Chapter 8 Atomic Electron Configurations and Chemical Periodicity.
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Transcript of Chapter 8 Atomic Electron Configurations and Chemical Periodicity.
Chapter 8Chapter 8
Atomic Electron Configurations Atomic Electron Configurations and Chemical Periodicityand Chemical Periodicity
Chapter goalsChapter goals
• Understanding the role magnetism Understanding the role magnetism plays in determining and revealing plays in determining and revealing atomic structure.atomic structure.
• Understand effective nuclear charge Understand effective nuclear charge and its role in determining atomic and its role in determining atomic properties.properties.
• Write the electron configuration of Write the electron configuration of neutral atoms and monatomic ions.neutral atoms and monatomic ions.
• Understand the fundamental physical Understand the fundamental physical properties of the elements and their properties of the elements and their periodic trends.periodic trends.
Electron Spin Electron Spin and the Fourth Quantum Numberand the Fourth Quantum Number
• The fourth quantum number is the spin quantum The fourth quantum number is the spin quantum number which has the symbol mnumber which has the symbol mss..
• The spin quantum number only has two possible The spin quantum number only has two possible values.values.
mms s = +1/2 or = +1/2 or −−1/21/2
mmss = ± 1/2 = ± 1/2• This quantum number tells us the spin and This quantum number tells us the spin and
orientation of the magnetic field of the electrons.orientation of the magnetic field of the electrons.• Wolfgang Pauli discovered the Exclusion Wolfgang Pauli discovered the Exclusion
Principle in 1925.Principle in 1925.No two electrons in an atom can have the same No two electrons in an atom can have the same
set of 4 quantum numbers, n, set of 4 quantum numbers, n, ll, m, mll, and m, and mss
Electron Spin Electron Spin
• Spin quantum number effects:Spin quantum number effects:– Every orbital can hold up to two Every orbital can hold up to two
electrons.electrons.• Consequence of the Pauli Exclusion Consequence of the Pauli Exclusion
Principle.Principle.– The two electrons are designated as The two electrons are designated as
havinghaving– one spin up one spin up m mss = +1/2 = +1/2– and one spin downand one spin downmmss = = −−1/21/2
• Spin describes the direction of the Spin describes the direction of the electron’s magnetic field.electron’s magnetic field.
Paramagnetism and DiamagnetismParamagnetism and Diamagnetism
• Unpaired electrons have their spins Unpaired electrons have their spins aligned aligned or or (in diff. (in diff. orbitals)orbitals)
– This increases the magnetic field of the This increases the magnetic field of the atom.atom.
Total spin Total spin 0, because they add up. 0, because they add up.
• Atoms with unpaired electrons are called Atoms with unpaired electrons are called paramagneticparamagnetic ..
– Paramagnetic atoms are attracted to a Paramagnetic atoms are attracted to a magnet.magnet.
Paramagnetism and DiamagnetismParamagnetism and Diamagnetism• Paired electrons have their spins Paired electrons have their spins
unaligned unaligned in the same orbitalin the same orbital– Paired electrons have no net magnetic Paired electrons have no net magnetic
field.field. Total spin = 0, because of cancellation,Total spin = 0, because of cancellation, ½ ½ −− ½ = 0 ½ = 0
• Atoms with no unpaired electrons are Atoms with no unpaired electrons are called called diamagneticdiamagnetic. . – Diamagnetic atoms are not attracted to a Diamagnetic atoms are not attracted to a
magnet.magnet.
Atomic Orbitals, Spin, and # of ElectronsAtomic Orbitals, Spin, and # of Electrons
• Because two electrons in the same orbital Because two electrons in the same orbital must be paired (due to Pauli’s Exclusion must be paired (due to Pauli’s Exclusion Principle), it is possible to calculate the Principle), it is possible to calculate the number of orbitals and the number of number of orbitals and the number of electrons in each n shell. electrons in each n shell.
• The number of orbitals per n level is given The number of orbitals per n level is given by nby n2 2 (see table at end of chapter 7.)(see table at end of chapter 7.)
• The maximum number of electrons per n The maximum number of electrons per n level is 2nlevel is 2n22 (two electrons per orbital.) (two electrons per orbital.)
– The value is 2nThe value is 2n22 because of the two because of the two paired electrons per orbital.paired electrons per orbital.
nn shellshell ll subshellsubshell mmll
#orbitals#orbitals#e#e––
11 KK 00 ss 00 11 2222 LL 00 ss 00 11 22
11 pp ––1,0,11,0,1 33 6633 MM 00 ss 00 11 22
11 pp ––1,0,11,0,1 33 66
88
22 dd -2,-1,0,1,2-2,-1,0,1,2 55 10101818
44 NN 00 ss 00 11 2211 pp ––1,0,11,0,1 33 6622 dd -2,-1,0,1,2-2,-1,0,1,2 55 101033 ff -3,-2,-1,0,1,2,3-3,-2,-1,0,1,2,3 77 1414
3232
n2
1
4
9
16
Max
Atomic Subshell Energies and Atomic Subshell Energies and Electron AssignmentsElectron Assignments
• The principle that describes how the The principle that describes how the periodic chart is a function of electronic periodic chart is a function of electronic configurations is the configurations is the Aufbau PrincipleAufbau Principle..
