Refraction and Lenses. Refraction The change in direction or ‘bending’ of light.
Chapter 26. The Refraction of Light: Lenses and Optical Instruments
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Transcript of Chapter 26. The Refraction of Light: Lenses and Optical Instruments
Chapter 26. The Refraction of Light: Lenses and Optical Instruments
26.1. The Index of Refraction26.2. Snell's Law and the Refraction of Light26.5. The Dispersion of Light: Prisms and Rainbows26.3. Total Internal Reflection26.4. Polarization and the Reflection and Refraction of Light26.6. Lenses26.7. The Formation of Images by Lenses26.8. The Thin-Lens Equation and the Magnification Equation26.10. The Human Eye
26.1 The Index of Refraction
sm1000.3 8cLight travels through a vacuum at a speed
Light travels through materials at a speed less than its speedin a vacuum.
DEFINITION OF THE INDEX OF REFRACTION
The index of refraction of a material is the ratio of the speed of light in a vacuum to the speed of light in the material:
v
cn
material in thelight of Speed
in vacuumlight of Speed
26.1 The Index of Refraction
Table 26.2 I ndices of Refraction n of Crown Glass at Various Wavelengths
Approximate Color Wavelength in Vacuum (nm) Index of Refraction, n Red 660 1.520 Orange 610 1.522 Yellow 580 1.523 Green 550 1.526 Blue 470 1.531 Violet 410 1.538
Index of Refraction
The index of refraction n in the different materials is different for the same wave length of lights.
The index of refraction n in the same
materials is different for different wave length of lights.
26.2 Snell’s Law and the Refraction of Light
SNELL’S LAW OF REFRACTION
When light travels from a material withone index of refraction to a material witha different index of refraction, the angleof incidence is related to the angle ofrefraction by
2211 sinsin nn
SNELL’S LAW
If n1>n2, then 1<2
If n1<n2, then 1>2
26.2 Snell’s Law and the Refraction of Light
Example 1 Determining the Angle of Refraction
A light ray strikes an air/water surface at anangle of 46 degrees with respect to thenormal. Find the angle of refraction whenthe direction of the ray is (a) from air towater and (b) from water to air.
26.2 Snell’s Law and the Refraction of Light
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33.1
46sin00.1sinsin
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n (a)
(b)
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n
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Check Your Understanding 1 The drawing shows three layers of liquids, A, B, and C, each with a different index of refraction. Light begins in liquid A, passes into B, and eventually into C, as the ray of light in the drawing shows. The dashed lines denote the normals to the interfaces between the layers. Which liquid has the smallest index of refraction?
26.2 Snell’s Law and the Refraction of Light
APPARENT DEPTH
Example 2 Finding a Sunken Chest
The searchlight on a yacht is being used to illuminate a sunkenchest. At what angle of incidence should the light be aimed?
26.2 Snell’s Law and the Refraction of Light
69.0
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31sin33.1sinsin
1
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n
n
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313.30.2tan 12
26.2 Snell’s Law and the Refraction of Light
1
2
n
ndd
Apparent depth,observer directlyabove object
26.2 Snell’s Law and the Refraction of Light
Conceptual Example 4 On the Inside Looking Out
A swimmer is under water and looking up at the surface. Someoneholds a coin in the air, directly above the swimmer’s eyes. To theswimmer, the coin appears to be at a certain height above the water. Is the apparent height of the coin greater, less than, or the same as its actual height?
26.2 Snell’s Law and the Refraction of Light
THE DISPLACEMENT OF LIGHT BY A SLAB OF MATERIAL
26.3 Total Internal Reflection
Total Internal Reflection
All the incident light is reflected back into the medium from which it came, a phenomenon called total internal reflection.
26.3 Total Internal Reflection
When light passes from a medium of larger refractive index into oneof smaller refractive index, the refracted ray bends away from the normal.
