Bulls Eye Sample Test Paper 2012
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Transcript of Bulls Eye Sample Test Paper 2012
CODE : A PAGE NO. # 15
Q.1 A positive number whose reciprocal equals oneless than the number, is
(A)
2
21(B)
4
12
(C)
2
51(D)
2
52
Q.2 A student took four exams, each time doublingthe score of the previous exam. If the average ofthe four exams was x then the score of the firstexam was kx where k equals
(A) 4
1(B)
9
2
(C) 16
3(D)
15
4
Q.3 Given a triangle with vertices A, B, C
if tan A = 3
2, tan B =
4
3 and the length of the
altitude from C to side AB is 6 then the area of thetriangle is(A) 30 (B) 36(C) 42 (D) 51
Q.4 One side of a rectangle is 5 meters long. The areaA of the rectangle as a function of its perimeter p,is
(A) A = 5p (B) A = 252
p5
(C) A = 5p � 25 (D) A = 252
p5
Q.5 Let A, B, C be the vertices of an equilateral triangle,and let D, E be points on the side AB such thatsegments AD, DE and EB each have length 1.Then tan CDE equals
(A) 23 (B) 32
(C) 33 (D) 2
33
Q.1 ,d /kukRed la[;k ftldk O;qRØe ml la[;k ls ,d
de gks] rks og la[;k gksxh&
(A)
2
21(B)
4
12
(C)
2
51(D)
2
52
Q.2 ,d fo|kFkhZ pkj ijh{kk,a nsrk gS] çR;sd ckj og viuh
fiNyh ijh{kk ds vadks dk nqxquk dj nsrk gSA ;fn pkj
ijh{kkvksa dk vkSlr x gks] rks çFke ijh{kk ds vad kx gksa]rks k cjkcj gksxk&
(A) 4
1(B)
9
2
(C) 16
3(D)
15
4
Q.3 ,d f=Hkqt ftlds 'kh"kZ A, B, C gS ;fn tan A = 3
2,
tan B = 4
3 vkSj dks.k C ls Hkqtk AB ij Mkys x;s
yEc dh yEckbZ 6 gks] rks f=Hkqt dk {ks=Qy gksxk&
(A) 30 (B) 36(C) 42 (D) 51
Q.4 vk;r dh ,d Hkqtk 5 ehVj yEch gSA vk;r dk {ks=Qy
A ifjeki p ds :i esa gksxk&
(A) A = 5p (B) A = 252
p5
(C) A = 5p � 25 (D) A = 252
p5
Q.5 ekuk A, B, C ,d leckgq f=Hkt ds 'kh"kZ gS rFkk D, EHkqtk AB ij bl çdkj gSa fd AD, DE vkSj EB çR;sddh yEckbZ bZdkbZ gSA rks tan CDE cjkcj gksxk&
(A) 23 (B) 32
(C) 33 (D) 2
33
BULL'S EYE (10th Pass) 2011Select the correct alternative. Only one is correct. [90×2 = 180]
There is NEGATIVE marking. For each wrong answer 0.5 mark will be deducted.
CODE : A PAGE NO. # 16
Q.6 The score of a certain multiple choice exam iscomputed as the number of right answers minusone fourth of the number of wrong answers. If thenumber of questions answered is N and the scoreis S then the number of right answers is
(A) 4
NS5 (B)
5
NS4
(C) 5
NS3 (D)
5
NS4
Q.7 In the figure shown, each edge of BCD haslength 1, D lies on AC, and ABC = 90°. The
length AB, is
(A) 2
3(B) 2
A B
C
D
(C) 2 (D) 3
Q.8 The sum of the distances AD and BD in the figureshown, is
A B
CD
8
21
6
(A) 27 (B) 28(C) 29 (D) 31
Q.9 In the figure shown, ABC and BDA areboth right angles. If v + w = 35 and x + y = 37,then the value of y, is(A) 11
xDC A
B
wv
y(B) 12(C) 13(D) 14
Q.10 Suppose AB and CD are two perpendicularchords of the same circle that intersect at the pointE, AE = 12, DE = 4 and CE = 6. The area of the
circle, is(A) 50
D
C
A BE
124
6(B) 45(C) 40(D) 35
Q.6 ,d cgqfodYih; ijh{kk esa vad bl çdkj tksMs tkrs gS
fd lgh gy fd, ç'uks dh la[;k esa ls xyr gy fd,
ç'uks dh la[;k dk ,d pkSFkkbZ ?kVk fn;k tkrk gSA ;fn
gy fd, ç'uks dh la[;k N gks rFkk dqy çkIr vad Sgksa] rks lgh gy fd, x, ç'uks dh la[;k gksxh&
(A) 4
NS5 (B)
5
NS4
(C) 5
NS3 (D)
5
NS4
Q.7 fp=kuqlkj, f=Hkqt BCD dh çR;sd Hkqtk dh yEckbZ
1 gS rFkk D Hkqtk AC ij fLFkr gS vkSj ABC = 90°
gSA yEckbZ AB cjkcj gksxh&
(A) 2
3(B) 2
A B
C
D
(C) 2 (D) 3
Q.8 fn;s x;s fp= ds vuqlkj] Hkqtk AD rFkk Hkqtk BD dh
yEckbZ;ksa dk ;ksx gksxk&
A B
CD
8
21
6
(A) 27 (B) 28(C) 29 (D) 31
Q.9 n'kkZ;s x;s fp=kuqlkj, ABC rFkk BDA nksuksledks.k gSA ;fn v + w = 35 vkSj x + y = 37 gks] rksy dk eku gksxk
(A) 11
xDC A
B
wv
y(B) 12(C) 13(D) 14
Q.10 ekuk AB vkSj CD ,d gh oÙk dh nks thok,a gS tks
ijLij yEcor gS] tks ,d nwljs dks fcUnq E ij blçdkj dkVrs gS fd AE = 12, DE = 4 vkSj CE = 6 gSAo`Ùk dk {ks=Qy gksxk&
(A) 50D
C
A BE
124
6
(B) 45(C) 40(D) 35
CODE : A PAGE NO. # 17
Q.11 An isosceles triangle has been cut from one cornerof a square with side s. If the area of the triangle isone quarter of the area of the original square, thenthe height h of the triangle is
(A) s2
1(B) s
2
24
45°
s
s
h(C) s4
1(D) s
2
1
Q.12 A certain point A inside an equilateral triangle withperimeter P is at distances x, y and z from thethree sides, respectively. The sum (x + y + z) isalways(A) P
(B) 3
P
z
yx
A
(C) 3
P2
(D) 32
P
Q.13 Which one of the numbers listed below is not adivisor of the number N = (230 � 1), is equal to
(A) 25 � 1 (B) 25 + 1(C) 26 � 1 (D) 210 + 1
Q.14 The two shortest sides of a right triangle have
lengths 3 and 2. Let be the smallest interior
angle of this triangle, then the value of sin , is
(A) 7
3(B)
7
4
(C) 5
3(D)
5
4
Q.15 Let x =
15·15·15·15
4
16
1
8
1
4
1
2
1
then (x + 1)48 is(A) 25 (B) 125(C) 625 (D) 5
Q.11 ,d oxZ ftldh Hkqtk s gS esa ls ,d lef}ckgq f=Hkqt
dkVk tkrk gSA ;fn f=Hkqt dk {ks=Qy] oxZ ds okLrfod
{ks=Qy dk pkSFkkbZ gks] rks f=Hkqt dh Å¡pkbZ h gksxh&
(A) s2
1(B) s
2
24
45°
s
s
h(C) s4
1(D) s
2
1
Q.12 ,d leckgq f=Hkqt ftldk ifjeki P gS fd vUnj ,d
fcUnq A bl çdkj fLFkr gS fd mldh rhu Hkqtkvksa ls
nwjh Øe'k% x, y vkSj z gS] rks ;ksx (x + y + z) ges'kkgksxk&
(A) P
(B) 3
P
z
yx
A
(C) 3
P2
(D) 32
P
Q.13 uhps nh la[;kvksa esa ls dkSu lh ,d la[;k
N = (230 � 1) dh Hkktd ugha gS&
(A) 25 � 1 (B) 25 + 1(C) 26 � 1 (D) 210 + 1
Q.14 ledks.kh; f=Hkqt dh nks NksVh Hkqtk,a Øe'k% 3 vkSj
2 gSaA ekuk f=Hkqt dk lcls NksVk vkUrfjd dks.k gS]
rks sin dk eku gksxk&
(A) 7
3(B)
7
4
(C) 5
3(D)
5
4
Q.15 ekuk x =
15·15·15·15
4
16
1
8
1
4
1
2
1
rks (x + 1)48 cjkcj gksxk&(A) 25 (B) 125(C) 625 (D) 5
CODE : A PAGE NO. # 18
Q.16 If cos5x=Acos5x+Bcos4x+Ccos3x+Dcos2x+Ecos x+F,
for all value of x, then the sum of A, B, C, D, Eand F equals(A) 0 (B) 1(C) 6 (D) none
Q.17 If sin x + cos x = 1, then let the value of(sin3x + cos3x) is and if tanx + cot x = 2, thenlet the value of (tan4x + cot4x) is .Let x2 + bx + c = 0 is the quadratic equationwhose roots are and . The value of (b + c)equals(A) 1 (B) � 1(C) 5 (D) 6
Q.18 If A to F are the vertices of a regular hexagonlisted in clockwise order, consider the triangleACE. The ratio of the area of the triangle to thearea of the hexagon, is(A) 1 : 2 (B) 1 : 3
(C) 2 : 3 (D) 1 : 3
Q.19 Difference of two different irrational numbers(A) cannot be an integer.(B) cannot be a rational number.(C) can be a rational number.(D) can not be a prime.