• The electron that distinguishes an element The electron that distinguishes an element from the previous element enters the from the previous element enters the lowest energy atomic orbital available.lowest energy atomic orbital available.
Penetrating and ShieldingPenetrating and Shielding• the radial distribution function the radial distribution function
shows that the 2shows that the 2ss orbital orbital penetrates more deeply into the penetrates more deeply into the 11ss orbital than does the 2 orbital than does the 2pp
• the weaker penetration of the 2the weaker penetration of the 2pp sublevel means that electrons in sublevel means that electrons in the 2the 2pp sublevel experience more sublevel experience more repulsive force, they are more repulsive force, they are more shielded from the attractive force shielded from the attractive force of the nucleusof the nucleus
• the deeper penetration of the 2the deeper penetration of the 2ss electrons means electrons in the electrons means electrons in the 22ss sublevel experience a greater sublevel experience a greater attractive force to the nucleus and attractive force to the nucleus and are not shielded as effectivelyare not shielded as effectively
• the result is that the electrons in the result is that the electrons in the 2the 2ss sublevel are lower in ( sublevel are lower in (more more negativenegative) energy than the ) energy than the electrons in the 2electrons in the 2pp
Atomic Subshell Energies and Electron Atomic Subshell Energies and Electron AssignmentsAssignments
The The Aufbau PrincipleAufbau Principle
describes the electron describes the electron
filling order in atoms. Thisfilling order in atoms. This
is product of the effective is product of the effective
nuclear charge, Z*, nuclear charge, Z*, ZZeffeff
For the same n, Z* is higherFor the same n, Z* is higher
for s orbital: s > p > d > f for s orbital: s > p > d > f
Then, eThen, e−− in s is the most in s is the most
attracted by nucleus and hasattracted by nucleus and has
the lowest energythe lowest energy
Atomic Subshell Energies and Electron Atomic Subshell Energies and Electron AssignmentsAssignments
One mnemonic One mnemonic
to remember theto remember the
correct filling correct filling
order for order for
electrons electrons
in atoms is the in atoms is the
increasing increasing
(n + (n + ) value
Atomic Subshell Energies and Electron Atomic Subshell Energies and Electron AssignmentsAssignments
or we can use this periodic chart or we can use this periodic chart
Atomic Electron ConfigurationsAtomic Electron Configurations
• Now we will use the Aufbau Principle to Now we will use the Aufbau Principle to determine the electronic configurations of determine the electronic configurations of the elements on the periodic chart.the elements on the periodic chart.
• 11stst row elements row elements
22
11
1s He
1s H
ionConfigurat 1s
Atomic Electron ConfigurationsAtomic Electron ConfigurationsHund’s rule tells us that the electrons will fill the p and d orbitals
by placing electrons in each orbital singly and with same spin until half-filled. That is the rule of maximum spin. Then the electrons will pair to finish the p orbitals.
Electrons in orbitals of or same kind, such as p or d orbitals, in the sameshell (n), have the same energy; theare said to bedegenerate.
Atomic Electron ConfigurationsAtomic Electron Configurations3rd row elements…
62
18
5217
4216
3215
2214
1213
212
111
3p s3 Ne NeAr
3p s3 Ne Ne Cl
3p s3 Ne Ne S
3p s3 Ne Ne P
3p s3 Ne Ne Si
3p s3 Ne Ne Al
s3 Ne Ne Mg
s3 Ne NeNa
ionConfigurat 3p 3s
Atomic Electron ConfigurationsAtomic Electron Configurations4th row elements…
119 4s Ar ArK
ionConfigurat 4p 4s 3d
Atomic Electron ConfigurationsAtomic Electron Configurations4th row elements…
2
20
119
4s Ar ArCa
4s Ar ArK
ionConfigurat 4p 4s 3d
Atomic Electron ConfigurationsAtomic Electron Configurations4th row elements…The five d orbitals are degenerate
12
21
220
119
3d 4s Ar Ar Sc
4s Ar ArCa
4s Ar ArK
ionConfigurat 4p 4s 3d
Atomic Electron ConfigurationsAtomic Electron Configurations4th row elements…
