Chapter 5b. Upon completion of this chapter, you should be able to: Subnet an IPv4 address to make...
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Transcript of Chapter 5b. Upon completion of this chapter, you should be able to: Subnet an IPv4 address to make...
![Page 1: Chapter 5b. Upon completion of this chapter, you should be able to: Subnet an IPv4 address to make separate networks out of one address given Use.](https://reader037.fdocuments.us/reader037/viewer/2022083119/5a4d1ae37f8b9ab0599781b4/html5/thumbnails/1.jpg)
IP ADDRESSING & SUBNETTING
Chapter 5b
![Page 2: Chapter 5b. Upon completion of this chapter, you should be able to: Subnet an IPv4 address to make separate networks out of one address given Use.](https://reader037.fdocuments.us/reader037/viewer/2022083119/5a4d1ae37f8b9ab0599781b4/html5/thumbnails/2.jpg)
OBJECTIVES Upon completion of this chapter, you
should be able to:Subnet an IPv4 address to make separate
networks out of one address givenUse the new subnet mask to identify the
subnetAssign IPv4 addresses to hosts within your
network Identify each subnet’s new network ID and
broadcast addressFind the network, broadcast, or check if the
address is a valid host address by working backwards
![Page 3: Chapter 5b. Upon completion of this chapter, you should be able to: Subnet an IPv4 address to make separate networks out of one address given Use.](https://reader037.fdocuments.us/reader037/viewer/2022083119/5a4d1ae37f8b9ab0599781b4/html5/thumbnails/3.jpg)
CLASSFUL SUBNETTING
5.1.3
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PARTS OF THE NETWORK
Network
Subnetwork
Hosts
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SUBNETTING-SPLIT UP THE IP ADDRESS Borrow bits from host portion to make
new networks Ask yourself…
How many networks do you need?How many hosts per network are there?
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SOME RULES FIRST… You MUST borrow at least 2 bits or leave at
least 2 bits Class C has 1 octet to borrow from Class B has 2 octets to borrow from Class A has 3 octets to borrow from
Remember the powers of 2 22= 4 23= 8 24= 16 25= 32 26= 64
Remember 2 addresses you
can’t use: Network & Broadcast
![Page 7: Chapter 5b. Upon completion of this chapter, you should be able to: Subnet an IPv4 address to make separate networks out of one address given Use.](https://reader037.fdocuments.us/reader037/viewer/2022083119/5a4d1ae37f8b9ab0599781b4/html5/thumbnails/7.jpg)
199.72.101.0
![Page 8: Chapter 5b. Upon completion of this chapter, you should be able to: Subnet an IPv4 address to make separate networks out of one address given Use.](https://reader037.fdocuments.us/reader037/viewer/2022083119/5a4d1ae37f8b9ab0599781b4/html5/thumbnails/8.jpg)
199.72.101.0
1. 199.72.101.0-312. .32-.63 (.33-.62)3. .64-.95 (.65-.94)4. .96-.127 (.97-.126)5. .128-.159 (.129-.158)6. .160-.191 (.161- .190)7. .192-.223 (.191-.222)8. .224-.255
Total Range #3 Useable Range #2
Network ID 199.72.101.64 /27
Broadcast Address 199.72.101.95 /27
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ASSIGN ADDRESSES
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ROUTER…ACTION! A packet with a destination IP of
199.72.101.85 255.255.255.224 goes to a router It ANDs to come up with the NETWORK #
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HOW TO WORK BACKWARDS 221.17.125.46 /28
What class address? C: Only deal with the last octet!
255.255.255.24011111111.11111111.11111111.11110000How many bits borrowed?
4 24= 16 networks
How many bits left over? 4 24= 16 hosts per sub-network
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WORK BACKWARDS Based on the IP address & SM, identify…
The network addressThe broadcast addressHow many bits were borrowedHow many bits were left over Is the address valid
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WHAT’S WRONG? PC1 has an address of 199.15.1.40 /28.
PC2 has an address of 199.15.1.50 /28. Both are connected to a switch but they cannot communicate.The switch is working normally as are the PC’s NICs and Ethernet cables.Are the hosts on the same network or separate?
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QUESTIONS What’s the broadcast address for
201.78.90.0 /24?201.78.90.255Default SM, no subnetting
Sam’s Beef Hut uses network 215.67.106.0 & 255.255.255.240 to create subnets. How many useable hosts can be created per network?14
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QUESTIONS Which class gives you the most
hosts/network?A
Which class give you the most networks?C
Public IP addresses must be __________.
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CLASSLESS SUBNETTING
5.1.5
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CLASSLESS SUBNETTING Allows you to use part of the address for
the network portion Called partial subnetting or VLSM CIDR allows this
Helps reduce wasted addresses
You can subnet for each unequal network Your address is 210.1.17.64 /26
Net A needs 37 hosts Net B needs 15 hosts Net C needs 100 hosts
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TEST ON ADDRESSING & SUBNETTING
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IP ADDRESSING & SUBNETTING
Chapter 5b