Critical angle21
1
2 sin nnn
nc
Conditions of total internal reflection:•Light from a medium of larger refractive index into one of smaller refractive index.•Incident angle larger than critical angle
26.3 Total Internal Reflection
Example 5 Total Internal Reflection
A beam of light is propagating through diamond and strikes the diamond-airinterface at an angle of incidence of 28 degrees. (a) Will part of the beamenter the air or will there be total internal reflection? (b) Repeat part (a) assuming that the diamond is surrounded by water. n=2.42 for diamond, n=1.33 for water
26.3 Total Internal Reflection
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00.1sinsin 1
1
21
n
nc(a)
(b) 3.3342.2
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1
21
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26.3 Total Internal Reflection
Conceptual Example 6 The Sparkle of a Diamond
The diamond is famous for its sparkle because the light coming fromit glitters as the diamond is moved about. Why does a diamond exhibit such brilliance? Why does it lose much of its brilliance whenplaced under water?
26.3 Total Internal Reflection
26.3 Total Internal Reflection
26.4 Polarization and the Reflection and Refraction of Light
1
2tann
nB Brewster’s law
For incident angles other than 0°, unpolarized light becomes partially polarized in reflecting from a nonmetallic surface.
• There is one special angle of incidence,
called Brewster angle, at which the reflected light is completely polarized parallel to the surface, the refracted ray being only partially polarized.
9
A person sitting at the beach is wearing a pair of Polaroid sunglasses and notices little discomfort due to the glare from the water on a bright sunny day. When she lies on her side, however, she notices that the glare increases. Why?
26.5 The Dispersion of Light: Prisms and Rainbows
The net effect of a prism is to change the direction of a light ray.
Light rays corresponding to different colors bend by different amounts.
26.5 The Dispersion of Light: Prisms and Rainbows
26.5 The Dispersion of Light: Prisms and Rainbows
Conceptual Example 7 The Refraction of Light Depends on TwoRefractive Indices
It is possible for a prism to bend light upward,downward, or not at all. How can the situationsdepicted in the figure arise?
26.5 The Dispersion of Light: Prisms and Rainbows
26.6 Lenses
Lenses refract light in such a way that an image of the light source isformed.
With a converging lens, paraxial rays that are parallel to the principalaxis converge to the focal point.
26.6 Lenses
With a diverging lens, paraxial rays that are parallel to the principalaxis appear to originate from the focal point.
26.6 Lenses
26.7 The Formation of Images by Lenses
RAY DIAGRAMS
26.7 The Formation of Images by Lenses
IMAGE FORMATION BY A CONVERGING LENS
In this example, when the object is placed further thantwice the focal length from the lens, the real image is inverted and smaller than the object.
26.7 The Formation of Images by Lenses
When the object is placed between F and 2F, the real image is inverted and larger than the object.
26.7 The Formation of Images by Lenses
When the object is placed between F and the lens, the virtual image is upright and larger than the object.
26.7 The Formation of Images by Lenses
IMAGE FORMATION BY A DIVERGING LENS
A diverging lens always forms an upright, virtual, diminished image.
26.8 The Thin-Lens Equation and the Magnification Equation
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26.8 The Thin-Lens Equation and the Magnification Equation
Summary of Sign Conventions for Lenses
lens. converging afor is f
lens. diverging afor is f
lens. theofleft the toisobject theif is od
lens. theofright the toisobject theif is od
di is + for an image (real) formed to the right of the lens.
di is – for an image (virtual) formed to the left of the lens.
m is + for an image that is upright with respect to the object.
m is – for an image that is inverted with respect to the object.
26.8 The Thin-Lens Equation and the Magnification Equation
Example 9 The Real Image Formed by a Camera Lens
A 1.70-m tall person is standing 2.50 m in front of a camera. Thecamera uses a converging lens whose focal length is 0.0500 m. (a)Find the image distance and determine whether the image isreal or virtual. (b) Find the magnification and height of the imageon the film.
1m 6.19m 50.2
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m 0500.0
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(a)
m 0510.0id real image
(b) 0204.0m 50.2
m 0510.0
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Example 9 The Virtual I mage Formed by a Diverging Lens An object is placed 7.10 cm to the left of a diverging lens whose focal length is f=–5.08 cm (a diverging lens has a negative focal length). (a) Find the image distance and determine whether the image is real or virtual. (b) Obtain the magnification.
