Ch18_TextbookSolutions

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18.8. Solve: (a) The average speed is 25 avg 15 1 220 m/s m/s 20.0 m/s 11 11 n n v n (b) The root-mean-square speed is 2 rms avg v v 1 2 25 2 15 1 m/s 11 n n n 1 2 4510 20.2 m/s 11 18.9. Solve: (a) In tabular form we have Particle v x (m/s) v y (m/s) 2 x v (m/s) 2 2 y v (m/s) 2 v 2 (m/s) 2 v (m/s) 1 20 30 400 900 1300 36.06 2 40 70 1600 4900 6500 80.62 3 80 10 6400 100 6500 80.62 4 60 20 3600 400 4000 63.25 5 0 50 0 2500 2500 50.00 6 40 20 1600 400 2000 44.72 Average 0 0 3800 59.20 The average velocity is avg ˆ ˆ 0 0 v i j . (b) The average speed is avg 59 m/s v . (c) The root-mean-square speed is 2 2 2 rms avg 3800 m /s 62 m/s v v . 18.10. Solve: (a) The most probable speed is 4.0 m/s. (b) The average speed is avg 2 2 m/s 4 4 m/s 3 6 m/s 1 8 m/s 4.6 m/s 2 4 3 1 v (c) The root-mean-square speed is 2 2 2 2 rms 2 2 m/s 4 4 m/s 3 6 m/s 1 8 m/s 4.9 m/s 2 4 3 1 v 18.11. Solve: (a) The atomic mass number of argon is 40. This means the mass of an argon atom is 27 26 40 u 40(1.661 10 kg) 6.64 10 kg m The pressure of the gas is 2 1 rms 3 N p mv V 2 25 3 26 1 3 2.00 10 m 6.64 10 kg 455 m/s 9.16 10 4 Pa (b) The temperature of the gas in the container can be obtained from the ideal-gas equation in the form pV Nk B T: 4 25 3 23 B 9.16 10 Pa 332 K 2.00 10 m 1.38 10 J/K pV T Nk

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Transcript of Ch18_TextbookSolutions

  • 18.8. Solve: (a) The average speed is

    25

    avg

    15

    1 220 m/s m/s 20.0 m/s

    11 11

    n

    n

    v n

    (b) The root-mean-square speed is

    2

    rms avgv v

    1225

    2

    15

    1 m/s

    11

    n

    n

    n

    124510

    20.2 m/s11

    18.9. Solve: (a) In tabular form we have

    Particle vx (m/s) vy (m/s) 2xv (m/s)

    2 2

    yv (m/s)2 v

    2 (m/s)

    2 v (m/s)

    1 20 30 400 900 1300 36.06

    2 40 70 1600 4900 6500 80.62

    3 80 10 6400 100 6500 80.62

    4 60 20 3600 400 4000 63.25

    5 0 50 0 2500 2500 50.00

    6 40 20 1600 400 2000 44.72

    Average 0 0 3800 59.20

    The average velocity is avg 0 0v i j .

    (b) The average speed is avg 59 m/sv .

    (c) The root-mean-square speed is 2 2 2rms avg3800 m /s 62 m/sv v .

    18.10. Solve: (a) The most probable speed is 4.0 m/s. (b) The average speed is

    avg

    2 2 m/s 4 4 m/s 3 6 m/s 1 8 m/s4.6 m/s

    2 4 3 1v

    (c) The root-mean-square speed is

    2 2 2 2

    rms

    2 2 m/s 4 4 m/s 3 6 m/s 1 8 m/s4.9 m/s

    2 4 3 1v

    18.11. Solve: (a) The atomic mass number of argon is 40. This means the mass of an argon atom is

    27 2640 u 40(1.661 10 kg) 6.64 10 kgm

    The pressure of the gas is

    21rms3

    Np mv

    V

    225 3 261

    32.00 10 m 6.64 10 kg 455 m/s 9.16 10

    4 Pa

    (b) The temperature of the gas in the container can be obtained from the ideal-gas equation in the form pV NkBT:

    4

    25 3 23B

    9.16 10 Pa332 K

    2.00 10 m 1.38 10 J/K

    pVT

    Nk

  • 18.20. Solve: The formula for the root-means-square speed as a function of temperature is

    Brms T

    3k Tv

    m

    The ratio at 20 C and at 100 C is

    rms 100

    rms 20

    373 K1.13

    293 K

    v

    v

    18.21. Solve: Assuming ideal-gas behavior and ignoring relativistic effects, the root-mean-square speed of a molecule is

    Brms

    3k Tv

    m

    The temperature where vrms is the speed of light (c) for a hydrogen molecule

    227 822

    12rms

    23B B

    2 1.66 10 kg 3.0 10 m/s2 u7.22 10 K

    3 3 3 1.38 10 J/K

    cmvT

    k k