Chapter 4 Interpreting Histograms
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Chapter 4Interpreting Histograms
• Grouped Data are data presented in the form of a histogram, a frequency curve, an interval tally, or a similar display.
• An interval tally is a list of intervals and their frequency of scores.
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use class midpoint of classes for variable x
Mean from a Frequency Table
•m = class midpoint
• f = frequency
•N = total number
Estimated value of ScoresofNumberTotal
TotalScore
N
fmμ
k
iii
1
3
Standard Deviation from a Frequency Table
Estimated value of N
k
1i
2)(
ii mf
•m = class midpoint
•f = frequency
•N = total number=average
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Interval Frequency[32, 36) 3[28,32) 6[24,28) 12[20,24) 10 [16,20) 8[12,16) 2
ACT ScoresFind the average mean and standard deviation
Midpoint343026221814
Product10218031222014428
sum = 41 sum = 986
average mean is 986/41 = 24.04
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Midpoint343026221814
Interval Frequency[32, 36) 3[28,32) 6[24,28) 12[20,24) 10 [16,20) 8[12,16) 2
(mi - µ)9.965.961.96-2.04-6.04
-10.04
(mi - µ)2
99.2035.523.844.16
36.48100.8
fi(mi - µ)2
297.6213.1346.09941.616291.85201.16
sum = 1091.9
N
k
1i
2)(
ii mf
16.563.2690.1091
41
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Weighted Mean
x =w
(w • x)
A weighted mean of a group of scores is a mean computed in such a way that the frequency, or relative importance, of each score is taken into consideration
Used when the data values are assigned different weights, such as grades received and the computation of a GPA.
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Class Credit Grade
Math 4 B+
History 3 B
Physics 4 C
English 5 B-
Find the Grade Point Average
(4)(3.3)+3(3.0)+4(2.0)+5(2.6)
= 43.2
43.2/16 = 2.7
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Class Credit Grade
Starbursts 2 A
History 4 B+
Physics 3 A
Dieting 2 D-
Find Liz’s Grade Point Average
(2)(4.0)+4(3.33)+3(4.0)+2(.67) = 34.67
34.66/11 = 3.15
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x - s x x + s
68% within1 standard deviation
34% 34%
The Empirical Rule(applies to bell-shaped distributions)
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x - 2s x - s x x + 2sx + s
68% within1 standard deviation
34% 34%
95% within 2 standard deviations
The Empirical Rule(applies to bell-shaped distributions)
13.5% 13.5%
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x - 3s x - 2s x - s x x + 2s x + 3sx + s
68% within1 standard deviation
34% 34%
95% within 2 standard deviations
99.7% of data are within 3 standard deviations of the mean
The Empirical Rule(applies to bell-shaped distributions)
0.1% 0.1%2.4% 2.4%
13.5% 13.5%
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x
The Empirical Rule(applies to bell-shaped distributions)
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70 80 90 100 120 130110
68% within1 standard deviation
34% 34%
95% within 2 standard deviations
99.7% of data are within 3 standard deviations of the mean
0.1% 0.1%2.4% 2.4%
13.5% 13.5%
IQ Scores have an average of 100 with a standard deviation of 10
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Chebyshev’s Theorem applies to distributions of any shape.
the proportion (or fraction) of any set of data lying within K standard deviations of the mean is always at least 1 - 1/K2 , where K is any positive number greater than 1.
at least 3/4 (75%) of all values lie within 2 standard deviations of the mean.
at least 8/9 (89%) of all values lie within 3 standard deviations of the mean.
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Interval Frequency[32, 36) 3[28,32) 6[24,28) 12[20,24) 10 [16,20) 8[12,16) 2
ACT Scores
Midpoint343026221814
Product10218031222014428
average mean is 986/41 = 24.04 = 5.16
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What interval, centered around the mean in whichapproximately
a. 68% of the ACT scores?b. 95% of the ACT scores?c. 99% of the ACT scores?
x
2x
3x
a.
b.
c.
24.04 5.16
24.04 2(5.16)
24.04 3(5.16)
[18.9,29.2]
[13.72,34.36]
[8.58,39.44]
[8.58,36] Round to 36
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Using Chebyshev’s Theorem, what interval containsa. 3/4 of the ACT scores?b. 8/9 of the ACT scores?c. 15/16 of the ACT scores?
2x
3x
a.
b.
24.04 2(5.16)
24.04 3(5.16)
[13.74,34.12]
[8.58,36]
c. 4x 24.04 4(5.16) [3.12,36]
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Estimating the mode
Wba
aL
L lower limit of the modal interval W is the modal interval widtha and b are the differences in frequencies
ab
wL
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Estimating the median
Wf
F2N
L
L lower limit of the median interval W is the median interval widthN is the total number of scoresF is the sum of the frequencies up to but not including the median intervalf is the frequency of the median interval
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Wf
F2N
L
2 4 6 8 10
5
9
78
4
Find the estimated mode and median
Wba
aL
2
24
43
= 4.333
27
1233
5
4
= 5.714
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0 2 4 6 8 10
6
11
89
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Find the estimated mean, standard deviation,mode and median. Find an interval that would contain 95% of the data.
39
59978511361 x
795.4x
554.2
]903.9,313.[)554.2(2795.42 x
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Wf
F2N
L
0 2 4 6 8 10
6
11
89
5
Find the estimated mean, standard deviation,mode and median. Find an interval that would contain 95% of the data.
Wba
aL
2
35
52
= 3.25
28
12
39
4
7
= 4.625
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Control Charts
A control chart is a graph that can be used to indicate how a series of new scores compare witha historical based mean and standard deviation
mean
mean + 1 standard deviation
mean - 1 standard deviation