B.tech Project.cpd2014
-
Upload
audrey-patrick-kalla -
Category
Documents
-
view
220 -
download
0
Transcript of B.tech Project.cpd2014
-
8/13/2019 B.tech Project.cpd2014
1/85
CHEMICAL PROCESS QUANTITATIVE RISK ANALYSIS
AND
MANUFACTURE OF PARA NITRO CHLOROBENZENE
A PROJECT REPORT
Submitted by
MOHD. IBRAZ HUSSSAIN (41502203009)RATNA RAMANI (41502203013)S.SRILAKSHMI (41502203016)
In partial fulfillment for the award of the degree
of
BACHELOR OF TECHNOLOGY
In
CHEMICAL ENGINEERING
S.R.M. ENGINEERING COLLEGE,KATTANKULATHUR-603 203, KANCHEEPURAM DISTRICT
ANNA UNIVERSITY: CHENNAI-600 025
MAY 2006
-
8/13/2019 B.tech Project.cpd2014
2/85
ANNA UNIVERSITY: CHENNAI 600 025
BONAFIDE CERTIFICATE
Certified that this project report Part A "CHEMICAL PROCESS
QUANTITATIVE RISK ANALYSIS" and report
Part B- "MANUFACTURE OF PARA NITRO CHLOROBENZENE is the
bonafide work of MOHD. IBRAZ HUSSAIN (41502203009), RATNA RAMANI
(41502203013) and
S. SRILAKSHMI (41502203016) who carried out the project work under our
supervision.
Dr.R.KARTHIKEYAN Dr.R.KARTHIKEYAN
PROFESSOR SUPERVISOR
HEAD OF THE DEPARTMENT HEAD OF THE DEPARTMENT
CHEMICAL ENGINEERING CHEMICAL ENGINEERING
S.R.M.Engineering college S.R.M.Engineering college
Kattankulathur-603 203 Kattankulathur-603 203Kancheepuram District. Kancheepuram District.
ACKNOWLEDGEMENT
We take pleasure in expressing our heartfelt thanks to our Principal Prof. R.
Venkataramani, B.E., M.Tech. F.I.E., and Director Dr. T.P.Ganesan,
B.E.,(Lhons).,M.Sc.,(Engg.), for constantly looking into our needs and upgrading the
support system provided to students.
-
8/13/2019 B.tech Project.cpd2014
3/85
We also take this opportunity to thank our HOD
Prof. Dr. R Karthikeyan, B.E., Ph.D., who through his busy schedule always provided
time to guide us and motivate us.
Also, we would like to thank our faculty members who gave us valuable and
timely inputs which helped us to bring this project to a successful completion.
ABSTRACT
Para nitro chlorobenzene is an important compound in chemical industry with
respect to dyeing and production industry especially.
A conservative approach has been employed in the manufacture of Para nitro
chlorobenzene, as the other methods of production available are employed only for
laboratory purposes.
This project deals with design aspects of equipments used, cost estimation and
project feasibility.
-
8/13/2019 B.tech Project.cpd2014
4/85
TABLE OF CONTENTS
CHAPTER TITLE PAGE NO
ABSTRACT
1 INTRODUCTION 11.1 UNDERSTANDING RISK 11.2 SELECTED DEFINITIONS FOR
CPQRA 3
2 RELEVANCE OF THE TECHNIQUE 10CASE STUDIES2.1 CASE STUDY OF A DISTILLATION
COLUMN 102.1.1 Identification, Enumeration and 13
Selection of incidents2.2 INCIDENT CONSEQUENCE 18
ESTIMATION2.2.1 Flash, Discharge and Dispersions 18
Calculations2.2.2 Event Tress 232.2.3 Consequences of Incident 25
Outcomes2.3 INCIDENT FREQUENCY 30
ESTIMATION2.3.1 Frequencies of the Representative 30
set of Incidents2.3.2 Probabilities of Incident outcomes 332.3.3 Preparation of incident outcome 34
case frequencies2.4 RISK ESTIMATION 352.5 CONCLUSION 40
3 REVIEW OF RELATED LITERATURE 413.1 TORAP 41
3.1.1 The Accident Scenario general 41step
3.1.2 Consequence Analysis 423.1.3 Checking for higher degree of 42
accidents3.1.4 Characteristics of worst-accident 42
ScenarioCONCLUSION 44
APPENDIX 1 45APPENDIX 2 46
-
8/13/2019 B.tech Project.cpd2014
5/85
ABSTRACT
Chemical Process Quantitative Risk Analysis is a relatively new methodology
that is a valuable management tool in the overall safety performance of chemical
process industry.
CPQRA techniques provide advanced quantitative means to supplement hazard
identification, risk assessment, control and management methods to identify potential
for incidents and evaluate control strategies.
TABLE OF CONTENTS
CHAPTER TITLE PAGE NO
ABSTRACT
LIST OF SYMBOLS
1 INTRODUCTION
1.1 BRIEF INTRODUCTION 53
2 PROCESS
2.1 PROCESS DESCRIPTION 552.1.1 Equipment Description 57
2.2 MATERIAL BALANCE 59
2.3 ENERGY BALANCE 64
2.4 DESIGN 67
2.5 PROCESS CONTROL AND 71
INSTRUMENTATION
-
8/13/2019 B.tech Project.cpd2014
6/85
2.6 PLANT LAYOUT 74
2.7 COST ESTIMATION 79
2.8 PROCESS SAFETY 87
LIMITATIONS 96
CONCLUSION 96
LIST OF SYMBOLS
Hreaction - Heat of reaction (kJ)
Cp - Specific heat kJ
kgoC
T - Temperature difference
- Latent heat of varporisation
V - volume of the reactor (m3
)
VO - Volumetric flow rate of the reactor (m3/hr)
- Vapor flow rate (kmol/hr)
CHAPTER 1
INTRODUCTION
BRIEF INTRODUCTION
Understanding Risk
-
8/13/2019 B.tech Project.cpd2014
7/85
Risk is a measure of potential for loss in terms of both likelihood(events/year) of the incident and the consequences (effects/year) of the
incident. Risk in an industry may be due to natural hazards and
infrastructure.
Flixborough, Bhopal, Piper Alpha and other accidentsemphasized the need for risk analysis.
The development of a quantitative estimate of risk based onengineering evaluation and mathematical techniques for
combining estimates of incident likelihood and consequences.
Chemical process quantitative risk analysis is a relatively newmethodology that is valuable as a management tool in the overall safety
performance of the Chemical Process Industry (CPI).
Chemical Process Quantitative Risk Analysis (CPQRA)techniques provide advanced quantitative means to supplement
hazard identification, analysis, assessment, and control and management
methods to identify the potential for accidents to occur and to evaluate
control strategies.
-
8/13/2019 B.tech Project.cpd2014
8/85
A flow sheet is illustrated below to indicate the step-by- stepprocedure involved in CPQRA.
Selected Definitions for CPQRA
HazardA chemical or physical condition that has the potential for causing damage to
people, property or the environment (e.g. a pressurized tank containing 500 tonsof ammonia)
IncidentIncident can be defined as loss of containment of material orenergy(e.g. a
leak of 10 lb/sec of ammonia from a connecting pipeline to the ammonia tank,producing a toxic vapor cloud).This is pertaining to Risk Studies.
Event SequenceA specific unplanned sequence of events composed of initiating events
and intermediate events that may lead to an incident.
Initiating event
The first event in an event sequence (e.g. stress corrosion resulting inleak/rupture of the connecting pipeline to the ammonia tank)
Intermediate eventAn event that propagates or mitigates the initiating event during an event
sequence (e.g.: improper operator action fails to stop the initial ammonia leak and
causes propagation of the intermediate event to an incident, in this case theintermediate event could be a continuous release of Ammonia)
Incident outcomeThe physical manifestation of the incident; for toxic materials, the incident
outcome is a toxic release, while for flammable materials, the incident outcomecould be a BLEVE, flash fire, unconfined vapor cloud explosion, etc.
-
8/13/2019 B.tech Project.cpd2014
9/85
Incident outcome caseThe quantitative definition of a single result of an incident outcome through
specification of sufficient parameters to allow distinction of this case from all othersfor the same incident outcomes (e.g. a concentration of 3333 ppm (v) of ammonia2000 ft downwind from a 10lb/sec ammonia leak is estimated assuming a 1.4 mph
wind and stability Class D)
ConsequenceA measure of the expected effects of an incident outcome case (e.g., an
ammonia cloud from a 10lb/sec leak under stability Class D weather conditions,and a 1.4 mph wind traveling in a northerly direction will injure 50 people)
Effect zoneFor an incident that produces an incident outcome of toxic release, the areaover which the airborne concentration equals or exceeds some level of concern.
The area of the effect zone will be different for each incident outcome case[e.g.,given an IDLH for ammonia of 500 ppm (v) , an effect zone of 4.6 square milesis estimated for a 10 lb/sec ammonia leak].For a flammable vapor release, thearea over which a particular incident outcome case produces an effect based ona specified overpressure criterion (e.g., an effect zone from an unconfined
vapor cloud explosion of 28,000 Kg of hexane assuming 1 % yield is 0.18 km2if an overpressure criterion of 3 psig is established).For a loss of containmentincident producing thermal radiation effects, the area over which a particularincident outcome case produces an effect based on a specified thermal damagecriterion[e.g., a circular effect zone surrounding a pool fire resulting from aflammable liquid spill, whose boundary is defined by the radial distance at
which the radiative heat flux from the pool fire has decreased to 5 kW/m2(approximately 1600 Btu/hr-ft2]
Likelihood
Likelihood can be defined as a measure of the expected probability or
frequency of occurrence of an event. This may be expressed as a frequency (e.g.,events/year), a probability of occurrence during some time interval, or a conditionalprobability (i.e., probability of occurrence given that a precursor event has
occurred, e.g., the frequency of a stress corrosion hole in a pipeline of sizesufficient to cause a 10 lb/sec ammonia leak might be 1 x 10 -3 per year; theprobability that ammonia will be flowing in the pipeline over a period of 1 yearmight be estimated to be 0.1;and the conditional probability that the wind blows
toward a populated area following the ammonia release might be 0.1)
-
8/13/2019 B.tech Project.cpd2014
10/85
-
8/13/2019 B.tech Project.cpd2014
11/85
It is necessary to pay attention to the scope of a CPQRA, in order to satisfypractical budgets and schedules. If the scope is not clearly defined in advance, there is apossibility for the workload to explode. The concept of a STUDY CUBE has beenintroduced as shown above to relate scope, workload and goals. The three axes of thecube represent risk estimation technique, complexity of analysis and number ofincidents selected for study. Each axis of the cube has been arbitrarily divided into threelevels of complexity. These results in a total of 27 different categories of CPQRA,depending on what combinations of complexity of treatment are selected for threefactors. Each cell in the cube represents a potential CPQRA characterization. Howeversome cells represent a combination of characteristics that are more likely to be useful inthe course of a project or in the analysis of an existing facility
Risk estimation techniqueEach of the components of this axis corresponds to a study exit point .The
complexity and level of effort necessary increase along the axis-from consequence
through frequency to risk estimation.
