Chapter 14 Nuclear Magnetic Resonance Spectroscopy “study of interaction of light with...
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Transcript of Chapter 14 Nuclear Magnetic Resonance Spectroscopy “study of interaction of light with...
Chapter 14
Nuclear Magnetic Resonance Spectroscopy
“study of interaction of light with molecules”
14.1 Proton Magnetic Resonance Spectroscopy
Two or more E states are generated when external magnetic field is applied
radio wave absorption between these states
NMR spectroscopy
Hydrogen nucleus (1H) and the isotope of carbon (13C)
1H NMR and 13C NMR
Three types of information for H NMR spectrum
Chemical shift: the carbon to which proton is attached
Multiplicity( # of the peaks in each group): neighboring hydrogens
Integral: # of hydrogens
14.2 Theory of 1H-NMRTwo spin states are generated when external magnetic field is applied ( 546 Figure 14.3)
E (E difference between the two states) = hBo/2
h = plank constant,
= magnetogyric ratio (characteristic value for each nucleus)
Bo = external magnetic field
Typical values of E of proton (reference TMS)
External magnetic field 14,000 gauss (or 1.4-tesla)
then E =10-6 kcal/mol 60 x 106 s-1 or 60 MHz
46,700 gauss (4.67-tesla) magnet 200 MHz (in this book)
70,000 gauss 300 MHz
9.33-tesla magnetic 400 MHz (in this book)
Magnetic field , resolution of NMR to get high magnetic field superconducting maget is needed
(superconducting magnet is operated using liquid helium)
Magnetic field , $
13C, 19F, 2H and 31P have nuclear spins
NMR technique can be applied
12C and 16O do not have nuclear spins
no NMR absorption
Why? Ask god!
14.3 The Chemical Shift the field required for the hydrogen to resonance
varies slightly with the chemical environment of the hydrogen
The required field difference between the hydrogen of the sample and that of TMS (tetramethylsilane)
Chemical shift () =observed position of peak (Hz)
operating frequency of instrumentX 106
ex) 200MHz ( 46,700 gauss) 1H-NMR : aceton peak at 436 Hz
(436 x 106/200x106 =2.16 or 2.16 ppm
in 300 MHz NMR, this peak will be detected at 654 Hz
548 Figure 14.4
Factors on Chemical Shift ( )
downfield: left on an NMR spectrum deshielded
increased external field higher
upfield: right on an NMR spectrum shielded
decreased external field lower
Inductive effect
Exchangeable protons: O-H/N-H (H-bonding)
O-H: 2~5 (ppm), N-H: 1~3, CO2H: ~12 (10~15)
peak position varies
Pi Electron Effect
deshielding effect higher
Chemical equivalence
CH3CH3
HH
H
HCH3
H2C
HH
H
HCH2
CH3
HH
H
H
CH3CH3
AH
H
H
CH3CH3
HH
A
H
CH3CH3
HH
H
A
CH3CH3
HA
H
H
identical
identical
identical
A
A
Protons with chemically identical environment
Three different sets of chemically equivalent protons
Three NMR absorptions
Enantiomer: identical chemical shift
Diastereomer: different chemical shiftTwo different sets of chemically equivalent protons
two NMR absorptions
CBr
H3C
H
HC
Br
H3C
H
A CBr
H3C
A
H
CBr
H3C
H
H
enantiomers
C C
H
H
H
Cl
C C
H
A
H
ClC C
H
H
A
Cl
C C
H
H
H
Cl
diasteromers
Three different sets of chemically equivalent protons
Three NMR absorptions
CH3CCH3
O one NMR absorption peak
CH3H3C CH3-O-CH2Cl CH3C-O-CH3
O
SiCH3
H3C CH3
CH3
two NMR absorption peaks
CC
CH3
H3C
HH
HBr
five NMR absorption peak
A useful summary of the chemical shifts
Estimation of the chemical shift
approximate chemical shift of hydrogens
Empirical Correlation for predicting Chemical Shifts
Shoolery’s Rule (old text book)
Ex) To the value from Table 14.1, add
0.3 ppm if CH2
0.7 ppm if CH
OH
CH2
CH2
CH3
2-5 ppm according to concentration (actual value= 2.3 ppm)