22
22
1221
220
119
3d 4s Ar Ar Ti
3d 4s Ar Ar Sc
4s Ar ArCa
4s Ar ArK
ionConfigurat 4p 4s 3d
Atomic Electron ConfigurationsAtomic Electron Configurations4th row elements…The five d orbitals are degenerate
3223
2222
1221
220
119
3d 4s Ar Ar V
3d 4s Ar Ar Ti
3d 4s Ar Ar Sc
4s Ar ArCa
4s Ar ArK
ionConfigurat 4p 4s 3d
Atomic Electron ConfigurationsAtomic Electron Configurations4th row elements…
3223
2222
1221
220
119
3d 4s Ar Ar V
3d 4s Ar Ar Ti
3d 4s Ar Ar Sc
4s Ar ArCa
4s Ar ArK
ionConfigurat 4p 4s 3d
Atomic Electron ConfigurationsAtomic Electron Configurations4th row elements… The [Ar] 4s1 3d5 configuration of
Cr is more stable than [Ar] 4s2 3d4 (expected)
orbitals. filled completely and filled-half with
associatedstability of measure extraan is There
3d 4s Ar ArCr
3d 4s Ar Ar V
3d 4s Ar Ar Ti
3d 4s Ar Ar Sc
4s Ar Ar Ca
4s Ar ArK
ionConfigurat 4p 4s 3d
5124
3223
2222
1221
220
119
Atomic Electron ConfigurationsAtomic Electron Configurations4th row elements… The [Ar] 4s1 3d10 full d configuration
of Cu is more stable than [Ar] 4s2 3d9 (expected)
reason. same y theessentiallfor
andCr like exceptionAnother
3d 4s Ar Ar Cu
3d 4s Ar Ar Ni
3d 4s Ar Ar Co
3d 4s Ar Ar Fe
3d 4s Ar Ar Mn
ionConfigurat 4p 4s 3d
10129
8228
7227
6226
5225
Atomic Electron ConfigurationsAtomic Electron Configurations4th row elements…
102
30
10129
8228
7227
6226
5225
3d 4s Ar Ar Zn
3d 4s Ar Ar Cu
3d 4s Ar Ar Ni
3d 4s Ar Ar Co
3d 4s Ar Ar Fe
3d 4s Ar Ar Mn
ionConfigurat 4p 4s 3d
Atomic Electron ConfigurationsAtomic Electron Configurations4th row elements… (remember Hund’s rule):
__ is better (lower energy) than __ __
4p 4p
6102
36
510235
410234
310233
210232
110231
4p 3d 4s Ar ArKr
4p 3d 4s Ar ArBr
4p 3d 4s Ar Ar Se
4p 3d 4s Ar Ar As
4p 3d 4s Ar Ar Ge
4p 3d 4s Ar ArGa
ionConfigurat 4p 4s 3d
Atomic Electron ConfigurationsAtomic Electron ConfigurationsLanthanides (4f)
56Ba [Xe] 6s2
57La [Xe] 5d1 6s2
58Ce [Xe] 4f1 5d1 6s2
59Pr [Xe] 4f3 6s2 Praseodymium
70Yb [Xe] 4f14 6s2 Ytterbium
71Lu [Xe] 4f14 5d1 6s2 Lutetium
Periodic TablePeriodic Table
s, p, d, and f-block in the Periodic Tables, p, d, and f-block in the Periodic Table
GaGa3131
InIn4949
TlTl8181
BB55
AlAl1313
3A3A
GeGe3232
SnSn5050
PbPb8282
CC66
SiSi1414
4A4A
AsAs3333
SbSb5151
BiBi8383
NN77
PP1515
5A5A
SeSe3434
TeTe5252
PoPo8484
OO88
SS1616
6A6A
BrBr3535
II5353
AtAt8585
FF99
ClCl1717
7A7A
KrKr3636
XeXe5454
RnRn8686
NeNe1010
ArAr1818
HeHe228A8A
ZnZn
CeCe5858
PrPr5959
NdNd6060
PmPm6161
SmSm6262
EuEu6363
GdGd6464
TbTb6565
DyDy6666
HoHo6767
ErEr6868
TmTm6969
YbYb7070
LuLu7171
ThTh9090
PaPa9191
UU9292
NpNp9393
PuPu9494
AmAm9595
CmCm9696
BkBk9797
CfCf9898
EsEs9999
FmFm100100
MdMd101101
NoNo102102
LrLr103103
BaBa5656
BeBe44
MgMg
1212
CaCa
2020
SrSr
3838
RaRa8888
2A2A
1A1A
HH11
LiLi33
NaNa
1111
KK
1919
RbRb
3737
CsCs5555
FrFr8787
AcAc RfRf DbDb SgSg BhBh HsHs MtMt
HgHgLaLa5757
ScSc
2121
YY
3939
8989
3B3B
TiTi
2222
ZrZr4040
HfHf7272
104104
4B4B
VV
2323
NbNb4141
TaTa7373
105105
5B5B
CrCr2424
MoMo4242
WW7474
106106
6B6B
MnMn
TcTc
ReRe
2525
4343
7575
107107
7B7B
FeFe
OsOs
2626
RuRu4444
7676
108108
8B8B
IrIr
4545
7777
CoCo2727
RhRh
109109
8B8B
NiNi2828
PdPd
4646
PtPt7878
8B8B
CuCu2929
AgAg4747
AuAu7979
1B1B3030
CdCd4848
8080
2B2B
11
22
33
44
55
66
77
(P–1)d(P–1)d
(P)s(P)s
(P–2)f(P–2)f
(P)p(P)p
PP
Valence ElectronsValence Electronselectrons in shell with highest electrons in shell with highest nn, i.e., , i.e., the outermost the outermost
electronselectrons, those beyond the core electrons, those beyond the core electrons
1s1s22 2s 2s2 2 2p2p66 3s3s11
1s1s22 2s 2s2 2 2p2p66 3s3s22 3p 3p22
1s1s22 2s 2s2 2 2p2p66 3s 3s22 3p 3p66 3d 3d1010 4s4s22 4p 4p66
1s1s22 2s2s2 2
1s1s22 2s 2s2 2 2p2p66 3s3s22 3p 3p66 4s 4s22 3d 3d77
They determine the chemical properties of an They determine the chemical properties of an
element. element. For the representative elements, they For the representative elements, they
are the ns are the ns and npand np electrons; electrons; for transitionfor transition
elements they are the elements they are the ns and (nns and (n−1)d−1)d electrons electrons..
