Centroids
description
Transcript of Centroids
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Centroids
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Centroid PrinciplesObject’s center of gravity or center of massGraphically labeled as
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Centroid Principles
Point of applied force caused by acceleration due to gravityObject is in state of equilibrium if balanced along its centroid
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Centroid Principles
What is an object’s centroid location used for in statics?
Theoretical calculations regarding the interaction of forces and members are derived from the centroid location.
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Centroid PrinciplesOne can determine a centroid location by utilizing the cross-section view of a three-dimensional object.
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Centroid LocationSymmetrical Objects
Centroid location is determined by an object’s line of symmetry.
Centroid is located on the line of symmetry.
When an object has multiple lines of symmetry, its centroid is located at the intersection of the lines of symmetry.
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H
B
Centroid LocationThe centroid of a square or rectangle is located at a distance of 1/2 its height and 1/2 its base.
2B
2H
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H
B
Centroid LocationThe centroid of a right triangle is located at a distance of 1/3 its height and 1/3 its base.
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Centroid LocationThe centroid of a ½ circle or semi-circle is located at a distance of away from the axis on its line of symmetry
43
r 4 2 .
3in
0.849 in. = 0.8in.
.849in.
43r
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Centroid Location Equations Complex Shapes
i i
i
y Ay=
A
i i
i
x Ax=
A i i
i
z Az=
A
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Centroid Location Complex Shapes
1. Divide the shape into simple shapes.
12
3
2. Determine a reference axis.
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Centroid Location Complex Shapes
Review: Calculating area of simple shapes
Side2 Width * Height
πr2 ½ (base)(height)
Area of a square = Area of a rectangle =
Area of a circle =
Area of a triangle =
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Centroid Location Complex Shapes
3. Calculate the area of each simple shape.Assume measurements have 3 digits.
2
Area of shape #1 =
Area of shape #2 =
Area of shape #3 =
3.00in. x 6.00in. = 18.0in.2
18in.2
½x3.00in.x3.00in. = 4.50in.2
4.5in.2
(3.00in.)2 = 9.00in.2
9in.2
side2
½ base x height
width x height
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Centroid Location Complex Shapes4. Determine the centroid of each simple shape.
1/3 b
1/3 h
Shape #1 Centroid Location
Shape #2 Centroid Location
Shape #3 Centroid Location
Centroid is located at the intersection of the lines of symmetry.
Centroid is located at the intersection of the lines of symmetry.
Centroid is located at the intersection of 1/3 its height and 1/3 its base.
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Centroid Location Complex Shapes5. Determine the distance from each simple shape’s
centroid to the reference axis (x and y).
4in.
4.5in.
1.5in.
3in.
1.5in.
4in.
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Centroid Location Complex Shapes6. Multiply each simple shape’s area by its distance
from centroid to reference axis.Shape Area (Ai) xi Aixi
1 x2 x3 x
Shape Area (Ai) yi Aiyi
1 18.0in.2 x2 4.50in.2 x3 9.00in.2 x
18.0in.2
4.50in.2
9.00in.2
1.50in.4.00in.4.50in.
27.0in.3
18.0in.3
40.5in.3
54.0in.3
18.0in.3
13.5in.31.50in.4.00in.3.00in.
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Centroid Location Complex Shapes
7. Sum the products of each simple shape’s area and their distances from the centroid to the reference axis.
Shape Aiyi
1 54.0in.3
2 18.0in.3
3 13.5in.3
Shape Aixi
1 27.0in.3
2 18.0in.3
3 40.5in.3
3
3
3
27.0in.
+ 18.0in.
+ 40.5in.
85.5in.3
i iA x=
3
3
3
54.0in.
+ 18.0in.
+ 13.5in.
i iA y=
85.5in.3
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Centroid Location Complex Shapes8. Sum the individual simple shape’s area to
determine total shape area.
Shape A1 18in.2
2 4.5in.2
3 9in.2
2
2
2
18.0in.
+ 4.5in.