Q.20 The remainder when (x51 + 51) is divided by(x + 1), is
(A) 0 (B) 1(C) 51 (D) 50
Q.21 Solve for n in 4n + 4n + 4n + 4n = 22010.(A) 1005 (B) 2010(C) 1004 (D) 1003
Q.22 If sin cos = 1, then cos sin is equal to(A) 1 (B) 0
(C) � 1 (D) 2
1
Q.16 ;fn
cos5x=Acos5x+Bcos4x+Ccos3x+Dcos2x+Ecos x+F,x ds lHkh ekuksa ds fy, gks] rks A, B, C, D, E vkSj Fdk ;ksxQy gksxk&
(A) 0 (B) 1(C) 6 (D) dksbZ ugha
Q.17 ;fn sin x + cos x = 1 gks] rks ekuk fd (sin3x + cos3x)dk eku gksxk vkSj ;fn tanx + cot x = 2 gks] rks ekukfd (tan4x + cot4x) dk eku gksxkA
ekuk x2 + bx + c = 0 ,d f}?kkr lehdj.k gS ftlds
ewy ,oa gS] rks (b + c) dk eku cjkcj gksxk&
(A) 1 (B) � 1(C) 5 (D) 6
Q.18 ;fn A ls F fu;fer "kV~dks.k ds 'kh"kZ gS tks nf{k.kkorhZ
Øe esa gSaA ekuk f=Hkqt ACE gks] rks f=Hkqt o "kV~dks.k
ds {ks=Qy dk vuqikr gksxk&
(A) 1 : 2 (B) 1 : 3
(C) 2 : 3 (D) 1 : 3
Q.19 nks vifjes; la[;kvksa ds chp esa vUrj
(A) iw.kk±d ugha gks ldrkA
(B) ifjes; ugha gks ldrkA
(C) ifjes; gks ldrk gSA
(D) vHkkT; ugha gks ldrkA
Q.20 ;fn (x51 + 51) dks (x + 1) }kjk foHkkftr fd;k tkrk
gS] rks 'ks"kQy gksxk&
(A) 0 (B) 1(C) 51 (D) 50
Q.21 n ds fy, gy djsa 4n + 4n + 4n + 4n = 22010.(A) 1005 (B) 2010(C) 1004 (D) 1003
Q.22 ;fn sin cos = 1 gks] rks cos sin cjkcjgksxk&
(A) 1 (B) 0
(C) � 1 (D) 2
1
CODE : A PAGE NO. # 19
Q.23 The given square is a magic square. All rows,columns, and main diagonals add up to 3a. Thevalue of the centre square, is(A) a � 2(B) a � 1 3a
1a5a
(C) a(D) a + 1
Q.24 A bucket is currently full of water and has a massof 29 kg. When it is half filled with water, it has amass of 18.5 kg. The mass of the bucket when itis filled to one third of maximum capacity, is(A) 14 (B) 15(C) 16 (D) 17
Q.25 Let T be equilateral triangle of height h and Scan be a square of side s. If T and S have the
same area, then s
h is
(A) 4
1
3 (B) 32
(C) 4 32 (D) 1
Q.26 If Ac the area of a square inscribed in a circle orradius r and As is the area of the squareinscribed in a semicircle of the same circle, then
s
c
A
A is equal to
(A) 3
4(B)
4
5
(C) 2
5(D) 4
Q.27 The equation x2 � (2k + 1) x + k2 � 1 = 0 has two
roots : sin and cos , where k and are bothreal constants. Then k equals(A) � 1 (B) 0
(C) 2
1(D) 1
Q.28 A two digit number N contains the smaller of thetwo digits in the unit place. The product of thedigits is 40 and the difference between the digits is3. The sum of the digits in N is(A) 11 (B) 12(C) 13 (D) 14
Q.23 fn;k x;k oxZ ,d tknwbZ oxZ gSA lHkh iafDr;ks] LrEHkksa
,oa fod.kks± ds ekuksa dk ;ksx 3a gSA rks dsUnzh; oxZ dk
eku gksxk&
(A) a � 2(B) a � 1 3a
1a5a
(C) a(D) a + 1
Q.24 ,d ckYVh ikuh ls iwjh Hkjh gqbZ gS rFkk ftldk otu
29 fdxzk gSA tc ;g ikuh ls vk/kh Hkjh gqbZ gS rc
bldk otu 18.5 fdxzk gks tkrk gSA tc ;g ,d
frgkbZ ikuh ls Hkjh gks rc ckYVh dk otu gksxk
(A) 14 (B) 15(C) 16 (D) 17
Q.25 ekuk T ,d leckgq f=Hkqt ftldh Å¡pkbZ h gS rFkk,d oxZ S ftldh Hkqtk s gSA ;fn T vkSj S dk
{ks=Qy leku gks rks s
h dk eku gksxk&
(A) 4
1
3 (B) 32
(C) 4 32 (D) 1
Q.26 ;fn Ac oÙk ds vUnj cuk, x, oxZ dk {ks=Qy gS rFkk
o`Ùk dh f=T;k r gS vkSj As fn;s x;s o`Ùk ds v)ZoÙk
ds vUnj cuk;s x;s oxZ dk {ks=Qy gS] rks
s
c
A
A cjkcj
gksxk&
(A) 3
4(B)
4
5
(C) 2
5(D) 4
Q.27 lehdj.k x2 � (2k + 1) x + k2 � 1 = 0 ds nks ewy gS
sin vkSj cos , tgk¡ k rFkk nksuksa okLrfod vpj
gS] rks k dk eku cjkcj gksxk&
(A) � 1 (B) 0
(C) 2
1(D) 1
Q.28 nks vadks dh la[;k N ftlesa bZdkbZ LFkku ij NksVh
la[;k gSA nksuksa vadks dk xq.kuQy 40 gS vkSj nksuksa vadks
ds chp vUrj 3 gSA la[;k N ds nksuksa vadks dk ;ksx
gksxk&
(A) 11 (B) 12(C) 13 (D) 14
CODE : A PAGE NO. # 20
Q.29 If ax = cq = b and cy = az = d, then
(A) xy = qz (B) z
q
y
x
(C) x + y = q + z (D) x � y = q � z
Q.30 The smallest prime number that divides the sum(711 + 1113) is(A) 2 (B) 3(C) 5 (D) 7
Q.31 In quadrilateral ABCD,AC BC and AD CD,as shown.
