CEWB223 - Channel Geometry

30
 Dr. Mohd Hafiz bin Zawawi Hydraulic Engineering CEWB CHAPTER 2 (OPEN CHANNEL PROPERTIES)

description

lab report

Transcript of CEWB223 - Channel Geometry

  • 5/21/2018 CEWB223 - Channel Geometry

    1/30

    Dr. Mohd Hafiz bin Zawawi

    Hydraulic Engineering

    CEWB

    CHAPTER 2

    (OPEN CHANNEL PROPERTIES)

  • 5/21/2018 CEWB223 - Channel Geometry

    2/30

    Natural channel

    All watercourses that occurs naturally, for example streams

    and rivers

    The Hydraulic properties are generally irregular

    Not regular nor prismatic and their materials of construction

    can vary widely.

    The surface roughness will often change with time distance

    and even elevation.

    Types of open channel

  • 5/21/2018 CEWB223 - Channel Geometry

    3/30

    Man-made channel

    Constructed in a regular cross-section shape throuhout and thusare PRISMATIC CHANNELS.

    Made from concrete, steel or earth with well defined surfaceroughness.

    All watercourses that are constructed by human effort, forexample :

    Types of open channel

  • 5/21/2018 CEWB223 - Channel Geometry

    4/30

    Canal : a long and mild-sloped channel built in the ground thatmay be unlined or lined with stone masonry, concrete ,etc.

    Flume : a channel of concrete, masonry, etc that is usuallysupported on or above the surface of the ground to conveywater across a depression.

    Chute : a channel with steep slopes.

    Culvert : a covered channel of comparatively short length

    installed to drain water through highway and railroadembankments.

    Types of open channel

  • 5/21/2018 CEWB223 - Channel Geometry

    5/30

    Canal

  • 5/21/2018 CEWB223 - Channel Geometry

    6/30

    Trunk Drain - Wet Period

    Rigid Boundary Canal

  • 5/21/2018 CEWB223 - Channel Geometry

    7/30

    FLUME

  • 5/21/2018 CEWB223 - Channel Geometry

    8/30

    Existing Culvert

  • 5/21/2018 CEWB223 - Channel Geometry

    9/30

    Existing Pipe Culvert

  • 5/21/2018 CEWB223 - Channel Geometry

    10/30

    Existing Box Culvert

  • 5/21/2018 CEWB223 - Channel Geometry

    11/30

    Prismatic channel : a channel with

    unvarying cross section and constant

    bottom slope. Non-prismatic channel : a channel

    with varying cross section and

    constant bottom slope.

    Channel Geometry

  • 5/21/2018 CEWB223 - Channel Geometry

    12/30

    CHANNEL GEOMETRY

  • 5/21/2018 CEWB223 - Channel Geometry

    13/30

    Rectangular

    Properties and geometric elements of

    typical channel cross section

    Area

    , A

    Wetted

    perimeter,

    P

    Hydraulic

    Radius, R

    Top

    Width, B

    Hydraulic

    depth, D

    by b + 2y

    by /

    (b+2y) b y

  • 5/21/2018 CEWB223 - Channel Geometry

    14/30

    Trapezoidal

    Properties and geometric elements of typical

    channel cross section

    Area, A

    Wetted

    perimeter, P

    Hydraulic

    Radius, R

    Top Width,

    B

    Hydraulic

    depth, D

    (b + ty)y

    b + 2yw

    w= (1+ t2)0.5 A/P b + 2ty A/B

  • 5/21/2018 CEWB223 - Channel Geometry

    15/30

    Triangular

    Properties and geometric elements of typical

    channel cross section

    Area

    , A

    Wetted

    perimeter,

    P

    Hydraulic

    Radius, R

    Top

    Width, B

    Hydraulic

    depth, D

    ty2 2yw ty / (2w) 2ty A/B

  • 5/21/2018 CEWB223 - Channel Geometry

    16/30

    Circular

    Properties and geometric elements of typical

    channel cross section

    Area, A

    Wetted

    perimeter,

    P

    Hydraulic

    Radius, R

    Top Width,

    B

    Hydraulic

    depth, D

    ( - sin ) d2/8 r

    (1 - sin/)

