CHAPTER4MEC 451ThermodynamicsSecond Law of ThermodynamicsLecture Notes:MOHD HAFIZ MOHD NOH HAZRAN HUSAIN & MOHD SUHAIRIL Faculty of Mechanical EngineeringUniversiti Teknologi MARA, 40450 Shah Alam, SelangorFor students EM 220 and EM 221 only*

Faculty of Mechanical Engineering, UiTM*MEC 451 THERMODYNAMICSIntroductionA process must satisfy the first law in order to occur. Satisfying the first law alone does not ensure that the process will take place. Second law is useful: provide means for predicting the direction of processes,establishing conditions for equilibrium, determining the best theoretical performance of cycles, engines and other devices.

MEC 451 THERMODYNAMICSFaculty of Mechanical Engineering, UiTM*A cup of hot coffee does not get hotter in a cooler room.Transferring heat to a wire will not generate electricity.Transferring heat to a paddle wheel will not cause it to rotate.These processes cannot occur even though they are not in violation of the first law.

Faculty of Mechanical Engineering, UiTM*MEC 451 THERMODYNAMICSSecond Law of ThermodynamicsKelvin-Planck statementNo heat engine can have a thermal efficiency 100 percent.As for a power plant to operate, the working fluid must exchange heat with the environment as well as the furnace.

Faculty of Mechanical Engineering, UiTM*MEC 451 THERMODYNAMICSHeat EnginesWork can easily be converted to other forms of energy, but?Heat engine differ considerably from one another, but all can be characterized :they receive heat from a high-temperature sourcethey convert part of this heat to workthey reject the remaining waste heat to a low- temperature sink atmospherethey operate on a cycle

Faculty of Mechanical Engineering, UiTM*MEC 451 THERMODYNAMICSThe work-producing device that best fit into the definition of a heat engine is the steam power plant, which is an external combustion engine.

Faculty of Mechanical Engineering, UiTM*MEC 451 THERMODYNAMICSThermal EfficiencyRepresent the magnitude of the energy wasted in order to complete the cycle. A measure of the performance that is called the thermal efficiency.Can be expressed in terms of the desired output and the required inputFor a heat engine the desired result is the net work done and the input is the heat supplied to make the cycle operate.

Faculty of Mechanical Engineering, UiTM*MEC 451 THERMODYNAMICSThe thermal efficiency is always less than 1 or less than 100 percent.where

Faculty of Mechanical Engineering, UiTM*MEC 451 THERMODYNAMICSApplying the first law to the cyclic heat engineThe cycle thermal efficiency may be written as

Faculty of Mechanical Engineering, UiTM*MEC 451 THERMODYNAMICSA thermodynamic temperature scale related to the heat transfers between a reversible device and the high and low-temperature reservoirs by The heat engine that operates on the reversible Carnot cycle is called the Carnot Heat Engine in which its efficiency is

Faculty of Mechanical Engineering, UiTM*MEC 451 THERMODYNAMICSHeat Pumps and RefrigeratorsA device that transfers heat from a low temperature medium to a high temperature one is the heat pump.Refrigerator operates exactly like heat pump except that the desired output is the amount of heat removed out of the systemThe index of performance of a heat pumps or refrigerators are expressed in terms of the coefficient of performance.

Faculty of Mechanical Engineering, UiTM*MEC 451 THERMODYNAMICS

Faculty of Mechanical Engineering, UiTM*MEC 451 THERMODYNAMICS

Faculty of Mechanical Engineering, UiTM*MEC 451 THERMODYNAMICSCarnot Cycle

ProcessDescription1-2Reversible isothermal heat addition at high temperature2-3Reversible adiabatic expansion from high temperature to low temperature3-4Reversible isothermal heat rejection at low temperature4-1Reversible adiabatic compression from low temperature to high temperature

Faculty of Mechanical Engineering, UiTM*MEC 451 THERMODYNAMICSExecution of Carnot cycle in a piston cylinder device