A
D
C
11B
If AB = 11 units, then the sum of the squares ofthe sides of this quadrilateral, is(A) 122 (B) 132(C) 242 (D) 121
Q.32 ABCD is a trapezium and EF is its median. Thelength of the segment GH, is(A) 3(B) 2
B
F
CD
E
A
G H
6
14
(C) 4(D) 5
Q.33 The sum of all distinct solutions for
x : 111x7x
30x11x22
, is
(A) 11 (B) 13(C) 18 (D) 25
Q.34 Which one of the following in NOT a Pythagoreantriplet?(A) 13, 84, 85 (B) 24, 45, 63(C) 48, 55, 73 (D) 65, 72, 97
Q.35 The expression E = xtanxsec
xcosxsecxtan
wherever defined, simplifies to(A) cosec x (B) sin x(C) tan x (D) cot x
Q.36 Two circles touch each other externally. If the sumof their area is 28and the distance between theircentres is 6 then the length of their externalcommon tangent is(A) 4 (B) 8
(C) 102 (D) 28
Q.29 ;fn ax = cq = b vkSj cy = az = d gks] rks
(A) xy = qz (B) z
q
y
x
(C) x + y = q + z (D) x � y = q � z
Q.30 ;ksxQy (711 + 1113) dks foHkkftr djus okyh lcls
NksVh vHkkT; la[;k gksxh&
(A) 2 (B) 3(C) 5 (D) 7
Q.31 prqHkqZt ABCD esa]AC BC vkSj AD CD,tSlk fd n'kkZ;k x;k gSA
A
D
C
11B
;fn AB = 11 bZdkbZ gks] rks prqHkqZt dh Hkqtkvksa ds oxks±
dk ;ksx gksxk&
(A) 122 (B) 132(C) 242 (D) 121
Q.32 ABCD ,d leyEc gS vkSj EF bldh e/;kUrj gSA
Hkkx GH dh yEckbZ gksxh&
(A) 3(B) 2
B
F
CD
E
A
G H
6
14
(C) 4(D) 5
Q.33 x : 111x7x
30x11x22
ds fy, lHkh fofHkUu ekuksa dk ;ksx gksxk&
(A) 11 (B) 13(C) 18 (D) 25
Q.34 fuEu esa ls dkSu lk ,d ikbFkkxksfj;u f=d ugha gS?(A) 13, 84, 85 (B) 24, 45, 63(C) 48, 55, 73 (D) 65, 72, 97
Q.35 O;atd E = xtanxsec
xcosxsecxtan
tgk¡ ij Hkh ifjHkkf"kr gS, dk ljyhdj.k djus ij vk,xk
(A) cosec x (B) sin x(C) tan x (D) cot x
Q.36 nks o`Ùk ,d nwljs dks ckâ; Li'kZ djrs gSaA ;fn muds
{ks=Qy dk ;ksx 28gks vkSj muds dsUæksa ds chp dh
nwjh 6 gks rks mudh mHk;fu"B Li'kZ js[kk dh yEckbZ
gksxh&
(A) 4 (B) 8
(C) 102 (D) 28
CODE : A PAGE NO. # 21
Q.37 Equilateral triangle ABC is cut by line l such that lparallel BC. If AC = 1 and the area DAE isequal to the area of trapezoid BDEC, the heightof DAE, is
(A) 8
3(B)
2
2
A
D E
B C
l
(C) 4
6(D)
2
3
Q.38 An isosceles trapezoid ABCD (shown) has baseAB = 10, CD = 6. If the diagonals AC and BDintersect in point F and the altitude GE, of length8, passes through F, then the length of EF, is
(A) 25(B) 5
D C
A BE
G
F(C) 3(D) 4
Q.39 The sum of the values of m for which the quadraticpolynomial f(x) = x2 + (m + 5)x + (5m + 1) is aperfect square, is(A) 3 (B) 7(C) 8 (D) 10
Q.40 The value of
90
0x
2ºxsin
(A) 2 (B) 2
89
(C) 45 (D) 2
91
Q.41 The value of the sum
2001
1n 1n21n2
2, is
equal to
(A) 12002 (B) 14003
(C) 12002 (D) 14003
Q.37 leckgq f=Hkqt ABC dks ,d js[kk l }kjk bl çdkj
dkVk tkrk gS fd l Hkqtk BC ds lekUrj gksA ;fn
AC = 1 vkSj f=Hkqt DAE dk {ks=Qy rFkk leyEc
BDEC dk {ks=Qy cjkcj gks] rks f=Hkqt DAE dh
Å¡pkbZ gksxh&
(A) 8
3(B)
2
2
A
D E
B C
l
(C) 4
6(D)
2
3
Q.38 ,d lef}ckgq leyEc ABCD (n'kkZ;k x;k gS) ftldk
vk/kkj AB = 10, CD = 6 gSA ;fn fod.kZ AC vkSj
BD ,d nwljs dks fcUnq F ij çfrPNsfnr djrs gSa vkSj
yEc GE ftldh yEckbZ 8 gS fcUnq F ls xqtjrk gS] rks
EF dh yEckbZ gksxh&
(A) 25(B) 5
D C
A BE
G
F(C) 3(D) 4
Q.39 m ds mu lHkh ekuksa dk ;ksx ftlds fy, f}?kkr cgqin
f(x) = x2 + (m + 5)x + (5m + 1) iw.kZ:i ls oxZ cu
tkrk gks] gksxk&
(A) 3 (B) 7(C) 8 (D) 10
Q.40
90
0x
2ºxsin dk eku gksxk&
(A) 2 (B) 2
89
(C) 45 (D) 2
91
Q.41
2001
1n 1n21n2
2 dk eku cjkcj gksxk&
(A) 12002 (B) 14003
(C) 12002 (D) 14003
CODE : A PAGE NO. # 22
Q.42 If r1 and r2 are the roots of the equation323x2 � 1721x + 2001 = 0, then the value of
2212
21
212212
21
22
2212
21
21
rrrr
rr2
rrrr
r
rrrr
r
, is
(A) 2001
1721(B)
2001
1721
(C) 1721
2001(D)
1721
2001
Q.43 The number N = 33 5252 equals
(A) 1 (B) 15
(C) 3 2 (D) 3 25
Q.44 If the quadratic equation x2 � px � q = 0 has two
distinct real roots, then(A) p2 � 4q 0 (B) p2 + 4q 0(C) p2 > 4q (D) p2 > � 4q
Q.45 Given that 7y = 49x+6 and 32x = 16y�9,then | x � y | is
(A) 9 (B) 8(C) 12 (D) 16
Q.42 ;fn r1 ,oa r2 lehdj.k 323x2 � 1721x + 2001 = 0
ds ewy gks] rks 2212
21
212212
21
22
2212
21
21
rrrr
rr2
rrrr
r
rrrr
r
dk eku gksxk&
(A) 2001
1721(B)
2001
1721
(C) 1721
2001(D)
1721
2001
Q.43 la[;k N = 33 5252 cjkcj gksxh&
(A) 1 (B) 15
(C) 3 2 (D) 3 25
Q.44 ;fn f}?kkr lehdj.k x2 � px � q = 0 ds nks fHkUu
okLrfod ewy gksa] rks
(A) p2 � 4q 0 (B) p2 + 4q 0(C) p2 > 4q (D) p2 > � 4q
Q.45 fn;k gS 7y = 49x+6 vkSj 32x = 16y�9
gks] rks | x � y | dk eku gksxk&
(A) 9 (B) 8(C) 12 (D) 16
Q.46 Which position-versus-time graph represents themotion shown in the motion diagram.
