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    CHEMICAL PROCESS QUANTITATIVE RISK ANALYSIS

    AND

    MANUFACTURE OF PARA NITRO CHLOROBENZENE

    A PROJECT REPORT

    Submitted by

    MOHD. IBRAZ HUSSSAIN (41502203009)RATNA RAMANI (41502203013)S.SRILAKSHMI (41502203016)

    In partial fulfillment for the award of the degree

    of

    BACHELOR OF TECHNOLOGY

    In

    CHEMICAL ENGINEERING

    S.R.M. ENGINEERING COLLEGE,KATTANKULATHUR-603 203, KANCHEEPURAM DISTRICT

    ANNA UNIVERSITY: CHENNAI-600 025

    MAY 2006

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    ANNA UNIVERSITY: CHENNAI 600 025

    BONAFIDE CERTIFICATE

    Certified that this project report Part A "CHEMICAL PROCESS

    QUANTITATIVE RISK ANALYSIS" and report

    Part B- "MANUFACTURE OF PARA NITRO CHLOROBENZENE is the

    bonafide work of MOHD. IBRAZ HUSSAIN (41502203009), RATNA RAMANI

    (41502203013) and

    S. SRILAKSHMI (41502203016) who carried out the project work under our

    supervision.

    Dr.R.KARTHIKEYAN Dr.R.KARTHIKEYAN

    PROFESSOR SUPERVISOR

    HEAD OF THE DEPARTMENT HEAD OF THE DEPARTMENT

    CHEMICAL ENGINEERING CHEMICAL ENGINEERING

    S.R.M.Engineering college S.R.M.Engineering college

    Kattankulathur-603 203 Kattankulathur-603 203Kancheepuram District. Kancheepuram District.

    ACKNOWLEDGEMENT

    We take pleasure in expressing our heartfelt thanks to our Principal Prof. R.

    Venkataramani, B.E., M.Tech. F.I.E., and Director Dr. T.P.Ganesan,

    B.E.,(Lhons).,M.Sc.,(Engg.), for constantly looking into our needs and upgrading the

    support system provided to students.

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    We also take this opportunity to thank our HOD

    Prof. Dr. R Karthikeyan, B.E., Ph.D., who through his busy schedule always provided

    time to guide us and motivate us.

    Also, we would like to thank our faculty members who gave us valuable and

    timely inputs which helped us to bring this project to a successful completion.

    ABSTRACT

    Para nitro chlorobenzene is an important compound in chemical industry with

    respect to dyeing and production industry especially.

    A conservative approach has been employed in the manufacture of Para nitro

    chlorobenzene, as the other methods of production available are employed only for

    laboratory purposes.

    This project deals with design aspects of equipments used, cost estimation and

    project feasibility.

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    TABLE OF CONTENTS

    CHAPTER TITLE PAGE NO

    ABSTRACT

    1 INTRODUCTION 11.1 UNDERSTANDING RISK 11.2 SELECTED DEFINITIONS FOR

    CPQRA 3

    2 RELEVANCE OF THE TECHNIQUE 10CASE STUDIES2.1 CASE STUDY OF A DISTILLATION

    COLUMN 102.1.1 Identification, Enumeration and 13

    Selection of incidents2.2 INCIDENT CONSEQUENCE 18

    ESTIMATION2.2.1 Flash, Discharge and Dispersions 18

    Calculations2.2.2 Event Tress 232.2.3 Consequences of Incident 25

    Outcomes2.3 INCIDENT FREQUENCY 30

    ESTIMATION2.3.1 Frequencies of the Representative 30

    set of Incidents2.3.2 Probabilities of Incident outcomes 332.3.3 Preparation of incident outcome 34

    case frequencies2.4 RISK ESTIMATION 352.5 CONCLUSION 40

    3 REVIEW OF RELATED LITERATURE 413.1 TORAP 41

    3.1.1 The Accident Scenario general 41step

    3.1.2 Consequence Analysis 423.1.3 Checking for higher degree of 42

    accidents3.1.4 Characteristics of worst-accident 42

    ScenarioCONCLUSION 44

    APPENDIX 1 45APPENDIX 2 46

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    ABSTRACT

    Chemical Process Quantitative Risk Analysis is a relatively new methodology

    that is a valuable management tool in the overall safety performance of chemical

    process industry.

    CPQRA techniques provide advanced quantitative means to supplement hazard

    identification, risk assessment, control and management methods to identify potential

    for incidents and evaluate control strategies.

    TABLE OF CONTENTS

    CHAPTER TITLE PAGE NO

    ABSTRACT

    LIST OF SYMBOLS

    1 INTRODUCTION

    1.1 BRIEF INTRODUCTION 53

    2 PROCESS

    2.1 PROCESS DESCRIPTION 552.1.1 Equipment Description 57

    2.2 MATERIAL BALANCE 59

    2.3 ENERGY BALANCE 64

    2.4 DESIGN 67

    2.5 PROCESS CONTROL AND 71

    INSTRUMENTATION

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    2.6 PLANT LAYOUT 74

    2.7 COST ESTIMATION 79

    2.8 PROCESS SAFETY 87

    LIMITATIONS 96

    CONCLUSION 96

    LIST OF SYMBOLS

    Hreaction - Heat of reaction (kJ)

    Cp - Specific heat kJ

    kgoC

    T - Temperature difference

    - Latent heat of varporisation

    V - volume of the reactor (m3

    )

    VO - Volumetric flow rate of the reactor (m3/hr)

    - Vapor flow rate (kmol/hr)

    CHAPTER 1

    INTRODUCTION

    BRIEF INTRODUCTION

    Understanding Risk

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    Risk is a measure of potential for loss in terms of both likelihood(events/year) of the incident and the consequences (effects/year) of the

    incident. Risk in an industry may be due to natural hazards and

    infrastructure.

    Flixborough, Bhopal, Piper Alpha and other accidentsemphasized the need for risk analysis.