O-CH3 = 3.3 ppm, 3.3 + 0.3 (due to CH2) = 3.6 ppm
(actual value= 3.5 ppm)
C-CH3 = 0.9 ppm, 0.9 + 0.3 ( CH2) + 0.3 (CH3) = 1.5 ppm
(actual value= 1.5 ppm)
0.9 ppm (C-CH3 )
Practice
14.4 Spin Coupling (H,H Coupling)
Geminal coupling = Two-Bond Coupling
C
HHIf they are diastereotopic, then have different chemical shifts
Long-range Coupling: very small (not easily detected)
C C
H H Very thoroughly studied, both experimentally and theoretically
Vicinal coupling = Three-Bond Coupling
spin coupling: change in the local magnetic field
by nearby H atoms having different
multiplicity: Bo BH; 559 & Figure 14.6~7
splitting pattern: Jax in 0~20 Hz (typical 6); s (singlet), d
(doublet), t (triplet), q (quartet), m (multiplet), br (broad)
Differing spin relationships between HA and HB
NMR spectrum of this compound
The origin of spin-spin spliting in proton A’s NMR spectrum
Spin-spin splitting in ethyl iodide (CH3CH2I)
Splitting pattern of methyl hydrogens Splitting pattern of ethyl hydrogens
Spin-spin splitting rule: n+1 rule
C C ClCl
Cl H
HH
C C ClCl
Cl H
HH
Two neighboring
give triplet (three peaks)
n+1=3
One neighboring
give douplet two peaks
n+1=2
Pascal’s triangle
Peak number and area (height)
The Coupling Constant (J)
In 1H-NMR, peak area indicates the number of hydrogen for the corresponding absorption
See 559 Fig. 14.6~7
Proton is coupled to nonequivalent protons
14.5 Complex Coupling
Leaning
The downfield peak of the triplet is slightly larger than the upfield peak.
The quartet leans toward the triplet
As the difference in chemical shift becomes smaller, the leaning effect becomes larger. 562 Figure 14.8 vs 569 Figure 14.10
14.6 Chemical Exchange
H
H
H
HH
H
H
H
flip
NMR spectrum at RT one peak
NMR spectrum at low temp two peaks
No coupling in NMR spectrum of methanol (no splitting) unless the methanol is extremely pure
CH3 O H CH3 O H CH3 O H CH3 O H
H H
In general, H in oxygen or nitrogen are subject to the rapid exchange and do not couple to nearby H’s
SLOW CAMERA EFFECT
14.7 Deuterium
Solvent for NMR
no signal not to interfere the spectrum of the sample
CCl4 can be used poor solubility
Deuterated solvents (CDCl3, (CD3)2SO, C6D6) are used in NMR
Deuterium is invisible in NMR
1H-NMR measures E + small chemical shift
E (E difference between the two states) = hBo/2
(magnetogyric ratio) of the nucleus of deuterium is different from that of hydrogen it does not appear in 1H-NMR
carbocations by NMR: 565 Focus On
14.8 Interpretation of 1H-NMR Spectra
Step 1. Examine the general position of the peak.
Step 2. Examine the integral for the ratios of the different kinds of hydrogen.
Step 3. Examine the coupling pattern.
Step 4. Construct a tentative structure
Step 5. Determine whether all the information is consistent with this structure
14.9 13C-NMR Spectrum
Chemical shift range: 0~240 ppm
Broader than that of 1N-NMR
resolution is much higher
There is no, if any, 13C -13C coupling natural abundance: 13C 1.1% & 12C 98.9%
There is 13C –1H coupling, while this is removed by broad band decoupling technique
Then in 13C-NMR, all peaks are singlet
Other 13C-NMR Techniques
Off-resonance decoupling which allows hydrogens and carbons that are directly bonded to couple
CH3:quartet, CH2:triplet, CH:doublet, C:singlet
Old technique
DEPT-NMR: Three spectra are obtained: New technique
1. Broad band decoupled spectrum
2. DEPT 90o spectrum: only CH’s appear
3. DEPT 135o: CH’s and CH3’s appear as positive absorptions and CH2’s appears as negative absorptions
see next page
Chemical equivalence in 13C-NMR