1 and t2 denote the times corresponding to two consecutive
amplitudes
Logarithmic Decrement
There are many methods for measuring the damping of a vibration
system. Logarithmic decrement method and bandwidth method are
introduced here.
Logarithmic decrement method is used to measure damping in time
domain. In this method, the free vibration displacement amplitude
history of a system to an impulse is measured and recorded. A
typical free decay curve is shown as below. Logarithmic decrement
is the natural logarithmic value of the ratio of two adjacent peak
values of displacement in free decay vibration.
Contd.,
Torsion system with viscous damping
β’ The viscous damping torque for a single dof torsionalsystem
β’ Where ct is the torsional viscous damping
β’ The equation of motion is
Free vibration with coulomb damping
β’ In many mechanical systems, Coulomb or dry-friction dampers areused because of their mechanical simplicity and convenience.
β’ Coulomb s law of dry friction states that, when two bodies are incontact, the force required to produce sliding is proportional to thenormal force acting in the plane of contact.
β’ Thus, the friction force F is given by
πΉ = ππ = ππ = πππwhere N is normal force,
Β΅ is the coefficient of dry or kinetic or sliding friction.
β’ The friction force acts in a direction opposite to the direction ofvelocity.
β’ Coulomb damping is sometimes called constant damping.
β’ Since it is independent of the displacement and velocity; it dependsonly on the normal force N between the sliding surfaces.
β’ Consider a SDOF system with dry friction as shown in Fig. (a).
β’ Since friction force varies with the direction of velocity, we need to
consider two cases as indicated in Fig.(b) and (c).
Case 1: When x is positive and dx/dt is positive or when x is negative and
dx/dt is positive (i.e., for the half cycle during which the mass moves from
left to right) the equation of motion can be obtained using Newtonβs second
law (Fig.b):
β’ Case 2: When x is positive and dx/dt is negative or when x is
negative and dx/dt is negative (i.e., for the half cycle during which
the mass moves from right to left) the equation of motion can be
derived from Fig. (c):
Case (2):(When Frictional force in positive)
Case (1): SPRING MASS WITH COULOMB DAMPING
(When Frictional force in negative)
Q. What is the solution for this equation of motion?
Damping Material or Solid or Hysteretic Damping