CEWB223 - Channel Geometry
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Transcript of CEWB223 - Channel Geometry
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Dr. Mohd Hafiz bin Zawawi
Hydraulic Engineering
CEWB
CHAPTER 2
(OPEN CHANNEL PROPERTIES)
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Natural channel
All watercourses that occurs naturally, for example streams
and rivers
The Hydraulic properties are generally irregular
Not regular nor prismatic and their materials of construction
can vary widely.
The surface roughness will often change with time distance
and even elevation.
Types of open channel
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Man-made channel
Constructed in a regular cross-section shape throuhout and thusare PRISMATIC CHANNELS.
Made from concrete, steel or earth with well defined surfaceroughness.
All watercourses that are constructed by human effort, forexample :
Types of open channel
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Canal : a long and mild-sloped channel built in the ground thatmay be unlined or lined with stone masonry, concrete ,etc.
Flume : a channel of concrete, masonry, etc that is usuallysupported on or above the surface of the ground to conveywater across a depression.
Chute : a channel with steep slopes.
Culvert : a covered channel of comparatively short length
installed to drain water through highway and railroadembankments.
Types of open channel
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Canal
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Trunk Drain - Wet Period
Rigid Boundary Canal
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FLUME
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Existing Culvert
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Existing Pipe Culvert
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Existing Box Culvert
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Prismatic channel : a channel with
unvarying cross section and constant
bottom slope. Non-prismatic channel : a channel
with varying cross section and
constant bottom slope.
Channel Geometry
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CHANNEL GEOMETRY
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Rectangular
Properties and geometric elements of
typical channel cross section
Area
, A
Wetted
perimeter,
P
Hydraulic
Radius, R
Top
Width, B
Hydraulic
depth, D
by b + 2y
by /
(b+2y) b y
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Trapezoidal
Properties and geometric elements of typical
channel cross section
Area, A
Wetted
perimeter, P
Hydraulic
Radius, R
Top Width,
B
Hydraulic
depth, D
(b + ty)y
b + 2yw
w= (1+ t2)0.5 A/P b + 2ty A/B
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Triangular
Properties and geometric elements of typical
channel cross section
Area
, A
Wetted
perimeter,
P
Hydraulic
Radius, R
Top
Width, B
Hydraulic
depth, D
ty2 2yw ty / (2w) 2ty A/B
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Circular
Properties and geometric elements of typical
channel cross section
Area, A
Wetted
perimeter,
P
Hydraulic
Radius, R
Top Width,
B
Hydraulic
depth, D
( - sin ) d2/8 r
(1 - sin/)
d/4 2r sin(/2) A/B
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Semi circular
Properties and geometric elements of typical
channel cross section
Area, A
Wetted
perimeter,P HydraulicRadius, R Top Width,B Hydraulicdepth, D
r2/2 r r/2 2r r/4
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Properties and geometric elements of typical
channel cross section
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RECTANGULAR CHANNEL
TArea (A) = by
Wetted perimeter (P) = b+2y
Hydraulic Radius (R) = A/P=y2b
by
Top width (T) = b
Hydraulic Depth (D) = y
b
y
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TRAPEZOIDAL CHANNEL
Area = (b+zy)y
P =212 zyb
212
)(
zyb
yzyb
R =
T = zyb 2
D =zyb
yzyb
2
)(
y
b
z
1
T
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A concrete rectangular channel has a bottom
width of 4 meters. If the channel is on a 1%slope and is flowing 1 meter deep throughout its
length, what is the cross sectional area, wetted
perimeter and hydraulic radius?
Example 1
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Solution:
If the shape of the channel is rectangular, thedischarge computed as follows:
A = by = (4) (1) = 4m2
P = b+2y = 4 + 2 (1) = 6m
R = 4m2/ 6m = 0.67m
T
4
1
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A concrete trapezoidal channel has a bottom width of 4
meters and 45side slopes. If the channel is on a 1%
slope and is flowing 1 meter deep throughout its
length, what is the cross sectional area, wetted
perimeter and hydraulic radius?
Example 2
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Solution:If the shape of the channel is trapezoidal, the discharge
computed as follows:
A = (b+zy)y = (4+(1)(1))1 = 5.00m2
P = (b+ 2y (1+ z2)0.5)= 4 + 2 (1) (2)0.5= 6.83m
R = A/P = 5.00m2/6.83m = 0.73m
Example 2
T
4
1 11
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Water flows at a depth of 1.83 m in a trapezoidal,
concrete-lined section with a bottom width of 3 m and
side slopes of 2:1 (H:V). The slope of the channel is
0.0005 and the temperature is 20oC. Assuming uniformflow conditions, estimate the cross sectional area (A),
wetted perimeter (P) and hydraulic radius (R)?
Example 3
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Solution:Flow area, A = (b+zy)y = (3 + 2 (1.83)) x 1.83
= 12.2 m2
Wetted perimeter, P = 14.89m
Hydraulic Radius, R = A/P = 12.2/ 14.89 = 0.819 m
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Example 4
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TEXTBOOKS REFERENCES
Lariyah, M.S. & Norazli, O., Hydraulic Notes,
UNITEN, 2006
Roberson, J. A., Cassidy, J. J. & Chaudry, H.,Hydraulic Engineering, 1st S.I. Ed., John
Wiley, 1998
Chin, D., Water Resources Engineering,Prentice Hall, 2006
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Thank You