Chapter 7 Electrochemistry §7.10 Application of EMF and electrode potential.
Chapter 7 Electrochemistry
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Transcript of Chapter 7 Electrochemistry
Chapter 7 Electrochemistry
§7.7 Thermodynamics of reversible cell
7.7.1. Measurement of Electromotive forces (emf's)
Can voltameter be used to measure electromotive force?
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Discussion
What is electromotive forces?
High-impedance input
1) Poggendorff’s compensation method
i = 0, thermodynamic reversibility.
Principle of potentiometer
EW: working cell
Ex: test cell
Es: standard cell
A
Es
Ex G
Ew
Ex
Es
K
A B
C1 C2
2) Weston standard cell
Drawing from Edward Weston's US Patent 494827 depicting the standard cell
The Weston cell, is a wet-chemical cell that produces a highly stable voltage suitable as a laboratory standard for calibration of voltmeters. Invented by Edward Weston in 1893, it was adopted as the International Standard for EMF between 1911 and 1990.
Hg
Hg2SO4
4 2
8CdSO H O
3
Saturated CdSO4 solution
Cd(Hg)x
+ --
Cork sealed with paraffin or wax
Commercial Weston Standard cell
2) Weston standard cell
4 2 4
4 2 4
8Cd(5% 12%)(Hg) CdSO H O(s) CdSO (sat)
38
CdSO H O(s) HgSO (s) Hg(l)+3
x
E(T) /V = 1.01845 – 4.05 10-5(T/K –293.15)
– 9.5 10-7(T/K –293.15)2 + 1 10-8 (T/K –293.15)3
Weston standard cell
Temperature-dependence of emf
The original design was a saturated cadmium cell producing a
convenient 1.018638 Volt reference and had the advantage of having
a lower temperature coefficient than the previously used Clark cell
2. Nernst equation and standard EMF of cell
1889, Nernst empirical equation
G H
C D
lnr h
c d
a aRTE E
nF a a y
cC + dD = gG + hH
Walther H. Nernst1920 Noble Prize
Germany1864/06/25~1941/11/18Studies on thermodynamics
physical meaning of E
For a general electrochemical reaction:
cC + dD = gG + hH G H
C D
g h
a c d
a aK
a a
Van’t Horff equation G Hr m r m
C D
Δ Δ lng h
c d
a aG G RT
a a y
r mΔ G nFE r mΔ G nFEy y
G H
C D
lnr h
c d
a aRTE E
nF a a y
Theoretical deduction of Nernst Equation:
7.7.3. Standard electromotive forces
G H
C D
lnr h
c d
a aRTE E
nF a a y
EӨ equals E when the activity of any chemical species is unit.
For cell: Pb(s)-PbO(s)|OH–(c)|HgO(s)-Hg(l)
Write out the cell reaction and Nernst equation.
For: Pt(s), H2 (g, p)|HCl(m) |AgCl(s)-Ag(s)
Write out the cell reaction and Nernst equation.
2 2ln
RT RTAE m E m
F F y
2.0x10-4 4.0x10-4 6.0x10-40.070
0.071
0.072
0.073
0.074
0.075
E
1/ mol kgm
E /
VExperimental determination of standard electromotive force
Cf. Levine, p. 430
7.7.4. Temperature-dependence of emf's
Temperature coefficient:
For Weston Standard Cell:
E/V = 1.018646 - 4.0510-5(T/ -20) - 9.5℃ 10-7 (T/ -20)℃ 2 +
110-8(T/ -20)℃ 3
By differentiating the equation
- rGm = nFE
with respect to temperature, we obtain
r m(Δ )Δ
pp
G ES nF
T T
1-5 KV 10
pT
E
r m r m r mΔ Δ Δp p
E EH G T S nFE nFT nF T E
T T
By measuring E and (E/T)p, thermodynamic quantities of the
cell reaction can be determined.
Because E and (E/T)p can be easily measured with high
accuracy, historically, the thermodynamic data usually measured
using electrochemical method other than thermal method.
re Δp
EQ T S nFT
T
ΔG nFE
Δp
ES nF
T
7.7.5. Thermodynamic quantities of ions
2 2
1 1H ( ) Cl ( ) H (aq) Cl (aq)
2 2p p y y
+ 1r m f m f mΔ Δ [H (aq)] Δ [Cl (aq)] 167kJ molH H H y y y
The customary convention is to take the standard free energy of formation of H+(aq) at any temperatures to be zero.
+f mΔ [H (aq)] 0G y
+f mΔ [H (aq)] 0H y
+m [H (aq)] 0S y
How to solve this deadlock?
- 1f mΔ [Cl (aq)] 167kJ molH y
2
1Cl ( ) e Cl (aq)
2p y
+ -r m f m f m
1
Δ Δ [H (aq)] Δ [Cl (aq)]
167kJ mol
H H H
y y y
Ion / kJ·mol-1 Ion / kJ·mol-1
H+ 0.000 OH -157.3
Li+ -298.3 Cl -276.5
Na+ -261.87 Br -131.2
K+ -282.3 SO42 -742.0
Ag+ 77.1 CO32 -528.1
Standard free energies of formation of aqueous ions at 298.3 K
mΔGymΔGy
H+
Cl
Br
I
K+
Na+
Mg2+
Ca2+
By definition
Exercise-1
At 298 K, for cell
Ag(s)-AgCl(s)|KCl(m)|Hg2Cl2(s)-Hg(l),
E = 0.0455V, (E/T)p = 3.38 10-4 V·K-1. Write the cell
reaction and calculate rGm, rSm, rHm, and Qre.
At 198 K, for cell
Pt(s), H2(g, p)|KOH(aq)|HgO(s)-Hg(l)
E = 0.926 V, product of water Kw=10-14. Given fGm of
HgO(s) is –58.5 kJ· mol-1, calculate fGm of OH.
Exercise-2
Self reading:
Ira N. Levine, Physical Chemistry, 5th Ed., McGraw-Hill, 2002.
pp. 294-310
Section 10.10 standard-state thermodynamic properties of solution components
pp. 426
Section 14.6 thermodynamics of galvanic cells
Section 14.7 standard electrode potentials
Section 14.8 concentration cells
Section 14.9 liquid-junction potential