Complexity of StudyThis axis presents a complexity scale for CPQRAs .Position along the axis is
derived from two factors
The complexity of the models to be used in a studyThe number of incident outcome cases to be studied
Number of incidentsThere are three groups of incidents used
Bonding Group-this group contains a small number of incidents that arecatastrophic by nature
Representative Set-it includes incidents from the either group of incidents.
Expansive List- it contains incidents in all three classes selected throughthe incident enumeration technique
The STUDY CUBE provides a conceptual framework for discussing factorsthat influence the depth of a CPQRA.
-
8/13/2019 B.tech Project.cpd2014
12/85
CHAPTER 2
RELEVANCE OF THE TECHNIQUE
CASE STUDIES
2.1 CASE STUDY OF A DISTILLATION COLUMN
Consider a C6 distillation column, which is used to separate hexane and heptanefrom a feed stream consisting of 58 %( by weight and 42% heptane. The overhead
condenser, thermosyphon reboiler and accumulator are all included in this study. Thecolumn operating pressure is 4barg the temperature range is 130-160C from the top tothe bottom of the column respectively. The column bottoms and reboiler inventory is6000kg and there are about 10000kg of liquids on the trays. The condenser is assumedto have no liquid holdup and the accumulator drum inventory is 12000kg. The materialin the bottom of the column is approximately 90% heptane and 10% hexane and that atthe top is approximately 90% hexane and 10% heptane.
-
8/13/2019 B.tech Project.cpd2014
13/85
Table
Physical properties Hexane Heptane
Boiling point (oC) 69 99
Molecular weight 86 100
Upper flammable limit (vol%) 7.5 7.0
Lower flammable limit (vol%) 1.2 1.0
Heat of combustion (J/kg) 4.5x107 4.5x107
Ratio of specific heats, 1.063 1.054
Liquid density at boiling point (kg/m3) 615 614
Heat of vaporization at boiling point (J/kg) 3.4x105 3.2x105
Liquid heat capacity (J/kg/ok) 2.4x103 2.8x103
-
8/13/2019 B.tech Project.cpd2014
14/85
The plant layout and surroundings The wind rose
The study objective is to estimate the risk to the residential community fromthe fractionation system from both individual and societal risk perspectives.
In order to limit the number of calculations, only one average weathercondition is considered a wind speed of 1.5 m/s and F stability- representing a worstcase weather condition with a reasonable probability of occurrence. The wind roseused in this example, gives the probability of wind from each of eight directions.
-
8/13/2019 B.tech Project.cpd2014
15/85
2.1.1 Identification, Enumeration and Selection of incidents
An initial list of incidents is listed to consider all possible breaks orruptures of items of equipment which would lead to a loss of
containment
The initial list is modified to produce a revised list which excludesproblems such as polymerization, corrosion, over pressurization pertaining
to this distillation column.
Each vessel may break or rupture in a number of ways. A pipebreak may be of any size from a pin hole to a full bore rupture and may
be in any position between the pipe ends.
The spectrum of incidents is reduced to a Representative Set ofIncidents. Possible pipe failures are represented by either full bore ruptures
or holes of 20% of the pipe diameter.
Flange leaks, pump seal leaks do not cause any long distance effectsbut may result in a pool fire. Diking around the column limits the pool size to
10m2.
Incident outcomes such as fire and explosions should beconsidered since the material is flammable.
The final choice of incidents is modeled based on the following factors:
the size of the release whether the release is instantaneous or continuous whether the release is liquid or vapor The revised list of incidents include: Complete Rupture Column Accumulator Reboiler Condenser
-
8/13/2019 B.tech Project.cpd2014
16/85
Liquid leaks(full bore rupture and hole equivalent to 20% ofdiameter)
Column feed line Reboiler feed line Heptane pump(pump 2) suction line(including flanges and pump) Heptane pump(pump 2)discharge line(including flanges) Condenser discharge line Reflux pump (pump1)suction line (including flanges and pump) Reflux pump(pump1) discharge line (including flanges) Shell leak(of column, accumulator, reboiler or condenser) of holesize equivalent to 20% of pipe diameter only.
Vapor leaks(full bore rupture and hole equivalent to 20% of diameter) Column overhead line Reboiler discharge line Shell leakage (of the column, accumulator, reboiler orcondenser) of hole size equivalent to 20% of pipe diameter only.
Assumptions pertaining to Representative List of Incidents
a. It is assumed that automatic isolation exists at the system boundaries suchthat no additional fuel other than that present in the system at the time of incident
contributes to the release. Hence an instantaneous failure of one vessel will lead to
the rapid release of the entire contents of all other connected vessels. It may be
noted that there are no automatic isolation valves with in the system.
b. It is assumed that all liquid lines have a diameter of 0.15m.Discharge ratefrom these lines is used to determine whether full bore rupture of these lines can be
treated as an instantaneous or continuous release. Here releases close to the
vessel are better approximated by the liquid discharge model as compared
to two-phase discharge model. Discharge equation for continuous releases from
the 0.15m diameter line is :
-
8/13/2019 B.tech Project.cpd2014
17/85
GL= Cd A !(2(p-pa) / ! + 2 g h )1/2
GL= Liquid discharge rate (kg/s)
Cd=discharge coefficient (0.61 for liquids)
A = hole cross-sectional area ( for 0.15m diameter pipe)=0.0176m2
!=liquid density (615 kg/m3)
p=upstream pressure (5 bar=5*105N/m2)
pa=down stream pressure(1 bar = 1*105N/m2)
h=liquid head (assumed to be negligible)
g= acceleration due to gravity (9.8 m/s)
It has been calculated that discharge rate is 240 kg/s bysubstituting all the above values in equation.
Flow rate can double if pipe breaks in such a way that flow isunimpeded from both ends.
It is estimated that at the initial rate the entire contents of column,reboiler and accumulator would be emptied in 2 minutes. But due to
pressure decrease in the system, it takes a larger time to empty the
contents.
It is considered reasonable to treat full bore ruptures of liquidlines in the same manner as a catastrophic failure of any vessel in the
fractionating system.
c. Vapor lines are 0.5m in diameter.A quick estimate of the discharge rate canbe used to establish whether the full bore rupture of these lines can be treated as
an instantaneous or continuous release. It is determined whether flow is sonic in
order to estimate the actual discharge rate from a catastrophic break in the gas
piping.
rcrit=(("+1)/2)("/("-1))
Where
-
8/13/2019 B.tech Project.cpd2014
18/85
"= gas specific heat ratio(1.063 for hexane, 1,054 for heptane)
rcrit=1.687 for hexane
rcrit=1.682 for heptane
Sincep=5*105N /m2 (absolute)
pa=1*105N/m2(absolute)
p/pa=5.0 > rcrit= 1.687
Therefore, vapor discharge will be sonic. For sonic flow the discharge rate is
given by
Gv=CdA p #/ $o
Where
Gv= gas discharge rate for choked vapor flow (kg/s)
Cd= discharge coefficient (assumed to be 1 for gases)
A =hole cross-sectional area ( for 10% of 0.5m pipe,m2)
p=absolute upstream pressure (N/m2)
$o =sonic velocity of gas at T =(RT"/M)1/2
#=flow factor = "(1/rcrit)("+1)/2")
M= molecular weight (86 for hexane, 100 for heptane)R=gas constant (8310 joules/kg-mole/K)
T=upstream temperature (403K for hexane, 433K for heptane)
"=gas specific heat ratio (1.063 for hexane, 1.054 for heptane)
rcrit=1.687 for hexane, 1.682 for heptane
The vapor discharge rate is 303 kg/s for pure hexane and 320 kg/sfor pure heptane. Therefore, full bore ruptures of vapor lines are also
treated the same as a catastrophic failure of any vessel in the fractionatingsystem.
Representative List of Incidents:
-
8/13/2019 B.tech Project.cpd2014
19/85
a. a catastrophic failure of the column, reboiler, condenser, accumulator, orany full bore liquid or vapor line rupture
b. a liquid release through a hole of diameter equal to 20%of a 0.15m diameterline
c. a vapor release through a hole of diameter equal to 20% of a0.5m diameterline
2.2 INCIDENT CONSEQUENCE ESTIMATION
2.2.1 Flash,Discharge and Dispersions Calculations (Incidents A,B & C)
Flash discharge and dispersion calculations are carried out for the Incidents A,B and C that are defined above.
Incident A : A Catastrophic failure
In the event of catastrophic failure of one of the vessels or full bore line
rupture; it is assumed that the entire contents of the column, reboiler, condenser, and
accumulator, are lost instantaneously. In the following calculation, the flash fraction is
determined assuming the column reboiler and accumulator contains pure heptane and
pure hexane, respectively, rather than mixtures.