    The development of a quantitative estimate of risk based onengineering evaluation and mathematical techniques for

    combining estimates of incident likelihood and consequences.

    Chemical process quantitative risk analysis is a relatively newmethodology that is valuable as a management tool in the overall safety

    performance of the Chemical Process Industry (CPI).

    Chemical Process Quantitative Risk Analysis (CPQRA)techniques provide advanced quantitative means to supplement

    hazard identification, analysis, assessment, and control and management

    methods to identify the potential for accidents to occur and to evaluate

    control strategies.

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    A flow sheet is illustrated below to indicate the step-by- stepprocedure involved in CPQRA.

    Selected Definitions for CPQRA

    HazardA chemical or physical condition that has the potential for causing damage to

    people, property or the environment (e.g. a pressurized tank containing 500 tonsof ammonia)

    IncidentIncident can be defined as loss of containment of material orenergy(e.g. a

    leak of 10 lb/sec of ammonia from a connecting pipeline to the ammonia tank,producing a toxic vapor cloud).This is pertaining to Risk Studies.

    Event SequenceA specific unplanned sequence of events composed of initiating events

    and intermediate events that may lead to an incident.

    Initiating event

    The first event in an event sequence (e.g. stress corrosion resulting inleak/rupture of the connecting pipeline to the ammonia tank)

    Intermediate eventAn event that propagates or mitigates the initiating event during an event

    sequence (e.g.: improper operator action fails to stop the initial ammonia leak and

    causes propagation of the intermediate event to an incident, in this case theintermediate event could be a continuous release of Ammonia)

    Incident outcomeThe physical manifestation of the incident; for toxic materials, the incident

    outcome is a toxic release, while for flammable materials, the incident outcomecould be a BLEVE, flash fire, unconfined vapor cloud explosion, etc.

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    Incident outcome caseThe quantitative definition of a single result of an incident outcome through

    specification of sufficient parameters to allow distinction of this case from all othersfor the same incident outcomes (e.g. a concentration of 3333 ppm (v) of ammonia2000 ft downwind from a 10lb/sec ammonia leak is estimated assuming a 1.4 mph

    wind and stability Class D)

    ConsequenceA measure of the expected effects of an incident outcome case (e.g., an

    ammonia cloud from a 10lb/sec leak under stability Class D weather conditions,and a 1.4 mph wind traveling in a northerly direction will injure 50 people)

    Effect zoneFor an incident that produces an incident outcome of toxic release, the areaover which the airborne concentration equals or exceeds some level of concern.

    The area of the effect zone will be different for each incident outcome case[e.g.,given an IDLH for ammonia of 500 ppm (v) , an effect zone of 4.6 square milesis estimated for a 10 lb/sec ammonia leak].For a flammable vapor release, thearea over which a particular incident outcome case produces an effect based ona specified overpressure criterion (e.g., an effect zone from an unconfined

    vapor cloud explosion of 28,000 Kg of hexane assuming 1 % yield is 0.18 km2if an overpressure criterion of 3 psig is established).For a loss of containmentincident producing thermal radiation effects, the area over which a particularincident outcome case produces an effect based on a specified thermal damagecriterion[e.g., a circular effect zone surrounding a pool fire resulting from aflammable liquid spill, whose boundary is defined by the radial distance at

    which the radiative heat flux from the pool fire has decreased to 5 kW/m2(approximately 1600 Btu/hr-ft2]

    Likelihood

    Likelihood can be defined as a measure of the expected probability or

    frequency of occurrence of an event. This may be expressed as a frequency (e.g.,events/year), a probability of occurrence during some time interval, or a conditionalprobability (i.e., probability of occurrence given that a precursor event has

    occurred, e.g., the frequency of a stress corrosion hole in a pipeline of sizesufficient to cause a 10 lb/sec ammonia leak might be 1 x 10 -3 per year; theprobability that ammonia will be flowing in the pipeline over a period of 1 yearmight be estimated to be 0.1;and the conditional probability that the wind blows

    toward a populated area following the ammonia release might be 0.1)

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    It is necessary to pay attention to the scope of a CPQRA, in order to satisfypractical budgets and schedules. If the scope is not clearly defined in advance, there is apossibility for the workload to explode. The concept of a STUDY CUBE has beenintroduced as shown above to relate scope, workload and goals. The three axes of thecube represent risk estimation technique, complexity of analysis and number ofincidents selected for study. Each axis of the cube has been arbitrarily divided into threelevels of complexity. These results in a total of 27 different categories of CPQRA,depending on what combinations of complexity of treatment are selected for threefactors. Each cell in the cube represents a potential CPQRA characterization. Howeversome cells represent a combination of characteristics that are more likely to be useful inthe course of a project or in the analysis of an existing facility

    Risk estimation techniqueEach of the components of this axis corresponds to a study exit point .The

    complexity and level of effort necessary increase along the axis-from consequence

    through frequency to risk estimation.

    Complexity of StudyThis axis presents a complexity scale for CPQRAs .Position along the axis is

    derived from two factors

    The complexity of the models to be used in a studyThe number of incident outcome cases to be studied

    Number of incidentsThere are three groups of incidents used

    Bonding Group-this group contains a small number of incidents that arecatastrophic by nature

    Representative Set-it includes incidents from the either group of incidents.

    Expansive List- it contains incidents in all three classes selected throughthe incident enumeration technique

    The STUDY CUBE provides a conceptual framework for discussing factorsthat influence the depth of a CPQRA.

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    CHAPTER 2

    RELEVANCE OF THE TECHNIQUE

    CASE STUDIES

    2.1 CASE STUDY OF A DISTILLATION COLUMN

    Consider a C6 distillation column, which is used to separate hexane and heptanefrom a feed stream consisting of 58 %( by weight and 42% heptane. The overhead

    condenser, thermosyphon reboiler and accumulator are all included in this study. Thecolumn operating pressure is 4barg the temperature range is 130-160C from the top tothe bottom of the column respectively. The column bottoms and reboiler inventory is6000kg and there are about 10000kg of liquids on the trays. The condenser is assumedto have no liquid holdup and the accumulator drum inventory is 12000kg. The materialin the bottom of the column is approximately 90% heptane and 10% hexane and that atthe top is approximately 90% hexane and 10% heptane.

