Chapter 6: Phenomena - University of California, Santa...

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Chapter 6: Chemical Equilibrium Chapter 6: Phenomena Reaction 1: A(aq) B(aq) Reaction 2: B(aq) 2C(aq) Trial Initial After 10 Minutes After 20 Minutes After 30 Minutes Trial Initial After 10 Minutes After 20 Minutes [A] (M) [B] (M) [A] (M) [B] (M) [A] (M) [B] (M) [A] (M) [B] (M) [B] (M) [C] (M) [B] (M) [C] (M) [B] (M) [C] (M) 1 0.60 0.00 0.48 0.12 0.48 0.12 0.48 0.12 1 0.60 0.00 0.30 0.60 0.23 0.75 2 0.70 0.70 0.90 0.50 1.12 0.28 1.12 0.28 2 0.70 0.70 0.49 1.12 0.49 1.12 3 0.00 0.60 0.20 0.40 0.40 0.20 0.48 0.12 3 0.00 0.60 0.08 0.44 0.08 0.44 4 1.10 0.00 0.90 0.20 0.88 0.22 0.88 0.22 4 1.10 0.00 0.80 0.60 0.53 1.14 5 0.00 1.20 0.20 1.00 0.40 0.80 0.60 0.60 5 0.00 1.20 0.23 0.75 0.23 0.75 6 1.40 0.35 1.40 0.35 1.40 0.35 1.40 0.35 6 1.40 0.35 1.10 0.95 0.85 1.45 7 1.00 1.58 1.20 1.38 1.40 1.18 1.60 0.98 7 1.00 1.58 1.00 1.58 1.00 1.58 Phenomena: Scientists studied the following reactions by putting different amounts of substances (reactants and products) into a sealed rigid vessel and measuring the concentration as a function of time. What patterns do you notice about the data?

Transcript of Chapter 6: Phenomena - University of California, Santa...

Chapter 6: Chemical Equilibrium

Chapter 6: Phenomena

Reaction 1: A(aq) ⇌ B(aq) Reaction 2: B(aq) ⇌ 2C(aq)

Trial InitialAfter 10

Minutes

After 20

Minutes

After 30

MinutesTrial Initial

After 10

Minutes

After 20

Minutes

[A]

(M)

[B]

(M)

[A]

(M)

[B]

(M)

[A]

(M)

[B]

(M)

[A]

(M)

[B]

(M)

[B]

(M)

[C]

(M)

[B]

(M)

[C]

(M)

[B]

(M)

[C]

(M)

1 0.60 0.00 0.48 0.12 0.48 0.12 0.48 0.12 1 0.60 0.00 0.30 0.60 0.23 0.75

2 0.70 0.70 0.90 0.50 1.12 0.28 1.12 0.28 2 0.70 0.70 0.49 1.12 0.49 1.12

3 0.00 0.60 0.20 0.40 0.40 0.20 0.48 0.12 3 0.00 0.60 0.08 0.44 0.08 0.44

4 1.10 0.00 0.90 0.20 0.88 0.22 0.88 0.22 4 1.10 0.00 0.80 0.60 0.53 1.14

5 0.00 1.20 0.20 1.00 0.40 0.80 0.60 0.60 5 0.00 1.20 0.23 0.75 0.23 0.75

6 1.40 0.35 1.40 0.35 1.40 0.35 1.40 0.35 6 1.40 0.35 1.10 0.95 0.85 1.45

7 1.00 1.58 1.20 1.38 1.40 1.18 1.60 0.98 7 1.00 1.58 1.00 1.58 1.00 1.58

Phenomena: Scientists studied the following reactions by putting

different amounts of substances (reactants and products) into a

sealed rigid vessel and measuring the concentration as a

function of time. What patterns do you notice about the data?

