C 10J Lecture 6

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    Synthesis of Alkenes by Dehydrohalogenationof Alkyl Halides

    When an alkyl halide is treated with a strong base such as

    sodium or potassium hydroxide (NaOH, KOH).

    Sodium methoxide (NaOCH3), sodium ethoxide (NaOC2H5)

    or potassium tertiary butoxide, (KOC(CH3)3) an

    elimination reaction takes place and one or more alkenes is

    formed.

    C C

    X

    H

    CCstrong base

    -HX

    X = Br, Cl, I

    An Elimination Reaction

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    The E2 Mechanism of Dehydrohalogenation

    C C

    X

    H

    CC X

    B

    strong base ( B ) BH+ +

    ?The mechanism is concerted i.e. bond making

    and bond breaking occur simultaneously.

    ?Rate of Reaction = k[base][alkyl halide]

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    This type of elimination is referred to as a 1,2- elimination or

    as a ? -elimination. The hydrogen that is lost is attached to thecarbon that is in the ? -position with respect to the halogen

    atom.

    C C

    Br

    H

    ?

    ?

    12

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    Stereochemistry of the E2 Mechanism

    For the E2 mechanism to take place, the alkyl halide mustadopt a conformation in which the halogen atom and the ? -

    hydrogen are anti to each other.

    H

    X

    H

    X

    This is called the anti-periplanar or anti-coplanarconformation

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    Note!

    Dehydrohalogenation reactions can also take place under

    conditions that favour an E1 mechanism. However, the

    synthesis of alkenes is better achieved by way of an E2

    mechanism.

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    Dehydrobromination of 2-Bromopentane

    CH3 CH2 CH CH CH2

    H

    Br

    HH3C CH2 CH2 CH

    CH2

    CH3 CH2CH CH3CH

    2-bromopentane +

    1-pentene

    2-pentene (disubstituted alkene)

    B

    (monosubstituted alkene)

    Zaitsevs rule would dictate that the more highly

    substituted 2-pentene be the preferred product and thisis so when bases such as sodium hydroxide, potassium

    hydroxide, sodium methoxide and sodium ethoxide are

    used.

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    The Hofmann Product

    When potassium tertiary butoxide which is a much bulkier

    molecule than sodium or potassium hydroxide; sodium

    methoxide and sodium ethoxide, is used, the less substituted

    alkene, 1-pentene is the one that predominates and is referredto as the Hofmann product.

    C

    CH3

    CH3

    CH3

    OK

    potassium tertiary butoxide

    C O

    CHH

    H

    C

    H

    HH

    CHH

    H

    K

    potassium tertiary butoxide

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    Hofmann Product contd

    Bulky bases abstract the least hindered H+

    Least substituted alkene is major product.

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    Reactions of Alkenes

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    Reactivity of C=C

    Electrons in pi bond are loosely held.

    Electrophiles are attracted to the pi electrons.

    Carbocation intermediate forms (typically).

    Nucleophile adds to the carbocation.

    Net result is addition to the double bond.

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    Addition Reactions

    The typical mode of reaction of alkenes is that of

    addition. In addition reactions, two molecules combine to

    give a single molecule of product.

    Notice the bonding changes that occur.

    C C + A B C CA B

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    Addition Reactions Contd

    The reaction is energetically favourable. The amount of

    energy released by the formation of two sigma bonds is in excess of

    that needed to break one sigma bond and one pi bond. As a result,

    addition reactions of alkenes are usually exothermic (heat is given

    off).

    C C

    C CA B

    B

    Reaction Coordinate

    G

    G negative (exothermic reaction)

    G H T S

    Energy

    A,

    Energy Profile of Addition Reactions

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    What is the Mechanism of AdditionReactions of Alkenes?

    Remember that the term Reaction Mechanism refers to

    the sequence and timing of the bond breaking and bond

    making processes that bring about the conversion of

    starting materials into products.

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    The Reaction Mechanism tells us theorder in which the following bond

    changes occur:

    C C + A B C CA B

    Bond Breaking

    One pibond and one sigmabond are broken.

    Bond Making

    Two new sigmabonds are formed

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    The Mechanism of AdditionReactions of Alkenes

    Some addition reactions of alkenes are stepwise. They occurby way of a series of steps and involve the formation ofintermediate species.

