Chapter 11 - Carbohydrates
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Transcript of Chapter 11 - Carbohydrates
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Chapter 11 Carbohydrate
Monosaccharides are the Simplest Carbohydrates
- Carbohydrates = carbon-based molecules rich in hydroxyl groups
o Empirical formula (CH2O)n- Simple carbohydrates = monosaccharides = aldehydes or etones that ha!e 2 or more hydroxyl groups
- "ihydroxyacetone and glyceraldehyde are constitutional isomers # same molecular formula$ atoms ordered
di%erently- Stereoisomers are isomers that di%er in spatial arrangement (" or &)
o 'ost !ertebrate monosaccharides ha!e the " conguration
o " and & isomers are determined by the conguration of the asymmetric carbon atom farther from the
aldehyde or eto groupo "ihydroxyacetone is the only monosaccharide ithout at least one asymmetric carbon
*
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- 'onosaccharides made up of more than + carbon atoms ha!e multiple asymmetric carbons$ so they can exist
as enantiomers (mirror images) and diastereomers
o ,he number of possible stereoisomers is 2n$here n the number of asymmetric carbonso .-carbon aldose ith / asymmetric carbons can exist in *. possible diastereomers
Know aldehyde sugars Glyceraldehyde, Erythrose, Threose, Ribose, ylose, !llose, Glucose, Mannose,
and Galactose"
2
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Know #eto sugars $ihydro%yacetone, Erythrulose, Ribulose, ylulose, and &ructose" 'e able to draw
Sedoheptulose
+
,hese are the structures of most of the
most important sugars0
1otice that all biological sugars are "3$
meaning the last hydroxyl before the
CH2OH at the bottom goes to the right
1otice "-glucose and "-mannose di%er
only at C-20 Sugars that are
diastereomers di%ering in conguration
at only a single asymmetric center are
called epimers"
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Many common sugars e%ist in cyclic (orms
- ,he predominant forms of ribose$ glucose$ fructose$ and many other sugars in solution (inside the cell) are not
open chains4the open chain forms of these sugars cycli5e into rings
) Similarly$ a etone can react ith an alcohol to form a hemietal
/
6hen a eto sugar cycli5es you
get a hemietal ith OH and O7
here the eto carboxyl used to
be0
Hemietals and Hemiacetals are
reducing sugars3 because they
can be easily oxidi5ed0
6hen theanomeric OH is deri!ati5ed gi!ing
O7 an O7 instead of OH and O7
8ou ha!e an cetal or a 9etal (the
hemi3 goes aay) and you also
ha!e a non-reducing sugar0
6hen an aldehyde sugar
cycli5es you get a hemiacetal
ith OH and O70
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'e able to draw all assigned sugar structures either in &ischer or *aworth pro+ections"
:
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)$)sedoheptulo(uranose - .)$)%ylopyranose
'oats and Chairs
.
,he chair form$ shon here$ is the typical conformation of the
pyranose ring0
1otice that ha!ing buly groups mounted axially (straight up or
don$ perpendicular to the plane of the ring) leads to strong
steric hindrance$ so the OH and CH2OH groups should all be
e;uatorial (sharing the plane of the ring)0
,he only aldohexose that can do that$ ha!e all buly groups
e;uatorial$ is beta-"-glucose0 nd many people thin that is
hy glucose is the default sugar3 in biology0
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Reducing Sugars
>
?or the CH
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@lycoside3 has
something attached
to the nomeric
Hydroxyl (C-* for
aldehydes$ C-2 for
etones)0 ,his
stabili5es the sugarring structure0
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Sucrose, lactose, and maltose are the common disaccharides
- "isaccharide = 2 sugars oined by an O-glycosidic bond- &actose$ the disaccharide of mil$ consists of galactose oined to glucose by a beta-*$/-glycosidic linage- &actose is hydroly5ed to these monosaccharides by lactase in human beings
&actose (and Cellobiose) ha!e a beta- *$/ linage0 &actose or mil sugar is a disaccharide of @alactose beta *$/
@lucose0
Cellobiose (not shon) is @lucose beta *$/ @lucose0
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- &actose intolerance = hypolactasia # caused by deciency of the en5yme lactase$ hich clea!es lactose into
glucose and galactose- &actose is a good energy source for microorganisms in the colon$ and they ferment it to lactic acid hile
generating methane (CH/) and hydrogen gas (H2)G the gas creates the uncomfortable feeling of gut distension
and farting- ,he lactate produced by the microorganisms is osmotically acti!e and dras ater into the intestine and
undigested lactosediarrhea
*
Here is the basic structure of@lycogen0
&ong starch lie chains of alpha-
*$/ lined glucose$ but about
e!ery *thglucose there is an
alpha *$. branch point0
So the hole molecule is
branchy3 and that maes it easier
to metaboli5e ;uicly than the
linear starch molecules
Cellulose on the left
forms straight chains
and at sandich3
structures0 ,his is part
of hy it is hard to
metaboli5e (although
microorganisms can
mae Cellulase)0
Starch and glycogen
ha!e alpha *$ / lins
hich mae arc shapes
that are easier for
en5ymes to interact
ith0
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**
,he IO blood group
antigens are simply small
oligosaccharides0
,he di%erences are minimal$
but if you ha!e ,ype blood
and you get a transfusion of,ype I blood$ the response
from your immune system
could ill you0
,ype O is the uni!ersal donor0
JBotential test material this is
importantKKKL