Chapter 10 “Chemical Quantities”

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Chapter 10 Chapter 10 “Chemical Quantities” “Chemical Quantities” You will need a calculator for this chapter!

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Chapter 10 “Chemical Quantities”. Y ou will need a calculator for this chapter!. Section 10.1 p. 287 The Mole: A M easurement of Matter. How do we measure items?. You can measure mass , volume , or count pieces We measure mass in grams We measure volume in liters - PowerPoint PPT Presentation

Transcript of Chapter 10 “Chemical Quantities”

Page 1: Chapter 10 “Chemical Quantities”

Chapter 10Chapter 10“Chemical Quantities”“Chemical Quantities”

You will need a calculator for this

chapter!

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Section 10.1 p. 287Section 10.1 p. 287The Mole: A Measurement The Mole: A Measurement

of Matterof Matter

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How do we measure items?How do we measure items?You can measure mass, volume,or count pieces

We measure mass in gramsWe measure volume in litersWe count pieces in MOLES

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Other Ways to Measure Other Ways to Measure AmountAmount

Pair: 1 pair of socks = 2 socks Dozen: 1 dozen donuts = 12 donuts Gross: 1 gross of pencils = 144

pencils (12 dozen) Ream: 1 ream of paper = 500

sheets of paperGuided Practice Problem p. 289

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Practice Problem #2 Practice Problem #2 pg. 289pg. 289

• Assume 2.0 kg of apples is 1 dozen and that each apple has 8 seeds. How many apple seeds are in 14 kg of apples? (work INDEPENDENTLY to solve)

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What is the mole?

Not this kind of mole!

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Moles (abbreviated Moles (abbreviated molmol))Derived from German word molekül (molecule)

SI measurement of an amount 1 mole = 6.02 x 1023 of representative particles, or…..

# of carbon atoms in exactly 12 g of Carbon-12 isotope

Called Avogadro’s numberAvogadro’s number

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What are Representative Particles?What are Representative Particles?

(Table 10.1 p. 290)(Table 10.1 p. 290) The smallest pieces of a

substance:1) molecular cmpd - molecule2) ionic cmpd - formula unit (made

of ions)3) element: is the

• Remember the 7 diatomic elements? (made of molecules) BrINClHOFH2

N2 O2 F2Cl2

I2Br2

atoatomm

Guided Practice Problem #3 p. 291

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Mole Video 3:49

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Quick QuizQuick Quiz• How big is a mole?• If everyone in the world got a mole of

pennies, how much $ would every person have?

• If you stacked a mole of paper how many times would it go from the Earth to the moon?

• How long would it take for every person in the world to eat through a mole of marshmellows?

6.02 x 6.02 x 10102323

1 trillion bucks1 trillion bucks$1,000,000,000,000$1,000,000,000,000

80 billion 80 billion timestimes80,000,000,00080,000,000,000

40,000,000 years w/o 40,000,000 years w/o a bathroom break!a bathroom break!

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Consider these questions:Consider these questions:• How many oxygen atoms in

the following?CaCO3

Al2(SO4)3

• How many ions in the following?CaCl2NaOHAl2(SO4)3

3 atoms of oxygen

12 (3 x 4) atoms of oxygen

3 total ions (1 Ca2+ ion and 2 Cl1- ions)

2 total ions (1 Na1+ ion and 1 OH1- ion)

5 total ions (2 Al3+ + 3 SO42- ions)

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Practice problemsPractice problems

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The Mass of a Mole of an The Mass of a Mole of an ElementElement

Atomic mass of element (mass of 1 atom) expressed in amu- atomic masses - relative masses based on mass of C-12 (12.0 amu)

- 1 amu is 1/12 mass of C-12 atom

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Molar Mass…. Molar Mass…. = mass of 1 mol of element in in

gramsgrams (periodic table) 12.01 grams C has same #

particles as 1.01 g H & 55.85 g Fe 12.01 g C = 1 mol C 1.01 g H = 1 mol H 55.85 g Fe = 1 mol Fe

All All contain contain 6.02 x 6.02 x 10102323 atomsatoms

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Molar Mass Practice Molar Mass Practice ProblemsProblems

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What about compounds?What about compounds? 1 mol of H2O molecules has 2

mol of H atoms & 1 mol of O atoms (think of a compound as a molar ratio)

To find mass of 1 mol of a cmpd: odetermine # moles of elements presentoMultiply # times their mass (from periodic table)oadd up for total mass

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Calculating Molar MassCalculating Molar Mass

Calculate molar mass of magnesium carbonate, MgCO3.

24.3 g + 12.0 g + 3 x (16.00 g) = 84.3 g

So, 84.3 g = molar mass for MgCO3

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Section 10.2 Section 10.2 p. 297p. 297

Mole-Mass and Mole-Mole-Mass and Mole-Volume RelationshipsVolume Relationships

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Molar MassMolar MassMolar mass - generic term for

mass of 1 mol of any substance (expressed in grams/mol)

Same as: 1) Gram Molecular Mass (for molecules)

2) Gram Formula Mass (ionic

compounds) 3) Gram Atomic Mass (for elements)

o molar mass is more broad term than these other specific masses

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ExamplesExamples Calculate the molar mass of:Na2S

N2O4

C Ca(NO3)2

C6H12O6

(NH4)3PO4

= 78.05 g/mol

= 92.02 g/mol

= 12.01 g/mol

= 164.10 g/mol

= 180.12 g/mol

= 149.12 g/mol

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Molar Mass is…Molar Mass is…# of g in 1 mol of atoms, formula units, or molecules

Make conversion factors from these- To change btwn g of cmpd and mol of cmpd

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Using the Mole RoadmapUsing the Mole RoadmapHow many moles is 5.69 g of NaOH?0.142 mol NaOH

