CH 6: Thermochemistry. 6.1 Nature of Energy Thermochemistry – study of energy changes during...
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Transcript of CH 6: Thermochemistry. 6.1 Nature of Energy Thermochemistry – study of energy changes during...
CH 6: Thermochemistry
6.1 Nature of Energy
• Thermochemistry – study of energy changes during chemical reactions– Aspects of thermochemistry are studied in
both physics and chemistry
6.1
• Energy – the capacity to do work or produce heat
• Law of conservation of energy states that energy can be converted from one form to another, but it cannot be created or destroyed.– Energy of the universe is constant!
6.1
Two forms of energy1. Potential energy – stored energy
• Energy of position or composition• Examples
2. Kinetic energy – energy of motion• Heat, light, electricity• In this chapter our focus will (eventually) be on the
heat aspects of thermochemistry.
6.1
• Consider the diagram on page 237.
• Ball A has potential energy due to its position– Some of this energy is released as heat as A
rolls down the hill– Ball A hits Ball B and work is done as B
moves up the incline• Work = force acting over a distance
6.1
• The original potential energy of A is equal to the new potential energy of B plus the heat released as friction.
• Energy can be released as:– Heat (friction)– Work (ball rolling)
6.1
• The total energy released when ball A rolls down the hill is fixed – how it’s released is not.– How much is released as heat vs. work
depends upon the conditions– Total energy released does not depend on the
pathway.
6.1
• Total energy change is a state function.– State function is a property of a system that
depends only on its current state not its past• See last paragraph on page 237
– Energy of a system is a state function.• Heat and work are not state functions – they
depend on the path taken
6.1 Chemical Energy
• When studying chemical change we consider the system and the surroundings.– System includes the reactants and products
of a given reaction– Surroundings are everything else in the
universe!• Including the water if the reaction is done in
solution
Chemical Energy
• Exothermic reactions – energy flows out of the system– Products are of lower potential energy than
the reactants• Energy is released to the surroundings• Energy lost by the system = energy gained by the
surroundings
– There’s a loss of energy by the system…. Energy of the system is negative
Chemical Energy
• Endothermic reactions – energy flows into the system– Products are of higher potential energy than
the reactants• The system absorbs energy from the surroundings• The energy gained by the system = the energy lost
by the surroundings
There’s a gain of energy by the system……. Energy of the system is positive
Chemical Energy
• Exothermic: E < 0– System _______ energy
• Endothermic: E > 0– System ________ energy
More on Energy of the System
• The energy of the system can change as a result of 2 factors:– Heat (q)– Work (w)
• Change of energy of the system = heat flowing in/out of system + work being done to/by the system
E = q + w
E of the System
• Heat (q)– When heat flows into the system, q > 0
• Endothermic
– When heat flows out of the system, q < 0• Exothermic
• Work (w)– When work is done to the system, w > 0– When work is done by the system, w < 0
More on Work
• Most common form of work done by a system is the expanding or compressing of a gas, called pressure – volume work – Work – force applied over a distance
• Moving an object a distance = work
Pressure Volume Work
• Consider a gas in a cylinder with a movable piston on top
• Work = force x distance Force = pressure x area Distance = change in height of gas in cylinder ( h)
• Work = P x A x h
Volume• Page 241
Pressure Volume Work
• Work = P x V– The sign ( +/-) on work is assigned so that:
• When the gas expands, it is doing work on the surroundings (w < 0)
• When the gas is compressed, work is done on the system (w > 0)
Pressure Volume Work
• Final version of the equation that shows both magnitude and sign on work:
W = - P x V
• When the gas expands V is positive and w < 0 (work is done by the system)
• When the gas is compressed V is negative and w > 0 (work is done on the system)
6.2 Entahalpy
• Enthalpy (H)– Enthalpy is defined as: H = E + PV
• E is the energy of the system• P is the pressure of the system• V is the volume of the system
Enthalpy
• In chemistry we consider enthalpy at constant pressure– After much math this results in the formula:
qp
H is called the heat of the reactionH is a measure of the flow of heat (q)
into/out of the system at constant pressure
Enthalpy
• When heat leaves the system H < 0– Exothermic process
• When heat enters the system H > 0– Endothermic process
Finally – the Applications!
CH4 + 2 O2 CO2 + 2 H20 + energy
H = - 890 kJ
1. Is the reaction exothermic or endothermic?
2. How much energy will be ___________ if 6.50 grams of CH4 is burned at constant pressure?
Next…..#44 on page 277
Calorimetry
• The heat changes associated with a chemical reaction are often measured in a calorimeter.
Calorimetry
• Exothermic: The heat released by the reaction is used to heat up a known quantity of water.
• More heat released the hotter the water gets
• Endothermic: The heat absorbed by the reaction comes from the water
• More heat absorbed the colder the water gets
Terms
• Terms all describe the energy needed to heat or cool some amount of a given substance– Heat Capacity (C)– Specific heat capacity– Molar heat capacity
Terms
• Heat Capacity (C) – Amount of energy needed to raise the
temperature of a substance by 10C– Units: J/0C
– Substance is an entire/specific object…e.g.
Terms
• Specific Heat Capacity– Amount of energy needed to raise the
temperature of 1 gram of a substance by 10C– Units: J/g0C
– See page 245
Terms
• Molar Heat Capacity– Amount of energy needed to raise the
temperature of 1 mole of a substance by 10C– Units: J/mol 0C
Molar heat capacity = specific heat x molar mass
J/mol 0C = J/g 0C x g/mol
Calculating Heat Capacities
Heat Capacity = heat absorbed
T
Specific Heat = energy
(mass) ( T)
Page 277: 52, 54
Determining Specific Heat of a Metal
• Lab demonstration of experiment 27:E, page 347 of the lab manual– Assume the heat capacity of the ccc is 0 J/g0C