CAIRO UNIVERSITY FACULTY OF ENGINEERING CHEMICAL ENGINEERING DEPARTMENT Organic Chemical Process...
-
Upload
norah-gilmore -
Category
Documents
-
view
222 -
download
4
Transcript of CAIRO UNIVERSITY FACULTY OF ENGINEERING CHEMICAL ENGINEERING DEPARTMENT Organic Chemical Process...
![Page 1: CAIRO UNIVERSITY FACULTY OF ENGINEERING CHEMICAL ENGINEERING DEPARTMENT Organic Chemical Process Industries TA. Jasmine Amr Eng. Hassan El- Shimi Section.](https://reader035.fdocuments.us/reader035/viewer/2022062407/56649d135503460f949e7aca/html5/thumbnails/1.jpg)
CAIRO UNIVERSITYCAIRO UNIVERSITYFACULTY OF ENGINEERINGFACULTY OF ENGINEERINGCHEMICAL ENGINEERING DEPARTMENTCHEMICAL ENGINEERING DEPARTMENT
Organic Chemical Process Industries
TA. Jasmine AmrEng. Hassan El- Shimi
Section 1
Wednesday, September 22nd, 2010
![Page 2: CAIRO UNIVERSITY FACULTY OF ENGINEERING CHEMICAL ENGINEERING DEPARTMENT Organic Chemical Process Industries TA. Jasmine Amr Eng. Hassan El- Shimi Section.](https://reader035.fdocuments.us/reader035/viewer/2022062407/56649d135503460f949e7aca/html5/thumbnails/2.jpg)
Today’ AgendaToday’ Agenda General view on Organic Industries Course contents Marks Review on Chemical Kinetics Sheet 1
![Page 3: CAIRO UNIVERSITY FACULTY OF ENGINEERING CHEMICAL ENGINEERING DEPARTMENT Organic Chemical Process Industries TA. Jasmine Amr Eng. Hassan El- Shimi Section.](https://reader035.fdocuments.us/reader035/viewer/2022062407/56649d135503460f949e7aca/html5/thumbnails/3.jpg)
Course ContentsCourse Contents
Lectures Sections
Organic Technology (Overview)
o Nitrationo Nitrobenzene
o Dinitrobenzene
o TNB
o Aniline industry
o TNT, and ….
Sulfonation Intro to Petrochemical
Industry
Review on Chemical Kinetics (2 sections)
Nitration Thermodynamics ( 2 sections)
Peroxide value Saponification value O & G Estimation BOD5 & COD Dying
Mwt. Determination
Laboratory
Prof. Dr. SamiaProf. Dr. HodaProf. Dr. Sahar
TA. Jasmine AmrEng. Hassan El-
Shimi
![Page 4: CAIRO UNIVERSITY FACULTY OF ENGINEERING CHEMICAL ENGINEERING DEPARTMENT Organic Chemical Process Industries TA. Jasmine Amr Eng. Hassan El- Shimi Section.](https://reader035.fdocuments.us/reader035/viewer/2022062407/56649d135503460f949e7aca/html5/thumbnails/4.jpg)
MarksMarks (acceptable to change) (acceptable to change)
Total marks = 150 markFinal exam : 90 markYear work : 60 marko 1st midterm : 30 marko 2nd midterm : 10 markso Oral exam : 10 markso Lab : 10 mark
![Page 5: CAIRO UNIVERSITY FACULTY OF ENGINEERING CHEMICAL ENGINEERING DEPARTMENT Organic Chemical Process Industries TA. Jasmine Amr Eng. Hassan El- Shimi Section.](https://reader035.fdocuments.us/reader035/viewer/2022062407/56649d135503460f949e7aca/html5/thumbnails/5.jpg)
![Page 6: CAIRO UNIVERSITY FACULTY OF ENGINEERING CHEMICAL ENGINEERING DEPARTMENT Organic Chemical Process Industries TA. Jasmine Amr Eng. Hassan El- Shimi Section.](https://reader035.fdocuments.us/reader035/viewer/2022062407/56649d135503460f949e7aca/html5/thumbnails/6.jpg)
Chemical Reaction KineticsChemical Reaction KineticsFor any reaction A+B → C (product)Rate of reaction α no. of collisions
between molecules A, B.Rate of reaction α concentration of A, BAs rA α CA CB, hence rA = k CA CB