Chapter 6

Chemical

Equilibrium

• Dynamic Equilibrium

• Equilibrium Constant

• Reaction Quotient

• Determining Equilibrium

Concentration /

Pressure

• Le Chatelier’s Principle• Determining Equilibrium

Constants from Other

Systems

2

Big Idea: Reactions proceed to

an equilibrium

condition. When

equilibrium is reached

the rate of formation of

products equals the

rate of formations of

reactants. When a

system at equilibrium is

disturbed the reaction

responds by minimizing

the disturbance.

Chapter 6: Chemical Equilibrium

Student Question

Dynamic Equilibrium

Is the following statement true or false?

At equilibrium the amount of products always

equals the amount of reactants.

a) True

b) False

c) Not Enough Information

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Chapter 6: Chemical Equilibrium

Dynamic Equilibrium

Data from all day Chemistry Club beach BBQ

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Chapter 6: Chemical Equilibrium

Dynamic Equilibrium

Dynamic Equilibrium: The condition in which the

rate of the forward reaction equals the rate of the

reverse reaction.

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Chapter 6: Chemical Equilibrium

A⇌2B+C

Equilibrium Expressions

Activity (aJ): The effective concentration or

pressure of a species J expressed as the partial

pressure or concentration of the species relative to

its standard value.

Equilibrium Constant

Full Simplified

𝐾 =𝑎𝐵2𝑎𝐶𝑎𝐴

𝐾 =𝐵 2 𝐶

𝐴

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Chapter 6: Chemical Equilibrium

Liquids and Solids

Solids and liquids only have one concentration, therefore, this

is also the reverence concentration. Any number divide by

itself is 1 which results in solids and liquids not being included

in the equilibrium constant.

Note: Since the equation for activity is concentration over concentration or pressure

over pressure, many books do not put units on equilibrium expressions.

Equilibrium Constant

Aqueous Solutions Gas Solutions

𝑎𝑗 =𝐽

𝑐°𝑎𝑗 =

𝑃𝑗

𝑃°

[J] = concentration of J PJ = partial pressure of J

c° = reference concentration (1 M) P° = reference pressure (1 atm)

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Chapter 6: Chemical Equilibrium

What does Keq tell us?

Keq << 1

lots of reactants, not many products at equilibrium

reverse reaction is favored/faster*

Keq ~1

equal amounts of reactants and product at

equilibrium

neither direction favored/faster*

Keq >> 1

lots of products, not many reactants at equilibrium

forward reaction is favored/faster*

*when equal amounts of products and reactants are present

Equilibrium Constant

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Chapter 6: Chemical Equilibrium

Student Question

Before Class Question

How are K and KP related for the following

reaction?

CO(g) + ½O2(g) ⇌ CO2(g)

a) 𝐾𝑃 = K

b) 𝐾𝑃 = 𝑅𝑇𝐾

c) 𝐾𝑃 =1

RTK

d) 𝐾𝑃 = RTK

e) None of the above

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Chapter 6: Chemical Equilibrium

What does Q tell us?

Q > K

There are more products present than there should

be at equilibrium. Therefore, the reverse reaction is

spontaneous and products tend to decompose

into reactants.

Q = K

The system is at equilibrium.

Q < K

There are more reactants present than there

should be at equilibrium. Therefore, the forward

reaction is spontaneous and reactants tend form

into products.

Reaction Quotient

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Chapter 6: Chemical Equilibrium

Student Question

Reaction Quotient

The K for the following reaction at 1000.°C is

1.17. For a system with the concentrations

[CO2] = 0. 342 M and [CO] = 0.100 M one can

conclude that:

CO2(g) + C(s) ⇌ 2CO(g)

a) The system is not at equilibrium and the

reaction will proceed to the reactants.

b) The system is at equilibrium and no net

change will occur.

c) The system is not at equilibrium and the

reaction will proceed to the products.

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Chapter 6: Chemical Equilibrium

Determining Equilibrium Concentration/Pressure

Step 1: Write a balanced chemical reaction.

