1

BUSI 221 MORTGAGE FINANCE REVIEW QUESTIONS Detailed solutions are provided at the end of the questions. REVIEW QUESTION 1 Gordon and Helen have recently purchased a 2,500 square foot home for $300,000. They have requested a loan for $225,000. Real property taxes are estimated at $2,000 per annum. The loan will be at a rate of 10% per annum, compounded semi-annually with monthly payments to fully amortize the loan over 20 years. A. If the lender sets a GDSR of 32%, what is the minimum income required by the purchasers to

qualify for the desired loan? [$86,546.88] B. Assume that Gordon and Helen earn $80,000 per annum, Gordon has a car loan of $275 per

month and Helen has a boat loan with payments of $500 per quarter. If the lender sets a GDSR of 32% and a TDSR of 40%, what is the maximum allowable loan? Assume all other facts remain as in the original question. [$206,654.78 under GDSR]

REVIEW QUESTION 2 Five years ago, David obtained a mortgage from the Helpful Credit Union. The loan was written for a 5-year term at an interest rate of 13% per annum, compounded semi-annually. Monthly payments of $1,375 were specified, sufficient to amortize the principal over a 20-year period. The term of the loan is up. All payments were made on schedule. Dave may renew the mortgage for another 5-year term at the current rate of 7.5% per annum, compounded semi-annually. After considering his overall financial position, Dave decides he would like to make weekly payments. However, the maximum payment he can afford is $225 per week. The credit union is willing to allow this change as loan as the loan is amortized at the current rate over the remaining 15 years. What immediate balloon payment must Dave make to reduce the outstanding balance to the point where the weekly payments will fully amortize the loan over 15 years? [$4,446.62] REVIEW QUESTION 3 Colleen has a $120,000 mortgage with ABC Trust Company at an interest rate of 8% per annum, compounded semi-annually, amortized over 25 years with a 4-year term. Payments are monthly and rounded up to the next higher dollar. Colleen has made the first 40 payments on time and for the full amount. She then missed four payments and paid only $500 each on the final four payments. Calculate the OSB owing at the end of the term. [$118,227.97] REVIEW QUESTION 4 You are a loan officer for the Superior Insurance Company and are considering a loan secured by a luxury apartment building. You have been provided with an income statement for the building, which shows a rental schedule, which would generate $6,400,000 gross potential rental income per annum, if the units were continuously rented at rates advertised in the schedule. At full occupancy this building can also be expected to generate $230,000 per annum from parking fees

2

and $370,000 per annum from membership and usage fees in the Penthouse Club. The vacancy and bad debt loss estimate of 8% applies to each component of gross potential income. Expense items on the operating statement include $2,800,000 per annum depreciation of the building and equipment, $127,000 per annum to operate the Penthouse club, $880,000 per annum in property taxes, maintenance expenses of $440,000 per annum, utility costs of $362,000 per annum and property management fees of $678,000 per annum. Your guidelines include a net operating income capitalization rate of 9% per annum, a debt coverage ratio of 1.2 and a maximum loan-to-value ratio of 70%. The loan would require level quarterly payments adequate to fully amortize the principal over 20 years at an interest rate of 12% per annum, compounded quarterly. What is the largest loan you can make? [$24,871,587] REVIEW QUESTION 5 You have been hired as a consultant to provide your expertise to Mr. and Mrs. Miller regarding mortgage information. The Millers have been shopping for a loan and are confused by the terminology. (a) The Millers have found three repayment schemes and ask you to briefly define them in

simple terms: interest accrual loan;

interest only loan; and constant payment repayment scheme. (b) The Millers know they require $100,000 to help finance the purchase of their first home. They

call upon you, a mortgage finance expert, to calculate the size of the monthly payment and the outstanding balance owing at the end of a three-year term under each of the following scenarios:

(i) Bank A offers interest accrual loans at an effective annual rate of 12%. [no payment;

OSB = $140,492.80]

(ii) Credit Union B offers interest only loans at 11.75% per annum, compounded semi-annually. [payment = $956.02; OSB = $100,000 + $956.02]

(iii) Trust Company C offers a constant payment repayment scheme amortized over 20 years at a rate of 12.5% per annum, compounded monthly. [payment = $1,136.15; OSB = $95,898.62]

REVIEW QUESTION 6 Joanne and Fred recently arranged a $175,000 mortgage with the XYZ Trust Company. The mortgage contract is written at a rate of 10% per annum, compounded semi-annually, with monthly payments amortized over a 25-year period and a five-year term. Round the monthly payments up to the next higher dollar. a) Calculate the monthly payment required on this loan. [$1,566] b) Calculate the outstanding balance owing at the end of the term and after two years.