Faculty of Mechanical Engineering, UiTM*MEC 451 THERMODYNAMICS

Faculty of Mechanical Engineering, UiTM*MEC 451 THERMODYNAMICSThe thermal efficiencies of actual and reversible heat engines operating between the same temperature limits compare as followsThe coefficients of performance of actual and reversible refrigerators operating between the same temperature limits compare as follows

Faculty of Mechanical Engineering, UiTM*MEC 451 THERMODYNAMICSExample 4.1A steam power plant produces 50 MW of net work while burning fuel to produce 150 MW of heat energy at the high temperature. Determine the cycle thermal efficiency and the heat rejected by the cycle to the surroundings.Solution:

Faculty of Mechanical Engineering, UiTM*MEC 451 THERMODYNAMICSA Carnot heat engine receives 500 kJ of heat per cycle from a high-temperature heat reservoir at 652C and rejects heat to a low-temperature heat reservoir at 30C. Determine :(a) The thermal efficiency of this Carnot engine(b) The amount of heat rejected to the low-temperature heat reservoirExample 4.2Solution:

Faculty of Mechanical Engineering, UiTM*MEC 451 THERMODYNAMICSAn inventor claims to have developed a refrigerator that maintains the refrigerated space at 2C while operating in a room where the temperature is 25C and has a COP of 13.5. Is there any truth to his claim?Example 4.3Solution:- this claim is also false!

Faculty of Mechanical Engineering, UiTM*MEC 451 THERMODYNAMICSSupplementary Problem 4.1A 600 MW steam power plant, which is cooled by a river, has a thermal efficiency of 40 percent. Determine the rate of heat transfer to the river water. Will the actual heat transfer rate be higher or lower than this value? Why? [900 MW]A steam power plant receives heat from a furnace at a rate of 280 GJ/h. Heat losses to the surrounding air from the steam as it passes through the pipes and other components are estimated to be about 8 GJ/h. If the waste heat is transferred to the cooling water at a rate of 145 GJ/h, determine (a) net power output and (b) the thermal efficiency of this power plant. [ 35.3 MW, 45.4% ]

An air conditioner removes heat steadily from a house at a rate of 750 kJ/min while drawing electric power at a rate of 6 kW. Determine (a) the COP of this air conditioner and (b) the rate of heat transfer to the outside air. [ 2.08, 1110 kJ/min ]

Faculty of Mechanical Engineering, UiTM*MEC 451 THERMODYNAMICSDetermine the COP of a heat pump that supplies energy to a house at a rate of 8000 kJ/h for each kW of electric power it draws. Also, determine the rate of energy absorption from the outdoor air. [ 2.22, 4400 kJ/h ]An inventor claims to have developed a heat engine that receives 700 kJ of heat from a source at 500 K and produces 300 kJ of net work while rejecting the waste heat to a sink at 290 K. Is this reasonable claim?An air-conditioning system operating on the reversed Carnot cycle is required to transfer heat from a house at a rate of 750 kJ/min to maintain its temperature at 24oC. If the outdoor air temperature is 35oC, determine the power required to operate this air-conditioning system. [ 0.463 kW ]A heat pump is used to heat a house and maintain it at 24oC. On a winter day when the outdoor air temperature is -5oC, the house is estimated to lose heat at a rate of 80,000 kJ/h. Determine the minimum power required to operate this heat pump. [ 2.18 kW ]

Faculty of Mechanical Engineering, UiTM*MEC 451 THERMODYNAMICSEntropyThe 2nd law states that process occur in a certain direction, not in any direction.It often leads to the definition of a new property called entropy, which is a quantitative measure of disorder for a system.Entropy can also be explained as a measure of the unavailability of heat to perform work in a cycle.This relates to the 2nd law since the 2nd law predicts that not all heat provided to a cycle can be transformed into an equal amount of work, some heat rejection must take place.

Faculty of Mechanical Engineering, UiTM*MEC 451 THERMODYNAMICSEntropy ChangeThe entropy change during a reversible process is defined as For a reversible, adiabatic process The reversible, adiabatic process is called an isentropic process.