1A1A
HH11
LiLi33
NaNa
1111
KK
1919
RbRb
3737
CsCs5555
FrFr8787
11
22
33
44
55
66
77
PP
1s1s11
2s2s11
3s3s11
4s4s11
5s5s11
6s6s11
7s7s11
# of valence electrons = 1
BaBa5656
BeBe44
MgMg
1212
CaCa
2020
SrSr
3838
RaRa8888
2A2A
2s2s22
3s3s22
4s4s22
5s5s22
6s6s22
7s7s22
# of valence electrons = 2
GaGa3131
InIn4949
TlTl8181
BB55
AlAl1313
3A3A
2s2s22 2p 2p11
3s3s22 3p 3p11
4s4s22 4p 4p11
5s5s22 5p 5p11
6s6s22 6p 6p11
# of valence electrons = 3
BrBr3535
II5353
AtAt8585
FF99
ClCl1717
7A7A
2s2s22 2p 2p55
3s3s22 3p 3p55
4s4s22 4p 4p55
5s5s22 5p 5p55
6s6s22 6p 6p55
For the representative elements, the # of valence electrons = # of group
# of valence electrons = 7
The element X has the valence shell The element X has the valence shell electron configuration, nselectron configuration, ns22 np np44. .
X belongs to what group?X belongs to what group?
chalcogenschalcogens
ZnZn
BaBa5656
BeBe44
MgMg
1212
CaCa
2020
SrSr
3838
RaRa8888
2A2A
1A1A
HH11
LiLi33
NaNa
1111
KK
1919
RbRb
3737
CsCs5555
FrFr8787
AcAc UnqUnq UnpUnp UnhUnh UnsUns UnoUno UneUne
HgHgLaLa5757
ScSc
2121
YY
3939
8989
3B3B
TiTi
2222
ZrZr4040
HfHf7272
104104
4B4B
VV
2323
NbNb4141
TaTa7373
105105
5B5B
CrCr2424
MoMo4242
WW7474
106106
6B6B
MnMn
TcTc
ReRe
2525
4343
7575
107107
7B7B
FeFe
OsOs
2626
RuRu4444
7676
108108
8B8B
IrIr
4545
7777
CoCo2727
RhRh
109109
8B8B
NiNi2828
PdPd
4646
PtPt7878
8B8B
CuCu2929
AgAg4747
AuAu7979
1B1B3030
CdCd4848
8080
2B2B
GaGa3131
InIn4949
TlTl8181
BB55
AlAl1313
3A3A
GeGe3232
SnSn5050
PbPb8282
CC66
SiSi1414
4A4A
AsAs3333
SbSb5151
BiBi8383
NN77
PP1515
5A5A
SeSe3434
TeTe5252
PoPo8484
OO88
SS1616
6A6A
BrBr3535
II5353
AtAt8585
FF99
ClCl1717
7A7A
KrKr3636
XeXe5454
RnRn8686
NeNe1010
ArAr1818
HeHe228A8A
Energy (Orbital) DiagramEnergy (Orbital) Diagram
EE
1s1s
2s2s2p2p
3s3s3p3p
4s4s 3d3d
4p4p
Be 1sBe 1s22 2s 2s22
1s1s 2s2s 2p2p 3s3s
BeBe
Orbital Box DiagramsOrbital Box Diagrams
1s1s 2s2s 2p2p
NN
Orbital Box DiagramsOrbital Box Diagrams
Formation of CationsFormation of Cationselectrons lost from subshell with highest electrons lost from subshell with highest
n and n and ll first ( first (from valence electronsfrom valence electrons))
examplesexamples
KK 1s1s22 2s 2s22 2p 2p66 3s 3s22 3p 3p66 4s 4s11
[Ar] [Ar] 4s4s11
KK++ 1s1s22 2s 2s22 2p 2p66 3s 3s22 3p 3p66
[Ar][Ar]
CaCa 1s1s22 2s 2s22 2p 2p66 3s 3s22 3p 3p66 4s 4s22
[Ar] [Ar] 4s4s22
CaCa2+2+ 1s1s22 2s 2s22 2p 2p66 3s 3s22 3p 3p66
[Ar][Ar]
Al Al 1s1s22 2s 2s22 2p 2p66 3s3s22 3p 3p11
AlAl3+3+ [Ne] [Ne]
In [Kr] 4dIn [Kr] 4d1010 5s5s22 5p 5p11
InIn3+3+ [Kr] 4d [Kr] 4d1010
Transition Metal CationsTransition Metal CationsIn the process of ionization transition metals In the process of ionization transition metals
the ns electrons are lost before the (n-1)d the ns electrons are lost before the (n-1)d
Fe: [Ar] 3dFe: [Ar] 3d66 4s 4s22 Fe Fe2+2+: [Ar] 3d: [Ar] 3d66
FeFe2+2+: [Ar] 3d: [Ar] 3d66 Fe Fe3+3+: [Ar] 3d: [Ar] 3d55
Cu: [Ar] 3dCu: [Ar] 3d1010 4s 4s11 Cu Cu++: [Ar] 3d: [Ar] 3d1010
CuCu++: [Ar] 3d: [Ar] 3d1010 Cu Cu2+2+: [Ar] 3d: [Ar] 3d99
Fe, FeFe, Fe2+2+, Fe, Fe3+3+, Cu, and Cu, Cu, and Cu2+2+ are paramagnetic are paramagnetic