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The Mole-Volume RelationshipThe Mole-Volume Relationshipgases

- hard to determine masshow many moles of gas?2 things affect gas V:

a) Temp & b) Pressurecompare all gases at = temp & pressure

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Standard Temperature and PressureStandard Temperature and Pressure 0ºC & 1 atm pressure

- abbreviated “STP” At STP, 1 mol of anyany gas has V of 22.4 L- Called molar volume

1 mol of any gas at STP = 22.4 L

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Practice ExamplesPractice Examples

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Mole DayCelebrated on October 23rd from 6:02 am until 6:02 pm(6:02 on 10-23)

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Density of a gasDensity of a gas D = m / V (density = mass/volume)- for gas units are: g / L

find density of a gas at STP if formula known

You need: 1) mass and 2) volume Assume 1 mol, so mass is molar mass (from periodic table)

At STP, V = 22.4 L

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Practice Examples Practice Examples (D=m/V)(D=m/V)

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Another way:Another way: If given densityIf given density, find molar mass

of gas Assume 1 mol at STP, so V = 22.4 L

modify: D = m/V to show: “m” will be mass of 1 mol, given

22.4 L What is molar mass of a gas with

density of 1.964 g/L? How about a density of 2.86 g/L?

= 44.0 g/mol

64.0 g/mol

m = D x V

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SummarySummary• all equal:all equal:

a) 1 moleb) molar mass (in grams/mol)c) 6.02 x 1023 representative particles (atoms, molecules, or formula units)

d) 22.4 L of gas at STPmake conversion factors from these 4 values (p.303)

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Notice all conversions Notice all conversions must go through the must go through the

MOLE!MOLE!Copy this conversion Copy this conversion map into your notes!map into your notes!

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Section 10.3Section 10.3p. 305p. 305

Percent Composition Percent Composition and Chemical and Chemical

FormulasFormulas

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All percent problems: part whole

1)1) Find mass of each element,Find mass of each element,

2)2) Divide by total mass of cmpd; & x Divide by total mass of cmpd; & x 100100

x 100 % = percent

%mass of element = mass of element

x 100% mass of cmpd

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% composition from mass% composition from mass Calculate the percent

composition of a compound that is made of 29.0 grams of Ag with 4.30 grams of S.

29.0 g Ag33.3 g total

X 100 = 87.1 % Ag

4.30 g S33.3 g total

X 100 = 12.9 % S

Total = 100 %

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% comp from the chemical formula% comp from the chemical formula If we know formula, assume

you have 1 mole, Subscripts used to calculate

mass of each element in 1 mole of cmpd

sum of masses is molar mass

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% Composition Examples% Composition Examples

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% composition as % composition as conversion factorconversion factor

We can also use % as conversion factor conversion factor to calculate # grams of element in cmpd

Calculate % C in Calculate % C in C3H8

What is mass of C in 82.0 g sample of propane (C3H8)

67.1 g C

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% Composition% Composition4:15

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What is an Empirical Formula?What is an Empirical Formula?• Like ingredients for recipe –

double recipe, you double each ingredient, but ratioratio of ingredients stays same

• Empirical formula: lowest whole number ratio of atoms in cmpd

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Calculating EmpiricalCalculating EmpiricalFind lowest whole number ratio

C6H12O6

CH4NA formula is not just ratio of

atomsatoms, it is also ratio of moles1 moleculemolecule of CO2 = 1 atom of C atom of C and 2 atoms of O 2 atoms of O

1 mol of CO2 = 1 mol C and 2 mol O

= CH2O

= this is already the lowest ratio.

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Calculating EmpiricalCalculating Empirical get a ratio from % composition1)Assume you have a 100 g

sample- the percentagepercentage become gramsgrams (75.1%75.1% = 75.1 75.1

gramsgrams)

2) Convert gramsgrams to molesmoles. 3) Find lowest whole number ratio

by dividing each # of molesmoles by smallest value

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ExampleExampleCalculate empirical formula of cmpd composed of 38.67 % C, 16.22 % H, and 45.11 %N.

Assume 100 g sample, so 38.67 g C x 1mol C = 3.22 mole C

12.0 g C 16.22 g H x 1mol H = 16.22 mole

H 1.0 g H 45.11 g N x 1mol N = 3.22 mole

N 14.0 g N

Now divide each value by the smallest value

CH5N

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ExampleExample The ratio is 3.22 mol C = 1 mol C

3.22 mol N 1 mol N

The ratio is 16.22 mol H = 5 mol H 3.22 mol N 1 mol

N

= C1H5N1 which is = CH5N

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Practice Problem 36 p. 310Practice Problem 36 p. 310

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What is a Molecular Formula?What is a Molecular Formula?• Molecular formula: true # of atoms of

each element in formula of cmpd

• molecular cmpds only• Example: molecular formula for

benzene is C6H6 (note that everything is divisible by 6) • Therefore, empirical formula =

CH (the lowest whole number ratio)

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FormulasFormulas (continued)(continued)

ionic compoundsionic compounds ALWAYS empirical (cannot be reduced).

Examples:

NaCl MgCl2 Al2(SO4)3 K2CO3

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FormulasFormulas (continued)(continued)

Formulas for molecular compoundsmolecular compounds

MIGHT be empirical (lowest whole number ratio).

Molecular:

H2O

C6H12O6 C12H22O11

Empirical:

H2O

CH2O C12H22O11

(Correct formula)

(Lowest whole number ratio)

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Empirical to molecularEmpirical to molecularSince empirical formula is lowest ratio, the actual molecule weighs more

Molar mass

Empirical formula masswhole # to increase each coefficient in empirical formula

=

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Empirical to molecular Empirical to molecular practice problempractice problem

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Empirical and Empirical and Molecular FormulasMolecular Formulas

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