Step 2: Write the expression for K or KP.

Step 3: Make a chart.

Step 4: Plug in equilibrium values into equilibrium

expression.

Step 5: Use guess and check, quadratic formula,

or an assumption to solve for x.

Step 6: Calculate equilibrium concentrations/

pressures.

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Species 1 Species 2

Initial (Concentration/Pressure)

Change

Equilibrium

Chapter 6: Chemical Equilibrium

Example 1:

3.4 mol of SO3 is put in an otherwise empty 1.0 L

container. What are the concentrations of the

species at equilibrium if the following reaction

occurs:

2SO2(g) + O2(g) ⇌ 2SO3(g)

K=3.43 (at 1000. K)

Determining Equilibrium Concentration/Pressure

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Chapter 6: Chemical Equilibrium

Example 2:

The following data was collected at equilibrium

for the system:

H2(g) + I2(g) ⇌ 2HI(g)

𝑃𝐻2 = 0.639𝑎𝑡𝑚

𝑃𝐼2 = 0.0586𝑎𝑡𝑚

𝑃𝐻𝐼 = 0.135𝑎𝑡𝑚

If 0.300 atm of each gas was added to the

container after the equilibrium was established.

What are the new equilibrium pressures?

Determining Equilibrium Concentration/Pressure

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Chapter 6: Chemical Equilibrium

Example 3:

The following equilibrium is known to occur:

H2CO3(aq) ⇌ 2H+(aq) + CO32-(aq)

K=2.4×10-17

What are the concentrations at equilibrium if

initially there is only 0.14 M H2CO3 present?

Determining Equilibrium Concentration/Pressure

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Chapter 6: Chemical Equilibrium

Checking Assumptions:

Assumption are good when the amount

subtracted off is less than 5% of the number it is

being subtracted from. (5% Rule)

Calculating the Percentage Lost/Gained𝑎𝑚𝑜𝑢𝑛𝑡 𝑙𝑜𝑠𝑡/𝑔𝑎𝑖𝑛𝑒𝑑

𝑜𝑟𝑖𝑔𝑖𝑛𝑎𝑙 𝑐𝑜𝑛𝑐𝑒𝑛𝑡𝑎𝑟𝑖𝑜𝑛100%

Determining Equilibrium Concentration/Pressure

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Note: This assumption is usually good when K or KP is less than 10-5.

Note: For test you mist check your assumption to receive full credit.

Chapter 6: Chemical Equilibrium

Le Chatelier’s Principle

Le Chatelier’s Principle: When a chemical system at

equilibrium is disturbed, the system shifts in a direction

that minimizes the disturbance.

Concentration

If the concentration of a species is increased, to restore

equilibrium, the reaction must proceed in the opposite

direction of the added species.

If the concentration of a species is decreased, to restore

equilibrium, the reaction must proceed towards the

direction of the removed species.

Volume

If the volume is decreased, to restore equilibrium, the

reaction must proceed towards the side of the equation

with fewer moles of gas. then

If the volume is increased , to restore equilibrium, the

reaction must proceed towards the side of the equation

with more moles of gas.17

Chapter 6: Chemical Equilibrium

Endothermic Reaction: A reaction that absorbs

heat (reactants + energy ⇌ products)

Exothermic Reaction: A reaction that releases

heat (reactants ⇌ products + energy)

Le Chatelier’s Principle

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Chapter 6: Chemical Equilibrium

Le Chatelier’s Principle

Temperature

Exothermic Reactions (R ⇌ P + heat)

If the temperature is raised,

equilibrium shifts to the reactants.

If the temperature is lowered,

equilibrium shifts to the products.

Endothermic Reactions (R + heat ⇌ P)

If the temperature is raised,

equilibrium shifts to the products.

If the temperature is lowered,

equilibrium shifts to the reactants.