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    Table

    Physical properties Hexane Heptane

    Boiling point (oC) 69 99

    Molecular weight 86 100

    Upper flammable limit (vol%) 7.5 7.0

    Lower flammable limit (vol%) 1.2 1.0

    Heat of combustion (J/kg) 4.5x107 4.5x107

    Ratio of specific heats, 1.063 1.054

    Liquid density at boiling point (kg/m3) 615 614

    Heat of vaporization at boiling point (J/kg) 3.4x105 3.2x105

    Liquid heat capacity (J/kg/ok) 2.4x103 2.8x103

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    The plant layout and surroundings The wind rose

    The study objective is to estimate the risk to the residential community fromthe fractionation system from both individual and societal risk perspectives.

    In order to limit the number of calculations, only one average weathercondition is considered a wind speed of 1.5 m/s and F stability- representing a worstcase weather condition with a reasonable probability of occurrence. The wind roseused in this example, gives the probability of wind from each of eight directions.

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    2.1.1 Identification, Enumeration and Selection of incidents

    An initial list of incidents is listed to consider all possible breaks orruptures of items of equipment which would lead to a loss of

    containment

    The initial list is modified to produce a revised list which excludesproblems such as polymerization, corrosion, over pressurization pertaining

    to this distillation column.

    Each vessel may break or rupture in a number of ways. A pipebreak may be of any size from a pin hole to a full bore rupture and may

    be in any position between the pipe ends.

    The spectrum of incidents is reduced to a Representative Set ofIncidents. Possible pipe failures are represented by either full bore ruptures

    or holes of 20% of the pipe diameter.

    Flange leaks, pump seal leaks do not cause any long distance effectsbut may result in a pool fire. Diking around the column limits the pool size to

    10m2.

    Incident outcomes such as fire and explosions should beconsidered since the material is flammable.

    The final choice of incidents is modeled based on the following factors:

    the size of the release whether the release is instantaneous or continuous whether the release is liquid or vapor The revised list of incidents include: Complete Rupture Column Accumulator Reboiler Condenser

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    Liquid leaks(full bore rupture and hole equivalent to 20% ofdiameter)

    Column feed line Reboiler feed line Heptane pump(pump 2) suction line(including flanges and pump) Heptane pump(pump 2)discharge line(including flanges) Condenser discharge line Reflux pump (pump1)suction line (including flanges and pump) Reflux pump(pump1) discharge line (including flanges) Shell leak(of column, accumulator, reboiler or condenser) of holesize equivalent to 20% of pipe diameter only.

    Vapor leaks(full bore rupture and hole equivalent to 20% of diameter) Column overhead line Reboiler discharge line Shell leakage (of the column, accumulator, reboiler orcondenser) of hole size equivalent to 20% of pipe diameter only.

    Assumptions pertaining to Representative List of Incidents

    a. It is assumed that automatic isolation exists at the system boundaries suchthat no additional fuel other than that present in the system at the time of incident

    contributes to the release. Hence an instantaneous failure of one vessel will lead to

    the rapid release of the entire contents of all other connected vessels. It may be

    noted that there are no automatic isolation valves with in the system.

    b. It is assumed that all liquid lines have a diameter of 0.15m.Discharge ratefrom these lines is used to determine whether full bore rupture of these lines can be

    treated as an instantaneous or continuous release. Here releases close to the

    vessel are better approximated by the liquid discharge model as compared

    to two-phase discharge model. Discharge equation for continuous releases from

    the 0.15m diameter line is :

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    GL= Cd A !(2(p-pa) / ! + 2 g h )1/2

    GL= Liquid discharge rate (kg/s)

    Cd=discharge coefficient (0.61 for liquids)

    A = hole cross-sectional area ( for 0.15m diameter pipe)=0.0176m2

    !=liquid density (615 kg/m3)

    p=upstream pressure (5 bar=5*105N/m2)

    pa=down stream pressure(1 bar = 1*105N/m2)

    h=liquid head (assumed to be negligible)

    g= acceleration due to gravity (9.8 m/s)

    It has been calculated that discharge rate is 240 kg/s bysubstituting all the above values in equation.

    Flow rate can double if pipe breaks in such a way that flow isunimpeded from both ends.

    It is estimated that at the initial rate the entire contents of column,reboiler and accumulator would be emptied in 2 minutes. But due to

    pressure decrease in the system, it takes a larger time to empty the

    contents.

    It is considered reasonable to treat full bore ruptures of liquidlines in the same manner as a catastrophic failure of any vessel in the

    fractionating system.

    c. Vapor lines are 0.5m in diameter.A quick estimate of the discharge rate canbe used to establish whether the full bore rupture of these lines can be treated as

    an instantaneous or continuous release. It is determined whether flow is sonic in

    order to estimate the actual discharge rate from a catastrophic break in the gas

    piping.

    rcrit=(("+1)/2)("/("-1))

    Where

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    "= gas specific heat ratio(1.063 for hexane, 1,054 for heptane)

    rcrit=1.687 for hexane

    rcrit=1.682 for heptane

    Sincep=5*105N /m2 (absolute)

    pa=1*105N/m2(absolute)

    p/pa=5.0 > rcrit= 1.687

    Therefore, vapor discharge will be sonic. For sonic flow the discharge rate is

    given by

    Gv=CdA p #/ $o

    Where

    Gv= gas discharge rate for choked vapor flow (kg/s)

    Cd= discharge coefficient (assumed to be 1 for gases)

    A =hole cross-sectional area ( for 10% of 0.5m pipe,m2)

    p=absolute upstream pressure (N/m2)

    $o =sonic velocity of gas at T =(RT"/M)1/2

    #=flow factor = "(1/rcrit)("+1)/2")

    M= molecular weight (86 for hexane, 100 for heptane)R=gas constant (8310 joules/kg-mole/K)

    T=upstream temperature (403K for hexane, 433K for heptane)

    "=gas specific heat ratio (1.063 for hexane, 1.054 for heptane)

    rcrit=1.687 for hexane, 1.682 for heptane

    The vapor discharge rate is 303 kg/s for pure hexane and 320 kg/sfor pure heptane. Therefore, full bore ruptures of vapor lines are also

    treated the same as a catastrophic failure of any vessel in the fractionatingsystem.