xv
Motion diagram
0
t = 0
(A) 0
x
t (B) 0
x
t
(C) 0
x
t (D) 0
x
t
Q.46 dkSulk fLFkfr le; oØ fp= esa nh x;h xfr dks n'kkZrk
gS&
xv
Motion diagram
0
t = 0
(A) 0
x
t (B) 0
x
t
(C) 0
x
t (D) 0
x
t
CODE : A PAGE NO. # 23
Q.47 The figure shows a binary star system. The massof star-2 is twice the mass of star-1. Compared
to 2on1F
, the magnitude of the force 1on2F
is
m2
m1
F2 on 1
(A) Four times as big (B) Twice as big(C) The same size (D) Half as big
Q.48 Bats can detect small objects such as insects thatare of a size on the order of a wavelength. If batsemit a chirp at a frequency of 60 kHz and thespeed of soundwaves in air is 330 m/s, what is thesmallest size insect they can detect ?(A) 1.5 mm (B) 3.5 mm(C) 5.5 mm (D) 7.5 mm
Q.49 When a child throws a body upwards :(1) During throw biochemical energy of child istransformed into the kinetic energy of the body.(2) After throw, the kinetic energy of child startconverting into the potential energy of body.(A) both 1 and 2 are correct(B) both are wrong(C) only 1 is correct(D) only 2 is correct
Q.50 In order for two objects to have the sametemperature, they must(A) be in thermal equilibrium(B) be in thermal contact with each other.(C) have the same feeling of "hotness" or"coldness" when touched(D) have all of the properties listed above.
Q.51 A 5kg piece of lead (specific heat 0.03 cal/g°C)
having temperature of 80°C is added to 500 g of
water specific heat 1 cal/g°C having a temperature
of 20°C. What is the final equilibrium temperature
(in °C) of the system ?
(A) 79 (B) 34(C) 54 (D) 26
Q.47 fp= esa nksgjs rkjs (binary star) fudk; dks n'kkZ;k x;k
gSA rkjs-2 dk nzO;eku rkjs-1 ls nqxquk gSA 2on1F
dh
rqyuk esa 1on2F
dk ifjek.k gksxk&
m2
m1
F2 on 1
(A) pkj xquk cM+k (B) nks xquk cM+k(C) cjkcj (D) vk/kk
Q.48 pexknM+ NksVs dhV dks idM+ ldrk gS ftudk vkdkj
rjaxnS/;Z ds Øe dk gksrk gSA ;fn pexknM+ 60 kHz dh
vko`fr iSnk djrk gS rFkk gok esa /ofu rjaxks dh pky
330 m/s gS] rks lcls NksVs dhV dk vkdkj ftls
pexknM+ idM+ ldrk gS crkvksa \
(A) 1.5 mm (B) 3.5 mm(C) 5.5 mm (D) 7.5 mm
Q.49 tc dksbZ ckyd oLrq dks Åij dh rjQ Qsadrk gS&
(1) Qsadrs le; tSo jklk;fud ÅtkZ] oLrq dh xfrt
ÅtkZ esa cny tkrh gS
(2) Qsadus ds ckn] ckyd dh xfrt ÅtkZ] oLrq dh
fLFkfrt ÅtkZ esa cny tkrh gS
(A) 1 ,oa 2 nksuksa lgh gS
(B) nksuks xyr gS
(C) dsoy 1 lgh gS
(D) dsoy 2 lgh gS
Q.50 nks oLrqvksa dk rkieku leku gksus ds fy;s&
(A) nksuks dks Å"eh; lkE;koLFkk esa gksuk vko';d gS
(B) nksuks dks ,d nwljs ds Å"eh; lEidZ esa gksuk
vko';d gS
(C) Nwus ij leku **xjekgV** ;k **B.Mk** eglwl gksxk
(D) Åij nh xbZ lkjh voLFkk,a gksuh pkfg,A
Q.51 80ºC rkieku ds 5kg lhls (lead) ds VqdM+s (fof'k"VÅ"ek 0.03 cal/g°C) dks 20ºC rkieku ,oa 1 cal/gºC
fof'k"V Å"ek ds 500 g ikuh ds lkFk feyk;k tkrk gSA
fudk; dk vafre rkieku (°C esa) gksxk \(A) 79 (B) 34(C) 54 (D) 26
CODE : A PAGE NO. # 24
Q.52 Two cannonballs are dropped from a second floorphysics lab at height h above the ground. Ball Bhas four times the mass of ball A. When the ballspass the bottom of a first floor window at height
4
h above the ground, the relation between their
kinetic energies, KA and KB is(A) KA = 4KB (B) KA = 2KB(C) KA = KB (D) KB = 4KA
Q.53 Tanu says that if you release the string whenswinging a ball in a horizontal circle, the ball fliesout in the radial direction defined by the string atthe instant you release the ball. Manu says that itflies out along a tangent line perpendicular to thestring. Which one, if either, is correct ?(A) Tanu & Manu both are wrong(B) Tanu is correct & Manu is wrong(C) Tanu is wrong & Manu is correct(D) Either may be correct depending on the initialspeed.
Q.54 You throw a ball up in the air and hold your handunder it to catch it when it comes down. The reasonwhy the ball stops is because.(A) your hand exerts a force on the ball in thedirection opposite to its velocity.(B) your hand exerts a force on the ballperpendicular to its velocity.(C) your hand exerts a force on the ball in thedirection of its velocity.(D) Your hand and the ball exert forces in the samedirection on each other.
