Chapter-2

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Chapter-2 Motion Along a Straight Line

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Chapter-2. Motion Along a Straight Line. Ch 2-1 Motion Along a Straight Line. Motion of an object along a straight line Object is point mass Motion along a horizontal or vertical or inclined (line with finite slope) line Motion : Change in position No change in position, body at rest. - PowerPoint PPT Presentation

Transcript of Chapter-2

Page 1: Chapter-2

Chapter-2

Motion Along a Straight Line

Page 2: Chapter-2

Ch 2-1 Motion Along a Straight Line

Motion of an object along a straight line

Object is point mass Motion along a horizontal or vertical

or inclined (line with finite slope) line Motion: Change in position No change in position, body at rest

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Axis are used to define position of an object

Position of an object defined with respect to origin of an axis

Position x of an object is its distance from the origin at any time t

Displacement x, a vector, is change in position.

x = xf-xi

When an object changes its position, it has a velocity

Ch 2-3 Position and Displacement

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Ch 2-4 Average Velocity, Average Speed

Average Velocity vavg= x/ t

vavg = (xf-xi) /(tf-ti) Average speed Savg: a scalar

Savg = total distance/ total time Instantaneous Velocity v: v= lim (x/ t) t0 Position-time graph used to

define object position at any time t and to calculate its velocity

v is slope of the line on position-time graph

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Ch 2-6 Acceleration

When an object changes its velocity, it undergoes an acceleration

Average acceleration aavg

aavg = v/ t = (vf-vi) /(tf-ti) Instantaneous acceleration

a: a= lim (v/ t) t0 = dv/dt=d2x/dt2

Velocity-time graph used to define object velocity at any time t and calculate its acceleration

a is slope of the line on velocity-time graph

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Constant Acceleration: Variable Slope of position-

time graph Constant Slope of velocity

-time graph Zero Slope of acceleration

-time graph For constant acceleration a =aavg= (vf-vi)/(tf-ti)

vavg= (vf+vi)/2

Ch 2-7 Constant Acceleration

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Equations for Motion with Constant Acceleration

v=v0+at x-x0=v0t+(at2)/2 v2=v0

2+2a(x-x0) x-x0=t(v+v0)/2 x-x0 =vt-(at2)/2

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Ch 2-9 Free Fall Acceleration

Free fall acceleration ‘g’ due to gravity

Directed downward towards Earth’s center along negative y-axis

with a = -g = -9.8 m/s2

equations of motion with constant acceleration are valid for free fall motion

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x-x0=vt

x-x0= v dt

v dt= area between velocity curve and time axis from t0 to t

Similarly v-v0= a dt

a dt = area between acceleration curve and time axis from t0 to t

Ch 2-10 Graphical Integration in Motion Analysis