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: calculation of cement bags in 1:2:4 concrete mix Answer

#16For 1 m3 of concrete (1:2:4)

for Required volume of concrete 1.00

Add extra for additional voids in concrete (50%)

0.50

Total qty= 1.50 CumMix total (1+2+4) 7

Therefore Quantity of cement = (1.50/7) 0.2143 Cum

Qty of Cement in bags = ( 0.2143*1440)=308.57kg

Therefore; Bag of Cement=50kg

Qty of Cement in Mix Ratio 1;2;4 = 308.57/50kg = 6.17 Bags

say(6 bag)

Qty of sand in bags = (2/7)*1.5 = 0.43 Cum

Qty of Aggregate = (4/7)*1.5 = 0.86 Cum

for 1 cu.m of concrete, (1:2:4)

1=cement; 2=sand; 4=gravel

add 25% for loose volume(to cover voids),

total concrete volume = 1.25 cu.m.

total parts = 1+2+4 = 7 parts

cement = (1/7)*1.25

= 0.1786 cu.m

density of cement = 1440kg/cu.m

thus, 0.1786 * 1440 = 257.184kg.

for 40kg per bag of cement:

bag of cement = 257.14kg/(40kg per bag)

= 6.4 bags....answer

For 1 m3 of concrete (1:2:4)

Required volume of concrete = 1 m3

Estimated volume of dry material = 1 x 1.65 = 1.65 m3

Mix totals = 1+2+4 = 7 (1:2:4 cement:sand:gravel)

Ingredient Volumes: 1.65 x 1/7 = 0.235 m3 cement

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# Bags of cement: 0.235 m3 cement / .0332 m3 per 50 Kg bag

= 7 bags of cement

For 1 m3 of concrete (1:2:4)

for Required volume of concrete 1.00

Add extra for additional voids in concrete ( 25% to 35%)=Say

35%=35/100=0.35.

Total qty=1+0.35=1.35 Cum

Mix total (1+2+4)=7

Therefore Quantity of cement = (1.35/7)=0.19 Cum

Qty of Cement in Kgs = (0.19*1440)=273.6Kgs

(1cum=1440Kgs)Qty of Cement in bags= 273.6/50=5.4 bags=Say 6 bags

(50kgs=1 bag)

Qty of sand in bags = ( 0.19*2)=0.39Cum

Qty of Aggregate = ( 0.19*4)=0.77Cum

For 1 m3 of concrete (1:2:4)

for Required volume of concrete 1.00

Add extra for additional voids in concrete ( 25% to 35%)

0.35Total qty= 1.35 Cum

Mix total (1+2+4) 7

Therefore Quantity of cement = (1.35/7) 0.19

Cum

Qty of Cement in bags = ( 0.19/0.03) 6.4 Bags say(7

bag)

Qty of sand in bags = ( 0.19*2) 0.39 Cum

Qty of Aggregate = ( 0.19*4) 0.77 Cum

: How to calculate cement and sand quantities in cement mortar As 1:1,1:2,1:4,1:6 ? Answer

#1the procedure to calculate quanity is given below

eg. if cement mortar ratio is ( 1:6)

suppose 1 cum of cement mortar work is to be done

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then add 60% extra for voids & cavities in case of plaster

then total volume of work = 1 + 60/100 x1 =1.6 cum

quantity of cement in cum = 1.6 / (1+6)= 1.6/7=0.228 cum

but as we know cement is available in market in 50 kgbags (volume of 50kg cement is = 0.0347 cum)

thu quantity of cement in bags = 0.228/0.0347= 6.57 bags

quantity of sand in cum= 0.228 x 6 =1.36 cum

eg. if cement mortar ratio is ( 1:4)

suppose 1 cum of cement mortar work is to be done

then add 60% extra for voids & cavities in case of plaster

then total volume of work = 1 + 60/100 x1 =1.6 cum

quantity of cement in cum = 1.6 / (1+4)= 1.6/5=0.32 cum

but as we know cement is available in market in 50 kg

bags (volume of 50kg cement is = 0.0347 cum)

the quantity of cement in bags = 0.32/0.0347= 9.22 bags

quantity of sand in cum= 0.32 x 4 =1.28 cum

this is exact procedure. you can calculate for any ratio of

cement & mortar

First assume the ratio of plaster is 1:4 (1 cement and 4 sand)

now we have to plaster the wall having area of 100 sft assume the thickness of plaster 0.5 inches.

first convert thickness in to feet so 0.5/12 = 0.0416

now to calculate the material use in cft so 100 sft x 0.0416 = 4.16 cft

so we required 4.16 cft material to complete the plaster multiply it by dry factor 1.5

4.16 x 1.5 = 6.24 cft

to calculate cement 6.24/(1+4) = 1.24 cft

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1 cement bag volume 1.25 cft so calculate no of bags 1.24/1.25 = 1 bag

to calculate sand

(6.24/(1+4)) x 4 = 4.99 cft