    Representative List of Incidents:

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    a. a catastrophic failure of the column, reboiler, condenser, accumulator, orany full bore liquid or vapor line rupture

    b. a liquid release through a hole of diameter equal to 20%of a 0.15m diameterline

    c. a vapor release through a hole of diameter equal to 20% of a0.5m diameterline

    2.2 INCIDENT CONSEQUENCE ESTIMATION

    2.2.1 Flash,Discharge and Dispersions Calculations (Incidents A,B & C)

    Flash discharge and dispersion calculations are carried out for the Incidents A,B and C that are defined above.

    Incident A : A Catastrophic failure

    In the event of catastrophic failure of one of the vessels or full bore line

    rupture; it is assumed that the entire contents of the column, reboiler, condenser, and

    accumulator, are lost instantaneously. In the following calculation, the flash fraction is

    determined assuming the column reboiler and accumulator contains pure heptane and

    pure hexane, respectively, rather than mixtures.

    Fv=Cp((T-Tb)/Hfg)

    Where

    Fv= fraction of fluid flashed to vapor

    Cp= average liquid heat capacity (range T to Tb)(2400J/kg/K for hexane, 2800

    J/kg/K for heptane)

    T= operating temperature (130C for hexane, 99C for heptane)

    Tb=atmospheric boiling point (69C for hexane, 99C for heptane)

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    Hfg= latent heat of vaporization at Tb (3.4x105 J/kg for hexane, 3.2x105

    J/kg for Heptane)

    The calculated flash fractions are 0.43 for hexane and 0.51 for heptane.Therefore, both of these materials exhibit a flash fraction of roughly 0.5. It is

    reasonable to assume that all of the hexane and heptane released will release as gas and

    aerosol .It is further assumed that the aerosol droplets are small enough to remain

    suspended and evaporate instead of raining out onto the ground. DENSE CLOUD

    MODEL is used to calculate the dispersion of the instantaneous release of the

    mentioned gases. Since thermo physical properties of hexane and heptane are similar,

    the dispersion calculations are based on hexane that comprises approximately 2/3 of

    the inventory of the system. The release is supposed to consist only of gas and aerosoldroplets that eventually evaporate into cloud and hence an all gaseous release is chosen

    for dispersion analysis. The temperature used is 69C , which is the temperature to

    which hexane liquid will flash when released to the atmosphere. It is also necessary to

    estimate the initial dilution, which is the number of volumes of air containing one

    volume of gas in the cloud after expansion to atmospheric pressure and before heat

    transfer and dispersion processes begin. A dilution factor of ten is chosen. The initial

    cloud radius is set equal to height, which is the most common default for top-hat

    models.

    Incident B & C: Liquid and Vapour Release from Hole in Piping

    For liquid release, the flash fraction is same as that considered for incident A

    i.e. 0.43 for hexane and 0.51 for heptane. It is assumed that entire release is a gas and

    aerosol cloud, with no liquid rainout.

    The discharge rate for the liquid release (incident B) can be estimated usingequation and assuming a hole diameter of 0.03m.The resulting rate discharge rate is 9.6

    kg/s.

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    The discharge rate for gaseous release i.e. incident C can be estimated using

    equation assuming a hole diameter of 0.12m. The discharge rate is calculated as 12.6

    kg/s.

    Since both releases are gaseous and discharge is similar incidents B and C are

    combined and on average release rate of 11 kg/s is obtained. Top hat dense cloud

    model of WHAZAN is used to calculate dispersion. The flammability zone from

    continuous release will extend in residential area.

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    This is the output obtained in case of instantaneous heavy gas dispersion

    W H A Z A N***********

    HEAVY CLOUD DISPERSION MODEL****************************

    Copyright (C)DNV Technica Ltd.

    Date 28 Sep 1996 Time 02:53

    Instantaneous release of n-Hexane (Gaseous)

    Mass released : 28000. kgInitial flash : .000

    Temp. after release : 342.0 KMolecular weight : 86.17Boiling point : 344.6 KSpecified lower conc.: 10000.000 ppmInitial dilution : 10.0 TimesFraction liquid : .000Initial cloud temp. : 308.0 KInitial cloud conc. : 78912.050 ppmInitial density : 1.317 kg/cu mInitial radius : 32.1 mInitial volume : 104011. cu mInitial height : 32.1 mSurface roughness : .100

    Ambient temperature : 293.0 KRoughness length : .18 m

    Air density : 1.196 kg/cu mRelative humidity : 80. %

    Wind speed : 1.5 m/sMixing ratio : .012Pasquill category : F

    TIME DISTANCE CLOUD CLOUD C/L CLOUDDOWNWIND RADIUS HEIGHT CONC. TEMP.

    (s) (m) (m) (m) (ppm vol) (K)

    .0 .0 32.1 32.1 78912.050 308.03Forced convection from .0 m

    6.7 10.0 58.6 19.9 37354.630 300.7413.3 20.0 76.6 16.0 26933.910 298.1920.0 30.0 91.3 13.9 21768.740 297.0426.7 40.0 104.0 12.5 18586.480 296.3633.3 50.0 115.4 11.5 16387.550 295.91

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    40.0 60.0 125.8 10.7 14759.090 295.5846.7 70.0 135.4 10.1 13497.570 295.3353.3 80.0 144.4 9.6 12483.410 295.1360.0 90.0 152.9 9.2 11644.780 294.9766.7 100.0 161.0 8.8 10935.520 294.8373.3 110.0 168.7 8.5 10325.010 294.71

    10000.000 ppm vol concentration reached 289.4 m at time 77. s

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    This is the output obtained in case of continuous heavy gas dispersion

    W H A Z A N***********

    HEAVY CLOUD DISPERSION MODEL****************************

    Copyright (C)DNV Technica Ltd.