Where k: specific rate constantRate of reaction is rate of consumption or
production of component (i) rA= - dCA/dt = - dCB/dt = +dCC/dt = kCACB
![Page 7: CAIRO UNIVERSITY FACULTY OF ENGINEERING CHEMICAL ENGINEERING DEPARTMENT Organic Chemical Process Industries TA. Jasmine Amr Eng. Hassan El- Shimi Section.](https://reader035.fdocuments.us/reader035/viewer/2022062407/56649d135503460f949e7aca/html5/thumbnails/7.jpg)
If aA+bB → cC+dD (balanced equation)Hence, rA = k CA
a CBb (rate equation)
Where, a: order of reaction w.r.t. reactant (A) and b: order of reaction w.r.t. reactant (B)
Overall order of reaction = a+b
In case of reversible reaction: aA+bB ↔ cC+dDRate eq.: rA= kf CA
aCBb – kb CC
cCDd
Order of reaction= (a+b) – (c+d)
![Page 8: CAIRO UNIVERSITY FACULTY OF ENGINEERING CHEMICAL ENGINEERING DEPARTMENT Organic Chemical Process Industries TA. Jasmine Amr Eng. Hassan El- Shimi Section.](https://reader035.fdocuments.us/reader035/viewer/2022062407/56649d135503460f949e7aca/html5/thumbnails/8.jpg)
Mechanism of reactionMechanism of reaction
Elementary Reactions Non-elementary Reactions
Reactions occur in a single step and the rate expression is suggested from the stiochiometric equation.
2A+B → R+S
rA = k CA2CB
Reactions which we observe as a single reaction, but in the real, it’s the result of a sequence of elementary reactions and the rate equation can’t be detected from the stiochiometric equation.
2A+B → R+S In fact: A+B → AB AB+A → A2B +S A2B → R These 3 steps are called: the
reaction mechanism Rate eq. = rate eq. of determining
step (slowest step) ≠ kCA2CB
![Page 9: CAIRO UNIVERSITY FACULTY OF ENGINEERING CHEMICAL ENGINEERING DEPARTMENT Organic Chemical Process Industries TA. Jasmine Amr Eng. Hassan El- Shimi Section.](https://reader035.fdocuments.us/reader035/viewer/2022062407/56649d135503460f949e7aca/html5/thumbnails/9.jpg)
Arrhenius EquationArrhenius Equation
K= Ao e –E/RT
K: specific rate constantAo: Arrhenius constantE: activation energyT: absolute temperature (Kelvin or oR)R: universal gas constant= 8.314 J/gmole.K or
R= 0.082 lit.atm/gmole.K or R= 1.987 cal/gmole. K = 10.73 Btu/Ib. R
![Page 10: CAIRO UNIVERSITY FACULTY OF ENGINEERING CHEMICAL ENGINEERING DEPARTMENT Organic Chemical Process Industries TA. Jasmine Amr Eng. Hassan El- Shimi Section.](https://reader035.fdocuments.us/reader035/viewer/2022062407/56649d135503460f949e7aca/html5/thumbnails/10.jpg)
Dependence of Rx Rate on Concentration:
r = k CAn CB
m; n & m order of Rx
If B is in large excess; CB ≈ constant, i.e. –dCB/dt ≈ 0, hence
CBm = constant and rA = k’ CA n, where
k’= k CBm, and it’s easy to get (n).
Molecularity:o It’s the number of reactant molecules in the
stiochiometric equation (Elementary Rx) OR number of molecules in the rate determining step (Non-elementary Rx).
o N.B.: if order of Rx = Molecularity, the reaction is called simple order reaction.
![Page 11: CAIRO UNIVERSITY FACULTY OF ENGINEERING CHEMICAL ENGINEERING DEPARTMENT Organic Chemical Process Industries TA. Jasmine Amr Eng. Hassan El- Shimi Section.](https://reader035.fdocuments.us/reader035/viewer/2022062407/56649d135503460f949e7aca/html5/thumbnails/11.jpg)
Sheet 1Sheet 1Problem no. 1
A → B, r = kCAn; n=?