[$164,435.92; $171,379.96]

3

c) Calculate the interest and principal portions of the 1st, 36th and 60th monthly payments. Month Interest Principal 1 $1,428.85 $137.15 36 $1,383.69 $182.31 60 $1,344.40 $221.60

d) Calculate the total interest paid and total principal repaid during the term. [Total interest =

$83,395.92; Total principal = $10,564.08] e) Suppose that 2 years after the loan is initiated (i.e. 24 payments have been made), the XYZ

Trust Co. decides to liquidate their investment. At this point, if the trust company finds an investor who will pay $162,000, determine the following:

(i) What yield will XYZ Trust Co. earn on their investment, expressed, as an annual

rate with semi-annual compounding. [7.3877%]

(ii) What yield, expressed as an annual rate with semi-annual compounding, will the investor earn, and assuming the mortgage is held until the end of the term? [12.32374%]

(iii) If the investor demands a return of 15% per annum, compounded semi-annually,

on his/her investment, what price would the investor is willing to pay today? How much of a discount, in dollars, has the investor received? [Price = $152,010.38; Discount = $19,369.58]

REVIEW QUESTION 7 Dorothy and Leonard have recently purchased their first home in Langley, a suburb of Vancouver, BC, for $300,000. They require a $285,000 mortgage loan. The total family income is $70,000 per annum and they have no debts outstanding. Net property taxes are estimated to be $2,800 per year. The ABC Credit Union will provide funds on an insured first mortgage with an interest rate of 6% per annum, compounded semi-annually, amortized over 25 years with monthly payments. ABC requires a 32% gross debt service ratio and a 95% loan-to-value ratio on this insured loan. Assume that a 2.75% premium will be added onto the loan amount. a) What is the maximum first mortgage loan that Dorothy and Leonard qualify for?

[$255,284.95] b) How large of a second mortgage is required in order for the borrowers to obtain the total

amount desired? [$37,552.55] c) If the lender set a maximum total debt service ratio of 40%, will the borrowers qualify

under this constraint? The second mortgage rate will be 8% per annum, compounded semi-annually and payable with monthly payments over a 15-year amortization period. [Yes, max 2nd = $49,218.85 or TDSR is 38.1%]

REVIEW QUESTION 8 On January 1, 2006, Susan Shopper borrowed $95,000 as a mortgage loan. The interest rate on the loan was set at 10.5% per annum, compounded semi-annually, with level quarterly payments over a 15-year amortization period. The term was set for one year.

4

At the end of the one year term, January 1, 2007, Susan prepaid 10% of the outstanding balance and renewed the remaining balance for a 3-year term at a rate of 9.5% per annum, compounded semi-annually. Payments were maintained at the original amount. On the anniversary of her mortgage, January 1, 2008, she again prepaid 10% of the outstanding balance and increased future payments by 20%. Due to a recent cash flow problem, Susan did not make the final two payments due (October 1

st

and January 1st) and the previous two were for $1,000 each (April 1

st and July 1

st). All other

payments were on schedule and for the full amount. Calculate the amount owed to the lender on January 1, 2010, to fully repay the loan. [$65,323.35] REVIEW QUESTION 9 A potential borrower is analyzing several mortgage loan alternatives and wants you to calculate the payment obligation(s) under each option and the outstanding balance owing at the end of a two-year period. The loan amount required is $100,000. OPTIONS 1. A constant payment repayment scheme at 9% per annum, compounded semi-annually,

amortized over 25 years with monthly payments. [PMT = $827.98; OSB = $97,603.23] 2. A straight (line) principal reduction loan at 10% per annum, compounded semi-annually,

repaid over 10 years with semi-annual payments. [1st pmt = $10,000, 2nd pmt = $9,750 3rd pmt = $9,500, 4th pmt = $9,250; OSB = $80,000] 3. An interest accrual loan at a rate of 12% per annum, compounded semi-annually. [no

pmt; OSB = $126,247.70] 4. An interest only loan, repaid with quarterly payments at a rate of 12% per annum,

compounded semi-annually. [PMT = $2,956.30; OSB = $100,000 + $2,956.30] 5. A variable rate loan with the initial rate of 8% per annum, compounded semi-annually,

amortized over 25 years. Payments will be made annually. The interest rate adjustment will be made annually. Changes in interest rates will be reflected by changes in payments. The rate prevailing at the end of Year 1 will be 11% per annum, compounded semi-annually. Payments are to be calculated on the basis on the remaining amortization. [pmt year 1 = $9,496.25; pmt year 2 = $12,075.74; OSB = $97,739.48]