Fv=Cp((T-Tb)/Hfg)
Where
Fv= fraction of fluid flashed to vapor
Cp= average liquid heat capacity (range T to Tb)(2400J/kg/K for hexane, 2800
J/kg/K for heptane)
T= operating temperature (130C for hexane, 99C for heptane)
Tb=atmospheric boiling point (69C for hexane, 99C for heptane)
-
8/13/2019 B.tech Project.cpd2014
20/85
Hfg= latent heat of vaporization at Tb (3.4x105 J/kg for hexane, 3.2x105
J/kg for Heptane)
The calculated flash fractions are 0.43 for hexane and 0.51 for heptane.Therefore, both of these materials exhibit a flash fraction of roughly 0.5. It is
reasonable to assume that all of the hexane and heptane released will release as gas and
aerosol .It is further assumed that the aerosol droplets are small enough to remain
suspended and evaporate instead of raining out onto the ground. DENSE CLOUD
MODEL is used to calculate the dispersion of the instantaneous release of the
mentioned gases. Since thermo physical properties of hexane and heptane are similar,
the dispersion calculations are based on hexane that comprises approximately 2/3 of
the inventory of the system. The release is supposed to consist only of gas and aerosoldroplets that eventually evaporate into cloud and hence an all gaseous release is chosen
for dispersion analysis. The temperature used is 69C , which is the temperature to
which hexane liquid will flash when released to the atmosphere. It is also necessary to
estimate the initial dilution, which is the number of volumes of air containing one
volume of gas in the cloud after expansion to atmospheric pressure and before heat
transfer and dispersion processes begin. A dilution factor of ten is chosen. The initial
cloud radius is set equal to height, which is the most common default for top-hat
models.
Incident B & C: Liquid and Vapour Release from Hole in Piping
For liquid release, the flash fraction is same as that considered for incident A
i.e. 0.43 for hexane and 0.51 for heptane. It is assumed that entire release is a gas and
aerosol cloud, with no liquid rainout.
The discharge rate for the liquid release (incident B) can be estimated usingequation and assuming a hole diameter of 0.03m.The resulting rate discharge rate is 9.6
kg/s.
-
8/13/2019 B.tech Project.cpd2014
21/85
The discharge rate for gaseous release i.e. incident C can be estimated using
equation assuming a hole diameter of 0.12m. The discharge rate is calculated as 12.6
kg/s.
Since both releases are gaseous and discharge is similar incidents B and C are
combined and on average release rate of 11 kg/s is obtained. Top hat dense cloud
model of WHAZAN is used to calculate dispersion. The flammability zone from
continuous release will extend in residential area.
-
8/13/2019 B.tech Project.cpd2014
22/85
This is the output obtained in case of instantaneous heavy gas dispersion
W H A Z A N***********
HEAVY CLOUD DISPERSION MODEL****************************
Copyright (C)DNV Technica Ltd.
Date 28 Sep 1996 Time 02:53
Instantaneous release of n-Hexane (Gaseous)
Mass released : 28000. kgInitial flash : .000
Temp. after release : 342.0 KMolecular weight : 86.17Boiling point : 344.6 KSpecified lower conc.: 10000.000 ppmInitial dilution : 10.0 TimesFraction liquid : .000Initial cloud temp. : 308.0 KInitial cloud conc. : 78912.050 ppmInitial density : 1.317 kg/cu mInitial radius : 32.1 mInitial volume : 104011. cu mInitial height : 32.1 mSurface roughness : .100
Ambient temperature : 293.0 KRoughness length : .18 m
Air density : 1.196 kg/cu mRelative humidity : 80. %
Wind speed : 1.5 m/sMixing ratio : .012Pasquill category : F
TIME DISTANCE CLOUD CLOUD C/L CLOUDDOWNWIND RADIUS HEIGHT CONC. TEMP.
(s) (m) (m) (m) (ppm vol) (K)
.0 .0 32.1 32.1 78912.050 308.03Forced convection from .0 m
6.7 10.0 58.6 19.9 37354.630 300.7413.3 20.0 76.6 16.0 26933.910 298.1920.0 30.0 91.3 13.9 21768.740 297.0426.7 40.0 104.0 12.5 18586.480 296.3633.3 50.0 115.4 11.5 16387.550 295.91
-
8/13/2019 B.tech Project.cpd2014
23/85
40.0 60.0 125.8 10.7 14759.090 295.5846.7 70.0 135.4 10.1 13497.570 295.3353.3 80.0 144.4 9.6 12483.410 295.1360.0 90.0 152.9 9.2 11644.780 294.9766.7 100.0 161.0 8.8 10935.520 294.8373.3 110.0 168.7 8.5 10325.010 294.71
10000.000 ppm vol concentration reached 289.4 m at time 77. s
-
8/13/2019 B.tech Project.cpd2014
24/85
This is the output obtained in case of continuous heavy gas dispersion
W H A Z A N***********
HEAVY CLOUD DISPERSION MODEL****************************
Copyright (C)DNV Technica Ltd.
Date 4 Oct 1996 Time 00:40
Continuous release of n-Hexane (Gaseous)
Rate of release : 11.00 kg/sInitial flash : .000Duration : 100.0 s
Temp. after release : 342.0 KMolecular weight : 86.17Boiling point : 344.6 KSpecified lower conc.: 12000.000 ppmInitial dilution : 10.0 TimesFraction liquid : .000Initial cloud temp. : 308.0 KInitial cloud conc. : 78912.050 ppmInitial density : 1.317 kg/cu mInitial semi-width : 3.7 mCross sectional area : 27. sq mInitial height : 3.7 mSurface roughness : .100
Ambient temperature : 293.0 KRoughness length : .18 m
Air density : 1.196 kg/cu mRelative humidity : 80. %
Wind speed : 1.5 m/sMixing ratio : .012Pasquill category : F
TIME DISTANCE CLOUD CLOUD C/L CLOUDDOWNWIND RADIUS HEIGHT CONC. TEMP.
(s) (m) (m) (m) (ppm vol) (K)
.0 .0 3.7 3.7 78912.050 308.03Forced convection from .0 m
6.7 10.0 12.4 2.3 36603.000 300.2313.3 20.0 18.8 2.0 28127.050 298.0220.0 30.0 24.3 1.8 23755.340 296.9326.7 40.0 29.3 1.7 20884.200 296.24
-
8/13/2019 B.tech Project.cpd2014
25/85
33.3 50.0 34.0 1.6 18778.020 295.7440.0 60.0 38.4 1.6 17110.050 295.3646.7 70.0 42.6 1.5 15732.440 295.0653.3 80.0 46.6 1.5 14556.420 294.8160.0 90.0 50.5 1.5 13527.630 294.6066.7 100.0 54.2 1.5 12611.990 294.42
12000.000 ppm vol concentration reached 107.4 m at time 72. s
-
8/13/2019 B.tech Project.cpd2014
26/85
2.2.2 Event Trees
A number of different outcomes are possible for incidents A, B, C depending
on
If and when ignition occurs Consequences of ignition Two events have been drawn below to illustrate the incidentoutcomes of these releases.
Though ignition may occur at a number of positions depending onignition sources it.
It is assumed that the immediate ignition will cause a BLEVE from an
instantaneous release and a jet fire from a continuous release. If ignition is delayed until
the cloud has developed, the consequences will be either a UVCE or a flash fire. From
the event trees, the following incident outcomes are identified for the risk analysis:
BLEVE due to immediate ignition of an instantaneous release UVCE due to delayed ignition of an instantaneous release Flash fire due to delayed ignition of an instantaneous release Jet fire from immediate ignition of a continuous release Flash fire due to delayed ignition of a continuous release
-
8/13/2019 B.tech Project.cpd2014
27/85
Event tree for incident A
C o n t in u o u s
R e l e a s e
I m m e d i a t e I g n i t io n
N o I m m e d ia t e I g n it io n
D e la y e d I g n i t io n
N o I g n it io n
F l a s h F i r e
J e t F i re
T o x ic E f f e c t s
N o C o n s e q u e n c e s
Event tree for incident B and C
-
8/13/2019 B.tech Project.cpd2014
28/85
2.2.3 Consequences Of Incident Outcomes
The consequences of incident outcomes are calculated in the following sections.
The discrete zone approach is used to define flammable effects. It is assumed in thisapproach that within a zone people are assumed to be fatalities and outside the zonepeople are assumed to be non-fatalities. This method overestimates the proportion offatalities within the zone and underestimates them beyond it. The zones of fatal effectsfor various incident outcomes are calculated as follows:
Incident Outcome No.1: BLEVE due to immediate ignition of anInstantaneous Release.
Consider a BLEVE involving 28,000 kg of hexane (M), the followingparameters that is peak BLEVE diameter, BLEVE duration and center
height of BLEVE are calculated from following equations as shown below
Peak BLEVE diameter (Dmax) =6.48 x M 0.325= 181m BLEVE duration (tBLEVE) = 0.825 x M 0.26 = 12s Center height of BLEVE (HBLEVE) = 0.75 x Dmax= 136m
For duration of 12s, the incident radiation required for fatality ofan average individual of an average individual is approximately 75kW/m2
.This is derived from the figure that is for the 50% fatality line at 12s.
The incident radiation from a BLEVE is given by equation
QR = %E F21
Where%= transmissivity
F21= view factorE = surface emitted flux (kW/m2)
The transmissivity is given by equation given below!= 2.02 (P wx)
-0.09
Where
-
8/13/2019 B.tech Project.cpd2014
29/85
Pw= water partial pressure at ambient conditions (N/m2)
x = path length between flame surface and receiver (m)
The path length x is calculated asx = ( H2BLEVE+ r
2)1/2- 0.5 * Dmax= (1362+ r2)1/2 90.5
Where r is the horizontal distance from the column to the receiver
Assuming Pw = 2820 N/m2 , substituting in equation no.then the equation reduces to
%= 0.99 ((1362+ r2)0.5 90.5) -0.09
Consider the equation
F21= D2/ 4r2
Now, substitute D = Dmaxin the above equation and we getF21= 8190 r
-2
From an energy balance on the emitted energy we haveE = (Eradx M x He) / &x D
2maxxt BLEVE
Erad= 0.25 and heat of combustion for hexane is 4.5x 10+7J/kg. Therefore, E = 255 kW/ m2.This value may be
entered into the expanded equation.
QR= 0.99 ((1362+ r2)0.5- 90.5) -0.09x 8190 x r-2x 255
For a radiation level QRof 75 kW/m2, this equation may be solved byiteration to give r = 135m.Therefore,the area of fatal effect is a circle of
radius 135m, centered on column which would extend into the residential
area.