    d/4 2r sin(/2) A/B

  • 5/21/2018 CEWB223 - Channel Geometry

    17/30

    Semi circular

    Properties and geometric elements of typical

    channel cross section

    Area, A

    Wetted

    perimeter,P HydraulicRadius, R Top Width,B Hydraulicdepth, D

    r2/2 r r/2 2r r/4

  • 5/21/2018 CEWB223 - Channel Geometry

    18/30

    Properties and geometric elements of typical

    channel cross section

  • 5/21/2018 CEWB223 - Channel Geometry

    19/30

    RECTANGULAR CHANNEL

    TArea (A) = by

    Wetted perimeter (P) = b+2y

    Hydraulic Radius (R) = A/P=y2b

    by

    Top width (T) = b

    Hydraulic Depth (D) = y

    b

    y

  • 5/21/2018 CEWB223 - Channel Geometry

    20/30

    TRAPEZOIDAL CHANNEL

    Area = (b+zy)y

    P =212 zyb

    212

    )(

    zyb

    yzyb

    R =

    T = zyb 2

    D =zyb

    yzyb

    2

    )(

    y

    b

    z

    1

    T

  • 5/21/2018 CEWB223 - Channel Geometry

    21/30

    A concrete rectangular channel has a bottom

    width of 4 meters. If the channel is on a 1%slope and is flowing 1 meter deep throughout its

    length, what is the cross sectional area, wetted

    perimeter and hydraulic radius?

    Example 1

  • 5/21/2018 CEWB223 - Channel Geometry

    22/30

    Solution:

    If the shape of the channel is rectangular, thedischarge computed as follows:

    A = by = (4) (1) = 4m2

    P = b+2y = 4 + 2 (1) = 6m

    R = 4m2/ 6m = 0.67m

    T

    4

    1

  • 5/21/2018 CEWB223 - Channel Geometry

    23/30

    A concrete trapezoidal channel has a bottom width of 4

    meters and 45side slopes. If the channel is on a 1%

    slope and is flowing 1 meter deep throughout its

    length, what is the cross sectional area, wetted

    perimeter and hydraulic radius?

    Example 2

  • 5/21/2018 CEWB223 - Channel Geometry

    24/30

    Solution:If the shape of the channel is trapezoidal, the discharge

    computed as follows:

    A = (b+zy)y = (4+(1)(1))1 = 5.00m2

    P = (b+ 2y (1+ z2)0.5)= 4 + 2 (1) (2)0.5= 6.83m

    R = A/P = 5.00m2/6.83m = 0.73m

    Example 2

    T

    4

    1 11

  • 5/21/2018 CEWB223 - Channel Geometry

    25/30

    Water flows at a depth of 1.83 m in a trapezoidal,

    concrete-lined section with a bottom width of 3 m and

    side slopes of 2:1 (H:V). The slope of the channel is

    0.0005 and the temperature is 20oC. Assuming uniformflow conditions, estimate the cross sectional area (A),

    wetted perimeter (P) and hydraulic radius (R)?

    Example 3

  • 5/21/2018 CEWB223 - Channel Geometry

    26/30

    Solution:Flow area, A = (b+zy)y = (3 + 2 (1.83)) x 1.83

    = 12.2 m2

    Wetted perimeter, P = 14.89m

    Hydraulic Radius, R = A/P = 12.2/ 14.89 = 0.819 m

  • 5/21/2018 CEWB223 - Channel Geometry

    27/30

    Example 4

  • 5/21/2018 CEWB223 - Channel Geometry

    28/30

  • 5/21/2018 CEWB223 - Channel Geometry

    29/30

    TEXTBOOKS REFERENCES

    Lariyah, M.S. & Norazli, O., Hydraulic Notes,

    UNITEN, 2006

    Roberson, J. A., Cassidy, J. J. & Chaudry, H.,Hydraulic Engineering, 1st S.I. Ed., John

    Wiley, 1998

    Chin, D., Water Resources Engineering,Prentice Hall, 2006

  • 5/21/2018 CEWB223 - Channel Geometry

    30/30

    Thank You