REVIEW QUESTION 10 J. Seinfeld arranged a $225,000 mortgage loan five years ago at an interest rate of 13.5% per annum, compounded semi-annually, with a 20-year amortization, a 10-year term and quarterly payments. Interest rates have declined since the mortgage was arranged. Seinfeld has decided to refinance the loan and is considering two options. Option 1 Seinfeld can refinance his existing loan over an amortization of 15 years and a 5-year term at an interest rate of 9.75% per annum, compounded semi-annually. The lender is willing to waive the prepayment penalty, but will charge $250 for administration costs. Assume the fee is paid in cash at the time of refinancing. Payments will continue to be made quarterly.

5

Option 2 Seinfeld can refinance his existing loan with a new lender over a 15-year amortization and a 5-year term at an interest rate of 9% per annum, compounded semi-annually. Payments will be made quarterly. The prepayment penalty charge on the existing loan is 3 months' interest. Additional refinancing costs will total $1,000. Assume the fees will be paid in cash at the time of refinancing. 1) Calculate the actual cost of refinancing under both options. Express your final solution as

an annual rate with semi-annual compounding.

[Option 1 - 9.78% per annum, compounded semi-annually Option 2 - 10.07% per annum, compounded semi-annually] 2) On the basis of interest rates, which option should Seinfeld choose?

[Choose Option 1] 3) What other considerations should Seinfeld take into account before making a final

decision? REVIEW QUESTION 11 Cooperative Credit Union has agreed to lend $150,000 to Bob and Lydia in the form of a shared appreciation mortgage on a purchase price of $200,000. This loan is written at an interest rate of 9.25% per annum, compounded semi-annually with monthly payments over a 20-year amortization and 5-year term. In addition, Bob and Lydia must give the lender 45% of any capital gains realized (after selling costs) upon the sale of the house. Selling costs are estimated to be 8% of the selling price. If Cooperative has an expected return of 14% per annum, compounded monthly and Bob and Lydia plan to sell the house at the end of the term, what rate of house appreciation does Cooperative expect to accrue? Express your answer as an effective annual rate. [11.18%]

REVIEW QUESTION 12 A lender has recently advanced a participation mortgage for $700,000 at a rate of 12% per annum, compounded monthly. The loan will be repaid with monthly payments over a 20-year amortization and a 5-year term. In addition, the lender will participate by taking 10% of the property's annual gross potential income. If the lender expects to earn 17% per annum, compounded annually overall, calculate the anticipated gross potential rental income. [$277,450.75] DETAILED SOLUTIONS FOR BUSI 221 REVIEW QUESTIONS QUESTION 1 SOLUTION A. $225,000 = PMT x a[[240, j12 = 9.79781526228%]] PMT = $2,141.25 per month = $25,695 per year Press Display Comments

10 NOM% 2 P/YR

6

EFF% 10.25 (j1) 12 P/YR NOM% 9.79781526228 (j12) 225000 PV 240 N 0 FV PMT -2,141.24496349

Gross Income = PIT/GDSR Gross Income = $25,695 + $2,000 0.32 Gross Income = $86,546.88 B. GDSR 0.32 = PMT + $2,000 $80,000 PMT = ($80,000 x 0.32) - $2,000 PMT = $23,600 per year = $1,966.66 per month PV = $1,966.66 x a[[240, j12 = 9.79781526228%]]

PV = $206,654.78

Press Display Comments 10 NOM% 2 P/YR EFF% 10.25 (j1) 12 P/YR NOM% 9.79781526228 (j12) 1966.66 +/- PMT 240 N 0 FV PV 206,654.776798

TDSR 0.40 = PMT + $2,000 + ($275 x 12) + ($500 x 4) $80,000 PMT = ($80,000 x 0.40) - $7,300 PMT = $24,700 per year = $2,058.33 per month PV = $2,058.33 x a[[240, j12 = 9.79781526228%]] PV = $216,287.37 Press Display Comments

10 NOM% 2 P/YR EFF% 10.25 (j1) 12 P/YR NOM% 9.79781526228 (j12) 2058.33 +/- PMT 240 N 0 FV PV 216,287.373886

Max loan is $206,654.78 under GDSR.

