CE 374 K – Hydrology · Evaporation from a Water Surface • National Weather Service Class A...
Transcript of CE 374 K – Hydrology · Evaporation from a Water Surface • National Weather Service Class A...
CE 374 K – Hydrology
Evaporation
Daene C. McKinney
Evaporation
• Terminology– Evaporation: liquid water passes directly to
the vapor phase– Transpiration: liquid water passes from
liquid to vapor through plant metabolism– Sublimation: water passes directly from the
solid phase to the vapor phase
Factors Influencing Evaporation• Energy supply for vaporization (latent heat)
– Solar radiation
• Transport of vapor away from evaporative surface– Wind velocity over surface– Specific humidity gradient above surface
• Vegetated surfaces– Supply of moisture to the surface– Evapotranspiration (ET)
• Potential Evapotranspiration (PET) – moisture supply is not limited
Evaporation from a Water Surface
• National Weather Service Class A type
• Installed on a wooden platform in a grassy location
• Filled with water to within 2.5 inches of the top
• Evaporation rate is measured by manual readings or with an analog output evaporation gauge
h
Area, A
CSwρ
aρ
AEm wv ρ=&
dtdhE −=
nRsHSensible
heat to airNet radiation Vapor flow rate
Heat conductedto ground
G
Methods of Estimating Evaporation
• Energy method• Aerodynamic method• Combined method
Energy MethodContinuity of Liquid Phase
∫∫ ⋅+∫∫∫ ∀=−CS
wCV
wv ddtdm dAVρρ&
0=
dtdhAwρ=
No flow of liquid No flow of liquid water through CSwater through CS
AEm wv ρ=&
dtdhE −=
hwρ
aρ
vm&
dtdhE −=
nRsH
G
Energy Method (2)
Vapor Phase - Continuity
∫∫ ⋅=CS
avw qAE dAVρρ
0=Steady flow of airSteady flow of air
over waterover water
AEwρ=
∫∫ ⋅+∫∫∫ ∀=CS
avCV
avv qdqdtdm dAVρρ&
∫∫ ⋅=CS
avw
qA
E dAVρρ
1
∫∫ ⋅=CS
avv qm dAVρ&
hwρ
aρ
vm&
dtdhE −=
nRsH
G
∫∫ ⋅+++
∫∫∫ ∀++=−
CSu
CVu
dgzVe
dgzVedtd
dtdW
dtdH
AVrr
ρ
ρ
)2/(
)2/(
2
2
Energy Method (3)Energy Eq.
0=
hwρ
aρ
vm&
dtdhE −=
nRsH
G
.,0;0 consthV ≈=≈
∫∫∫ ∀=CV
wu dedtd
dtdH ρ
GHRdtdH
sn −−=
GHR sn −−=
Energy Method (4)Energy Eq. for Water in CV
Assume:1. Constant temp of water in CV2. Change of heat is change in internal
energy of evaporated water hwρ
aρ
vm&
dtdhE −=
nRsH
Gvvml
dtdH
&=
GHRdtdH
sn −−=
GHRml snvv −−=& AEm wρ=&
( )GHRAl
E snwv
−−=ρ1
Recall:Recall:
wv
nr l
REρ
= Neglecting sensible Neglecting sensible and ground heat fluxesand ground heat fluxes
Aerodynamic Method• Include transport of vapor
away from water surface as function of: – Humidity gradient above
surface– Wind speed across surface
• Upward vapor flux
• Upward momentum flux
nR
E
Net radiation
Evaporation
Air Flow
1212
zzqq
Kdz
dqKm vvwa
vwa −
−−=−= ρρ&
1212
zzuuK
dzduK mama −
−== ρρτ
( )( )12
21uuKqqKm
m
vvw−
−=
τ&
Aerodynamic Method (2)
• Log-velocity profile
• Momentum flux
( )( )12
21
uuKqqK
mm
vvw
−
−=τ&
⎟⎟⎠
⎞⎜⎜⎝
⎛=
oa
ZZ
ku ln1
ρτ
( )( )
2
12
12ln ⎥
⎦
⎤⎢⎣
⎡ −=
ZZuuk
aρτ
( )( )( )[ ]212
122
ln21
ZZK
uuqqkKm
m
vvaw −−=
ρ&
Thornthwaite-Holzman Equation
nR
E
Net radiation
Evaporation
Air Flow
Too many variables! Often only know qv and u at 1 elevation
Aerodynamic Method (3)
( )eeBE sa −=
( )[ ]22
22
ln622.0
ow
a
ZZPukB
ρρ
=
pressure vapor =e
nR
E
Net radiation
Evaporation
Air Flow
• Simplify
pressure vapor sat. =se
Combined Method• Evaporation could be calculated by
– Aerodynamic method: when energy supply is not limiting– Energy method: when vapor transport is not limiting
• Normally, both are limiting, so use a combination method
Combined Method (Cont.)• Combining
– Energy balance – Aerodynamic Methods
• Combined Method
– Well suited to small areas with detailed data
• Net Radiation• Air Temperature• Humidity• Wind Speed• Air Pressure
wv
nr l
REρ
=
( )eeBE sa −=
ar EEEγ
γγ +Δ
++ΔΔ
=wv
hp
KlpKC
622.0=γ
2)3.237(4098
Tes+
=Δ
rEEγ+Δ
Δ= 3.1 Priestly & Taylor
Example
z = 2 mP = 101.3 kPau = 3 m/sRn = 200 W/m2
T = 25 degCRh = 40%
• Use Combo Method to find Evaporation
kJ/kg 244110)25*36.22500(
237010501.23
6
=−=
−=
x
Txlv
mm/day10.7997*102441
2003
=
==xl
REwv
nr ρ
Example (Cont.)