Two problems of ions, charge, and electron configurationTwo problems of ions, charge, and electron configuration
An anion has a 3An anion has a 3− charge and electron configuration− charge and electron configuration1s1s22 2s 2s22 2p 2p66 3s 3s22 3p 3p66. What is the symbol of the ion. What is the symbol of the ion?? The neutral atom has gained 3e- to form the ion, thenThe neutral atom has gained 3e- to form the ion, thenthe neutral atom had 15 e-. In the neutral atom the # e- the neutral atom had 15 e-. In the neutral atom the # e- = # p+ = Atomic number, that is 15. The element is,= # p+ = Atomic number, that is 15. The element is,then, phosphorus (phosphorus). Symbol of ion is Pthen, phosphorus (phosphorus). Symbol of ion is P33−−..
A cation has a 2+A cation has a 2+ chargecharge and its electron and its electron configuration is [Ar] 3dconfiguration is [Ar] 3d77. What is the symbol of the ion?. What is the symbol of the ion? Here, the neutral atom has lost 2e-. It is a transition Here, the neutral atom has lost 2e-. It is a transition metal, due to the 3d electrons. Remember they firstlymetal, due to the 3d electrons. Remember they firstlylose e-s in 4s orbital. Symbol of ion is Colose e-s in 4s orbital. Symbol of ion is Co2+2+..Neutral atom has 18 + 7 + 2 = 27 e- = 27 p+ = atomic #Neutral atom has 18 + 7 + 2 = 27 e- = 27 p+ = atomic # [Ar] [Ar] 3d3d77 lost lost
Atomic Properties and Periodic Atomic Properties and Periodic TrendsTrends
Periodic Properties of Periodic Properties of
the Elementsthe Elements
1.1. Atomic RadiiAtomic Radii
2.2. Ionization EnergyIonization Energy
3.3. Electron AffinityElectron Affinity
4.4. Ionic RadiiIonic Radii
Atomic Properties and Periodic TrendsAtomic Properties and Periodic Trends
• Establish a classification scheme of the elements Establish a classification scheme of the elements based on their electron configurations.based on their electron configurations.
• Noble GasesNoble Gases– All of them have completely filled electron All of them have completely filled electron
shells. They are not very reactive.shells. They are not very reactive.• Since they have similar electronic structures, Since they have similar electronic structures,
their chemical reactions are similar.their chemical reactions are similar.– HeHe 1s1s22
– NeNe [He] 2s[He] 2s22 2p 2p66
– ArAr [Ne] 3s[Ne] 3s22 3p 3p66
– Kr Kr [Ar] 4s[Ar] 4s22 4p 4p66
– XeXe [Kr] 5s[Kr] 5s22 5p 5p66
– RnRn [Xe] 6s[Xe] 6s22 6p 6p66
Atomic Properties and Periodic TrendsAtomic Properties and Periodic TrendsRepresentative Elements Representative Elements areare
the elements in A groupsthe elements in A groups
on periodic chart.on periodic chart.
These elements will haveThese elements will have
their “last” electron in an their “last” electron in an
outer outer ss or or pp orbital. orbital.
These elements have fairlyThese elements have fairly
regular variations in their regular variations in their
properties.properties.
Metallic character, for expl, Metallic character, for expl,
increases from right to left increases from right to left
and top to bottom. and top to bottom.