7

QUESTION 2 SOLUTION Original Loan PV = $1,375 x a[[240, j12 = 12.6612887764%]] PV = $119,822.54 OSB60 = $110,616.15

Press Display Comments 13 NOM% 2 P/YR EFF% 13.4225 (j1) 12 P/YR NOM% 12.6612887764 (j12) 1375 +/- PMT 240 N 0 FV PV 119,822.538077 119822.54 PV 60 INPUT AMORT = = = 110,616.151432

New Loan PV = $225 x a[[780, j52 = 7.36800965722%]] PV = $106,169.53

Press Display Comments 7.5 NOM% 2 P/YR EFF% 7.640625 (j1) 52 P/YR NOM% 7.36800965722 (j52) 225 +/- PMT 15 x 52 = N 780 0 FV PV 106,169.531071

Repay $110,616.15 - $106,169.53 = $4,446.62 QUESTION 3 SOLUTION $120,000 = PMT x a[[300, j12 = 7.86983632387%]] PMT = $916 per month

Press Display Comments 8 NOM% 2 P/YR EFF% 8.16 (j1) 12 P/YR NOM% 7.86983632387 (j12) 120000 PV 300 N 0 FV PMT -915.856145953

8

Option 1 FV of loan with no pmts less FV of pmts made FV of loan with no pmts FV = $120,000(1+ i)

48 = $164,228.29

Press Display Comments 8 NOM% 2 P/YR EFF% 8.16 (j1) 12 P/YR NOM% 7.86983632387 (j12) 120000 PV 48 N 0 PMT FV -164,228.286049

FV of pmts made 1st 40 pmts: FV = 916 x s[[40, j12 = 7.86983632387%]](1+imo)

8

FV = $41,739.72(1+imo)8

FV = $43,980.55 last 4 pmts: FV = $500 x s[[4, j12 = 7.86983632387%]] FV = $2,019.76

Press Display Comments 8 NOM% 2 P/YR EFF% 8.16 (j1) 12 P/YR NOM% 7.86983632387 (j12) 916 +/- PMT 40 N 0 PV FV 41,739.7158345 41739.72 PV 0 PMT 8 N FV -43,980.5494241 500 +/- PMT 0 PV 4 N FV 2,019.76075174

OSBterm = $164,228.29 - $43,980.55 - $2,019.76 = $118,227.98 Option 2 (Current Balance) OSB40 = $114,121.06 Find OSB44 FV = $114,121.06(1+imo)

4 = $117,144.35

New Loan

9

with PV of $117,144.35 + $500 payment per month, find OSB 4 periods later = $118,227.97

Press Display Comments 8 NOM% 2 P/YR EFF% 8.16 (j1) 12 P/YR NOM% 7.86983632387 (j12) 120000 PV 300 N 0 FV PMT -915.856145953 916 +/- PMT 40 INPUT AMORT = = = 114,121.062749 114121.06 PV 0 PMT 4 N FV -117,144.352559 117144.35 PV 500 +/- PMT 0 FV 4 INPUT AMORT = = = 118,227.974738

QUESTION 4 SOLUTION NOI = $6,400,000 + $230,000 + $370,000 (total of $7,000,000) -8% Vacancy of $560,000 - expenses of $2,487,000* = $3,953,000 *Expenses = $880,000 + $440,000 + $362,000 + $678,000 + $127,000 = $2,487,000 Market Value = $3,953,000/0.09 = $43,922,222.22 Loan-Value = 70% x $43,922,222.22 = $30,745,556 DCR PMT = $3,953,000/1.2 PMT = $3,294,166.66 per year = $823,541.66 per quarter PV = $823,541.66 x a[[80, j4 = 12%]] PV = $24,871,587

Press Display Comments 12 I/YR 4 P/YR 823541.66 +/- PMT 80 N 0 FV PV 24,871,586.8614

Binding constraint is DCR, maximum loan is $24,871,587. QUESTION 5 SOLUTION

10

(a) interest accrual loan: no payment during loan; owe loan amount and accumulated interest over term interest only loan: periodic payments of interest only; owe principal at end constant payment: blended and equal payments; increasing principal and decreasing interest over time

(b) Interest Accrual

FV = $100,000(1+0.12)

