Chapter 7. SIMPLIFY: 20 12 3 20 = 4 5 = 2 5 12 3 12 3 3 3 3 4 3==
Transcript of Chapter 7. SIMPLIFY: 20 12 3 20 = 4 5 = 2 5 12 3 12 3 3 3 3 4 3==
![Page 1: Chapter 7. SIMPLIFY: 20 12 3 20 = 4 5 = 2 5 12 3 12 3 3 3 3 4 3==](https://reader033.fdocuments.us/reader033/viewer/2022052401/5697bf741a28abf838c7fd01/html5/thumbnails/1.jpg)
Chapter 7
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SIMPLIFY:
20 12 3
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20 = 4 5 = 2 5
12 3 12 3 3 3 3
4 3= =
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MULTIPLY:
( 2 5 )2
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(2 5 )2 = 4 25 = 4 5 = 20.
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COMPLETE:
( ___ )2 + ( ___ )2 = ( ___ )2
leg1
leg2
hyp
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(leg1)2 + (leg2)2 = (hyp)2
Pythagorean Theorem
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Complete to form RIGHT triangles:
3, 4, ____ 5, 12, ____
6, 8, ____ 8, 15, ____
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3, 4, 5 5, 12, 13 6, 8, 10 8, 15, 17
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Given segment lengths a, b, c longest
Right c2 a2 + b2
Obtuse c2 a2 + b2
Acute c2 a2 + b2
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Right c2 = a2 + b2
Obtuse c2 > a2 + b2
Acute c2 < a2 + b2
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COMPLETE:
L = ____
H = ____
45
45
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L = L
H = L 2
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SOLVE:
x = _____
y = _____
8
x
y45
45
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x = 8
y = 8 2
![Page 16: Chapter 7. SIMPLIFY: 20 12 3 20 = 4 5 = 2 5 12 3 12 3 3 3 3 4 3==](https://reader033.fdocuments.us/reader033/viewer/2022052401/5697bf741a28abf838c7fd01/html5/thumbnails/16.jpg)
COMPLETE:
LL = _____
H = _____30
60
Ls
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LL = Ls 3
H = 2 Ls
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SOLVE:
x = _____
y = _____30
604
x
y
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x = 4 3
y = 8
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AREA OF EQUILATERAL TRIANGLES:
A = ½ ( ____ )( ____ )
A = ½ ( ____)( ____ )
A = ( ____ )2
( ____ )
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A = ½ bh
A = ½ ap
A = s2 4
3
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Find the area:
(Equilateral Triangle)
6 3
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30
63
9
18
33
A = ½ bh
A = ½ (18)(9 )
A = 81
3
3
A = ½ ap
A = ½ (3 )(54)
A = 81
3
3
A = s2 4
A = (18)2
4
A = 81
3
3
3
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AREA OF SQUARES:
A = ( ____ )2
A = ½ ( ____ )( ____ )
A = ½ ( ____ )( ____ )
![Page 25: Chapter 7. SIMPLIFY: 20 12 3 20 = 4 5 = 2 5 12 3 12 3 3 3 3 4 3==](https://reader033.fdocuments.us/reader033/viewer/2022052401/5697bf741a28abf838c7fd01/html5/thumbnails/25.jpg)
A = s2 A = ½ ap A = ½ d1d2
side (s)
a
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Find the area:
(Square)
10 2
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10 210
10
20
A = s2
A = 202
A = 400
A = ½ ap
A = ½ (10)(80)
A = 400
A = ½ d1d2
A = ½ (20 )(20 )
A = 400
2 2
45
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AREA OF REGULAR HEXAGONS:
A = ½ ( ____ )( ____ )
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A = ½ ap
120
a60
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Find the area:
8
(Regular Hexagon)
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8
4 4
4 3
60
A = ½ ap
A = ½ (4 3)(48)
A = 96 3
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AREA OF PARALLELOGRAMS:
A = ( ____ )( ____ )
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A = bh
Base (b)
Height (h)
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AREA OF ANY TRIANGLE:
A = ½ ( ____ )( ____ )
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A = ½bh
base (b)
height (h)
![Page 36: Chapter 7. SIMPLIFY: 20 12 3 20 = 4 5 = 2 5 12 3 12 3 3 3 3 4 3==](https://reader033.fdocuments.us/reader033/viewer/2022052401/5697bf741a28abf838c7fd01/html5/thumbnails/36.jpg)
Find the height:
6 6
4
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h2 + 22 = 62
h2 = 32h = 32 = 4 2
6 6
4
2 2
h
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AREA OF RIGHT TRIANGLES:
A = ½ ( ____ )( ____ )
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A = ½ (l1)( l2)
leg (l1) leg (l2)
![Page 40: Chapter 7. SIMPLIFY: 20 12 3 20 = 4 5 = 2 5 12 3 12 3 3 3 3 4 3==](https://reader033.fdocuments.us/reader033/viewer/2022052401/5697bf741a28abf838c7fd01/html5/thumbnails/40.jpg)
AREA OF RHOMBUSES:
A = ½ ( ____ ) ( ____ )
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A = ½ (d1)(d2)
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AREA OF TRAPEZOIDS:
A = ½ ( ____ ) ( ____ + ____ )
![Page 43: Chapter 7. SIMPLIFY: 20 12 3 20 = 4 5 = 2 5 12 3 12 3 3 3 3 4 3==](https://reader033.fdocuments.us/reader033/viewer/2022052401/5697bf741a28abf838c7fd01/html5/thumbnails/43.jpg)
A = ½ (h)(b1 + b2)
base (b1)
base (b2)
height (h)
![Page 44: Chapter 7. SIMPLIFY: 20 12 3 20 = 4 5 = 2 5 12 3 12 3 3 3 3 4 3==](https://reader033.fdocuments.us/reader033/viewer/2022052401/5697bf741a28abf838c7fd01/html5/thumbnails/44.jpg)
FOR CIRCLES:
Circumference = ( __ )( __ )( __ )
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C = 2rπ
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What fraction of the circumference is arc AB?
r
120o
A
B
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120 = 1 360 3
![Page 48: Chapter 7. SIMPLIFY: 20 12 3 20 = 4 5 = 2 5 12 3 12 3 3 3 3 4 3==](https://reader033.fdocuments.us/reader033/viewer/2022052401/5697bf741a28abf838c7fd01/html5/thumbnails/48.jpg)
AREA OF CIRCLES:
A = ( ____ )( ____ )2
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A = πr2
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What fraction of the circle is shaded?
450
r
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45 = 1 360 8