+ 9.0in.31.5in.2
iA=
18in.2
4.5in.2
9in.2
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Centroid Location Complex Shapes9. Divide the summed product of areas and distances
by the summed object total area.
3
231.585.5
in.i .= n =
31.5in.2iA=
85.5in.3i iA x
=i iA y
= 85.5in.3
3
231.585.5
in.i .= n = 2.71in.
2.7in.
2.7i
n.2.71in.
Does this shape have any lines of symmetry?
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Alternative Solution
• The same problem solved a different way– Previous method added smaller, more manageable
areas to make a more complex part.
– Alternative Method = Subtractive Method• Uses the exact same equations• Uses nearly the exact same process
– Start with a bigger and simpler shape– Treat shapes that need to be removed as
“negative” areas
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Centroid Location – Subtractive Method
1. Determine reference axis and start with an area that is bigger than what is given
Square = Shape 1
2. Remove an area to get the centroid of the complex shape
Triangle = Shape 2
6 in.
6 in.
3 in.
3 in.
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Centroid Location Complex Shapes
3. Calculate the area of each simple shape.Assume measurements have 3 digits. Area of shape #1 =
6.0in. x 6.0in. = 36 in.2
-½x3.0in.x3.0in. = -4.5 in.2
-½ base x height
width x height
Area of shape #2 =
6 in.
6 in.
3 in.
3 in.
Note: Since the area is being removed, we are going to call it a negative area.
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Centroid Location Complex Shapes4. Determine the centroid of each simple shape.
Shape #1 Centroid LocationCentroid is located at the intersection of the lines of symmetry.
Middle of the square
Centroid is located at the intersection of 1/3 its height and 1/3 its base.
6 in.
6 in.
3 in.
3 in.
1/3 b
1/3 h
Shape #2 Centroid Location
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Centroid Location Complex Shapes5. Determine the distance from each simple shape’s
centroid to the reference axis (x and y).
6 in.
6 in.
3 in.
3 in.
5in.
3in.
3in.5in.
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Centroid Location Complex Shapes6. Multiply each simple shape’s area by its distance
from centroid to reference axis.Shape Area (Ai) xi Aixi
1 x
2 x
Shape Area (Ai) yi Aiyi
1 36in.2 x
2 -4.5in.2 x
36in.2
-4.5in.2
3.0in.
5.0in.
108in.3
-22.5in.3
108in.3
-22.5in.35.0in.3.0in.
6 in.
6 in.
3 in.
3 in.
5 in.
3 in.
3 in.
5 in.
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Centroid Location Complex Shapes
7. Sum the products of each simple shape’s area and their distances from the centroid to the reference axis.
Shape Aiyi
1 108in.3
2 22.5in.3
Shape Aixi
1 108in.3
2 22.5in.3
3
3
108.0in.
+ -22.5in.
85.5in.3
i iA x=
3
3
108.0in.
+ -22.5in.
85.5in.3
i iA y=
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Centroid Location Complex Shapes8. Sum the individual simple shape’s area to
determine total shape area.
Shape Ai
1 36 in.2
2 -4.5 in.2
2
2
36.0in.
+ -4.5in.
31.5in.2
iA=
3 in.
6 in.
6 in.
3 in.
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3 in.
3 in.
Centroid Location Complex Shapes9. Divide the summed product of areas and distances
by the summed object total area.
3
231.585.5
in.i .= n =
31.5in.2iA=
85.5in.3i iA x
=i iA y
= 85.5in.3
3
231.585.5
in.i .= n = 2.71in.
2.71in.Does this shape have any lines of symmetry?
2.7i
n.
2.7in.
6 in.
6 in.
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Centroid Location Equations Complex Shapes
i i
i
y Ay=
A
i i
i
x Ax=
A i i
i
z Az=
A
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Common Structural Elements
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Angle Shape (L-Shape)
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Channel Shape (C-Shape)
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Box Shape
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I-Beam
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Centroid of Structural Member
Cross Section View
Neutral Plane(Axes of symmetry)
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Neutral Plane
Tension
CompressionNeutral Plane(Axes of symmetry)