Chapter 2: Transformations Section 2.6: Perimeters and Areas of Similar Figures.

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Chapter 2: Transformation s Section 2.6: Perimeters and Areas of Similar Figures

Transcript of Chapter 2: Transformations Section 2.6: Perimeters and Areas of Similar Figures.

Page 1: Chapter 2: Transformations Section 2.6: Perimeters and Areas of Similar Figures.

Chapter 2: TransformationsSection 2.6: Perimeters and Areas of Similar Figures

Page 2: Chapter 2: Transformations Section 2.6: Perimeters and Areas of Similar Figures.

Quote of the Day• “Everybody’s a genius, it’s just a matter of whether you love

yourself enough to admit it to yourself and fly with whatever your area of genius is.”• Orlando Mcguire

Page 3: Chapter 2: Transformations Section 2.6: Perimeters and Areas of Similar Figures.

Do Now• On separate sheet of paper.• Answers:

• 1. Perimeter: 32 in. Area: 63 inches squared• 2. Perimeter: 60 cm. Area: 225 cm squared• 3. Perimeter: 12 cm. Area: 6 cm squared• 4. Perimeter: 48 in. Area: 130 inches squared

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Today’s Objectives• Students will find ratios of perimeters and areas.• Students will use proportions to find perimeters and areas.

Page 5: Chapter 2: Transformations Section 2.6: Perimeters and Areas of Similar Figures.

Key Idea• Perimeters of similar figures:• When two figures are similar, the ratio of their perimeters is

equal to the ratio of their corresponding side lengths.

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Example 1

Page 7: Chapter 2: Transformations Section 2.6: Perimeters and Areas of Similar Figures.

Key Idea• Areas of similar figures:• When two figures are similar, the ratio of their areas is equal to

the square of the ratio of their corresponding side lengths.

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Example 2

Page 9: Chapter 2: Transformations Section 2.6: Perimeters and Areas of Similar Figures.

Example 3