3 = $140,492.80

Press Display Comments 12 I/YR 1 P/YR 100000 PV 3 N 0 PMT FV -140,492.8 Interest Only $100,000 x imo = $956.02 Where imo = j1212 and j12 = 11.4722852558%

Press Display Comments

11.75 NOM% 2 P/YR EFF% 12.09515625 (j1) 12 P/YR NOM% 11.4722852558 (j12)

12 = 9.56023771E-1 (imo)

% x 100000 = 956.023771317 Constant Payment Repayment Scheme $100,000 = PMT x a[[240, j12=12.5%]] PMT = $1,136.15 OSB36 = $95,898.62

Press Display Comments 12.5 I/YR 12 P/YR 100000PV 240 N 0 FV PMT -1,136.14054971 1136.15 +/- PMT 36 INPUT AMORT = = = 95,898.6195312

QUESTION 6 SOLUTION

(a) $175,000 = PMT x a[[300, j12=9.79781526228%]] PMT = $1,566.00 Press Display Comments

11

10 NOM% 2 P/YR EFF% 10.25 (j1) 12 P/YR NOM% 9.79781526228 (j12) 175000 PV 300 N 0 FV PMT -1,565.35264363 1566 +/- PMT

(b) OSB60 = $164,435.99

Press Display Comments 60 INPUT AMORT = = = 164,435.916103 24 INPUT AMORT = = = 171,379.956183

(c) Month Interest Principal 1 $1,428.85 $137.15 36 $1,383.69 $182.31 60 $1,344.40 $221.60

Press Display Comments 1 INPUT AMORT = -137.1519402 = -1,428.84805908 36 INPUT AMORT = -182.30819974 = -1,383.69180026

60 INPUT AMORT = -221.59675621 = -1,344.40324379 (d) Total interest = $83,395.92; Total principal = $10,564.08

Press Display Comments 1 INPUT 60 AMORT = -10,564.0838966

= -83,395.9161034

(e) (i) $175,000 = $1,566 x a[[24, j12=?]] + $162,000(1+imo)-24

j12 = 7.27648632236% j2 = 7.38768899418% Press Display Comments 12 P/YR

175000 PV 1566 +/- PMT 162000 +/- FV 24 N I/YR 7.27648632236 (j12)

EFF% 7.52413386587 (j1) 2 P/YR NOM% 7.38768899418 (j2)

(ii) $162,000 = $1,566 x a[[36, j12=?]] + $164,435.92(1+imo)

-36

j12 = 12.0187552008% j2 = 12.3237427874%

12

Press Display Comments 12 P/YR

162000 PV 1566 +/- PMT 164435.92 +/- FV 36 N I/YR 12.0187552008 (j12)

EFF% 12.7034293781 (j1) 2 P/YR NOM% 12.3237427874 (j2)

(iii) PV = $1,566 x a[[36, j12=14.5516549135%]] + $164,435.92(1+imo)-36

PV = $152,010.38 Press Display Comments 15 NOM% 2 P/YR EFF% 15.5625 (j1) 12 P/YR NOM% 14.5516549135 (j12)

1566 +/- PMT 164435.92 +/- FV 36 N PV 152,010.380609 Discount = $171,379.96 - $152,010.38 = $19,369.58 QUESTION 7 SOLUTION

(a) LTV 95% x $300,000 = $285,000 Premium = 2.75% x $285,000 = $7,837.50 Face Value = $285,000 + $7,837.50 = $292,837.50 GDSR PMT = (0.32 x $70,000) - $2,800 PMT = $19,600 per year = $1,633.33 per month PV = $1,633.33 x a[[300, j12 = 5.92634643744%]] Press Display Comments 6 NOM% 2 P/YR EFF% 6.09 (j1) 12 P/YR NOM% 5.92634643744 (j12)

1633.33 +/- PMT 300 N 0 FV

PV 255,284.946976 $255,284.95 < face value of $292,837.50 Maximum loan = $255,284.95

13

(b) Maximum 2nd

mortgage = $292,837.50 - $255,284.95 = $37,552.55

(c) TDSR PMT = (0.40 x $70,000) – ($1,633.33 x 12) - $2,800 PMT = $5,600.04 per year = $466.67 per month PV = $466.67 x a[[180, j12 = 7.86983632387%]] Press Display Comments 8 NOM% 2 P/YR EFF% 8.16 (j1) 12 P/YR NOM% 7.86983632387 (j12)

