Ch-9 Nyquist Plot

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    Chapter 9

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    Given open loop

    frequency response ,

    determine closedloop system stability

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    .

    .

    .

    .

    P1

    P2

    P3

    P4

    s

    >

    3

    )1+s(

    1(s)H(s)G ====

    K = 8

    K

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    Polar plot

    1)s(s

    K

    (s)H(s)G ++++====

    >

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    O+

    A s = 0 to

    j polar plotC O - s = - j to 0

    complex conjugate

    of polar plot

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    +

    = +

    90:0:90-

    0where

    esOO j-

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    Polar plot&

    its conjugate

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    .A C

    >

    >O

    -

    O+

    The infinite semi circle

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    The infinite semi circle

    maps on to origin.

    For the infinitesimal

    semi circle,

    ====j

    esput

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    )1s(s1(s)H(s)G

    ++++

    ====

    )1e(e

    1

    jj ++++

    ====

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    This is a radius

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    This is a radius

    vector of infinite

    magnitude and angle

    changes from

    .90-to0to90 ++++

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    ABC

    O+

    O-

    .- 1

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    P = 0

    N = 0

    Z = 0

    Close Loop System stable

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    Root locus>

    >

    >

    >

    )1+s(s

    1(s)H(s)G ====