    Date 4 Oct 1996 Time 00:40

    Continuous release of n-Hexane (Gaseous)

    Rate of release : 11.00 kg/sInitial flash : .000Duration : 100.0 s

    Temp. after release : 342.0 KMolecular weight : 86.17Boiling point : 344.6 KSpecified lower conc.: 12000.000 ppmInitial dilution : 10.0 TimesFraction liquid : .000Initial cloud temp. : 308.0 KInitial cloud conc. : 78912.050 ppmInitial density : 1.317 kg/cu mInitial semi-width : 3.7 mCross sectional area : 27. sq mInitial height : 3.7 mSurface roughness : .100

    Ambient temperature : 293.0 KRoughness length : .18 m

    Air density : 1.196 kg/cu mRelative humidity : 80. %

    Wind speed : 1.5 m/sMixing ratio : .012Pasquill category : F

    TIME DISTANCE CLOUD CLOUD C/L CLOUDDOWNWIND RADIUS HEIGHT CONC. TEMP.

    (s) (m) (m) (m) (ppm vol) (K)

    .0 .0 3.7 3.7 78912.050 308.03Forced convection from .0 m

    6.7 10.0 12.4 2.3 36603.000 300.2313.3 20.0 18.8 2.0 28127.050 298.0220.0 30.0 24.3 1.8 23755.340 296.9326.7 40.0 29.3 1.7 20884.200 296.24

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    33.3 50.0 34.0 1.6 18778.020 295.7440.0 60.0 38.4 1.6 17110.050 295.3646.7 70.0 42.6 1.5 15732.440 295.0653.3 80.0 46.6 1.5 14556.420 294.8160.0 90.0 50.5 1.5 13527.630 294.6066.7 100.0 54.2 1.5 12611.990 294.42

    12000.000 ppm vol concentration reached 107.4 m at time 72. s

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    2.2.2 Event Trees

    A number of different outcomes are possible for incidents A, B, C depending

    on

    If and when ignition occurs Consequences of ignition Two events have been drawn below to illustrate the incidentoutcomes of these releases.

    Though ignition may occur at a number of positions depending onignition sources it.

    It is assumed that the immediate ignition will cause a BLEVE from an

    instantaneous release and a jet fire from a continuous release. If ignition is delayed until

    the cloud has developed, the consequences will be either a UVCE or a flash fire. From

    the event trees, the following incident outcomes are identified for the risk analysis:

    BLEVE due to immediate ignition of an instantaneous release UVCE due to delayed ignition of an instantaneous release Flash fire due to delayed ignition of an instantaneous release Jet fire from immediate ignition of a continuous release Flash fire due to delayed ignition of a continuous release

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    Event tree for incident A

    C o n t in u o u s

    R e l e a s e

    I m m e d i a t e I g n i t io n

    N o I m m e d ia t e I g n it io n

    D e la y e d I g n i t io n

    N o I g n it io n

    F l a s h F i r e

    J e t F i re

    T o x ic E f f e c t s

    N o C o n s e q u e n c e s

    Event tree for incident B and C

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    2.2.3 Consequences Of Incident Outcomes

    The consequences of incident outcomes are calculated in the following sections.

    The discrete zone approach is used to define flammable effects. It is assumed in thisapproach that within a zone people are assumed to be fatalities and outside the zonepeople are assumed to be non-fatalities. This method overestimates the proportion offatalities within the zone and underestimates them beyond it. The zones of fatal effectsfor various incident outcomes are calculated as follows:

    Incident Outcome No.1: BLEVE due to immediate ignition of anInstantaneous Release.

    Consider a BLEVE involving 28,000 kg of hexane (M), the followingparameters that is peak BLEVE diameter, BLEVE duration and center

    height of BLEVE are calculated from following equations as shown below

    Peak BLEVE diameter (Dmax) =6.48 x M 0.325= 181m BLEVE duration (tBLEVE) = 0.825 x M 0.26 = 12s Center height of BLEVE (HBLEVE) = 0.75 x Dmax= 136m

    For duration of 12s, the incident radiation required for fatality ofan average individual of an average individual is approximately 75kW/m2

    .This is derived from the figure that is for the 50% fatality line at 12s.

    The incident radiation from a BLEVE is given by equation

    QR = %E F21

    Where%= transmissivity

    F21= view factorE = surface emitted flux (kW/m2)

    The transmissivity is given by equation given below!= 2.02 (P wx)

    -0.09

    Where

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    Pw= water partial pressure at ambient conditions (N/m2)

    x = path length between flame surface and receiver (m)

    The path length x is calculated asx = ( H2BLEVE+ r

    2)1/2- 0.5 * Dmax= (1362+ r2)1/2 90.5

    Where r is the horizontal distance from the column to the receiver

    Assuming Pw = 2820 N/m2 , substituting in equation no.then the equation reduces to

    %= 0.99 ((1362+ r2)0.5 90.5) -0.09

    Consider the equation

    F21= D2/ 4r2

    Now, substitute D = Dmaxin the above equation and we getF21= 8190 r

    -2

    From an energy balance on the emitted energy we haveE = (Eradx M x He) / &x D

    2maxxt BLEVE

    Erad= 0.25 and heat of combustion for hexane is 4.5x 10+7J/kg. Therefore, E = 255 kW/ m2.This value may be

    entered into the expanded equation.