Atomic Properties and Periodic TrendsAtomic Properties and Periodic Trends• dd-Transition Elements-Transition Elements
Elements on periodic Elements on periodic
chart in B groups.chart in B groups.
Sometimes called Sometimes called
transition metals.transition metals.• Each metal has Each metal has dd
electrons.electrons.
nnssxx (n-1) (n-1)ddyy configurations configurations• These elements make the These elements make the
transition from metals to transition from metals to nonmetals.nonmetals.
• Exhibit smaller variations Exhibit smaller variations from row-to-row than the from row-to-row than the representative elements.representative elements.
Atomic Properties and Periodic TrendsAtomic Properties and Periodic Trends• ff - transition metals - transition metals
Sometimes called innerSometimes called inner
transition metals.transition metals.
• Electrons are being Electrons are being added to added to ff orbitals. orbitals.
• Electrons are being Electrons are being added two shells below added two shells below the valence shell!the valence shell!
• Consequently, very Consequently, very slight variations of slight variations of properties from one properties from one element to another.element to another.
Atomic Properties and Periodic TrendsAtomic Properties and Periodic Trends
OutermostOutermost electrons (valence electrons) electrons (valence electrons)
have the greatest Influence on the chemicalhave the greatest Influence on the chemical
properties of elements.properties of elements.
Atomic Properties and Periodic TrendsAtomic Properties and Periodic Trends
Atomic radiiAtomic radii describe the describe the
relative sizes of atoms.relative sizes of atoms.
Atomic radii increase within aAtomic radii increase within a
column going from the top to column going from the top to
the bottom of the periodic table.the bottom of the periodic table.
The outermost electrons are The outermost electrons are
assigned to orbitals with assigned to orbitals with
increasingly higher values of n. increasingly higher values of n.
The underlying electrons The underlying electrons
require some space, so the require some space, so the
electrons of the outer shells electrons of the outer shells
must be further from the must be further from the
nucleus.nucleus.
Atomic Properties and Periodic TrendsAtomic Properties and Periodic Trends
Atomic radiiAtomic radii decrease decrease
within a row going fromwithin a row going from
Left to right on theLeft to right on the
periodic table.periodic table.
This last fact seems This last fact seems
contrary to intuition.contrary to intuition.
How does nature make How does nature make
the elements smallerthe elements smaller
even though the electron even though the electron
number is increasing?number is increasing?
Atomic RadiiAtomic Radii• The reason the atomic radii decrease across a The reason the atomic radii decrease across a
period is due to period is due to shieldingshielding or or screeningscreening effect. effect.– Effective nuclear charge, ZEffective nuclear charge, Zeffeff, experienced by , experienced by
an electron is less than the actual nuclear an electron is less than the actual nuclear charge, Z.charge, Z.
– The inner electrons block the nuclear charge’s The inner electrons block the nuclear charge’s effect on the outer electrons.effect on the outer electrons.
• Moving across a period, each element has an Moving across a period, each element has an increased nuclear charge and the electrons are increased nuclear charge and the electrons are going into the same shell (2s and 2p or 3s and 3p, going into the same shell (2s and 2p or 3s and 3p, etc.).etc.).– Consequently, the outer electrons feel a Consequently, the outer electrons feel a
stronger effective nuclear charge.stronger effective nuclear charge.– For Li, ZFor Li, Zeffeff ~ +1 ~ +1– For Be, ZFor Be, Zeffeff ~ +2 ~ +2 — — For B, ZFor B, Zeffeff ~ +3 ~ +3
Atomic RadiiAtomic Radii• Example: Arrange these elements based on Example: Arrange these elements based on
their their increasingincreasing atomic radii. atomic radii.
– Se, S, O, TeSe, S, O, Te
O < S < Se < TeO < S < Se < Te
In the same group atomic size increases In the same group atomic size increases
as n (and Z) increasesas n (and Z) increases
─ ─ Br, Ca, Ge, FBr, Ca, Ge, F
F < Br < Ge < CaF < Br < Ge < Ca
same group same periodsame group same period
Ionization EnergyIonization Energy
• First ionization energy (IEFirst ionization energy (IE11))
– The minimum amount of energy required to The minimum amount of energy required to remove the most loosely bound electron from remove the most loosely bound electron from an isolated gaseous atom to form a 1+ ion.an isolated gaseous atom to form a 1+ ion.
• Symbolically:Symbolically:AtomAtom(g)(g) + energy + energy ion ion++
(g)(g) + e + e- -
EndothermicEndothermic
Mg(g) + 738kJ/mol Mg+ + e- IE1= IE1= 738kJ/mol
Ionization EnergyIonization Energy• Second ionization energy (IESecond ionization energy (IE22))
– The amount of energy required to remove the The amount of energy required to remove the second electron from a gaseous 1+ ion.second electron from a gaseous 1+ ion.