1) Assume zero order reaction (n=0)
Hence, r= - dC/dt = k[C]n=0 = k
Get CA-CAo = - k*t
Hence, CA=CAo – k*t
CA
t
Slope = k
![Page 12: CAIRO UNIVERSITY FACULTY OF ENGINEERING CHEMICAL ENGINEERING DEPARTMENT Organic Chemical Process Industries TA. Jasmine Amr Eng. Hassan El- Shimi Section.](https://reader035.fdocuments.us/reader035/viewer/2022062407/56649d135503460f949e7aca/html5/thumbnails/12.jpg)
2) Assume 1st order reaction ( n=1)
r= -dCA/dt = k[CA]
-dC/[C] = k dt
Hence, Ln CA- Ln CAo = -k*t
Finally, ln CA = ln CAo –k*t
Ln CA
t
Slope = k
![Page 13: CAIRO UNIVERSITY FACULTY OF ENGINEERING CHEMICAL ENGINEERING DEPARTMENT Organic Chemical Process Industries TA. Jasmine Amr Eng. Hassan El- Shimi Section.](https://reader035.fdocuments.us/reader035/viewer/2022062407/56649d135503460f949e7aca/html5/thumbnails/13.jpg)
3) Assume 2nd order reaction ( n=2)
r= -dCA/dt = k[CA]2
-dC/[C]2 = k dt
Hence, 1/CA- 1/CAo = k*t
Finally, 1/CA = 1/CAo + k*t
1/CA
t
Slope = k1/CAo
![Page 14: CAIRO UNIVERSITY FACULTY OF ENGINEERING CHEMICAL ENGINEERING DEPARTMENT Organic Chemical Process Industries TA. Jasmine Amr Eng. Hassan El- Shimi Section.](https://reader035.fdocuments.us/reader035/viewer/2022062407/56649d135503460f949e7aca/html5/thumbnails/14.jpg)
a) Plot C vs t
b) Plot 1/C vs t
The order of reaction is 2nd order
Slope = k = 1.415E-06 lit/gmole. Sec
![Page 15: CAIRO UNIVERSITY FACULTY OF ENGINEERING CHEMICAL ENGINEERING DEPARTMENT Organic Chemical Process Industries TA. Jasmine Amr Eng. Hassan El- Shimi Section.](https://reader035.fdocuments.us/reader035/viewer/2022062407/56649d135503460f949e7aca/html5/thumbnails/15.jpg)
Problem no. 2Problem no. 2Given E= 75000 calK at 650oC and 500oCHence, T1= 923ok & T2= 773ok
Since k= Ao e-E/RT
k1= Ao e-E/R(773) → 1
k2= Ao e-E/R(923) → 2
k1/k2 =
![Page 16: CAIRO UNIVERSITY FACULTY OF ENGINEERING CHEMICAL ENGINEERING DEPARTMENT Organic Chemical Process Industries TA. Jasmine Amr Eng. Hassan El- Shimi Section.](https://reader035.fdocuments.us/reader035/viewer/2022062407/56649d135503460f949e7aca/html5/thumbnails/16.jpg)
k1/k2 =
Since E= 73000 cal & R= 1.987 cal/gmol .k
Thus, k1/k2 = 2/3 and k1=(2/3) k2
i.e. k2 > k1 , thus the reaction at (T2= 650oC) is faster than the reaction at (T1= 500oC).
![Page 17: CAIRO UNIVERSITY FACULTY OF ENGINEERING CHEMICAL ENGINEERING DEPARTMENT Organic Chemical Process Industries TA. Jasmine Amr Eng. Hassan El- Shimi Section.](https://reader035.fdocuments.us/reader035/viewer/2022062407/56649d135503460f949e7aca/html5/thumbnails/17.jpg)
Chemical Third Year, CHE2012Any Question
![Page 18: CAIRO UNIVERSITY FACULTY OF ENGINEERING CHEMICAL ENGINEERING DEPARTMENT Organic Chemical Process Industries TA. Jasmine Amr Eng. Hassan El- Shimi Section.](https://reader035.fdocuments.us/reader035/viewer/2022062407/56649d135503460f949e7aca/html5/thumbnails/18.jpg)
For any problem, please contact me:
Eng. Hassan El- ShimiE-mail: [email protected]
Mobile: 011 80 87 86 2
![Page 19: CAIRO UNIVERSITY FACULTY OF ENGINEERING CHEMICAL ENGINEERING DEPARTMENT Organic Chemical Process Industries TA. Jasmine Amr Eng. Hassan El- Shimi Section.](https://reader035.fdocuments.us/reader035/viewer/2022062407/56649d135503460f949e7aca/html5/thumbnails/19.jpg)
Thank You