Chapter 22 Gauss’ Law. Mathematics Reminder Math: Area Vector.
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Transcript of Chapter 22 Gauss’ Law. Mathematics Reminder Math: Area Vector.
![Page 1: Chapter 22 Gauss’ Law. Mathematics Reminder Math: Area Vector.](https://reader035.fdocuments.us/reader035/viewer/2022081802/56649ef45503460f94c070e0/html5/thumbnails/1.jpg)
Chapter 22Gauss’ Law
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Mathematics Reminder
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Math: Area Vector
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Gauss’ Law
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Why it makes senseAll capture the same number of field lines.
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Flux by Integration
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Relates the outside to the inside
Flux through the area of the Gaussian surface Charge inside the
Gaussian surface
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A. greater. B. the same.
C. less, but not zero. D. zero.
E. not enough information given to decide
+q
Gaussian surface #1
Gaussian surface #2
A spherical Gaussian surface (#1) encloses and is centered on a point charge +q. A second spherical Gaussian surface (#2) of the same size also encloses the charge but is not centered on it.
Compared to the electric flux through surface #1, the flux through surface #2 is
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A. surface A B. surface B
C. surface C D. surface D
E. both surface C and surface D
Two point charges, +q (in red) and –q (in blue), are arranged as shown.
Through which closed surface(s) is the net electric flux equal to zero?
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Area vector of a cube
Convention: Area vector of a close surface points outward.
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Sign of Flux• Positive when E field is going out• Negative when E field is going in
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Sign of Flux (Example)
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Example (constant E)
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Φ is difficult to find in general … so we need to be smart.
+
E here is different than E there.
You are allowed to change the shape of the Gaussian surface to make the surface integral easy.
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Spherical Gaussian Surface
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Simplify the integral
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xr
Gaussian surface
q
Outside Uniform Sphere of Charge
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What to write in the exam
In the exam, just a few words of explanation is enough in simplifying the flux integral:
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Must include diagrams
When answering questions on Gauss’ law, you MUST include a diagram to indicate the Gaussian surface you picked.Without defining the Gaussian surface with the diagram, the flux cannot be defined, and your integral will have no meaning. You will lose half your points without a diagram.
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Linear fly density
L=4m
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Linear charge density, λ
+++++++++++++++++++++++++++++++++++++
L=4m
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Surface charge density σ
++++++
++++++++++++++++++
++++++
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Volume charge density ρ
R
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Charge Density Summary
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A Line of Charge
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Simplify the integral
S1
S2
S3
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Simplify the integral
S1
S2
S3
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An Plane Sheet of Charge
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σ is the charge per area
Gaussian surface(cylinder, pillbox)
xr
area A
A Plane Sheet of Charge
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Two Parallel Plates
E = σ/ ε0
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Derivation with Gauss Law++++++++++++++++
E
No E inside a conductor
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A Solid Conducting Sphere
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Useful fact
E field is always zero inside a conductor at equilibrium (no movement of charges).
Since F=qE, if E is non-zero, the electric force will push the charges around. Therefore the only way equilibrium can be established is if F=0, which implies E=0.
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An Uniformly Charged Sphere
R
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Outside (r > R)
R
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Inside (r < R)
R
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R