Capacitance Lab
-
Upload
crystal-young -
Category
Documents
-
view
16 -
download
1
Transcript of Capacitance Lab
Capacitors
October 2, 2014
Kortney Melancon and Austin Morris
Abstract
The purpose of the experiment was to observe the properties of a parallel
plate capacitor as well as determine the equivalent capacitance of several capacitors
connected in series and parallel. The capacitance of each individual capacitor was
measured using the LCR multimeter. The capacitors were then connected in a
parallel and series connection and their capacitance values were recorded. It is clear
that it is ineffective to calculate the dielectric constant from only a single
measurement.
Introduction
The purpose of the experiment was to observe the properties of a parallel
plate capacitor as well as determine the equivalent capacitance of several capacitors
connected in series and parallel. Capacitance is characterized by a parallel plate
arrangement and is defined in terms of the charge stored by
C=QV
Where Q is the magnitude of the charge stored and V is the potential
difference between them. The capacitance is expressed in units of Farad, equal to 1
Coulomb/volt. A capacitor is a charged storage device that is typified by two parallel
plates separated by a layer of insulating material and is dependent on dielectrics. If
the size of these two plates is greater than the spacing that exists between them, the
equation for this arrangement is
C=K ε0 Ad
Where K is the relative permittivity of the dielectric material between the
plates, ε 0 is the permittivity of vacuum, A represents the area of a plate and d is the
separation distance that exists between the plates. K is equal to 1 in free space,
greater than 1 for other materials.
If two or more capacitors are connected, the equivalent capacitance can be
determined by using the following equations
1) If the capacitors are connected together in series:
1C
= 1C1
+ 1C2
+ 1C3
+…
2) If the capacitors are connected in parallel:
C=C 1+C2+C3+…
The dielectric constant will be determined by rearranging to solve for K in
the second formula given above. The capacitance of this capacitor will be measured
for several separation distances, d, to observe the affect the distance has on the
capacitor. Individual capacitors will be connected in series and parallel and their
equivalent capacitance will be measured and compared to those given by the third
and fourth equations stated above.
Experimental Procedure
Using a micrometer, the thickness of a single insulating sheet was measured
at four different places to determine the consistency of thickness. Average thickness
was recorded. A single sheet of the transparency blanks was placed between the two
flat disk shaped conductors. The short cables of the LCR multimeter were then
connected to the upper and lower connecting terminals on the capacitor setup. The
LCR multimeter was switched to the capacitance position. The ends of the leads
were connected to the two connectors on the capacitor setup into the slots on the
LCR multimeter. The capacitance was then measured and the value for the dielectric
constant was determined.
The capacitance was then measured as a function of the number of
transparency blanks placed between the two parallel plates. One additional
transparency sheet was added in between the plates and the capacitance was again
measured using the LCR multimeter. This process was repeated until ten
measurements were obtained.
The capacitance of each individual capacitor was measured using the LCR
multimeter. The capacitors were then connected in a parallel and series connection
and their capacitance values were recorded.
Measurement Results
Table 1. The measured capacitance values as a function of the number of sheets of
transparency.
0 0.0002 0.0004 0.0006 0.0008 0.001 0.00120
500000000
1000000000
1500000000
2000000000
2500000000
3000000000
f(x) = 2346854722178.89 x + 433273868.889184R² = 0.971034204913911
Graph 1. Graphical analysis of capacitance values as a function of the number of
transparency sheets separating the parallel plates.
Data Analysis
C=K ε0 Ad
To calculate the dielectric constant, K, the above equation can be rearranged
as follows
K= Cdε0 A
=(0.0001m )(5.85×10−12)(8.85×10−12)(0.0165)
=0.004006
K= 1ε0× A ×a
= 1(8.85×10−12) (0.2347 ) (0.0165 )
=2.917
Discussion
The dielectric constant of the transparencies (cellulose acetate) is 2.917. This
is well within the expected range of 2.5-5.0. In the first part of the experiment, the
dielectric constant was calculated to be 0.004006, which is nonphysical because it is
below 1. The dielectric constant is a ratio between the permittivity of the material
and the permittivity of free space. Thus, it cannot hold a value below 1. It is clear
that it is ineffective to calculate the dielectric constant from only a single
measurement.