Incident Outcome No.2: UVCE due to delayed ignition of an Instantaneous
Release.
-
8/13/2019 B.tech Project.cpd2014
30/85
This incident outcome involves 28,000 kg of hexane. The equivalentmass of TNT is given by the equation given below.
Hence, the equivalent mass of TNT is 27,400 kg. The use of an empirical explosion yield of 0.1 should represent areasonable worst case result for an explosion incident outcome.
An overpressure of 3 psi is used to calculate the extent of fataleffects.
Hence the area of fatal effect for a UVCE of 28,000 kg of hexane isa circle of radius 239m, centered 85m downwind of the column, which
would extend well into the residential area.
Incident Outcome No.3: Flash fire due Delayed Ignition of an Instantaneous
Release.
For flash fires, an approximate estimate for the extent of fataleffect zone is the area over which the cloud is above the LFL.
It is assumed that this area is not increased by cloud expansion duringburning.
This is a circular zone of 148m radius centered 85m downwind.
Incident Outcome No.4: Jet fire from immediate ignition of a Continuous
Release.
Rough calculations based on the method of Considine and Grint thatis very strictly applicable to LPG, yield an end hazard range of 50% lethality at
31m for a 100-s exposure.
This result suggests that there is no direct threat to the residentialarea and this incident outcome shall not be considered further.
Incident Outcome No.5: Flash fire due to delayed ignition of a Continuous
Release.
This gives a pie shaped hazard zone 127m long downwind (71mdistance + 56m radius) with 48 of arc.
-
8/13/2019 B.tech Project.cpd2014
31/85
This incident can impact the residential area and has to beconsidered for further study.
The net result of these consequence effect calculations is that fourof the five Incident Outcomes could impact the Residential Area.
The next step in the calculation procedure is to determine Incidentand Incident Outcome Frequencies.
2.3 INCIDENT FREQUENCY ESTIMATION2.3.1 Frequencies Of The Representative Set Of Incidents
Data from the historical record have been used in order to estimatethe frequencies of the Representative Set of incidents.
In this case the column, vessels, pipes and pumps are standard processequipment and historical failure rate data are available for such items.
The basic failure rate data are listed in Table below. For each itemof equipment, the frequencies of a number of different sizes of failure are
given. These are quoted per item year except for piping for which
frequencies are given per meter year.
Item Size of failure Failure Rate
Piping
Small '50mm diameter
Full bore rupture 20% of pipe
diameter rupture
8.8 x 10-7(m yr-1)
8.8 x 10-6(m yr-1)
Medium > 50mm
diameter
'150mm diameter
Full bore rupture 20% of pipe
diameter rupture
2.6 x 10-7(myr-1)
5.3 x 10-6(myr-1)
Large > 150mm
diameter
Full bore rupture 20% of pipe
diameter rupture
8.8 x 10-8(myr-1)
2.6 x 10-6(myr-1)
Fractionating system
(excluding piping)
Serious leakage Catastrophic
failure
1.0 x 10-5(yr-1)
6.5 x 10-6(yr-1)
Using Table, the numbers of vessels, pumps, and pipe lengthsincluded in the Representative Set of incidents, the frequencies are calculated
as follows :-
-
8/13/2019 B.tech Project.cpd2014
32/85
Incident A: Instantaneous Release. This incident includes the following failures:
Catastrophic rupture of any component in the fractionating system Catastrophic (full bore) rupture of any pipework There is approximately 25 m of 0.5-m-diameter piping and 55 m of0.15-m equivalent diameter piping included in this incident. Hence, the
frequency is calculated as follows :
Catastrophic rupture of 6.5 x 10-6 = 6.5 x 10-6yr-1fractionating system
Full bore of55m of medium pipe 55 x 2.6 x 10
-7
= 1.4 x 10-5
yr-1
25m of large pipe 25 x 8.8 x 10-8= 2.2 x 10-6yr-1Total 2.3 x 10-5yr-1
Incidents B and C : Continuous Release.
This incident includes holes of 20% of the diameter for all pipingand serious leakage from vessels. There are approximately 25 m of large 0.5
m diameter piping and 55 m of medium 0.15-m-diameter piping included
in this incident. Hence, the frequency is calculated as follows:
Leaks from55 m of medium pipe 55 x 5.3 x 10-6= 2.9 x 10-4
25 m of large pipe 25 x 2.6 x 10-6= 6.5 x 10-5
Serious leakage fromfractionating system 1.0 x 10-5 = 1.0 x 10-5yr-1
Total 3.7 x 10-4yr-1
2.3.2 PROBABILITIES OF INCIDENT OUTCOMES
The Probabilities of each incident outcome is determined byassigning probabilities to all the branches of the event trees of figures.
Some of the probabilities are direction dependent. (ie., the proportion of
the residential area involved affects the probability of ignition).
-
8/13/2019 B.tech Project.cpd2014
33/85
For this case, two event trees have been developed for eachindent one that considers wind directions toward the residential area
and one that considers all other directions. The results of this exercise are
shown in figure 8.15 through 8.18. For this case study, the branch
probabilities for these event trees have been derived using engineering
judgement.
In a real risk assessment better validated sources would be preferred.It is important that such assumptions are documented for later review and
sensitivity analyst if warranted. A summary of the values selected and their
justification is listed in tables given below Preparation of incident
outcome case frequencies.
2.3.3 Preparation of incident outcome case frequencies
The prior analysis of a revised list of potential incidents (under thecategories of complete rupture, liquid leaks and vapor leaks) gives
Representative Set of three potential incidents (Incidents A, B and C).
It is assumed that with minimal loss in accuracy, those incidentscan be characterized as a single catastrophic incident (Incident A) and a single
continuous release (Incidents B and C).
The event tree analysis developed the instantaneous andcontinuous release incidents to four specific incident outcomes that
can impact the residential area. These can be listed as:
Incident Outcomenumber
Incident outcome
1 BLEVE due to immediate ignition of an instantaneousrelease
2 UVCE due to delayed ignition of an instantaneous release
3 Flash fire due to delayed ignition of an instantaneous release4 Flash fire due to delayed ignition of a continuous release
The frequencies of incident outcome cases, which are dependent on winddirection, are calculated in table given below. In that table the headings are defined are
Incident - The incident from the Representative Set chosen for theAnalysis.
-
8/13/2019 B.tech Project.cpd2014
34/85
Incident outcome - The incident outcomes related to a particularincident which were shown to have potential for public impact.
Incident frequency The frequency of each incident in theRepresentative Set
Incident outcome probability - The probability of an incident outcomebased on event tree analysis given that the probability of the incident is
1.0
2.4 RISK ESTIMATIONIndividual Risk
The individual risk in the area around the column is estimated from the above
incident outcome case frequencies and consequences effect zones (Chapter 4). The
discrete consequence effect zones were estimated previously.
Incident Outcome
1. BLEVE a circle of radius 135 m centered on the column2. UVCE a circle of radius 239 m centered 85m from the column3. Flash fire (instantaneous) a circle of radius 148 m centered 85 m from the
column4. Flash fire (continuous) a pie shaped section (48oangle) that extends a total of
127 m from the column. The radius is 56m centered on a point 71 m from thecolumn.
These four consequence effect zones have been superimposed over the plantlayout to scale in the east direction in Figure 8.19. From consequence considerationonly. The consequence effects, ranked in descending order, are UVCE, Flash fire(instantaneous). BLEVE, and Flash Fire (continuous).
The four consequence effects described above can be divided into 3 commontypes :
Circular shaped, centered on column (Incident Outcomes 1)Circular shaped centered 85 m from column (incident outcomes 2 and 3)Pie shaped, originating at column (incident outcome 5)
Each of these must be treated slightly differently in calculating individual risk,but it is straightforward to extend this procedure to any effect zone shape and position.
-
8/13/2019 B.tech Project.cpd2014
35/85
Figures illustrate the general shape of the individual risk profile as a function of
distance, for each of the four incident outcomes, along any wind direction (including
the east direction that contains the residential area). The zero point in each of the
figures is the location of the fractionating system.
It is very important in the estimation of individual risk (and as will be shown
later, in the estimation of societal risk) that overlapping incidents be properly
considered. Thus, with the large UVCE consequence effect zone, consideration of only
the W to E wind case would greatly underestimate the risk for those living to the east as
UVCE incidentxs from all 8 directions contribute to the risk.
The calculation of the individual risk at any point assumes that the
contributions of all incident outcomes cases are additive. Therefore, the total individual
risk at each point is equal to the sum of the individual risxks from all possible incident
outcome cases.
The individual risk in this study is not symmetrical around the column because
of the directional probabilities of the wind and ignition. Ideally, an individual risk
contour could be developed that includes points in each of the eight wind directions.
However, in this study, the population is only situated east of the plant and an
individual risk curve will be developed only for that easterly direction.
Each of figures contains a set of distances for that incident outcome. Each
distance listed on a particular figure represents a subset of incident outcome cases that
reach that distance. However, other incident outcomes can also provide cases that
-
8/13/2019 B.tech Project.cpd2014
36/85
apply at the same distance. Therefore, for every distance listed in figure a calculation
should be made that sums all of the total incident outcome cases that contribute at that
distance.
Table presents a summation of the individual risk for a distance of 0-63m in an
easterly direction from the column. All incident outcome cases contribute in this
calculation with the expection of Flash fire (continuous) wind directions N to S, NE to
SW, E to W, SE to NW and S to N.
Table has been developed to show the changes to total individual risk the result
at each discrete distance. The permits development of the Total (ndividual Risk Curve
in the East Direction.
Some observations on the results are :
1. The risk near the column has property been underestimated, sincesmall incidents that may contribute to the risk in this area have been excluded
from the analysis (e.g jet fire hazards).
2. The choice of only two places for ignition (immediate and delayeduntil the LFL concentration is reached) simplifies the real situation of
ignition points at intermediate locations due to residential areas, fired
process equipment, roads, etc. A different ignition distribution could be
considered, but with increased calculational burden.
3. The use of only one weather condition (F stability, 1.5 m/s windspeed) generally tends to overestimate risk at a given distance, because the
longest dispersion distances are usually associated with F stability, low
wind speed conditions.