466.67 +/- PMT 180 N 0 FV

PV 49,218.8524284 Maximum 2

nd mortgage of $49,218.85 is greater than amount desired of $37,552.55;

therefore, borrowers qualify for loan. Alternatively, find payment on desired amount and calculate TDSR $37,552.55 = PMT x a[[180, j12 = 7.86983632387%]] Press Display Comments 8 NOM% 2 P/YR EFF% 8.16 (j1) 12 P/YR NOM% 7.86983632387 (j12) 37552.55 PV

180 N 0 FV

PMT -356.055609667 TDSR = [($1,633.33 + $356.06)(12) + $2,800]/$70,000 TDSR = $26,672.68/$70,000 TDSR = 38.1% < maximum TDSR of 40%

QUESTION 8 SOLUTION

$95,000 = PMT x a[[60, j4 = 10.3656905737%]] PMT = $3,137.90 OSB4 = $92,188.86 (January 1, 2007) Press Display Comments 10.5 NOM% 2 P/YR EFF% 10.775625 (j1) 4 P/YR NOM% 10.3656905737 (j4)

95000 PV

14

60 N 0 FV

PMT -3,137.89626518 3137.9 +/- PMT 4 INPUT AMORT = = = 92,188.8626446 Prepay 10% = $92,188.86 x 10% = $9,218.89 “new” loan Jan 1, 2007 = $92,188.86 - $9,218.89 “new” loan = $82,969.97 $82,969.97 = $3,137.90 x a[[N, j4 = 9.38978980917%]] N = 41.7792892823 quarters OSB4 = $78,038.80 Jan 1, 2008 Press Display Comments 9.5 NOM% 2 P/YR EFF% 9.725625 (j1) 4 P/YR NOM% 9.38978980917 (j4)

82969.97 PV 3137.9 +/- PMT 0 FV N 41.7792892823 4 INPUT AMORT = = = 78,038.7976613 Prepay 10% = $78,038.80 x 10% = $7,803.88 “new” loan Jan 1, 2008 = $78,038.80 - $7,803.88 “new” loan Jan 1, 2008 = $70,234.92 New payment = $3,137.90 x 1.2 = $3,765.48 $70,234.92 = $3,765.48 x a[[N, j4 = 9.38978980917%]] N = 24.8238504473 8 payments remain to end of term: 4 in full and on time; 2 for $1,000 each and final two

payments not made Option 1 OSB at end assuming all payments made + FV of unpaid payments (deficit amount) = OSB as at Jan 1, 2010 + FV of unpaid payments OSB Jan 1, 2010 assuming all remaining payments made in full

Press Display Comments 9.5 NOM% 2 P/YR EFF% 9.725625 (j1) 4 P/YR

15

NOM% 9.38978980917 (j4) 70234.92 PV

3765.48 +/- PMT 0 FV N 24.8238504473 8 INPUT AMORT = = = 51,842.3189994 OSB Jan 1, 2010 FV of final two unpaid payments FV = $3,765.48 x s[[2, j4 = 9.38978980917%]] FV = $7,619.35 Press Display Comments 9.5 NOM% 2 P/YR EFF% 9.725625 (j1) 4 P/YR NOM% 9.38978980917 (j4) 3765.48 +/- PMT 0 PV 2 N FV 7,619.35266433 FV of two payments for $1,000 (shortfall amount is $2,765.48 ($3,765.48 - $1,000)) FV = $2,765.48 x s[[2, j4 = 9.38978980917%]](1+iq)

2

FV = $5,595.88(1+iq))2

FV = $5,861.68 Press Display Comments 9.5 NOM% 2 P/YR EFF% 9.725625 (j1) 4 P/YR NOM% 9.38978980917 (j4) 2765.48 +/- PMT 0 PV 2 N FV 5,595.8781898 5595.88 PV 0 PMT 2 N FV -5,861.6843 OSB as at January 1, 2010 = OSB at end assuming all payments made + FV of unpaid payments (deficit amount) OSB Jan 1, 2010 = $51,842.32 + $7,619.35 + $5,861.68 OSB Jan 1, 2010 = $65,323.35 Option 2 Find the FV (OSB Jan 1, 2010) assuming no further payments are made and then subtract the FV of the payments actually made in the final year

16

FV of loan (no further payments) FV = OSB Jan 1, 2009(1+iq)

4

FV = $61,465.08(1+iq)4

OSB Jan 1, 2010 (no further payments) = FV = $61,465,08(1+iq)4

FV = $67,442.94 (OSB Jan 1, 2010)