Q.55 A particle confined to motion along the x-axismoves with constant acceleration from x = 2.0 mto x = 8.0 m during a 2.5 s time interval. Thevelocity of the particle at x = 8 m is 2.8 m/s. Whatis the acceleration during this time interval(A) 0.48 m/s2 (B) 0.32 m/s2
(C) 0.65 m/s2 (D) 0.80 m/s2
Q.52 nks xsanksa dks HkkSfrd iz;ksx'kkyk dh 'h' ÅWpkbZ f}rh;
eafty ls NksM+k x;k gSA xsan B dk nzO;eku xsan A ls pkj
xquk gSA tc nksuksa xsan igyh eafty dh f[kM+dh ds
fupys fljs tks ry ls 4
h ÅWpkbZ ij gS] ls xqtjrh gS] rks
mudh xfrt ÅtkZ KA rFkk KB ds chp esa lEcU/k
gksxk&
(A) KA = 4KB (B) KA = 2KB(C) KA = KB (D) KB = 4KA
Q.53 ruq dgrk gS fd tc rqe {kSfrt oÙk esa ?kwe jgh jLlh dks
eqDr djrs gks rks xsan dks eqDr djus ds {k.k xsan f=T;h;
fn'kk esa ckgj dh vksj xfr djrh gSA euq dgrh gS fd
;g jLlh ds yEcor~ Li'kZjs[kh; fn'kk esa xfr djsxhA
dkSu] ;fn gks rks lR; gS \
(A) ruq ,oa euq nksuksa xyr gS
(B) ruq lR; gS ,oa euq xyr gS
(C) ruq xyr gS ,oa euq lR; gS
(D) izkjfEHkd pky ds vk/kkj ij nksuksa lR; gks ldrs gS
Q.54 tc ge xsan dks gok esa Åij dh rjQ Qsadrs gS rFkk
vkius gkFkksa dks uhps j[krs gS rkfd xsan dks uhps vkrs
oDr idM+ ldsaA xsan ds :dus dk dkj.k gksxk&
(A) rqEgkjs gkFk xsan ij osx dh fn'kk ds foijhr cy
yxkrs gS
(B) rqEgkjs gkFk xsan ij osx ds yEcor~ fn'kk esa cy
yxkrs gS
(C) rqEgkjs gkFk xsan ij osx dh fn'kk esa cy yxkrs gS
(D) rqEgkjs gkFk rFkk xsan nksuksa ,d nwljs dks ,d gh
fn'kk esa cy yxkrs gS
Q.55 ,d d.k fu;r Roj.k ls x = 2.0 m ls x = 8.0 m 2.5s ds le; vUrjky esa xfr djus ds fy;s ck/; gSA
x = 8 m ij d.k dk osx 2.8 m/s gSA bl le; vUrjky
esa mldk Roj.k gksxk&
(A) 0.48 m/s2 (B) 0.32 m/s2
(C) 0.65 m/s2 (D) 0.80 m/s2
CODE : A PAGE NO. # 25
Q.56 Unit of the quantity. coefficient of viscosity is,
given = )vv(A
)xx(F
12
12
.
F force, A area, (v2 � v1) change invelocity, (x2 � x1) difference of positions.(A ) N- m /s2 (B) N-s/m2
(C) N/m2-s (D) N/s-m2
Q.57 1 gm of coal on complete combustion liberates350 kJ of energy. Then the power of a hearth, inkilowatts, in which 36 kg of coal is burnt per hourwill be :(A) 350 kW (B) 1260 kW(C) 1,26,000 kW (D) 3500 kW
Q.58 Three pith balls supported by insulating threadshang from a support. We know that ball X ispositively charged. When ball X is brought nearballs Y and Z without touching them, it attracts Yand repels Z. We can say that(A) Y has negative charge and Z has positive charge(B) Y has positive charge and Z has �ve charge
(C) Y as well as Z have positive charges.(D) Y as well as Z have negative charge.
Q.59 If R1 = 10, R2 = 15, R3 = 20, and I = 0.50A, at what rate is heat being generated in theseresistors?
I
R2
R3
R1
(A) 11 W (B) 16 W(C) 22 W (D) 1.1 W
Q.60 What is the equivalent resistance between pointsA and B in the figure when R = 10?
R
2R
2R
5R
R
B
A
(A) 20 (B) 10 (C) 25 (D) 15
Q.56 = )vv(A
)xx(F
12
12
}kjk nh tkus okyh jkf'k ';kurk
xq.kkad dk ek=d gksxk&
F cy] A {kS=Qy] (v2 � v1) osx esa ifjorZu](x2 � x1) fLFkfr esa vUrj
(A) N- m /s2 (B) N-s/m2
(C) N/m2-s (D) N/s-m2
Q.57 1 gm dks;yk iw.kZngu ds ckn 350 kJ ÅtkZ iSnk djrk
gSA rc ml HkV~Vh (hearth) dh 'kfDr crk;s ftlesa ;fn
36 kg dks;yk izfr ?k.Vk tyk;k tkrk gS&
(A) 350 kW (B) 1260 kW(C) 1,26,000 kW (D) 3500 kW
Q.58 rhu xsan dqpkyd jfLl;ksa dh lgk;rk ls ,d vk/kkj ls
Vaxh gqbZ gSA ge tkurs gS fd xsan X ij /kukRed vkos'k
gSA tc xsan X dks fcuk Li'kZ fd;s Y rFkk Z ds ikl esa
yk;k tkrk gS rks Y dks vkdf"kZr djrh gS rFkk Z dks
izfrdf"kZr djrh gS rks ge fu"d"kZ fudky ldrs gS] fd&
(A) Y ij _.kkRed o Z ij /kukRed vkos'k gSA
(B) Y ij /kukRed vkos'k ,oa Z ij �ve vkos'k gksxk
(C) Y o Z ij /kukRed vkos'k gSA
(D) Y ,oa Z ij _.kkRed vkos'k gSA
Q.59 ;fn R1 = 10, R2 = 15, R3 = 20, rFkk I =0.50 A, rks bu izfrjks/kks esa fdl nj ls Å"ek iSnk gks
jgh gS \
I
R2
R3
R1
(A) 11 W (B) 16 W(C) 22 W (D) 1.1 W
Q.60 fp= esa fn, x;s A rFkk B ds chp esa rqY; izfrjks/k Kkr
djksA ;fn R = 10gS ?
R
2R
2R
5R
R
B
A
(A) 20 (B) 10 (C) 25 (D) 15
CODE : A PAGE NO. # 26
Q.61 Which two circuits are exactly equivalent ?
(a)
R3R1
R2
110V (b)
R2R1
R3
110V
(c)
R3R2
R1
110V (d)
R2R1
R3
110V
(e)
R1R2
R3
110V
(A) (a) and (b) (B) (b) and (c)(C) (c) and (d) (D) (b) and (e)
Q.62 A series circuit consists of a 100 V DC powersource, a 100 resistor, and a variable resistorof resistance R, which varies from 0 to 100 .The current in the circuit is
R100
100V
(A) directly proportional to R(B) inversely proportional to R(C) directly proportional to (100 + R)(D) inversely proportional to (100 + R)
Q.63 Which diagram correctly shows the magnetic fieldlines created by a circular current loop in whichcurrent flows in the direction shown ?
(A) B
I
(B)
BI
(C)
IB
(D)
IB
Q.61 blesa ls dkSu&ls nks ifjiFk fcYdqy rqY; gS \
(a)
R3R1
R2
110V (b)
R2R1
R3
110V
(c)
R3R2
R1
110V (d)
R2R1
R3
110V
(e)
R1R2
R3
110V
(A) (a) ,oa (b) (B) (b) ,oa (c)(C) (c) ,oa (d) (D) (b) ,oa (e)
Q.62 ,d Js.kh ifjiFk esa ,d 100 dk izfrjks/k rFkk
ifjorZu'khy izfrjks/k R tks 0 ls 100 rd ifjofrZr
gks ldrk gS dks 100 V DC L=ksr ls tksM+k x;k gSA
ifjiFk esa /kkjk gksxh&
R100
100V
(A) R ds vuqØekuqikrh
(B) R ds O;qRØekuqikrh
(C) (100 + R) ds vuqØekuqikrh
(D) (100 + R) ds O;qRØekuqikrh
Q.63 fuEu ls dkSulk fp= fn;s x;s ywi esa nh xbZ /kkjk ds
vuqlkj pqEcdh; cy js[kkvksa dks lgh iznf'kZr dj jgk
gS \
(A) B
I
(B)
BI
(C)
IB
(D)
IB
CODE : A PAGE NO. # 27
Q.64 The reason the north pole of a bar magnet free torotate points north is because(A) the south geographic pole of the earth is theearth's magnetic north pole.(B) the south geographic pole of the earth is theearth's magnetic south pole.(C) there is a net accumulation of negative magneticcharge at the earth's south geographic pole.(D) there is a net accumulation of positive magneticcharge at the earth's north geographic pole.