    QR= 0.99 ((1362+ r2)0.5- 90.5) -0.09x 8190 x r-2x 255

    For a radiation level QRof 75 kW/m2, this equation may be solved byiteration to give r = 135m.Therefore,the area of fatal effect is a circle of

    radius 135m, centered on column which would extend into the residential

    area.

    Incident Outcome No.2: UVCE due to delayed ignition of an Instantaneous

    Release.

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    This incident outcome involves 28,000 kg of hexane. The equivalentmass of TNT is given by the equation given below.

    Hence, the equivalent mass of TNT is 27,400 kg. The use of an empirical explosion yield of 0.1 should represent areasonable worst case result for an explosion incident outcome.

    An overpressure of 3 psi is used to calculate the extent of fataleffects.

    Hence the area of fatal effect for a UVCE of 28,000 kg of hexane isa circle of radius 239m, centered 85m downwind of the column, which

    would extend well into the residential area.

    Incident Outcome No.3: Flash fire due Delayed Ignition of an Instantaneous

    Release.

    For flash fires, an approximate estimate for the extent of fataleffect zone is the area over which the cloud is above the LFL.

    It is assumed that this area is not increased by cloud expansion duringburning.

    This is a circular zone of 148m radius centered 85m downwind.

    Incident Outcome No.4: Jet fire from immediate ignition of a Continuous

    Release.

    Rough calculations based on the method of Considine and Grint thatis very strictly applicable to LPG, yield an end hazard range of 50% lethality at

    31m for a 100-s exposure.

    This result suggests that there is no direct threat to the residentialarea and this incident outcome shall not be considered further.

    Incident Outcome No.5: Flash fire due to delayed ignition of a Continuous

    Release.

    This gives a pie shaped hazard zone 127m long downwind (71mdistance + 56m radius) with 48 of arc.

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    This incident can impact the residential area and has to beconsidered for further study.

    The net result of these consequence effect calculations is that fourof the five Incident Outcomes could impact the Residential Area.

    The next step in the calculation procedure is to determine Incidentand Incident Outcome Frequencies.

    2.3 INCIDENT FREQUENCY ESTIMATION2.3.1 Frequencies Of The Representative Set Of Incidents

    Data from the historical record have been used in order to estimatethe frequencies of the Representative Set of incidents.

    In this case the column, vessels, pipes and pumps are standard processequipment and historical failure rate data are available for such items.

    The basic failure rate data are listed in Table below. For each itemof equipment, the frequencies of a number of different sizes of failure are

    given. These are quoted per item year except for piping for which

    frequencies are given per meter year.

    Item Size of failure Failure Rate

    Piping

    Small '50mm diameter

    Full bore rupture 20% of pipe

    diameter rupture

    8.8 x 10-7(m yr-1)

    8.8 x 10-6(m yr-1)

    Medium > 50mm

    diameter

    '150mm diameter

    Full bore rupture 20% of pipe

    diameter rupture

    2.6 x 10-7(myr-1)

    5.3 x 10-6(myr-1)

    Large > 150mm

    diameter

    Full bore rupture 20% of pipe

    diameter rupture

    8.8 x 10-8(myr-1)

    2.6 x 10-6(myr-1)

    Fractionating system

    (excluding piping)

    Serious leakage Catastrophic

    failure

    1.0 x 10-5(yr-1)

    6.5 x 10-6(yr-1)

    Using Table, the numbers of vessels, pumps, and pipe lengthsincluded in the Representative Set of incidents, the frequencies are calculated

    as follows :-

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    Incident A: Instantaneous Release. This incident includes the following failures:

    Catastrophic rupture of any component in the fractionating system Catastrophic (full bore) rupture of any pipework There is approximately 25 m of 0.5-m-diameter piping and 55 m of0.15-m equivalent diameter piping included in this incident. Hence, the

    frequency is calculated as follows :

    Catastrophic rupture of 6.5 x 10-6 = 6.5 x 10-6yr-1fractionating system

    Full bore of55m of medium pipe 55 x 2.6 x 10

    -7

    = 1.4 x 10-5

    yr-1

    25m of large pipe 25 x 8.8 x 10-8= 2.2 x 10-6yr-1Total 2.3 x 10-5yr-1

    Incidents B and C : Continuous Release.

    This incident includes holes of 20% of the diameter for all pipingand serious leakage from vessels. There are approximately 25 m of large 0.5

    m diameter piping and 55 m of medium 0.15-m-diameter piping included

    in this incident. Hence, the frequency is calculated as follows:

    Leaks from55 m of medium pipe 55 x 5.3 x 10-6= 2.9 x 10-4

    25 m of large pipe 25 x 2.6 x 10-6= 6.5 x 10-5

    Serious leakage fromfractionating system 1.0 x 10-5 = 1.0 x 10-5yr-1

    Total 3.7 x 10-4yr-1

    2.3.2 PROBABILITIES OF INCIDENT OUTCOMES

    The Probabilities of each incident outcome is determined byassigning probabilities to all the branches of the event trees of figures.

    Some of the probabilities are direction dependent. (ie., the proportion of

    the residential area involved affects the probability of ignition).

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    For this case, two event trees have been developed for eachindent one that considers wind directions toward the residential area

    and one that considers all other directions. The results of this exercise are

    shown in figure 8.15 through 8.18. For this case study, the branch

    probabilities for these event trees have been derived using engineering

    judgement.

    In a real risk assessment better validated sources would be preferred.It is important that such assumptions are documented for later review and

    sensitivity analyst if warranted. A summary of the values selected and their

    justification is listed in tables given below Preparation of incident

    outcome case frequencies.

    2.3.3 Preparation of incident outcome case frequencies

    The prior analysis of a revised list of potential incidents (under thecategories of complete rupture, liquid leaks and vapor leaks) gives

    Representative Set of three potential incidents (Incidents A, B and C).

    It is assumed that with minimal loss in accuracy, those incidentscan be characterized as a single catastrophic incident (Incident A) and a single

    continuous release (Incidents B and C).