Press Display Comments 9.5 NOM% 2 P/YR EFF% 9.725625 (j1) 4 P/YR NOM% 9.38978980917 (j4)

70234.92 PV 3765.48 +/- PMT 0 FV N 24.8238504473 4 INPUT AMORT = = = 61,465.080358 OSB Jan 1, 2009 61465.08 PV 0 PMT 4 N FV 67,442.9431867 OSB Jan 1, 2010 FV of payments made April 1, 2009 payment FV = $1,000(1+iq)

3

FV = $1,072.09 July 1, 2009 payment FV = $1,000(1+iq)

2

FV = $1,047.50

Press Display Comments 2 P/YR EFF% 9.725625 (j1) 4 P/YR NOM% 9.38978980917 (j4)

1000 PV 0 PMT 3 N FV -1,072.08951206 FV of April 1st payment 2 N FV -1,047.5 FV of July 1

st payment

OSB as at Jan 1, 2010 = $67,442.94 - $1,072.09 - $1,047.50 OSB as at Jan 1, 2010 = $65,323.35

QUESTION 9 SOLUTION

1. Constant payment repayment scheme $100,000 = PMT x a[[300, j12 = 8.83574763%]] PMT = $827.98 OSB24 = $97,603.23

17

Press Display Comments 9 NOM% 2 P/YR EFF% 9.2025 (j1) 12 P/YR NOM% 8.83574763 (j12) 100000 PV 300 N 0 FV PMT -827.977389468 827.98 +/- PMT 24 INPUT AMORT = = = 97,603.2266763

2. Straight line principal reduction Principal amount of each payment = $100,000/20 = $5,000 per semi-annual period Total payment = Interest + Principal Interest1 = $100,000 x 5% = $5,000 Payment1 = $5,000 + $5,000 = $10,000 Interest2 = ($100,000 - $5,000) x 5% Interest2 = $95,000 x 5% = $4,750 Payment2 = $4,750 + $5,000 = $9,750 Interest3 = ($95,000 - $5,000) x 5% Interest3 = $90,000 x 5% = $4,500

Payment3 = $4,500 + $5,000 = $9,500

Interest4 = ($90,000 - $5,000) x 5% Interest4 = $85,000 x 5% = $4,250 Payment4 = $4,250 + $5,000 = $9,250

OSB4 = $100,000 – ($5,000 x 4) = $80,000

3. Interest accrual loan

FV = $100,000(1+6%)

4

FV = $126,247.70

Press Display Comments 12 I/YR 2 P/YR 100000PV 0 PMT 4 N FV -126,247.696

4. Interest only loan

Interest = $100,000 x iq

Interest = $100,000 x 2.95630140988% Interest = $2,956.30 End of Year 2, owe $100,000 + 8

th payment of $2,956.30

18

Press Display Comments 12 NOM% 2 P/YR EFF% 12.36 (j1) 4 P/YR NOM% 11.8252056395 (j4) 4 = 2.95630140988 (iq)

% 2.95630141E-2 x 100000 = 2,956.30140988

5. Variable rate loan Year 1 $100,000 = PMT x a[[25, j1 = 8.16%]] PMT = $9,496.25 OSB1 = $98,663.75 Press Display Comments 8 NOM% 2 P/YR EFF% 8.16 (j1) 1 P/YR NOM% 8.16 100000 PV 25 N 0 FV PMT -9,496.24089171 9496.25 +/- PMT 1 INPUT AMORT = = = 98,663.75 OSBYear 1

Year 2 $98,663.75 = PMT x a[[24, j1 = 11.3025%]] PMT = $12,075.74 OSB2 = $97,739.48

Press Display Comments 11 NOM% 2 P/YR EFF% 11.3025 (j1) 1 P/YR NOM% 11.3025 98663.75 PV 24 N 0 FV PMT -12,075.7330769 12075.74 +/- PMT 1 INPUT AMORT = = = 97,739.4803438 OSBYear 2

QUESTION 10 SOLUTION Original Loan

$225,000 = PMT x a[[80, j4 = 13.2795663954%]]

19

PMT = $8,060.87 OSB20 = $208,589.46 Press Display Comments 13.5 NOM% 2 P/YR EFF% 13.955625 j1 4 P/YR NOM% 13.2795663954 j4