4. The risk from UVCE is probably overestimated because of the highexplosive yield chosen.
-
8/13/2019 B.tech Project.cpd2014
37/85
These assumptions have been chosen to provide a reasonable, but conservative,
risk estimate using a minimum number of manual calculations. Where the resulting
risk estimates indicate a potential problem, the analyst can decide whether some
simplifying assumptions should be made more realistic, and the calculations repeated.
However, each change in an assumption probably represents a significant increase in
the number of incident outcome cases. An alternative approach is to use a computer
tool that automates the calculation procedures, allowing analysis of a greater number of
incident outcome cases.
SOCIETAL RISK
The first step in the estimation of societal risk is to calculate the number of
fatalities for each incident outcome case. For this case study, consequence effect zones
are discrete (within the zone there will be 100% fatalities) and an assumption is made
that the residential area has a uniform population distribution. Therefore, the fraction
of residential area covered by each incident outcome case will represent the fraction of
200 fatalities which would result table summarizes these results.
The data in Table represent the raw information from which the societal risk
estimate may be developed. The data must be put into a cumulative frequency form in
order to plot the F-N curve. This is accomplished by rearranging the incident outcome
cases by descending number of fatalities and then calculating the frequency of having N
or more fatalities. This procedure is presented in table.
-
8/13/2019 B.tech Project.cpd2014
38/85
The data in the first and last columns are plotted on logarithmic scales to
produce the F-N curve shown in Figure. Adding more incident outcomes cases will
produce a smoother curve because of the additional data points, but will not necessarily
produce significant upward or downward bias.
2.5 CONCLUSION
The largest contribution to individual risk near to the column is from flash fires
from pipe rupture equivalent to 20% of the pipe diameter. Remedial measures might
include more frequent inspection or monitoring of wall thickness, if significant
corrosion and/or erosion effects are anticipated.
The largest contributor to the societal risk, not unexpectedly, is from
instantaneous release of the contents and delayed ignition resulting in an unconfined
vapor cloud explosion.
The radius of the consequence zone is proportional to the 1/3 power of the
quantity released. Therefore, only a very major reduction in quantity has a significant
effect in reducing that radius. Nonetheless, additional remote isolation for the system
could be considered. Vessel and piping integrity is the major concern. Additional
ispection, perhaps utilizing different methods, could be considered.
-
8/13/2019 B.tech Project.cpd2014
39/85
Finally, because of the magnitude of the societal risk, additional study could
consider other causes of vessel failure, such as overpressurization, that could lead to
identical consequences. These studies, probably utilizing FTA, could indicate whether a
threat of overpressurization is significantly higher than basic vessel failure and
engineering or procedural controls could be implemented to reduce that risk.
CHAPTER 3
REVIEW OF RELATED LITERATURE
3.1 TORAP
TORAP(Tool for Rapid riskAssessment in Petroleum refinery) A new toolfor conducting assessments in petroleum refineries and petrochemical industries. Thispackage is used to identify steps to prevent / manage accidents
TORAP involves the following main steps: The accident scenario general step Consequence Analysis Checking for higher degree of accidents Characterization of worst-accident scenario
3.1.1 The accident scenario general step
An accident scenario is basically a combination of different likely accidental
events that may occur in an industry. Such scenarios are generated based on the
properties of chemicals handled by the industry, physical conditions under which
reactions occur or reactants / products stored, geometries and material strength of
vessels and safety arrangement etc. External factors such as site characteristics &
metrological conditions are also considered.This step would help in the development of
more appropriate & effective strategies for crisis prevention & management.
-
8/13/2019 B.tech Project.cpd2014
40/85
3.1.2 Consequence Analysis
This involves the assessment of likely consequences if an accident occurs. Theconsequences are quantified in terms of :Damage radii the radius of the area in which damage would readily occur.
Damage to propertyToxic effects
3.1.3 Checking for higher degree of accidents
Higher degrees of accident like secondary and tertiary accidents are moreprobable in petroleum refineries and petrochemical industries.The TORAP packageestimates the damage potential of secondary accident (provided it is higher than theminimum value) and its likelihood of causing third degree accidents.
3.1.4 Characteristics of worst-accident scenario
This is the final step in TORAP algorithm. This step determines the worst-accident scenario based on the results of a consequences analysis. This step helps todevise strategies to avert a crisis or to minimize its adverse impact if the crisis does takeplace.
AdvantagesCharacterization of accidents as primary, secondary, tertiary is possible
FLOW CHART indicating the procedure of TORAP
-
8/13/2019 B.tech Project.cpd2014
41/85
-
8/13/2019 B.tech Project.cpd2014
42/85
CONCLUSION
Chemical process quantitative risk analysis is an effective management tool forcarrying out safety analysis in process industries.
In this study project a distillation column has been taken as the focus of interest
and detailed report, concerning the RISK posed by it, the incident outcomes possible
has been discussed.
Also TORAP, i.e method for risk assessment in refineries had been disused.
CHAPTER 1
INTRODUCTION
BRIEF INTRODUCTION
1-Chloro -4- nitrobenzene is produced and used in chemical industryand is not known to occur naturally.
It is used in the synthesis of industrial chemicals (e.g. para nitrophenol, para-nitro aniline, para-aminophenol, 4-nitroanisole, and
para-anisidine), pesticides (e.g.parathion methyl parathion, ethyl
parathion and nitrophen), the analgesic drugs phenacitin and
acetaminophen, and the antimicrobial drug dapsone which is
used to treat leprosy among other conditions.
1 Chloro 4 nitrobenzene is also used in the synthesis of 4-nitrodiphenylamine-based antioxidants for rubber.
-
8/13/2019 B.tech Project.cpd2014
43/85
p-Nitrochlorobenzene is used as an intermediate for organic synthesis;p-nitrophenol, azo dyes and sulfate dyes, pharmaceuticals(such as
phenacetin and acetaminophen) and pesticides (such as nitrofen,
parathion) and rubber chemicals.
-
8/13/2019 B.tech Project.cpd2014
44/85
Physical and Chemical Properties
1-Chloro-4-nitrobenzene is a crystalline yellow solid at room temperature with a
sweet odor and is slightly soluble in water (243 mg/L at 20oC).
Molecular Formula : C6H4ClNO2
Molecular Weight : 157.56
Chemical Class : nitroaromatic
Melting point : 82.6oC
Boiling point : 242oC
Vapor Pressure : 0.15mm Hg (at 30oC)
Synonyms
Para-chloronitrobenzene, 4-chloro-1-nitrobenzene, 4-nitrochlorobenzene, para-
nitrochlorobenzene, 1-nitro-4-chlorobenzene, 4-nitro-1-chlorobenzene.
REVIEW OF LITERATURE
Methods of preparing chlorontrobenzene include.
1. diazotisation of nitroanilines of replacement by chlorine
2. Reaction of phosphorous pentachloride with nitrophenols
But all these methods are applicable to laboratories and not of commercial
interest. Hence, manufacture of paranitrochlorobenzene from chlorination of
nitrobenzene is used for commercial purpose.
CHAPTER 2
PROCESS
2.1 PROCESS DESCRIPTION
Chlorobenzene is the main raw material used in the manufacture ofpara nitro chlorobenzene.
Cl
No2
-
8/13/2019 B.tech Project.cpd2014
45/85
It is fed into a nitrator where chlorobenzene is nitrated usingnitrating acid. This acid is composed of 52.5 weight percent of H2SO4, 35.5
weight percent of HNO3 and 12 weight percent of H2O.
A slight excess of chlorobenzene usually is fed into the nitrator toensure that the nitric acid present is consumed to the maximum possible
extent. The reaction mixture flows from the nitrator into a separator or a
centrifuge where the organic phase is separated from the aqueous phase.
This aqueous phase or spent acid is drawn from the bottom andconcentrated and recycled to the nitrator, where it is mixed with nitric acid
and sulphuric acid immediately prior to being fed into the nitrator.
Crude nitro chlorobenzene is obtained at this stage which is mainly amixture of isomers. Further, purification is needed to obtain para nitro
chlorobenzene from the mixture of isomers which also contains small
quantities of chlorobenzene and sulphuric acid.
The crude nitro chlorobenzene flows through a couple of washer-separators where residual acid is removed by washing with dilute base
followed by final washing with water.
The product then is distilled to remove chlorobenzene from themixture of isomers. The bottom product which is a mixture of isomers
contains about 34 weight percent ortho nitro chlorobenzene, 65 weight
percent para nitro chlorobenzene and 1weight percent meta nitro
chlorobenzene.
The mixture is cooled to a temperature slightly above its freezingpoint and a large portion of para isomer slowly crystallizes and is
separated from the mother liquor. Thus para nitro chlorobenzene is
obtained in the form of crystals with very less impurities.
-
8/13/2019 B.tech Project.cpd2014
46/85
The reaction time takes about 10-30 minutes and theoretical yield isabout 96-99 %.
2.1.1 Equipment Description
NITRATOR
The reaction vessels are acid resistant, glass-lined steel vesselsequipped with efficient agitators.
Optimum mass transfer of reactants is maintained by vigorousagitation. The reactors contain internal cooling coil which control the
temperature of the highly exothermic reaction.
CRYSTALLISER
The crystallizer used in this process is SWENSON- WALKERcrystallizer.
It consists of a open trough with a semi- cylindrical bottom, a waterjacket welded to the outside of the trough and a slow speed long pitch,
spiral agitator running at about 7 rpm and set as close to the bottom of the
trough as possible.
-
8/13/2019 B.tech Project.cpd2014
47/85
Nitrator Acid
separator
Spent acid
reconcentration
Washtower(1)
Washtower(2)
Di
c
W aste water
treatment
Nitro c
(I
Salt + water
Cr
paranitro
Fresh
Sulphuric acid
Nitrating
Ac id
Chlorobenzene
Reaction mixture
Crude
Nitrochlorobenzene
Dilute baseNaOH Water
Spent
Ac id
FreshNitric acid
-
8/13/2019 B.tech Project.cpd2014
48/85
2.2 MATERIAL BALANCE
NITRATOR
BASIS: 1000 kg/hr of nitrating acid.