Faculty of Mechanical Engineering, UiTM*MEC 451 THERMODYNAMICSEntropy Change and Isentropic ProcessesThe entropy-change and isentropic relations for a process can be summarized as follows:i. Pure substances: Any process: s = s2 s1 (kJ/kgK)Isentropic process: s2 = s1 ii. Incompressible substances (liquids and solids):Any process: s2 s1 = cav T2/T1 (kJ/kg Isentropic process: T2 = T1

Faculty of Mechanical Engineering, UiTM*MEC 451 THERMODYNAMICSiii. Ideal gases: a) constant specific heats (approximate treatment): for isentropic processfor all process

Faculty of Mechanical Engineering, UiTM*MEC 451 THERMODYNAMICSExample 4.5Steam at 1 MPa, 600oC, expands in a turbine to 0.01 MPa. If the process is isentropic, find the final temperature, the final enthalpy of the steam, and the turbine work.Solution:

Faculty of Mechanical Engineering, UiTM*MEC 451 THERMODYNAMICSSince that the process is isentropic, s2=s1Work of turbine

Faculty of Mechanical Engineering, UiTM*MEC 451 THERMODYNAMICSIsentropic Efficiency for Turbine

Faculty of Mechanical Engineering, UiTM*MEC 451 THERMODYNAMICSIsentropic Efficiency for Compressor

Faculty of Mechanical Engineering, UiTM*MEC 451 THERMODYNAMICSExample 4.6Steam at 1 MPa, 600C, expands in a turbine to 0.01 MPa. The isentropic work of the turbine is 1152.2 kJ/kg. If the isentropic efficiency of the turbine is 90 percent, calculate the actual work. Find the actual turbine exit temperature or quality of the steam.Solution:Theoretically:

Faculty of Mechanical Engineering, UiTM*MEC 451 THERMODYNAMICSObtain h2a from Wa

Faculty of Mechanical Engineering, UiTM*MEC 451 THERMODYNAMICSExample 4.7Air enters a compressor and is compressed adiabatically from 0.1 MPa, 27C, to a final state of 0.5 MPa. Find the work done on the air for a compressor isentropic efficiency of 80 percent.Solution:From energy balanceFor isentropic process of IGLThen

Faculty of Mechanical Engineering, UiTM*MEC 451 THERMODYNAMICSSupplementary Problems 4.2The radiator of a steam heating system has a volume of 20 L and is filled with the superheated water vapor at 200 kPa and 150oC. At this moment both inlet and exit valves to the radiator are closed. After a while the temperature of the steam drops to 40oC as a result of heat transfer to the room air. Determine the entropy change of the steam during this process. [ -0.132 kJ/.K ]A heavily insulated piston-cylinder device contains 0.05 m3 of steam at 300 kPa and 150oC. Steam is now compressed in a reversible manner to a pressure of 1 MPa. Determine the work done on the steam during this process. [ 16 kJ ]A piston cylinder device contains 1.2 kg of nitrogen gas at 120 kPa and 27oC. The gas is now compressed slowly in a polytropic process during which PV1.3=constant. The process ends when the volume is reduced by one-half. Determine the entropy change of nitrogen during this process. [ -0.0617 kJ/kg.K ]

Faculty of Mechanical Engineering, UiTM*MEC 451 THERMODYNAMICSSteam enters an adiabatic turbine at 8 MPa and 500oC with a mass flow rate of 3 kg/s and leaves at 30 kPa. The isentropic efficiency of the turbine is 0.90. Neglecting the kinetic energy of the steam, determine (a) the temperature at the turbine exit and (b) the power output of the turbine. [ 69.09oC,3054 kW ]Refrigerant-R134a enters an adiabatic compressor as saturated vapor at 120 kPa at a rate of 0.3 m3/min and exits at 1 MPa pressure. If the isentropic efficiency of the compressor is 80 percent, determine (a) the temperature of the refrigerant at the exit of the compressor and (b) the power input, in kW. Also, show the process on a T-s diagram with respect to the saturation lines. [ 58.9oC,1.70 kW ]

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