Q.65 The difference between a DC and an ACgenerator is that(A) the DC generator has one slip ring split in twohalves.(B) the DC generator has one unbroken slip ring.(C) the AC generator has one unbroken slip ring.(D) the AC generator has one slip ring split in twohalves.
Q.66 The speed of light changes when it goes from ethylalcohol (n = 1.361) to carbon tetrachloride (n =1.461). The ratio of the speed in carbontetrachloride to the speed in ethyl alcohol, v2/v1,is(A) 1.99 (B) 0.93(C)1.07 (D) 0.51
Q.67 A telescope is constructed with two lensesseparated by a distance of 25 cm. The focal lengthof the objective is 20 cm. The focal length of theeyepiece is 5 cm. Calculate the angularmagnification of the telescope.(A) 6 (B) 4(C) 8 (D) 10
Q.68 If you stand closer to a concave mirror than adistance of one focal length, the image you see is(A) real and inverted(B) virtual and upright(C) real and upright(D) none of the above because you do not get animage.
Q.64 ?kw.kZu ds fy;s eqDr pqEcd ds mÙkjh /kzqo dk mÙkj dh
vksj gksus dk dkj.k gksxk&
(A) HkkSxksfyd nf{k.k /kzqo] Hkw&pqEcd dk mÙkj /kzqo gS
(B) HkkSxksfyd nf{k.k /kzqo] Hkw&pqEcd dk nf{k.k /kzqo gS
(C) Hkw&nf{k.k /kzqo ij _.kkRed pqEcdh; vkos'k bB~Bk
jgrk gS
(D) Hkw&mÙkj /kzqo ij /kukRed pqEcdh; vkos'k bB~Bk
jgrk gS
Q.65 DC rFkk AC tfu= esa vUrj gS&
(A) DC tfu= esa ,d lihZ oy; nks Hkkxksa esa VwVh gqbZgksrh gS
(B) DC tfu= esa ,d fcuk VwVh gqbZ lihZ oy; gksrh gS
(C) AC tfu= esa ,d fcuk VwVh gqbZ lihZ oy; gksrh gS(D) AC tfu= esa ,d lihZ oy; nks Hkkxks esa VwVh gksrh
gS
Q.66 tc izdk'k ,Fkkby ,Ydksgy (n = 1.361) ls dkcZu
VªsVk DyksjkbM (n = 1.461) esa tkrk gS] rks mldk osx
ifjofrZr gks tkrk gSA dkcZu VªsVk DyksjkbM rFkk ,Fkkby
,Ydksgy esa izdk'k ds osx dk vuqikr v2/v1 Kkr djksa&
(A) 1.99 (B) 0.93(C)1.07 (D) 0.51
Q.67 ,d nwjn'khZ (telescope) nks ysalks ls cuk;k x;k gS
ftuds chp dh nwjh 25 cm gSA vfHkn`';d ysal dh
Qksdl yEckbZ 20 cm rFkk vfHkus=d dh Qksdy yEckbZ
5 cm gSA nwjn'khZ dk dks.kh; vko/kZu D;k gksxk \
(A) 6 (B) 4(C) 8 (D) 10
Q.68 ;fn ge fdlh vory niZ.k ls mldh Qksdy yEckbZ ds
cjkcj nwjh ij [kM+s gS rks ge tks izfrfcEc ns[kxsa] og&
(A) okLrfod rFkk mYVk
(B) vkHkklh rFkk lh/kk
(C) okLrfod rFkk lh/kk
(D) mijksDr esa ls dksbZ ugh D;ksafd rqEgs izfrfcEc gh
izkIr ugh gksxk
CODE : A PAGE NO. # 28
Q.69 Which ray diagrams are correct ? The three raysin each diagram are distinguished by different typesof lines.
(a) I
O
(b) I
O
(c) I
O
(d) I
O
(e) I
O
(A) (b) and (c) (B) (c) and (d)(C) (d) and (e) (D) (c), (d) and (e)
Q.70 Consider an arrangement which consists of twoconverging lenses of focal lengths 40 cm and
100 cm having a common optical axis. A light beam
of diameter 4 mm is incident on the 40 cm focal
length lens as shown in figure. The diameter of thefinal beam will be
(A) 2.5 cm (B) 0.8 cm(C) 1 cm (D) 2 cm
Q.71 What value of Z (atomic number) and A (massnumber) result in the following gamma decay ?
XC AZ
126
(A) Z = 5 ; A = 12 (B) Z = 4 ; A = 8(C) Z = 7 ; A = 12 (D) Z = 6 ; A = 12
Q.72 How much work is done in stopping a body ofmass 5kg moving at a speed 5m/s on a smoothfrictionless plane:(A) 31.25 Joule (B) 125 Joule(C) 60 Joule (D) 62.5 Joule
Q.69 fuEu esa ls dkSulk fdj.k fp= lgh gSA izR;sd fp= esa
rhuksa fdj.k vyx&vyx js[kkvksa ls n'kkZ;h xbZ gS \
(a) I
O
(b) I
O
(c) I
O
(d) I
O
(e) I
O
(A) (b) ,oa (c) (B) (c) ,oa (d)(C) (d) ,oa (e) (D) (c), (d) ,oa (e)
Q.70 ,d fudk; eas nks mÙky ysal ftudh Qksdy yEckbZ
40 cm rFkk 100 cm gS rFkk nksuksa ysal dh izdkf'kd
v{k ,d gSA ,d izdk'k iaqt ftldk O;kl 4 mm gS] 40cm Qksdy yEckbZ okys ysal ij vkifrr gksrk gS] fudyus
okys iaqt dk O;kl crkvksaA
(A) 2.5 cm (B) 0.8 cm(C) 1 cm (D) 2 cm
Q.71 fn;s x;s xkek& {k; ds fy;s Z (ijek.kq la[;k) rFkk A(nzO;eku la[;k) D;k gksxsa \
XC AZ
126
(A) Z = 5 ; A = 12 (B) Z = 4 ; A = 8(C) Z = 7 ; A = 12 (D) Z = 6 ; A = 12
Q.72 ,d oLrq ftldk nzO;eku 5kg gS] 5m/s ls fpdus ry
ij xfr'khy gSA oLrq dks jksdus ds fy;s fdruk dk;Z
djuk djuk iM+sxk \
(A) 31.25 Joule (B) 125 Joule(C) 60 Joule (D) 62.5 Joule
CODE : A PAGE NO. # 29
Q.73 Select the correct matching sequence.(1) Stoney (a) A stream of positively
charged particles(2) Milliken (b) Electron(3) Wein (c) neutron(4) Chadwick (d) charge on an electron(A) 1�d; 2�b; 3�c; 4�a
(B) 1�b; 2�d; 3�a; 4�c
(C) 1�c; 2�b; 3�a; 4�d
(D) none of these is correct.
Q.74 Select the correct sequence of True (T) and false(F) statement :(I) Ethanoic acid is used as a coagulating agentfor preparation of casein from milk.(II) Acetic acid dissolves sulphur.(III) Esterification reaction is reversible.(A) T,T,F (B) T, F, F(C) F, F, T (D) none of these is correct.
