Chapter 2.a( Introduction)
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Transcript of Chapter 2.a( Introduction)
8/19/2019 Chapter 2.a( Introduction)
http://slidepdf.com/reader/full/chapter-2a-introduction 1/11
CHAPTER I
INTRODUCTION TO
STATICS
STATICS
8/19/2019 Chapter 2.a( Introduction)
http://slidepdf.com/reader/full/chapter-2a-introduction 2/11
Basic Unit
Length(m) Mass(kg) Time(s) Force(N)
STATICS
8/19/2019 Chapter 2.a( Introduction)
http://slidepdf.com/reader/full/chapter-2a-introduction 4/11
A particle originally at rest or moving in a
straight line with constant velocity will remainin this state provided the particulars not
subjected to an unbalanced force.
VF2F1
F3
8/19/2019 Chapter 2.a( Introduction)
http://slidepdf.com/reader/full/chapter-2a-introduction 5/11
A particle acted upon by an unbalanced
force. F experiences an acceleration a
that has the same direction as the force
and a magnitude that is directly
proportional to the force
F=ma
aF
8/19/2019 Chapter 2.a( Introduction)
http://slidepdf.com/reader/full/chapter-2a-introduction 6/11
The mutual forces of action and reaction on
between two particles are equal, oppositeand collinear
a
F F
b
8/19/2019 Chapter 2.a( Introduction)
http://slidepdf.com/reader/full/chapter-2a-introduction 7/11
Exponential
Form
Prefix SI Symbol
M!ti"!e
1 ### ### ### 1#$ %iga %1 ### ### 1#& Mega M
1 ### 1#3 'i!o k
SbM!ti"!e
###1 1#3 Mi!!i m
#### ##1 1#& Micro μ
#### ### ##1 1#$ nano n
8/19/2019 Chapter 2.a( Introduction)
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3 9
6 2
6 2
3 3
2
(50 mN) (6GN) [50(10 ) N][6(10 )N]
300(10 ) N
1kN 1kN300(10 ) N
10 N 10 N
300kN
−=
=
= ÷ ÷
=
8/19/2019 Chapter 2.a( Introduction)
http://slidepdf.com/reader/full/chapter-2a-introduction 9/11
2 3 6 2
3 12 2
9 2
2
(400 mm)(0.6 MN) [400(10 ) m][0.6(10 )N]
[400(10 ) m][0.36(10 )N ]
144(10 )m.N
144Gm.N
−
−
=
=
=
=
8/19/2019 Chapter 2.a( Introduction)
http://slidepdf.com/reader/full/chapter-2a-introduction 10/11
6 3
3
6
12 3
3
12 3
3
3 3
3
45(10 N)45MN /900Gg
900(10 )kg
0.05(10 ) N / kg
1kN 10.05 (10 ) N
10 N kg
0.05(10 ) kN / kg50kN /kg
=
=
= ÷
==