    The event tree analysis developed the instantaneous andcontinuous release incidents to four specific incident outcomes that

    can impact the residential area. These can be listed as:

    Incident Outcomenumber

    Incident outcome

    1 BLEVE due to immediate ignition of an instantaneousrelease

    2 UVCE due to delayed ignition of an instantaneous release

    3 Flash fire due to delayed ignition of an instantaneous release4 Flash fire due to delayed ignition of a continuous release

    The frequencies of incident outcome cases, which are dependent on winddirection, are calculated in table given below. In that table the headings are defined are

    Incident - The incident from the Representative Set chosen for theAnalysis.

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    Incident outcome - The incident outcomes related to a particularincident which were shown to have potential for public impact.

    Incident frequency The frequency of each incident in theRepresentative Set

    Incident outcome probability - The probability of an incident outcomebased on event tree analysis given that the probability of the incident is

    1.0

    2.4 RISK ESTIMATIONIndividual Risk

    The individual risk in the area around the column is estimated from the above

    incident outcome case frequencies and consequences effect zones (Chapter 4). The

    discrete consequence effect zones were estimated previously.

    Incident Outcome

    1. BLEVE a circle of radius 135 m centered on the column2. UVCE a circle of radius 239 m centered 85m from the column3. Flash fire (instantaneous) a circle of radius 148 m centered 85 m from the

    column4. Flash fire (continuous) a pie shaped section (48oangle) that extends a total of

    127 m from the column. The radius is 56m centered on a point 71 m from thecolumn.

    These four consequence effect zones have been superimposed over the plantlayout to scale in the east direction in Figure 8.19. From consequence considerationonly. The consequence effects, ranked in descending order, are UVCE, Flash fire(instantaneous). BLEVE, and Flash Fire (continuous).

    The four consequence effects described above can be divided into 3 commontypes :

    Circular shaped, centered on column (Incident Outcomes 1)Circular shaped centered 85 m from column (incident outcomes 2 and 3)Pie shaped, originating at column (incident outcome 5)

    Each of these must be treated slightly differently in calculating individual risk,but it is straightforward to extend this procedure to any effect zone shape and position.

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    Figures illustrate the general shape of the individual risk profile as a function of

    distance, for each of the four incident outcomes, along any wind direction (including

    the east direction that contains the residential area). The zero point in each of the

    figures is the location of the fractionating system.

    It is very important in the estimation of individual risk (and as will be shown

    later, in the estimation of societal risk) that overlapping incidents be properly

    considered. Thus, with the large UVCE consequence effect zone, consideration of only

    the W to E wind case would greatly underestimate the risk for those living to the east as

    UVCE incidentxs from all 8 directions contribute to the risk.

    The calculation of the individual risk at any point assumes that the

    contributions of all incident outcomes cases are additive. Therefore, the total individual

    risk at each point is equal to the sum of the individual risxks from all possible incident

    outcome cases.

    The individual risk in this study is not symmetrical around the column because

    of the directional probabilities of the wind and ignition. Ideally, an individual risk

    contour could be developed that includes points in each of the eight wind directions.

    However, in this study, the population is only situated east of the plant and an

    individual risk curve will be developed only for that easterly direction.

    Each of figures contains a set of distances for that incident outcome. Each

    distance listed on a particular figure represents a subset of incident outcome cases that

    reach that distance. However, other incident outcomes can also provide cases that

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    apply at the same distance. Therefore, for every distance listed in figure a calculation

    should be made that sums all of the total incident outcome cases that contribute at that

    distance.

    Table presents a summation of the individual risk for a distance of 0-63m in an

    easterly direction from the column. All incident outcome cases contribute in this

    calculation with the expection of Flash fire (continuous) wind directions N to S, NE to

    SW, E to W, SE to NW and S to N.

    Table has been developed to show the changes to total individual risk the result

    at each discrete distance. The permits development of the Total (ndividual Risk Curve

    in the East Direction.

    Some observations on the results are :

    1. The risk near the column has property been underestimated, sincesmall incidents that may contribute to the risk in this area have been excluded

    from the analysis (e.g jet fire hazards).

    2. The choice of only two places for ignition (immediate and delayeduntil the LFL concentration is reached) simplifies the real situation of

    ignition points at intermediate locations due to residential areas, fired

    process equipment, roads, etc. A different ignition distribution could be

    considered, but with increased calculational burden.

    3. The use of only one weather condition (F stability, 1.5 m/s windspeed) generally tends to overestimate risk at a given distance, because the

    longest dispersion distances are usually associated with F stability, low

    wind speed conditions.

    4. The risk from UVCE is probably overestimated because of the highexplosive yield chosen.

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    These assumptions have been chosen to provide a reasonable, but conservative,

    risk estimate using a minimum number of manual calculations. Where the resulting

    risk estimates indicate a potential problem, the analyst can decide whether some

    simplifying assumptions should be made more realistic, and the calculations repeated.

    However, each change in an assumption probably represents a significant increase in

    the number of incident outcome cases. An alternative approach is to use a computer

    tool that automates the calculation procedures, allowing analysis of a greater number of

    incident outcome cases.

    SOCIETAL RISK

    The first step in the estimation of societal risk is to calculate the number of

    fatalities for each incident outcome case. For this case study, consequence effect zones

    are discrete (within the zone there will be 100% fatalities) and an assumption is made

    that the residential area has a uniform population distribution. Therefore, the fraction

    of residential area covered by each incident outcome case will represent the fraction of

    200 fatalities which would result table summarizes these results.

    The data in Table represent the raw information from which the societal risk

    estimate may be developed. The data must be put into a cumulative frequency form in

    order to plot the F-N curve. This is accomplished by rearranging the incident outcome

    cases by descending number of fatalities and then calculating the frequency of having N

    or more fatalities. This procedure is presented in table.

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    The data in the first and last columns are plotted on logarithmic scales to

    produce the F-N curve shown in Figure. Adding more incident outcomes cases will

    produce a smoother curve because of the additional data points, but will not necessarily

    produce significant upward or downward bias.