z = 2 mP = 101.3 kPau = 3 m/sRn = 200 W/m2
T = 25 degCRh = 40%
• Use Combo Method to find Evaporation
( )mm/day45.7
)day1/s86400(*)m1/mm1000(*126731671054.4 11
=−= −xEa
( )[ ] ( )[ ]sm/Pa1054.4
1032ln997*3.101
3*19.1*4.0*622.0ln
622.0 1124
2
22
22
⋅=== −−
xxZZP
ukBow
aρ
ρ
Pa3167=se
Pa12673167*4.0* === sh eRe
Example (Cont.)
z = 2 mP = 101.3 kPau = 3 m/sRn = 200 W/m2
T = 25 degCRh = 40%
Pa/degC1.67102441*622.0103.101*1005
622.0 3
3===
xx
KlpKC
wv
hpγ
• Use Combo Method to find Evaporation
Pa/degC7.188)253.237(
3167*4098)3.237(
409822 =
+=
+=Δ
Tes
738.0=+ΔΔγ
mm/day2.745.7*262.010.7*738.0 =+=+Δ
++ΔΔ
= ar EEEγ
γγ
262.0=+Δ γγ
Example
• Use Priestly-Taylor Method to find Evaporation rate for a water body
rEEγ+Δ
Δ= 3.1 Priestly & Taylor
mm/day10.7=rE 738.0=+ΔΔγ
mm/day80.610.7*738.0*3.1 ==E
z = 2 mP = 101.3 kPau = 3 m/sRn = 200 W/m2T = 25 degCRh = 40%
Evapotranspiration
• Evapotranspiration– Combination of evaporation from soil surface and
transpiration from vegetation– Governing factors
• Energy supply and vapor transport• Supply of moisture at evaporative surfaces
– Reference crop• 8-15 cm of healthy growing green grass with abundant water
– Combo Method works well if B is calibrated to local conditions
Potential Evapotranspiration
• Multiply reference crop ET by a Crop Coefficient and a Soil Coefficient
rcs ETkkET =
3.10.2t;Coefficien Crop
≤≤=
c
ck
k
10t;Coefficien Soil
≤≤=
s
sk
k
ET Actual =ET
ET Crop Reference =rET
http://www.ext.colostate.edu/pubs/crops/04707.html
CORN
0
0.1
0.2
0.3
0.4
0.5
0.6
0.7
0.8
0.9
1
0 20 40 60 80 100 120 140 160
Time Since Planting (Days)
Cro
p C
oeff
icie
nt, k
c
Combined Method• Evaporation could be calculated by
– Aerodynamic method: when energy supply is not limiting– Energy method: when vapor transport is not limiting
• Normally, both are limiting, so use a combination method
• Sensible heat flux is difficult to estimate– Assume it is proportional to the vapor heat flux– Where β = Bowen ratio– Energy balance equation (G=0)
( )vvs mlH &β=
( )
( )βρ
+=
−−=
1
1
mlR
GHRAl
E
vn
snwv&
Combined Method (2)• Transport equations for heat and vapor
dzdqKH v
was ρ−=dzdTKCm hpav ρ−=&
( ))(
12
12
vvw
hp
v
sqqKTTKC
mH
−
−=
&
( ))(622.0 12
12
eeKlTTpKC
wv
hp
−
−=β
( )vvs mlH &β=peqv 622.0=
wv
hp
KlpKC
622.0=γ
( ))( 12
12eeTT
−−
= γβ 1≈w
hKK
Recall Vapor Pressure
Temperature
Vap
or P
ress
ure
ese
Measured temp, TDew Point temp, Td
Saturate vapor pressurefor given temperature
Vapor Pressure
Saturation Vapor Pressure
sh e
eR =
⎟⎠⎞
⎜⎝⎛
+=
TTes 3.237
27.17exp6112)3.237(
4098T
edTde ss
+==Δ