Q.75 Correct IUPAC matching option out of these is
(A) (P)�(J); (Q)�(L) ; (R)�(K) ; (S)�(M)
(B) (P)�(L) ; (Q)�(J) ; (R)�(M) ; (S)�(K)
(C) (P)�(M); (Q)�(L) ; (R)�(K) ; (S)�(J)
(D) None of these is correct
Q.76 Select correct sequence of True (T), False (F)statement-I. Calcium hydroxide is a weak baseII. Boric acid is tribasic acidIII. 80% (w/w) solution of ethanoic acid is strongerthan a 20% (w/w) solution of sulphuric acidIV. A insoluble base is formed when sodiumhydroxide reacts with iron (III) chloride(A) F F F T (B) T F F T(C) T F F F (D) T T T F
Q.73 lgh feyku dk Øe pqfu;sA
(1) LVksuh (a) /kukosf�kr d.kksa dk iqat
(2) fefydu (b) bysDVªkWu
(3) ohu (c) U;wVªkWu(4) pSMohd (d) bysDVªkWu ij vkos�k
(A) 1�d; 2�b; 3�c; 4�a
(B) 1�b; 2�d; 3�a; 4�c
(C) 1�c; 2�b; 3�a; 4�d
(D) buesa ls dksbZ lgh ugha
Q.74 lgh ;k xyr dFku dk lgh Øe pqfu;sA
(I) ,FksuksbZd vEy dk mi;ksx nw/k ls dslhu ds cukus
ds fy;s Ldand ds :i esa fd;k tkrk gSA
(II) ,flfVd vEy xa/kd dks ?kqfyr dj ysrh gSA
(III) ,LVjhdj.k vfHkfØ;k mRØe.kh; gSA
(A) T,T,F (B) T, F, F(C) F, F, T (D) buesa ls dksbZ lgh ugha
Q.75 buesa ls lgh IUPAC feyku okyk fodYi pquksA
(A) (P)�(J); (Q)�(L) ; (R)�(K) ; (S)�(M)
(B) (P)�(L) ; (Q)�(J) ; (R)�(M) ; (S)�(K)
(C) (P)�(M); (Q)�(L) ; (R)�(K) ; (S)�(J)
(D) buesa ls dksbZ lgh ugha gS
Q.76 lgh ;k xyr dk lgh Øe pqfu;s &
I. dSfYl;e gkbMªkWDlkbM ,d nqcZy {kkj gSA
II. cksfjd vEy f={kkjh; vEy gSA
III. ,FksuksbZd vEy dk 80% (w/w) foy;u lY¶;wfjd
vEy ds 20% (w/w) foy;u ls izcy gSA
IV. tc lksfM;e gkbMªkWDlkbM] vk;ju (III) DyksjkbM
ls vfHkfØ;k djrk gS rks ,d vfoys; {kkj izkIr gksrk
gSA
(A) F F F T (B) T F F T(C) T F F F (D) T T T F
CODE : A PAGE NO. # 30
Q.77 You are given four reactions-I. Fe2O3 + 3CO 2 Fe + 3CO2II. H2S + Br2 2 HBr + SIII. 3 MnO2 + 4 Al 2 Al2O3 + 3 MnIV. ZnO + C Zn + COSelect incorrect statement about these(A) In I Fe2O3 is oxidising agent(B) In II H2S is reducing agent(C) In III MnO2 is reducing agent(D) In IV ZnO is oxidising agent
Q.78 Which one of the following is correct option aboutshowing the catenation property of element-(A) Benzene (B) S8 molecule(C) H�S�(S)n � S�H (D) All A, B, C
Q.79 Consider the given part of P.T. and select incorrectstatement
B C N O F
Al Si P S Cl
Ga Ge As Se Br
In Sn Sb Te I
Tl Pb Bi Po At
(A) In, Tl, Bi, Po are four elements showingductility
(B) B, C, Si all three can form giant moleculeswith other atoms on combination
(C) N, O, P, I all four form small molecules(D) None of these
Q.80 Given that the vapour pressure of liquid mercury[density = 13.6 g/ml] is 0.0000041 atmp at 27ºC.
What weight of mercury would it take to pollute aroom that is 4 × 3 × 2 m3 [Assume mercury vapourto be an ideal gas R = .082 L atm k�1 mol�1][Hg = 200](A) 800 gm (B) 600 gm(C) 180 gm (D) None of these
Q.77 vkidks pkj vfHkfØ;k,sa nh xbZ gS &
I. Fe2O3 + 3CO 2 Fe + 3CO2II. H2S + Br2 2 HBr + SIII. 3 MnO2 + 4 Al 2 Al2O3 + 3 MnIV. ZnO + C Zn + COblds fy;s xyr dFku dk p;u dhft;sA
(A) I esa Fe2O3 vkWDlhdkjd ?kVd gSA
(B) II esa H2S vipk;d ?kVd gSA
(C) III esa MnO2 vipk;d ?kVd gSA
(D) IV esa ZnO vkWDlhdkjd ?kVd gSA
Q.78 fuEu esa dkSulk lgh fodYi gS tks rRo ds Catenationxq.k dks n�kkZrk gSA
(A) cSUthu (B) S8 v.kq
(C) H�S�(S)n � S�H (D) lHkh A, B, C
Q.79 fn, x, vkorZ lkj.kh ds Hkkx ds fy, xyr dFku
gksxkA
B C N O F
Al Si P S Cl
Ga Ge As Se Br
In Sn Sb Te I
Tl Pb Bi Po At
(A) In, Tl, Bi, Po pkjkssa rRo rU;rk n�kkZrs gSA(B) B, C, Si rhuksa vU; v.kqvksa ds lkFk tqM+ dj cM+s
v.kqvksa dk fuekZ.k djrs gSA
(C) N, O, P, I pkjks NksVs v.kqvksa dk fuekZ.k djrs gSA
(D) buesa ls dksbZ ugha
Q.80 27°C ij nzo ikjs dk ok"i ?kuRo 0.0000041 atmpfn;k x;k gSA ikjs dk ?kuRo = 13.6 g/ml gSA4 × 3 × 2 m3 okys dejs dks iznwf"kr djus ds fy;s ikjs
dk fdruk Hkkj fy;k tk,xk\
[ekuk dh ikjs dh ok"i ,d vkn'kZ xSl gS]
R = .082 L atm k�1 mol�1] [Hg = 200](A) 800 gm (B) 600 gm(C) 180 gm (D) buesa ls dksbZ ugha
CODE : A PAGE NO. # 31
Q.81 Two elements Q and R form a compound withformula Q2R5. 100 gm of sample of this compoundcontains 50 g of Q. Then the ratio of atomic massof Q to at. mass of R will be-
(A) 2
5(B)
5
2
(C) 5
3
(D) Can not be predicted data insufficient
Q.82 Select incorrect statement[C = 12, H = 1, Ge = 72.6](A) The term would a chemist use to describe
haematite is ore(B) The molar mass of tetraphenyl germane
[(C6H5)4 Ge] will be 380.6(C) A refrigerant should have high volatility and
low reactivity(D) Fuels are materials with energy stored is the
bonds of molecules
Q.83 Select incorrect statement-(A) An addition compound obtained by a reactioninvolving no valency change is called an adduct(B) Formula of aluminium acetate is CH3COOAl(C) Silicon carbide is used as an abrasive(D) One degree absolute is equal to one degreecentigrade