The reaction given below takes place in the reactor.
C6H5Cl + HNO3 )C6H4ClNO2+ H2O
Composition of Nitrating Acid
Components Weight(kg) Molecular
weight(kg/kmole)
No. of moles
(in kmole)
HNO3 355 63 5.635
H2SO4 525 98 5.357
H20 120 18 6.667
Amount of chlorobenzene to be taken ( 20% excess) = 1.2 x 5.635
=6.762 kmoles
Products from Nitrator
H2SO4 = 5.357 kmoles
H2O = 6.667+(0.98 x 5.635) =12.98 kmoles
C6H4ClNO2= 0.98 x 5.635 = 5.522 kmoles
HNO3= 0.02 x 5.635 = 0.113 kmolesC6H5Cl = (0.02 x 5.635) + (0.2 x 5.635) =1.24 kmoles
-
8/13/2019 B.tech Project.cpd2014
49/85
ii
WASHING
Input to wash tower 1
Crude Nitrochlorobenzene
C6H4ClNO2 = 869.7 kg
H2SO4= 26.25 kgH20 = 10.27 kg
C6H5Cl = 139.5 kg
Dilute base required to neutralize H2SO4completely
2NaOH + H2SO4 " Na2SO4+ 2H20
NaOH required = 2 x 0.2679 = 0.536 kmoles = 21.44 kg
Total input = 1760.72kgTotal output = 1760.72kg
-
8/13/2019 B.tech Project.cpd2014
50/85
iii
Input to wash tower 2
C6H4ClNO2: 869.7 kg
Na2SO4:38.042 kg
H2O: 20.62 kg
C6H5Cl: 139.5 kg
Amount of water required to dissolve Na2SO4completely =96.48 kg
-
8/13/2019 B.tech Project.cpd2014
51/85
iv
D = F ( x F x B ) / ( x D x B)
Input to Distillation Column
Feed contains: C6H5Cl = 139.5 kg
C6H4ClNO2= 869.7 kg
Total = 1009.2 kg
In mass fraction:
x F = 0.14 ; x D= 0.98 ; x B= 0.03
D= 116.85kg B= 892.35kg
-
8/13/2019 B.tech Project.cpd2014
52/85
v
Crystallizer
Solubility of para C6H4ClNO2at 80oC is
kg para C6H4ClNO20.085
kg ortho C6H4ClNO2
Feed Mother liquor =328.25kgorthoC6H4ClNO2 orthoC6H4ClNO2=302.65kg=302.95kg para C6H4ClNO2=25.6kgpara C6H4ClNO2=562.93kg para C6H4ClNO2
crystals = 537.33kgTotal = 865.58kg Total = 865.58kg
ENERGY BALANCE
Crystallizer
Total =1009.2kgTotal =1009.2kg
-
8/13/2019 B.tech Project.cpd2014
53/85
vi
*Hreaction = +(mcp*T)products+*Ho
reaction +(mcp*T)reactants
+(mcp*T)products = (mcp*T) C6H4ClNO2 - +(mcp*T)H2SO4+
(mcp*T)HNO3+(mcp*T)H2O+(mcp*T)C6H5Cl
= [(869.7 x 1.589) + (52.5 x 2.425) +
(7.12 x 2.941) + (219.4 x 4.186) +
(139.5 x 1.2104)] x (70.25)
= 1,69,347.5 KJ
*Horeaction = *Hf-products- *Hf reactant
*Hf product = [(-309.46 x 869.7) + (454.13 x 139.5)
+ (-8273.3 x 525) + (2747.47 x 7.12) +
(-68.3174 x 219.4)]
= 45,44,695.6 kJ
*Hf reactants = (454.13 x 760.72) + (-8273.3 x 525)
+ (2747.47 x 355) + (-68.3174 x 120)
= 30,30,862.9 kJ
*Horeaction = -45,44,695.6 (-30,30,862.9)
= -15,13,832.7 kJ
+(mcp*T)reactants = (mcp*T)C6H5Cl+ (mcp*T)H2SO4 + (mcp*T)HNO3
+ (mcp*T)H2O
= [(760.07 x 1.2104) + (525 x 2.425)
+ (355 x 2.941) + (120 x 4.186)] x (40-25)= 56104.13 kJ
*Hreaction = 169347.5 -1513832.7-56104.13
= - 1400589.3 kJ
-
8/13/2019 B.tech Project.cpd2014
54/85
vii
Mass of cooling water required.
Heat to be removed = 1400589.3 kJ
(mcp*T)water = 1400589.3*T = 40
m (4.186)(40) = 1400589.3
m = 8364.7 kg.
Distillation column
Condenser Hot fluid: distillate
Cold fluid: water
Distillate = 116.85 kg. = 1.03 kmoles
Latent heat of distillate = 36564.65 kJ/kmol = 322.44 kJ/kmol
(m,)hot fluid = (mcp*T)cold fluid
116.85 x 322.44 = m x 4.186 x 20
mass of water required = 450 kg.
Reboiler
-,= ms,s
- = V- F(1-q))
q = 1
-= v = D(R+1) = 1.03(5.75+1) = 6.953 kmoles
-=6.953 kmoles = 788.5 Kg.
,avg.= 36885.88 kJ/kmol = 236.2 kJ/kg.
-,= ms,
788.5 x 236.2 = ms x2259.83
mass of steam required = 82.42 kg.
Crystallizer
-
8/13/2019 B.tech Project.cpd2014
55/85
viii
Design summary:
Diameter of reactor = 0.56m
Length of reactor = 2.8 m
Heat from the crystallizer:
Q = Fcp*T + C,
= (865.58 x 1.589 * (245-80)) + (537.33*234.3)= 352838.5 kJ
cooling water requirement
Q = (mcp*T)cooling water
m = 352838.5/ 4.186 X (353-288)
= 1296.7 kg.
DESIGN
REACTOR DESIGN
Space time = %= 20 minutes
%= V / VO
VO = mo/!
= (760.72/1128) + (1000/1447.33)= 1.365m3/hr
V = 0.683 m3
Assumption: L/D = 5
(.D2 / 4)x L = O.683m3
D = 0.56 m
L = 2 .8 m
DISTILLATION COLUMN
-
8/13/2019 B.tech Project.cpd2014
56/85
ix
Design Summary:
No of theoretical stages = 6
Column diameter = 0.72m
Column height = 5.85m
x 0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1
y 0 0.28 0.46 0.6 0.7 0.77 0.84 0.89 0.93 0.97 1
Where y = $x /1+($-1 )xLet $= 3.5
/= D(R+1)
D = 1.03 kmoles/hr
R = 5.75
/= 6.953 kmoles/hr
At the top
No. of moles of vapour = 6.953 kmoles/hr
Assuming ideal gas behaviour, VO= nRT / P = (6.953 x 0.082 x 405) /1
= 230.91m3/hr
Assumption: vapour velocity = 0.2 m/s
Cross sectional area = 230.91/ (3600 x 0.2) = 0.321m2
Column diameter = 0.64 m
At the bottom
No.of moles of vapour = 6.953 kmoles/hr
Vapour flow rate = (6.953 x 0.082 x 518 )/1 = 295.33 kmoles/hr
Cross sectional area = 0.41 m2
Column diameter = 0.72m
COLUMN HEIGHT
Assumption: plate efficiency = 50%
Plate spacing = 0.45m
No.of actual plates = (7-1)/ 0.45 = 12
Column height= ((12-1)+ 2) x 0.45 = 5.85 m
-
8/13/2019 B.tech Project.cpd2014
57/85
x
Design Summary:
Area of the crystallizer =13.15m2
No of the sections = 6
CRYSTALLIZER DESIGN
Surface area required
Q =U A *Tlm
Where U = 250 kJ/hr m2K
*Tlm= (*T2 -*T1)/ln (*T2/*T1)= (165-65)/ln (165/65)
= 107.34
Area = 352838.35/(250 x 107.34)
= 13.15m2
Number of sections = total area / area of one section
Maximum length of 1 section is 5ft = 1.524m.
Assumption 1.5m2
of cooling surface per m length of crystallizer is available.Area of one section =1.5 x 1.524 =2.286m2
No of sections =13.15/2.286
=5.8
-
8/13/2019 B.tech Project.cpd2014
58/85
xi
PROCESS CONTROL AND INSTRUMENTATION
The primary objectives of the designer when specifying instrumentation and
control schemes are:
1. Safe Plant Operation
a.To keep the process variables within known safe operating limitsb.To detect dangerous situations as they develop and to
provide alarms and automatic shut-down systems.
c.To provide interlocks and alarms to prevent dangerousoperation procedures.
2. Production rate
To achieve the designed output.
3. Product quality
To maintain the product composition within specified quality standards.
4. Cost
To operate at the lowest production cost, commensurate with the other
objectives.
REACTOR CONTROL
The schemes used for reactor control depend on the process and the type of
reactor. If a reliable on-line analyzer is available, and the reactor dynamics are suitable,
the product composition can be monitored continuously and the rector conditions and
feed flows controlled automatically to maintain the desired product composition and
yield. More often, the operator is the final link in the control loop, adjusting the
-
8/13/2019 B.tech Project.cpd2014
59/85
xii
controller set points to maintain the product within specification, based on periodic
laboratory analysis.
Reactor temperature will normally be controlled by regulating the flow ofcooling medium. Pressure is usually held constant. Material balance control will be
necessary to maintain the correct flow of reactants to the reactor and flow of products
and unreacted, materials from the reactor.
INSTRUMENTATION
TEMPERATURE MEASUREMENT
The temperature measuring element in a control system for jacketed tank is
generally a thermocouple. The five most commonly used thermocouples are copper
constantan, iron constantan, chromel alumel, platinum platinum 13% rhodium,
platinum platinum 10% rhodium.
LEVEL MESUREMENT
The float- shaft type is employed either in open vessels. This method is suitable
for a wide range of liquids and semi-liquids. Difficulties are sometimes encountered
when the liquid deposits on the float and when the liquid level is foaming or turbulent.