26.9 Lenses in Combination
The image produced by one lens serves asthe object for the nextlens.
26.10 The Human Eye
ANATOMY
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If we read for a long time, our eyes become “tired.” When this happens, it helps to stop reading and look at a distant object. From the point of view of the ciliary muscle, why does this refresh the eyes?
26.10 The Human Eye
OPTICS
The lens only contributes about 20-25% of the refraction, but its functionis important.
26.10 The Human Eye
NEARSIGNTEDNESS
The lens creates an image of the distance object at the far pointof the nearsighted eye.
26.10 The Human Eye
Example 12 Eyeglasses for the Nearsighted Person
A nearsighted person has a far point located only 521 cm from theeye. Assuming that eyeglasses are to be worn 2 cm in front of the eye, find the focal length needed for the diverging lens of the glassesso the person can see distant objects.
26.10 The Human Eye
cm 519
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io ddf
cm 519f
26.10 The Human Eye
FARSIGNTEDNESS
The lens creates an image of the close object at the near pointof the farsighted eye.
26.10 The Human Eye
THE REFRACTIVE POWER OF A LENS – THE DIOPTER
metersin
1diopters)(in power Refractive
f
Optometrists who prescribe correctional lenses and the opticianswho make the lenses do not specify the focal length. Insteadthey use the concept of refractive power.
26.11 Angular Magnification and the Magnifying Glass
The size of the image on the retina determines how largean object appears to be.
26.11 Angular Magnification and the Magnifying Glass
o
o
d
h sizeAngular radiansin
26.11 Angular Magnification and the Magnifying Glass
Example 14 A Penny and the Moon
Compare the angular size of a penny held at arms length with that ofthe moon.
rad 027.0cm 71
cm 9.1
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d
hPenny
Moon rad 0090.0m 103.9
m 105.3
8
6
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26.11 Angular Magnification and the Magnifying Glass
Angular magnification
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Angular magnificationof a magnifying glass
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26.12 The Compound Microscope
To increase the angular magnification beyond that possible with a magnifyingglass, an additional converging lenscan be included to “premagnify” the object.
Angular magnification ofa compound microscope
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ff
NfLM
26.13 The Telescope
Angular magnification ofan astronomical telescope
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f
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26.14 Lens Aberrations
In a converging lens, sphericalaberration prevents light raysparallel to the principal axis fromconverging at a single point.
Spherical aberration can be reducedby using a variable-aperture diaphragm.
26.14 Lens Aberrations
Chromatic aberration arises when different colors are focused atdifferent points along the principal axis.
Conceptual Questions
2
Two slabs with parallel faces are made from different types of glass. A ray of light travels through air and enters each slab at the same angle of incidence, as the drawing shows. Which slab has the greater index of refraction? Why?
4
Two identical containers, one filled with water (n= 1.33) and the other filled with ethyl alcohol (n= 1.36), are viewed from directly above. Which container (if either) appears to have a greater depth of fluid? Why?
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A man is fishing from a dock. (a) If he is using a bow and arrow, should he aim above the fish, at the fish, or below the fish, to strike it? (b) How would he aim if he were using a laser gun? Give your reasoning.
9
A person sitting at the beach is wearing a pair of Polaroid sunglasses and notices little discomfort due to the glare from the water on a bright sunny day. When she lies on her side, however, she notices that the glare increases. Why?
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You are sitting by the shore of a lake on a sunny and windless day. Your Polaroid sunglasses are not equally effective at all times of the day in reducing the glare of the sunlight reflected from the lake. Account for this observation.
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A beam of blue light is propagating in glass. When the light reaches the boundary between the glass and the surrounding air, the beam is totally reflected back into the glass. However, red light with the same angle of incidence is not totally reflected, and some of the light is refracted into the air. Why do these two colors behave differently?
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Review Conceptual Example 7 as an aid in answering this question. A converging lens is made from glass whose index of refraction is n. The lens is surrounded by a fluid whose index of refraction is also n. Can this lens still form an image, either real or virtual, of an object? Why?