Q.84 Select false statement-(A) Life is built on the chemistry of carbon,whereas the solid earth that supports life is builton the chemistry of element below it in P.T.(B) There is a chemical difference between Iron,Pig rion, Cast iron and steel(C) The IV state of matter PLASMA can notconduct electricity(D) NaCl, HCl and Fe2O3 are all examples ofbinary compounds
Q.85 How many gms of O2 could you produce at themost from no more than 1 gm of OF2 and 1 gm ofH2O on reaction? [O = 16, F = 19](A) 0.592 gm (B) 2.48 gm(C) 1.235 gm (D) none of these
Q.81 nks rRo Q rFkk R ,d ;kSfxd cukrs gS ftldk lw=
Q2R5 gSA bl ;kSfxd ds 100 gm izfrn'kZ esa 50 g QmifLFkr gS rks Q rFkk R ds ijek.kq Hkkjks dk vuqikr
gksxk &
(A) 2
5(B)
5
2
(C) 5
3
(D) cuk;k ugha tk ldrk] vk¡dM+s vi;kZIr gSA
Q.82 xyr dFku dks pqfu;sA
[C = 12, H = 1, Ge = 72.6](A) gSesVkbV dks dsfeLV ds }kjk v;Ld dgk tkrk gSA
(B) VsVªkQsfuy teZu [(C6H5)4 Ge] dk eksy nzO;eku
380.6 gksxkA(C) ,d iz'khrd mPp ok"i'khy rFkk fuEu vfHkfØ;k'khy
gksrk gSA
(D) bZa/ku ,sls inkFkZ gS ftuesa ÅtkZ v.kqvksa ds ca/k esa
laxzfgr gksrh gSA
Q.83 xyr dFku dks pqfu;s &
(A) ,d vfHkfØ;k ls izkIr ;ksxkRed ;kSfxd ftlesa
la;kstdrk esa ifjorZu ugha gksrk adduct dgykrk gSA
(B) ,Y;qfefu;e ,flVsV dk lw= CH3COOAl gS(C) flyhdu dkcZbM dk mi;ksx vi?k"kZd esa gksrk gS
(D) ,d fMxzh ije rki ,d fMxzh lsUVhxzsM ds cjkcj
gksrk gSA
Q.84 vlR; dFku pquks &
(A) dkcZu ds jlk;u ls thou cuk gS] tcfd Bksl
i`Foh tks thou ds fy;s lgk;d gS og vkorZ lkj.kh esa
dkcZu ls uhps ds rRo ls cuh gSA
(B) yksgk] fiVok yksgk] <yok¡ yksgk rFkk bLikr esa
jlk;fud xq.kksa esa varj gSA
(C) nzo dh IV voLFkk IykTek fo|qr dk pkyu ugha
dj ldrh gSA
(D) NaCl, HCl rFkk Fe2O3 f}vaxh ;kSfxdks ds mnkgj.k
gSA
Q.85 1gm OF2 rFkk 1 gm H2O dh vfHkfØ;k ls O2 ds
vf/kdre fdrus xzke izkIr fd, tk ldrs gS\
[O = 16, F = 19](A) 0.592 gm (B) 2.48 gm(C) 1.235 gm (D) buesa ls dksbZ ugha
CODE : A PAGE NO. # 32
Q.86 Methane gas, water vapour, nitrogen gas anddioxygen all four react to give only two gases oneis acidic in nature, other is basic. Thenstoichiometric coefficients of acidic and basicgases formed in the balanced chemical equationrespectively are(A) 7, 16 (B) 9, 18(C) 7, 12 (D) 6, 14
Q.87 Which of the following has maximum number ofneutrons per proton?
(A) S3216 (B) Ag107
47
(C) Au19779 (D) Fe56
26
Q.88 Select incorrect statement(A) O2�, S2� and Se2�
are chalcogenide dianions(B) He�, Li, Be+ and B2+ will have sameelectronic configuration[At. No. He = 2, Li = 3, Be = 4, B = 5](C) House-hold LYE should never be used inaluminium containers(D) Fe(FeO2)2 is not an oxide of iron.
Q.89 Select incorrect statement(A) The molecules in chemistry are threedimensional assuming this to be true the forcesbetween two HCl polar molecules are alwaysattractive.(B) The inhibition or a complete suppression of achemical process by the reaction products is calledpassivation.(C) Antimony (At. wt. 121.8) forms more thanone oxide. When 20 gm of antimony reacts with3.95 gm dioxygen the formula of the oxide formedwill be Sb2O3(D) A hypothetical gaseous compound of C,H andS is burnt in air. It is found that 3 volume of thecompound gives 3 volume CO2 , 3 volume SO2and 6 volume water vapour. Then theformula of the compound can be CH4S.
Q.90 Which gas will form bubbles on being slowlypassed through water?(A) Ammonia(B) Phosphine(C) Hydrogen chloride gas(D) None of these
Q.86 esFksu xSl] ty ok"i] ukbVªkstu xSl rFkk MkbZvkWDlhtu
pkjks vfHkfØ;k djds dsoy nks xSl cukrh gS ,d
vEyh; iz�fr rFkk nwljh {kkjh; izd`fr dhA larqfyr
jlk;fud lehdj.k esa vEyh; rFkk {kkjh; xSlksa ds jl
lehdj.kferh xq.kkad Øe'k% gS &
(A) 7, 16 (B) 9, 18(C) 7, 12 (D) 6, 14
Q.87 fuEu esa ls fdlesa izfr izksVkWu U;wVªkWu dh la[;k
vf/kdre gS\
(A) S3216 (B) Ag107
47
(C) Au19779 (D) Fe56
26
Q.88 xyr dFku pqfu;s &
(A) O2�, S2� rFkk Se2� pkydkstuh f}_.kk;u gSA
(B) He�, Li, Be+ rFkk B2+ ds bysDVªkWuh; foU;kl
leku gksxsa
[At. No. He = 2, Li = 3, Be = 4, B = 5](C) ?kjsyw lTthnkj ikuh dk mi;ksx ,Y;qfefu;e okys
crZu esa ugha fd;k tkrkA
(D) Fe(FeO2)2 yksgs dk ,d vkWDlkbM ugha gSA
Q.89 xyr dFku pqfu;s &
(A) jlk;u esa v.kq f=fofe; gksrs gS ;g lR; ekuk tkrk
gS blfy;s nks /kzqoh; HCl v.kqvksa ds e/; lnSo vkd"kZ.k
cy gksrk gSA
(B) ,d jklk;fud izfØ;k dks vfHkfØ;k ds mRikn ds
}kjk jksduk ;k iw.kZ izfr caf/kr djuk fu"Øe.krk dgykrh
gSA
(C) ,UVheuh (At. wt. 121.8) ,d ls vf/kd vkWDlkbM
cukrh gS tc 20 gm ,UVheuh 3.95 gm MkbZvkWDlhtu
ls lkFk vfHk�r gksrh gS rks cuus okys vkWDlkbM dk
lw= Sb2O3 gksxkA
(D) C,H rFkk S ds ,d dkYifud ;kSfxd dks ok;q esa
tyk;k tkrk gSA ;kSfxd ds 3 vk;ru nsrs gS] CO2 ds
3 vk;ru] SO2 ds rhu vk;ru rFkk ty ok"i ds 6vk;ru cukrk gS] rks ;kSfxd dk lw= CH4S gks ldrk
gSA
Q.90 ty ls gksdj /khjs&/khjs izokfgr djus ij dkSulh xSl
cqycqys cukrh gS?(A) veksfu;k
(B) QkWLQhu
(C) gkbMªkstu DyksjkbM xSl
(D) buesa ls dksbZ ugha