Chapter 8 – Pipe Flow CE30460 - Fluid Mechanics Diogo Bolster.

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Chapter 8 – Pipe Flow CE30460 - Fluid Mechanics Diogo Bolster

Transcript of Chapter 8 – Pipe Flow CE30460 - Fluid Mechanics Diogo Bolster.

Page 1: Chapter 8 – Pipe Flow CE30460 - Fluid Mechanics Diogo Bolster.

Chapter 8 – Pipe FlowCE30460 - Fluid MechanicsDiogo Bolster

Page 2: Chapter 8 – Pipe Flow CE30460 - Fluid Mechanics Diogo Bolster.

Laminar or Turbulent Flow

Turbulent Flow http://www.youtube.com/watch?v=NplrDarMDF8

Laminar Flow http://www.youtube.com/watch?v=KqqtOb30jWs&NR=1

Re<1000

Re>4000

Re=UD /r m

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Fully Developed Flow

Entrance length:

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Fully Developed Laminar Flow

We’ve done this one already in chapter 6

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What about Turbulent Flow

Typically: n is between 6 and 10

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Dimensional Analysis

Pressure Drop depends onMean velocity V

Diameter D

Pipe length l

Wall Roughnesse

Viscosity m

Density r

By dimensional Analysis

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Pressure drop must increase linearly with length of tube

Recall from chapter 5

Therefore we can say that (part of) the loss in a pipe is

Δp1

2 ρV2

=l

Df Re,

ε

D

⎝ ⎜

⎠ ⎟

Friction factor – look up in table

hL ,major =l

D

V 2

2gf Re,

ε

D

⎝ ⎜

⎠ ⎟

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Moody Diagram (Friction Factor)

For non-laminar flow approximately true that

1

f= −1.8log

εD

3.7

⎝ ⎜ ⎜

⎠ ⎟ ⎟

1.11

+6.9

Re

⎢ ⎢

⎥ ⎥

For laminar

f =64

Re

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Roughness (Typical)

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Minor Losses

hL ,min =KLV 2

2g

KL depends on the flow (expansion, contraction, bend, etc)

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Minor Losses

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Minor Losses

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Sample Problem

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Sample Problem

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Sample Problem

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Pipe Flow Measurement

Q =CQideal =CA0

2 p1 − p2( )

ρ 1 − β4( )

C is a constant that depends on geometry

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Sample Problem

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More Problems

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Single Pipe – Determine Pressure Drop

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Single Pipe – Determine Flowrate

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Single Pipe – Determine Diameter

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Multiple Pipe Systems