    Some addition reactions are concerted. The conversion ofstarting material to product takes place in one step . Bondsare broken and formed simultaneously with no intermediate

    species being formed.

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    Electrophilic Addition

    An alkene is a nucleophile by virtue of itspi bond. The

    two lobes of the pi bonding orbital above and below the

    molecular framework contain a pair of fairly loosely held

    electrons which can be donated to an electrophile. We say

    that the electrons are loosely held because the pi bond isweaker than the sigma.

    CC lobes of pibonding orbitalabove and below the molecularframework

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    Electrophilic Addition Contd

    The addition is called Electrophilic Addition when the

    molecule, E Nu that adds to the alkene is highly

    polarized such that an electrophile E is provided.

    C C E Nu C CNu E?? ??

    +

    An electrophile is an electron deficient species that will accept an electron pair into an empty

    orbital to form a bond.

    The nucleophile is the electron rich species that will donate a pair of electrons to the

    electrophile

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    REMINDER!Representing Reaction Mechanisms

    on PaperUse of Curly Arrows

    A curly arrow represents the movement of a pair of

    electrons. The arrow originates at the source of the

    electrons and terminates at the place where the electronsend up.

    source ofelectrons

    destination ofelectrons

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    A B A B

    CC

    A

    CC

    A

    CC

    A B

    CC

    A

    B

    +

    +

    Electrons usually end up either on an atom itself or

    in the gap between two atoms where a new bond is

    being formed.

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    Step 1: Pi electrons attack the electrophile.

    The Mechanism of Electrophilic

    Addition is a Stepwise Mechanism.

    Step 2: Nucleophile attacks the carbocation.

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    Typical Highly Polarized Molecules thatadd to Alkenes

    H X

    H OSO3H

    H

    H

    OH

    ????

    ?? ??

    Hydrogen halides, (X= Br, Cl, I)

    Sulfuric acid (H2SO4)

    ??

    Hydronium ion

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    C C

    H Br

    C C

    H

    Br

    C C

    H

    Br

    C C

    H

    Br

    +Fast

    Slow

    Mechanism of Addition of HBr toAlkenes

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    Electrophilic Addition Reactions

    When a symmetrical alkene undergoes electrophilic

    addition of an unsymmetrical molecule, HY, only one

    product is possible regardless of the direction in which

    HY adds.

    C C

    H

    H H

    H

    C C

    H

    HH

    Y

    H

    H

    C C

    H

    HH

    Y

    H

    H

    HY

    2 1 2 1 2 1

    ethene, symmetrical alkene

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    Regioselectivity in Electrophilic AdditionReactions Contd

    If the alkene is unsymmetrical, for example propene, the

    addition of HY can in theory lead to two different products

    I and II which are structural or constitutional isomers

    C C

    H

    H H

    CH3

    C C

    CH3

    HH

    Y

    H

    H

    C C

    CH3

    HH

    Y

    H

    H

    HY+

    I II

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    The Two Possible Carbocations

    C C

    H

    H H

    CH3

    C C

    CH3

    HH

    Y

    H

    H

    C C

    CH3

    HH

    Y

    H

    H

    Y H

    HY

    +

    I II

    +

    C C

    CH3

    HH

    H

    H

    IIY

    Compound

    carbocation B

    C C

    CH3

    HH

    H

    H

    IY

    Compound

    carbocation A

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    Markovnikovs Rule

    (The Modern Statement)

    When an unsymmetrical reagent adds to a double bond by

    way of an ionic mechanism, the positive portion of the

    reagent (the electrophile) attaches itself to a carbon atom of

    the double bond so that the more stable of the two possible

    carbocations is formed as the intermediate.

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    Markovnikovs Rule Obeyed

    C C

    CH3

    HH

    H

    H

    C C

    H

    H H

    CH3

    C C

    CH3

    HH

    H

    HY

    ICompound

    HY

    A

    secondary carbocationformed preferentiallyfrom more stablecarbocation

    C C

    CH3

    HH

    H

    H

    IICompound

    HY

    B

    primary carbocation

    Not formed or formedin a minor amount

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    The MarkovnikovProduct is formed byway of the energeticallymore favorable route.

    Markovnikov

    product

    AntiMarkovnikov

    product

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    Markovnikovs Rule(The Original Statement)

    In the addition of HX to an alkene, the hydrogen atom adds

    to the carbon atom of the double bond that already has the

    greater number of hydrogens.