225000 PV 80 N

0 FV PMT -8,060.86323705 8060.87 +/- PMT 20 INPUT AMORT = = = 208,589.463563 OSB today Option 1 $208,589.46 = PMT x a[[60, j4 = 9.63398296528%]] PMT = $6,608.58 OSB20 = $168,479.33 $208,589.46 - $250 = $6,608.58 x a[[20, j4 = ?]] + $168,479.33(1+iq)

-20

j4 = 9.66701456742% j2 = 9.7838285307% Press Display Comments 9.75 NOM% 2 P/YR EFF% 9.98765625 j1 4 P/YR NOM% 9.63398296528 j4

208589.46 PV 60 N

0 FV PMT -6,608.57357552 6608.58 +/- PMT 20 INPUT AMORT = = = 168,479.332974 208589.46 – 250 = 208339.46 PV 6608.58 +/- PMT 168479.33 +/- FV 20 N I/YR 9.66701456742 j4 EFF% 10.0231367825 j1 2 P/YR NOM% 9.7838285307 j2 Option 2 $208,589.46 = PMT x a[[60, j4 = 8.90096600522%]] PMT = $6,332.36 OSB20 = $166,574.79

20

Penalty = $208,589.46 x (13.1352625224%12) x 3 = $6,849.69

Where 13.1352625224% is the j12 equivalent for the original contract rate of j2 = 13.5% $208,589.46 - $6,849.69 - $1,000 = $6,332.36 x a[[20, j4 = ?]] + $166,574.79(1+iq)

-20

j4 = 9.94960194553% j2 = 10.0733451692% Press Display Comments 9 NOM% 2 P/YR EFF% 9.2025 j1 4 P/YR NOM% 8.90096600522 j4

208589.46 PV 60 N

0 FV PMT -6,332.35924893 6332.36 +/- PMT 20 INPUT AMORT = = = 166,574.786777 208589.46 – 6849.69 – 1000 = PV 200,739.77 4 P/YR 6332.36 +/- PMT 166574.79 +/- FV 20 N I/YR 9.94960194553 j4 EFF% 10.3270258764 j1 2 P/YR NOM% 10.0733451692 j2 QUESTION 11 SOLUTION $150,000 = PMT x a[[240, j12 = 9.07662356656%]] PMT = $1,356.99 OSB60 = $133,190.98 $150,000 = $1,356.99 x a[[60, j12 = 14%]] + $133,190.98(1+imo)

-60 + SHARE(1+imo)

-60

FV = $183,875.55 - $133,190.98 FV = $50,684.57 (Share) Press Display Comments 9.25 NOM% 2 P/YR EFF% 9.46390625 j1 12 P/YR NOM% 9.07662356656 j12

150000 PV 240 N

0 FV PMT -1,356.98968515 1356.99 +/- PMT 60 INPUT AMORT = = = 133,190.981599

21

14 I/YR 12 P/YR 150000 PV 1356.99 +/- PMT 60 N FV -183,875.546116 Share = $50,684.57 Total Gain = $50,684.57/0.45 = $112,632.38 NSP = $112,632.38 + $200,000 = $312,632.38 GSP = $312,632.38/0.92 = $339,817.80 $200,000(1+ia)

5 = $339,817.80

ia = j1 = 11.18% Press Display Comments 200000 PV 339817.8 +/- FV 5 N 0 PMT 1 P/YR I/YR 11.1842384266 QUESTION 12 SOLUTION $700,000 = PMT x a[[240, j12 = 12%]] PMT = $7,707.61 OSB60 = $642,209.72 $700,000 = $7,707.61 x a[[60, j12 =15.8035333578%]] + $642,209.72(1+imo)

-60 +

Participation Pmt x a[[5 years, j1=17%]] $700,000 = $611,233.90 + Participation Pmt x a[[5 years, j1=17%]] $88,766.10 = Participation Pmt x a[[5 years, j1=17%]] Participation Pmt = $27,745.08 Gross Potential Rental Income = $27,745.08 0.10 = $277,450.75

Press Display Comments

12 I/YR 12 P/YR

700000 PV 240 N

0 FV PMT -7,707.60293499 7707.61 +/- PMT 60 INPUT AMORT = = = 642,209.724913 17 NOM% 1 P/YR EFF% 12 P/YR NOM% 15.8035333578

7707.61 +/- PMT 642209.72 +/- FV 60 N

22

PV 611,233.890432 17 I/YR 1 P/YR 700000 – 611233.89 = 88,766.11 PV 5 N 0 FV PMT -27,745.07583645 0.1 = -277,450.783645