• Symbolically:Symbolically:– ionion++ + energy + energy ionion2+2+ + e + e--
Mg+ + 1451 kJ/mol Mg2+ + e- IE2= IE2= 1451 kJ/molAtoms can have 3rd (IE3), 4th (IE4), etc. ionization energies. The values are consecutively getting larger.
Ionization EnergyIonization EnergyPeriodic trends for Ionization Periodic trends for Ionization EnergyEnergy::1) IE1) IE22 > IE > IE1 1
It always takes moreIt always takes more energy energy to remove a second electron to remove a second electron from an ion than from a from an ion than from a neutral atom. neutral atom. 2) IE2) IE11 generally increases generally increases moving from IA elements to moving from IA elements to VIIIA elements. VIIIA elements. Important exceptions at Be &Important exceptions at Be &B, N & O, etc. due to B, N & O, etc. due to ss and and ppand half-filled subshells.and half-filled subshells. 3) IE3) IE11 generally decreases generally decreases moving down a family. moving down a family. IEIE1 1 for Li > IEfor Li > IE11 for Na, etc for Na, etc
First Ionization Energies First Ionization Energies of Some Elementsof Some Elements
0
500
1000
1500
2000
2500
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
Atomic Number
Ionization Energy (kJ/mol)
Ionization EnergyIonization Energy
• Example: Arrange these elements based on Example: Arrange these elements based on their (their (increasingincreasing) first ionization energies.) first ionization energies.
– Sr, Be, Ca, MgSr, Be, Ca, Mg
Sr < Ca < Mg < BeSr < Ca < Mg < Be
– Al, Cl, Na, PAl, Cl, Na, P
Na < Al < P < ClNa < Al < P < Cl
– O, Ga, Sr, SeO, Ga, Sr, Se
Sr < Ga < Se < OSr < Ga < Se < O
Ionization EnergyIonization Energy
• The reason Na forms NaThe reason Na forms Na++ and not Na and not Na2+2+ is is that the energy difference between IEthat the energy difference between IE11 and and
IEIE22 is so large. is so large.
– Requires more than 9 times more energy Requires more than 9 times more energy to remove the second electron than the to remove the second electron than the first one.first one.
• The same trend is persistent throughout The same trend is persistent throughout the series.the series.
– Thus Mg forms MgThus Mg forms Mg2+2+ and not Mg and not Mg3+3+..
– Al forms AlAl forms Al3+3+ and not Aland not Al4+4+..
HH 1312 1312 Ionization Energies (kJ/mole)Ionization Energies (kJ/mole)HeHe 23712371 52475247LiLi 520520 72977297 1181011810BeBe 900900 17571757 1484014840 2100021000BB 800800 24302430 36593659 2502025020 3281032810CC 10861086 23522352 46194619 62216221 3780037800 4730047300NN 14021402 28572857 45774577 74737473 94439443 5325053250 6434064340OO 13141314 33913391 53015301 74687468 1098010980 1332013320 7130071300 8485084850FF 16811681 33753375 60456045 84188418 1102011020 1516015160 1786017860 9200092000NeNe 20802080 39633963 62766276 93769376 1219012190 1523015230NaNa 496496 45654565 69126912 95409540 1336013360 1661016610 2011020110 2549025490MgMg 738738 14501450 77327732 1055010550 1362013620 1800018000 2170021700 2566025660AlAl 577577 18161816 27442744 1158011580 1503015030 1837018370 2329023290 2746027460SiSi 786786 15771577 32293229 43564356 1608016080 1979019790 2378023780 2925029250PP 10121012 18961896 29102910 49544954 62726272 2127021270 2541025410 2984029840SS 10001000 22602260 33803380 45654565 69966996 84908490 2808028080 3172031720ClCl 12551255 22972297 38503850 51465146 65446544 93309330 1102011020 3360033600ArAr 15201520 26652665 39473947 57705770 72407240 88108810 1197011970 1384013840KK 419419 30693069 46004600 58795879 79717971 96199619 1138011380 1495014950
Electron Affinity (EA)Electron Affinity (EA)• Electron affinity is the amount of energy Electron affinity is the amount of energy
absorbed or emittedabsorbed or emitted when an electron is when an electron is added to an isolated gaseous atom to form added to an isolated gaseous atom to form an ion with a 1- charge.an ion with a 1- charge.
• Sign conventions for electron affinity.Sign conventions for electron affinity.
– If EA > 0 energy is absorbed (difficult)If EA > 0 energy is absorbed (difficult)
– If EA < 0 energy is released (easy)If EA < 0 energy is released (easy)
• Electron affinity is a measure of an atom’s Electron affinity is a measure of an atom’s ability to form negative ions.ability to form negative ions.
• Symbolically:Symbolically:
atom(g) + e- ion-(g) EA (kJ/mol)
Electron AffinityElectron Affinity• General periodic trend for electron affinity isGeneral periodic trend for electron affinity is
– the values the values become more negativebecome more negative from left from left to right across a period on the periodic to right across a period on the periodic chart chart ((affinity for electron increases).).