    C C

    H

    H H

    CH3

    C C

    CH3

    HH

    X

    H

    H

    C C

    CH3

    X

    HH

    H

    H

    HX+

    I II

    When a reaction such as the one above has the potential to

    produce two or more constitutional isomers and yet only one is

    formed or a mixture in which one predominates, the reaction is

    said to be regioselective.

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    Electrophilic Addition With Rearrangement

    CH3 CH

    CH3

    CH2

    CH CH3 CH

    CH3

    CH3

    CH

    CH3 C

    CH3

    CH3

    CH2

    Cl

    Cl

    HCl

    2-chloro-3-methylbutane

    2-chloro-2-methylbutane

    3-methyl-1-butene

    +

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    The Expected Outcome

    CH3 C

    CH3

    H

    C C

    H

    H

    HH

    CH3 C

    CH3

    H

    C C

    H

    H

    HH

    Cl

    CH3 C

    CH3

    H

    C C H

    HH

    H Cl

    Cl

    2-chloro-3-methylbutaneCarbocation formed in keepingwith Markovnikov's Rule

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    Rearrangement

    CH3 C

    CH3

    H

    C C

    H

    H

    HH

    CH3 C

    CH3

    C C

    H

    H

    H

    H

    H

    1,2-hydride shift

    Cl

    CH3 C

    CH3

    C C

    H

    H

    H

    H

    HCl

    2 31 4

    2-chloro-2-methylbutane

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    Addition of HBr to alkenes

    C C

    H

    H H

    CH3

    HBrC C

    CH3

    HH

    Br

    H

    H

    Markovnikov Product

    II

    C C

    H

    H H

    CH3

    HBr

    Anti-Markovnikov Product

    (under certaincircumstances)

    C C

    CH3

    HH

    Br

    H

    H

    Sometimes the expected Markovnikov addition was observed,

    yet at other times the regioselectivity was just the opposite.

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    Anti-Markovnikov addition of HBr toalkenes

    II

    C C

    H

    H H

    CH3

    HBr

    Anti-Markovnikov Product

    (under certain

    circumstances)

    C C

    CH3

    HH

    Br

    H

    H

    It was discovered that the anti-Markovnikovaddition occurred when there happened to beorganic peroxides present in the reaction

    mixture.

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    Anti-Markovnikov Addition of HBr toAlkenes contd.

    Organic peroxides have the following structures:

    O O RR

    O O HR

    alkyl peroxide

    alkyl hydroperoxide

    II

    C C

    H

    H H

    CH3

    HBr

    Anti-Markovnikov Product

    C C

    CH3

    HH

    Br

    H

    HROOR

    orROOH

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    Anti-Markovnikov Addition of HBr toAlkenes contd.

    In the presence of organic peroxides, addition of HBr

    proceeds by way of a Free Radical Mechanism.

    STEP 1 (Initiation)

    The weak oxygenoxygen bond in the organic peroxideundergoes homolysis to produce alkoxy radicals.

    O OR R +R O O Rheat

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    STEP 2 (Propogation)

    An alkoxy radical abstracts a hydrogen atom

    from H-Br thus producing a bromine radical.

    Anti-Markovnikov Addition of HBr toAlkenes contd.

    +R O H Br R O H + Br

    Electrophile

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    Anti-Markovnikov Addition of HBr toAlkenes contd.

    STEP 3 (Propogation)

    C C

    H

    H

    H3C

    H

    Br

    C C

    Br

    H

    HCH3

    H

    2 alkyl radical

    The bromine radical then adds to the double bond of thealkene in such a way as to give the more stable secondaryalkyl radical.

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    Anti-Markovnikov Addition of HBr toAlkenes contd.

    In the product forming fourth step, the secondary radicalabstracts a hydrogen atom from HBr to give an alkylbromide.

    STEP 4 (Propogation)

    C C

    H

    H

    Br

    CH3

    H

    H Br

    C C

    H

    H

    Br

    CH3

    H

    H

    + Br

    Electrophile

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    Anti-Markovnikov ??

    Tertiary radical is more stable, so that intermediate forms

    faster.

    CH3 C

    CH3

    CH CH3 Br+

    CH3 C

    CH3

    CH CH3

    Br

    CH3 C

    CH3

    CH CH3

    Br

    X