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Chapter 6: Chemical Equilibrium

Student Question

Le Chatelier’s Principle

The following equilibrium is going on in the 3

tubes:2NO2(g brown) ⇌ N2O4(g colorless) + heat

What color is the gas in the hot water?

a) Dark Brown (mainly reactant but some

products)

b) Light Brown (mainly products but some

reactants)

c) Not Enough Information

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Chapter 6: Chemical Equilibrium

Student Question

Le Chatelier’s Principle

The following KP values were collected for a

system.

KP=6.8×105 25°C

KP=1.9×10-4 400°C

What side of the equation is the heat on?

a) Reactants

b) Products

c) Not enough information

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Chapter 6: Chemical Equilibrium

Determining Equilibrium Constants From Other Systems

If you knew the equilibrium constants of the first

two reactions, could you determine the

equilibrium constant for the third reaction?

Reaction 1

2GeO(g) + W2O6(g) ⇌ 2GeWO4(g) 𝐾1 =𝐺𝑒𝑊𝑂4

2

𝐺𝑒𝑂 2 𝑊2𝑂6

Reaction 2

GeO(g) + W2O6(g) ⇌ GeW2O7(g) 𝐾2 =𝐺𝑒𝑊2𝑂7

𝐺𝑒𝑂 𝑊2𝑂6

Reaction 3

GeO(g) + GeW2O7(g) ⇌ 2GeWO4(g) 𝐾3 =𝐺𝑒𝑊𝑂4

2

𝐺𝑒𝑂 𝐺𝑒𝑊2𝑂7

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Chapter 6: Chemical Equilibrium

Student Question

Determining Equilibrium Constants From Other Systems

Given the following two reactions what is the equilibrium constant of 2A(aq)⇌D(aq) +E(aq)?

A(aq) + B(aq) ⇌ D(aq) + C(aq) K1 = 5.0

2C(aq) + D(aq) ⇌ 2B(aq) + E(aq) K2 = 2.0

a) 0.40

b) 2.5

c) 10.

d) 20.

e) None of the above

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Chapter 6: Chemical Equilibrium

Take Away From Chapter 6

Big Idea: Reactions proceed to a equilibrium condition.

When equilibrium is reached the rate of formation of

products equals the rate of formations of reactants. When a

system at equilibrium is disturbed the reaction responds by

minimizing the disturbance.

Dynamic Equilibrium

Know what it means to be at dynamic equilibrium. (10)

Equilibrium Constant

Be able to calculate the equilibrium expression for a

reaction.(21,31,35)

Solids and liquids not included in equilibrium constant.

Be able to convert between the equilibrium expression in

concentration and in pressure.(24,25,33)

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Numbers correspond to end of chapter questions.

Chapter 6: Chemical Equilibrium

Take Away From Chapter 6

Equilibrium Constant (Continued)

Know what the value of the equilibrium constant represents.

(2,11,13)

K=1 Similar number of product and reactant at equilibrium.

K<1 More reactant than product at equilibrium.

K>1 More product than reactant at equilibrium.

Reaction Quotient

Know what the value of Q represents when compare to

K.(27,28,37,38)

Q>K Too many products, reaction proceeds to reactant to reach

equilibrium.

Q=K at equilibrium

Q<K Too many reactants , reaction proceeds to products to reach

equilibrium.

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Numbers correspond to end of chapter questions.

Chapter 6: Chemical Equilibrium

Take Away From Chapter 6

Determining Equilibrium Concentration/Pressure

Be able to determine the equilibrium concentration or

pressures, give initial concentration/pressure, and equilibrium

constant.(43,44,45,46,49,50,54,75,76,79,82)

Guess and check

Quadratic equation

Assumption (usually good when K<10-5)

Le Chatelier’s Principle

Be able to determine what a system will do if equilibrium is

disturbed.(56,58,59,61,62,63,65)

Determining Equilibrium Constants from Other Systems (26,72,73)

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Numbers correspond to end of chapter questions.