– the values become more negative from the values become more negative from bottom to top at a group on the periodic bottom to top at a group on the periodic chart.chart.
−Noble gases have EA > 0 (full electron confg)
• An element with a high ionization energy generally has a high affinity for an electron, i.e., EA is largely negative. That is the case for halogens (F, Cl, Br, I), O, and S.
Electron AffinityElectron AffinityF (Z= 9) and Cl (Z = 17) have the most negative EAF (Z= 9) and Cl (Z = 17) have the most negative EA
Noble gases, He (2), Ne (10), and Ar (18), EA > 0; also Be, Mg, NNoble gases, He (2), Ne (10), and Ar (18), EA > 0; also Be, Mg, N
They are all first Electron Affinity. They are all first Electron Affinity. A(g)
- + e- A2-(g) EA2(kJ/mol) is the 2nd
Electron AffinityElectron AffinityTwo examples of electron affinity values: Mg(g) + e- + 231 kJ/mol Mg-(g) EA = 231kJ/mol
Br(g) + e- Br-(g) + 323 kJ/mol EA = -323 kJ/mol
Br has a larger affinity for e− than Mg. The greater the affinity an atom has for an e− , the more negative EA is, the smaller it is.
Ionic RadiiIonic RadiiCations (positive ions) are always smaller than
their respective neutral atoms. When one or more electrons are removed, the attractive force of the protons is now exerted on less electrons.
ElementElement NaNa
11 p+, 11e11 p+, 11e-
MgMg
12p+, 12 e12p+, 12 e--
AlAl
13 p+, 13e13 p+, 13e-
Atomic Atomic Radius (Radius (Å)Å)
1.861.86 1.601.60 1.431.43
IonIon NaNa++
11 p+, 10e11 p+, 10e-
MgMg2+2+
12 p+, 10 e12 p+, 10 e--
AlAl3+3+
13 p+, 10e13 p+, 10e-
Ionic Ionic
Radius (Radius (Å)Å)
1.161.16 0.850.85 0.680.68
Ionic RadiiIonic RadiiAnions (negative ions) are always larger than
their neutral atoms.
F 1s2 2s2 2p5 + e− F− 1s2 2s2 2p6 same Z nine electrons ten electrons
ElementElement NN
7 p+, 7e7 p+, 7e-
OO FF
AtomicAtomic
Radius(Radius(Å)Å)
0.750.75 0.730.73 0.720.72
IonIon NN3-3-
7 p+, 7 p+, 10e10e-
OO2-2-
8 p+, 8 p+, 10e10e-
FF−−
9 p+, 9 p+, 10e10e-
IonicIonic
Radius(Radius(Å)Å)
1.711.71
The threeThe three
1.261.26
ions are ions are
1.191.19isoelectronicisoelectronic
Ionic RadiiIonic Radii
Cation (positive ions) radii decrease from left to right across a period.
Increasing nuclear charge attracts the electrons and decreases the radius.Rb+ and Sr2+ are isoelectronic, same # of e-s
IonIon RbRb++
Z = 37 pZ = 37 p++
SrSr2+2+
Z = 38 pZ = 38 p++
InIn3+3+
Z = 49 pZ = 49 p++
IonicIonic
Radii(Radii(Å)Å) 1.661.66 1.321.32 0.940.94
Ionic RadiiIonic Radii
Anion (negative ions) radii decrease from left to right across a period.
Increasing electron numbers in highly charged ions cause the electrons to repel and increase the ionic radius.For these isoelectronic anions… 10 e− and 7 p+ 8 p+ 9 p+
IonIon NN3-3- OO2-2- FF−−
IonicIonic
Radii(Radii(Å)Å)
1.711.71 1.261.26 1.191.19
Ionic RadiiIonic RadiiExample: Arrange these ions in order of decreasing radius.
Ga3+, K+, Ca2+
K+ > Ca2+ > Ga3+
Cl−, Se2−, Br−, S2−
Se2− > Br− > S2− > Cl−
isoelectronic isoelectronic, same # of electrons
Se2−(34 p+) > Br−(35 p+); they have 36 e− each.
S2−(16 p+) > Cl−(17 p+); they have 18 e− each.
Br− > S2− because Br− is in the 4th period, S2− is in the 3rd.
Ionic Radii of isoelectronic speciesIonic Radii of isoelectronic speciesIsoelectronic species have the same number of electrons. Here are some examples with the number of (protons) and + or − charges
N3−(Z=7) > O2−(Z=8) > F−(Z=9) > Ne(Z=10) neutral >
Na+(Z=11) > Mg2+(Z=12) > Al3+ (Z=13) all have 10e−
The nuclear charge (+) increases from left to right, so does attraction force to electrons: r decreases.
S2−(Z=16) > Cl− (Z=17) > Ar0 (Z=18) > K+ (Z=19) >
Ca2+ (Z=20) > Sc3+ (Z=21) all of them have 18e−