Ch18_TextbookSolutions
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Transcript of Ch18_TextbookSolutions
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18.8. Solve: (a) The average speed is
25
avg
15
1 220 m/s m/s 20.0 m/s
11 11
n
n
v n
(b) The root-mean-square speed is
2
rms avgv v
1225
2
15
1 m/s
11
n
n
n
124510
20.2 m/s11
18.9. Solve: (a) In tabular form we have
Particle vx (m/s) vy (m/s) 2xv (m/s)
2 2
yv (m/s)2 v
2 (m/s)
2 v (m/s)
1 20 30 400 900 1300 36.06
2 40 70 1600 4900 6500 80.62
3 80 10 6400 100 6500 80.62
4 60 20 3600 400 4000 63.25
5 0 50 0 2500 2500 50.00
6 40 20 1600 400 2000 44.72
Average 0 0 3800 59.20
The average velocity is avg 0 0v i j .
(b) The average speed is avg 59 m/sv .
(c) The root-mean-square speed is 2 2 2rms avg3800 m /s 62 m/sv v .
18.10. Solve: (a) The most probable speed is 4.0 m/s. (b) The average speed is
avg
2 2 m/s 4 4 m/s 3 6 m/s 1 8 m/s4.6 m/s
2 4 3 1v
(c) The root-mean-square speed is
2 2 2 2
rms
2 2 m/s 4 4 m/s 3 6 m/s 1 8 m/s4.9 m/s
2 4 3 1v
18.11. Solve: (a) The atomic mass number of argon is 40. This means the mass of an argon atom is
27 2640 u 40(1.661 10 kg) 6.64 10 kgm
The pressure of the gas is
21rms3
Np mv
V
225 3 261
32.00 10 m 6.64 10 kg 455 m/s 9.16 10
4 Pa
(b) The temperature of the gas in the container can be obtained from the ideal-gas equation in the form pV NkBT:
4
25 3 23B
9.16 10 Pa332 K
2.00 10 m 1.38 10 J/K
pVT
Nk
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18.20. Solve: The formula for the root-means-square speed as a function of temperature is
Brms T
3k Tv
m
The ratio at 20 C and at 100 C is
rms 100
rms 20
373 K1.13
293 K
v
v
18.21. Solve: Assuming ideal-gas behavior and ignoring relativistic effects, the root-mean-square speed of a molecule is
Brms
3k Tv
m
The temperature where vrms is the speed of light (c) for a hydrogen molecule
227 822
12rms
23B B
2 1.66 10 kg 3.0 10 m/s2 u7.22 10 K
3 3 3 1.38 10 J/K
cmvT
k k