FLOW RATE MEASURING
The industrial devices for flow rate estimation are common orifice meter,
venturimeter, pilot tube and the Rota meter. The piping system must be made ofspecial corrosion resistant material when corrosive fluids are used.
pH MEASUREMENT
-
8/13/2019 B.tech Project.cpd2014
60/85
xiii
In this process we use the digital pH meters, these pH meters can measure the
pH of the solution accurately for two decimal places. These pH meters can be used
over wide range temperatures. These pH meters dont require additional current for the
working once they are dipped in the solution they measure the pH of the solution onthe display.
PLANT LAYOUT
Administrative
Block
Hospital
Canteen
P
A
RK
I
N
G
S
E
C
UR
I
T
Y
check
post
Transformer
Fire
Station
Training Academy
Health Club
Work shop
Water
Treatment
Area
Store
House
Quality Prod and control limit
Lab and testing area
Processing
Area
-
8/13/2019 B.tech Project.cpd2014
61/85
xiv
PLANT LOCATION AND SITE LAYOUT
The location of the plant can have a crucial effect on the profitability of a
project, and the scope for the future expansion. There are many factors must beconsidered while selecting a suitable site. Some of the principal factors while selecting a
suitable site. Some of the principal factors which must be considered for the selection
of chemical process site are:
1. Area of development favored by the government and the incentives, whichare available.
2. The likelihood of finding suitable employees in the area and of wagesubsides.
3. The peculiarities of climate.4. Sources of electricity gas and water.5. Area of atleast 100 acres of level ground on good boulder clay free from
any danger of flooding.
6. Not sensitive environmental area.7. Besides fresh water, adequate water must be available for cooling purposes.8. Readily linked railway system.9. Besides readily linked road system.10.Near a responsible population centre.11.Local community considerations.12.Environmental impact and effluent disposal.13.Political and strategic considerations.14.Climate.15.Expansion possibilities.
SITE LAYOUT
The process units and ancillary building should be laid out to give the most
economical flow of materials and personal around site. Hazardous process must be
located at a safe distance from other buildings.
-
8/13/2019 B.tech Project.cpd2014
62/85
xv
Considerations must also be given to future expansion of the site. The ancillary
buildings and services required on site, in addition to the main processing
units(buildings),will include :
1. Storages for raw material and products : Tank farms andWare house
2. Maintenance workshops.3. Store for maintenance and operating supplies.4. Laboratories for process control.5. Fire stations and other emergency services.6. Utilities : steam boilers , compressed air , power generation ,
Transformer station.7. Effluent disposal plant.8. Offices for general administration.9. Canteens and other amenity buildings, such as medical centers.10. Regulatory laws.11. Taxes.12. Car parks.
RAW MATERIALS SOURCES
Careful considerations should be given to the sources of raw materials to be
used, method of delivery and storage facilities of raw materials.
WASTE PRODUCT DISPOSAL
Another aspect, which is gaining importance these days, is the environmental
considerations. Careful attention should be given to the nature of products to be
wasted, their quantity, available methods of disposal and the legislations governing the
disposal.
-
8/13/2019 B.tech Project.cpd2014
63/85
xvi
Location can be an important factor for cost. If the bearing quality of the land
is low, considerable amount may be spent in piling support for heavy equipments or
multi-storied buildings. If the land is uneven and the site needs even level, the cost of
leveling may be considerable. Sometimes advantage can be taken of uneven levels so asto use gravity as a means of transportation of materials.
When planning the preliminary site layout, the process units will normally be
sited first and arranged to give a smooth flow of materials through various processing
steps, from raw material to final product storage. Process units are normally spaced at
least 30 meters apart. Administration offices and laboratories, in which a relatively large
number people will be working, should be located well away from potentially hazardous
process control rooms. The siting of the main process units will determine the layout ofthe plant roads, pipes, alleys and drains. Access roads will also be constructed for
operation and maintenance purpose. Utility building should be sited to give the most
economical run of the processing units. The main storage areas should be placed
between the loading and unloading facilities and the process units they serve. Storage
tanks containing hazardous materials should be sited at least 70 meter from site
boundary.
PLANT LAYOUT
The economic construction and efficient operation of a process unit will
depend on how well the plant and equipment specified on the process flow sheet is laid
out. The major principal factor that has to be considered while designing a plant layout
is as follows:
1. Economic considerations : Constructions and operating cost2. Damage to person and property an case of fire , explosion and3. toxic release4. The process requirements5. Convenience of maintenance.6. Safety7. Future expansion.
-
8/13/2019 B.tech Project.cpd2014
64/85
xvii
8. Modular constructions.
It is also advisable to check up the insurance regulations from the view of
getting the best coverage at minimum cost for plant building and inventory. Adjacent tofermentors a separate house can be provided for pumps, compressors, molasses
weighing system etc.
STORE AND WAREHOUSES
The engineer must decide whether the warehouses must be at ground level or
dock level.
The latter facilitates loading trains and trucks, but costs 15-20% more than one
placed on the ground. It is usually difficult to justify the added expenses of a dock-high
warehouse.
To size the amount of space needed, it must be determined how much is to be
stored in what size containers. The container sizes that will be used are obtained from
the scope. Liquids are generally stored in bulk containers. No more than a weeks
supply of liquid stored in drums should be planned. Solids, on the other hand, arefrequently stored in smaller containers or in a pile on the ground.
COST ESTIMATION
ESTIMATION OF THE TOTAL CAPITAL INVESTMENT
The total capital investment I involves the following:
A. The fixed capital investment in the process area, IF.
B. The capital investment in the auxiliary services, IA.C. The capital investment as working capital, IW.
i.e., I = IF + IA + IW
-
8/13/2019 B.tech Project.cpd2014
65/85
xviii
A. FIXED CAPITAL INVESTMENT IN THE PROCESS AREA, IF.
This is the investment in all processing equipment within the processing area.
Fixed capital investment in the process area, IF = Direct plant cost + Indirect
plant cost
The approximate delivered cost of major equipments used in the proposed P-
nitrochlorobenzene manufacturing plant are furnished below:
S.No. Equipment Units Cost in
lakhs/unit
Cost in lakhs
1 Crystallizer 1 350 350
2 Reactor 1 250 250
3 Condenser 1 308 308
5 Distillation column 1 420 420
6 Pump 4 0.5 2
7 Storage tank sealed 2 100 200
8 Miscellaneous 2600
TOTAL 4130 lakhs
Direct Cost Factor
S.No Items Direct cost factor
1 Delivered cost of major equipments 100
2 Equipment installation 15
3 Insulation 15
4 Instrumentation 15
5 Piping 75
-
8/13/2019 B.tech Project.cpd2014
66/85
xix
6 Land & building 30
7 Foundation 10
8 Electrical 15
9 Clean up 5
Total direct cost factor 280
Direct plant cost = (Delivered cost of major equipments)
(Total direct factor) / 100
Direct plant cost = (4130 x 280) / 100
= 11564 lakhs
Indirect Cost Factor
S.No. Item Indirect cost factor
1 Overhead contractor etc. 30
2 Engineering fee 13
3 Contingency 13
Total indirect cost factor 56
Indirect plant cost = (Direct plant cost)
(Total indirect cost factor)/ 100
= (115664 x 56) / 100
= 6475.84 lakhs
Fixed capital investment in the process area, IF = Direct plant cost + Indirect
plant cost
= 1156 + 6475.84
= 18039.84 lakh
B. THE CAPITAL INVESTMENT IN THE AUXILLARY SERVICES, IA.
Such items as steam generators, fuel stations and fire protection facilities are
commonly stationed outside the process area and serve the system under consideration.
-
8/13/2019 B.tech Project.cpd2014
67/85
xx
S.No. Items Auxiliary services cost factor
1 Auxiliary buildings 5
2 Water supply 23 Electric Main Sub station 1.5
4 Process waste system 1
5 Raw material storage 1
6 Fire protection system 0.7
7 Roads 0.5
8 Sanitary and waste disposal 0.2
9 Communication 0.2
10 Yard and fence lighting 0.2
Total 12.3Capital investment in the auxillary services = (Fixed capital investment in the
process area) (Auxiliary services cost factor) / 100
= (18039.84 x 12.3) / 100
= 2218.9 lakhs
Installed cost = Fixed capital investment in the process area + Capital
investment in the auxiliary services
= 18039.84 + 2218.9
= 20258.74 lakhs
C. THE CAPITAL INVESTMENT AS WORKING CAPITAL, IW.
This is the capital invested in the form of cash to meet day-to-day operational
expenses, inventories of raw materials and products. The working capital may be
assumed as 15% of the total capital investment made in the plant (I).
Capital investment as working capital, IW
= ((18039.84 + 2218.9) x 15) / 85
= (20258.74 x 15) / 85
= 3575.071 lakhs
-
8/13/2019 B.tech Project.cpd2014
68/85
xxi
Total capital investment, I = IF+ IA+ IW
= 18039.84 + 2218.9+ 3575.07
= 23833.81 lakhs
ESTIMATION OF MANUFACTURING COST
The manufacturing cost may be divided into three items, as follows:
A. Cost Proportional to total investment
B. Cost proportional to production rate
C. Cost proportional to labour requirement
A. COST PROPORTIONAL TO TOTAL INVESTMENT
This includes the factors, which are independent of production rate and
proportional to the fixed investment such as
- Maintenance-labour and material- Property taxes- Insurance- Safety expenses- Protection, security and first aid- General services, laboratory, roads, etc.- Administrative services
For this purpose we shall charge 15% of the installed cost of the plant
= (Installed cost x 15) / 100
= (20258.74 x 15) / 100
= 3038.811 lakhs
B. COST PROPORTIONAL TO PRODUCTION RATE
-
8/13/2019 B.tech Project.cpd2014
69/85
xxii
The factors proportional to production rate are
- Raw material costs- Utilities cost power, fuel, water. Steam, etc.- Maintenance cost- Chemical, warehouse, shipping expenses
Assuming that the cost proportional to production rate is nearly 60% of total
capital investment.
Cost proportional to production rate
= (Total capital investment x 60) / 100
= (23833.81 x 0.6)
= 14300.286 lakhs
C. COST PROPORTIONAL TO LABOUR REQUIREMENT
The cost proportional to labour requirement might amount to 10% of total
manufacturing cost.
Cost proportional to labour requirement
= (3038.811 + 14300.286)(0.1) / (0.9)
= 1926.566 lakhs
Therefore, manufacturing cost
= (3038.811 + 14300.286 + 1926.566)
= 19265.657 lakhs
SALES PRICE OF PRODUCT
Market price of Paranitrochlorobenzene = Rs.18/kg
Production rate =1.5x105TPA
Total sales income = 18x1.5x105 x1000
= 27000 lakhs
-
8/13/2019 B.tech Project.cpd2014
70/85
xxiii
PROFITABILITY ANALYSIS
A. DEPRECIATION
According to sinking fund method:
R = (V-VS) I / (1+ I)n
R = Uniform annual payments made at the end of each year
V = Installed cost of the plant
VS = Salvage value of the plant after n years
N = life period (assumed to be 15 years)I = Annual interest rate (taken as 15%)
R = (20258.74 x 0.15) / (1+0.15)15-1
= 425.779 lakhs
B. GROSS PROFIT
Gross profit = Total sales income - manufacturing cost
= 27000 19265.657= 7734.343 lakhs
C. NET PROFIT
It is defined as the annual return on the investment made after deducting
depreciation and taxes. Tax rate is assumed to be 40%.
Net profit = Gross profit-Depreciation-(Gross profit*Tax rate)= 7734.434-425.779-7734.434*0.4)
= 4214.8268 lakhs
D. ANNUAL RATE OF RETURN
-
8/13/2019 B.tech Project.cpd2014
71/85
xxiv
Rate of return = (100*Net profit/Installed cost)
= (100*4214.8268) / 20258.74 = 20.8%
E. PAYOUT PERIOD
Payout period = Depreciable fixed investment / ((profit)+(depreciation))
= 20258.74 / (4214.826 + 425.779)
= 4.365 years
PROCESS SAFETY
In recent years there has been an increased emphasis on process safety as aresult of number of serious accidents. This is due in part to the worldwide attention to
issues in the chemical industry brought on by several dramatic accidents involving gas
releases, major explosions and several environmental
Accidents: Public awareness of these and other accidents has provided a driving
force for industry to improve its safety record. Local and national governments are
taking a hard look at safety in the industry as a whole and the chemical industry in
particular. There has been an increasing amount of government regulations.
For many reasons, the public often associates chemical industry with
environmental and safety problems. It is vital for the future of the chemical industry
that process safety has a higher priority in the design and operation of chemical process
facilities.
Industrial accidents
An accident has been defined as an unplanned or unexpected event, whichcauses or is likely to cause an injury.
An accident occurs as a result of unsafe action or exposure to an unsafe
environment.
-
8/13/2019 B.tech Project.cpd2014
72/85
xxv
Unsafe actions or unsafe mechanical or physical conditions exist only because
of faults of a particular person.
Faults of persons are inherited from the environment and reasons for the faultsare:
Improper attitude Lack of knowledge or skill Physical unsuitability Improper mechanical or physical environment
Accident prevention
From the foregoing, it will be seen that the occurrence of an injury is the
culmination of a series of events circumstances that invariably occur in a fused and
logical order.
Knowledge of the factors in the accident sequence guides and assists in
selecting the point of attack in prevention work. It permits simplification without
sacrifice of effectiveness. The most important point is that unsafe condition or actions
are the immediate cause of accidents. The supervisions and management can control
the action of employed persons and so prevent unsafe acts and also guard or remove
unsafe conditions, even though previous events or circumstances in the sequence are
unfavorable.
The four factors that converge to cause accidents are:
Personal factor Hazard factor Unsafe factor Proximate casual factor
The solution under the four factors would also lead to the steps. These are
planning and organizing to
-
8/13/2019 B.tech Project.cpd2014
73/85
xxvi
1. Prevent unsafe mechanical or physical conditions.2. Prevent unsafe action being committed.
Unsafe condition examples:
Operating without securing, warning etc. Operating or working at unsafe speed. Making safety devices inoperative. Using unsafe equipment. Unsafe loading, placing, mixing etc. Taking unsafe position or posture. Working on moving or dangerous equipment. Unsafe mechanical and physical conditions. Inadequately guarded. Unguarded. Defective condition ( rough, delayed etc ). Unsafe design or construction. Hazardous arrangement or process. Inadequate or improperly distributed ventilation. Unsafe dress or apparel. Unsafe method, process, planning etc.
The most important means of accident prevention are:
Engineering revision. Instruction. Persuasion. Personal adjustment. Discipline.
-
8/13/2019 B.tech Project.cpd2014
74/85
xxvii
Industrial ventilation and lighting
The main functions of ventilation in an industry are:
To prevent harmful concentration of aerosols. To maintain reasonable condition of comfort for operators at
workplace.
It maintains the body heat balance and to provide reasonableconditions of comfort.
Ventilation should aim at
Keeping the air temperature of the workroom low enough to enablebody heat to be dissipated by convection
Preventing excessive humidity so as to assist body heat loss byevaporation.
regulating the rate of air movement so that loss of body heat byconvection is facilitated.
The amount of ventilation generally depends on the following factors:
Size and type of room or building and its usage. Duration and type of occupants and their activities. heat gains from sun , hot manufacturing. Temperature conditions. The operators of the ventilating system.
Types of ventilation
1. Natural ventilation2. Mechanical ventilation
-
8/13/2019 B.tech Project.cpd2014
75/85
xxviii
Natural ventilation
Forces, which operate to induce natural ventilation in building, arc due to :
Pressure exerted by outside wind. The temperature differences of the air within and withoutthe building.
Mechanical ventilation
It is brought out by their one or both of the following two methods:
Ventilation through windows or other openings owing to thesuction created by the exhaust of air.
Positive ventilation by means of a fan or blower.
Personal protective devices
Protective devices are required by regulation; the employers are required to
provide it free of cost and also should be responsible to ensure its usage maintenance
and renewal. Once it is decided to use personal protective devices, we must select the
proper type of devices. Make sure that the employees use and maintain these correctly.
For selection of device, two criteria should be used:
1. The degree of protection.
2. The ease with which it may be used.
Protective devices are divided into two groups:
1. Respiratory devices
2. Non-respiratory devices
-
8/13/2019 B.tech Project.cpd2014
76/85
xxix
Safety appliances
Helmets
Every employee inside the factory should always wear the safety helmet to
avoid head injuries. No worker will be allowed to enter any plant without a helmet.
Safety goggles
The goggles must be worn while entering the process areas. Special geoggles
must be worn for gas and grinding operations.
-
8/13/2019 B.tech Project.cpd2014
77/85
xxx
Safety shoes
All the employees working inside a factory should wear safety shoes and
gumboots should be used while handling acids and alkalis.
Hand gloves
While operating any valve or equipment and also while executing any
maintenance work including electrical maintenance work, the employees should wear
appropriate type of safety gloves.
Dust mask
While working in a dusty atmosphere, the employees must wear dust masks to
prevent dust and fumes entering the sensitive respiratory organs, which can cause a lot
of irritation and in the long run painful and incurable diseases.
Plastic aprons
This along with the hood gives protection to the operation and maintenance
staff while handling dangerous acids and other hazardous chemicals particularly whenthere is possible leakage.
In spite of safety appliances, the companys medical center is equipped to meet
any emergency and any employee coming in contact with acids or any hazardous
chemicals must be treated at the medical center immediately.
Health and Safety Factors
The mononitrochlorobenzenes are toxic substances which may be absorbed
through the skin and lungs giving rise to methemoglobin. their toxicity is about the
same as or greater than that of nitrobenzene. The para isomer is less toxic than the
ortho isomer, and the maximum allowable concentration that has been adopted for p-
nitrochlorobenzene is 1mg/m3(0.1ppm). The mononitrochlorobenzenes are moderate
fire hazards when exposed to heat or flame.
-
8/13/2019 B.tech Project.cpd2014
78/85
xxxi
LIMITATIONS
This compound is a derivative of nitrobenzene and information regarding the
various processes available for the manufacture of p-nitrochlorobenzene was not
available.
Thus, the short comings and advantages of this process of manufacture of p-
nitrochlorobenzene has not been discussed.
CONCLUSION
Para nitro chlorobenzene is an important compound used in theprocess of manufacture of intermediate for azo and sulphur dyes and also
industrial chemicals.
This project has dealt with material balance and energy balancerequired for production of para nitro chlorobenzene.
Also, the design aspects, process instrumentation, project feasibilityand health and safety factors have been discussed.
APPENDIX -1
AICHE-
DIPPR
American Instiute of Chemical Engineers-Design Institute for Physical
Property Data
ASME Americal Society of Mechanical Engineers
BLEVE Boiling Liquid Expanding Vapor Explosion
CCPS Center for Chemical Process Safety
CONSEQ Consequence Analysis Computer Software (Technica, Inc.)
CPI Chemical Process Industry
FMEA Failure Modes and Effects Analysis
FN Frequency Number
FTA Fault Tree Analysis
HAZOP Hazard and operability
OSHA Organization Safety and Heath administration
PERD Process Equiment Reliability Data
-
8/13/2019 B.tech Project.cpd2014
79/85
xxxii
PHA Preliminary Hazard Analysis
P&ID Piping and Instrumention Diagram
ROD Average Rate of Death
ROF Average Rate of FailureSYREL Systems Relibility Service Data Base
TCPA Toxic Catastrophe prevention Act
THERP Technique of Human Error Rate prediction
TNT Trinitrotoluene
TLV Threshold Limit Values
TNO Netherlands Organization for Applied Scientific Reserarch
TXDS Toxicity Dispersion
UCL Upper confidece LimitUFL Upper FlammableLimt
UVCE Union Nations Industrial Development Organization
VSP Vent Sizing Package
appendix 2Glossary
Aerosol fraction : The fraction of liquid phase which, when flashed to the
atmosphere, remains suspended asan aerosol.
Atmospheric dispersion : the low momentum mixing of a gas or vapor with air
the mixing is the result of turbulent energy exchange, which is a function of wind
(mechanical eddy formation ) and atmospherc