    2.5 CONCLUSION

    The largest contribution to individual risk near to the column is from flash fires

    from pipe rupture equivalent to 20% of the pipe diameter. Remedial measures might

    include more frequent inspection or monitoring of wall thickness, if significant

    corrosion and/or erosion effects are anticipated.

    The largest contributor to the societal risk, not unexpectedly, is from

    instantaneous release of the contents and delayed ignition resulting in an unconfined

    vapor cloud explosion.

    The radius of the consequence zone is proportional to the 1/3 power of the

    quantity released. Therefore, only a very major reduction in quantity has a significant

    effect in reducing that radius. Nonetheless, additional remote isolation for the system

    could be considered. Vessel and piping integrity is the major concern. Additional

    ispection, perhaps utilizing different methods, could be considered.

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    Finally, because of the magnitude of the societal risk, additional study could

    consider other causes of vessel failure, such as overpressurization, that could lead to

    identical consequences. These studies, probably utilizing FTA, could indicate whether a

    threat of overpressurization is significantly higher than basic vessel failure and

    engineering or procedural controls could be implemented to reduce that risk.

    CHAPTER 3

    REVIEW OF RELATED LITERATURE

    3.1 TORAP

    TORAP(Tool for Rapid riskAssessment in Petroleum refinery) A new toolfor conducting assessments in petroleum refineries and petrochemical industries. Thispackage is used to identify steps to prevent / manage accidents

    TORAP involves the following main steps: The accident scenario general step Consequence Analysis Checking for higher degree of accidents Characterization of worst-accident scenario

    3.1.1 The accident scenario general step

    An accident scenario is basically a combination of different likely accidental

    events that may occur in an industry. Such scenarios are generated based on the

    properties of chemicals handled by the industry, physical conditions under which

    reactions occur or reactants / products stored, geometries and material strength of

    vessels and safety arrangement etc. External factors such as site characteristics &

    metrological conditions are also considered.This step would help in the development of

    more appropriate & effective strategies for crisis prevention & management.

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    3.1.2 Consequence Analysis

    This involves the assessment of likely consequences if an accident occurs. Theconsequences are quantified in terms of :Damage radii the radius of the area in which damage would readily occur.

    Damage to propertyToxic effects

    3.1.3 Checking for higher degree of accidents

    Higher degrees of accident like secondary and tertiary accidents are moreprobable in petroleum refineries and petrochemical industries.The TORAP packageestimates the damage potential of secondary accident (provided it is higher than theminimum value) and its likelihood of causing third degree accidents.

    3.1.4 Characteristics of worst-accident scenario

    This is the final step in TORAP algorithm. This step determines the worst-accident scenario based on the results of a consequences analysis. This step helps todevise strategies to avert a crisis or to minimize its adverse impact if the crisis does takeplace.

    AdvantagesCharacterization of accidents as primary, secondary, tertiary is possible

    FLOW CHART indicating the procedure of TORAP

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    CONCLUSION

    Chemical process quantitative risk analysis is an effective management tool forcarrying out safety analysis in process industries.

    In this study project a distillation column has been taken as the focus of interest

    and detailed report, concerning the RISK posed by it, the incident outcomes possible

    has been discussed.

    Also TORAP, i.e method for risk assessment in refineries had been disused.

    CHAPTER 1

    INTRODUCTION

    BRIEF INTRODUCTION

    1-Chloro -4- nitrobenzene is produced and used in chemical industryand is not known to occur naturally.

    It is used in the synthesis of industrial chemicals (e.g. para nitrophenol, para-nitro aniline, para-aminophenol, 4-nitroanisole, and

    para-anisidine), pesticides (e.g.parathion methyl parathion, ethyl

    parathion and nitrophen), the analgesic drugs phenacitin and

    acetaminophen, and the antimicrobial drug dapsone which is

    used to treat leprosy among other conditions.

    1 Chloro 4 nitrobenzene is also used in the synthesis of 4-nitrodiphenylamine-based antioxidants for rubber.

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    p-Nitrochlorobenzene is used as an intermediate for organic synthesis;p-nitrophenol, azo dyes and sulfate dyes, pharmaceuticals(such as

    phenacetin and acetaminophen) and pesticides (such as nitrofen,

    parathion) and rubber chemicals.

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    Physical and Chemical Properties

    1-Chloro-4-nitrobenzene is a crystalline yellow solid at room temperature with a

    sweet odor and is slightly soluble in water (243 mg/L at 20oC).

    Molecular Formula : C6H4ClNO2

    Molecular Weight : 157.56

    Chemical Class : nitroaromatic

    Melting point : 82.6oC

    Boiling point : 242oC

    Vapor Pressure : 0.15mm Hg (at 30oC)

    Synonyms

    Para-chloronitrobenzene, 4-chloro-1-nitrobenzene, 4-nitrochlorobenzene, para-

    nitrochlorobenzene, 1-nitro-4-chlorobenzene, 4-nitro-1-chlorobenzene.

    REVIEW OF LITERATURE

    Methods of preparing chlorontrobenzene include.

    1. diazotisation of nitroanilines of replacement by chlorine

    2. Reaction of phosphorous pentachloride with nitrophenols

    But all these methods are applicable to laboratories and not of commercial

    interest. Hence, manufacture of paranitrochlorobenzene from chlorination of

    nitrobenzene is used for commercial purpose.

    CHAPTER 2

    PROCESS

    2.1 PROCESS DESCRIPTION

    Chlorobenzene is the main raw material used in the manufacture ofpara nitro chlorobenzene.

    Cl

    No2

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    It is fed into a nitrator where chlorobenzene is nitrated usingnitrating acid. This acid is composed of 52.5 weight percent of H2SO4, 35.5

    weight percent of HNO3 and 12 weight percent of H2O.

    A slight excess of chlorobenzene usually is fed into the nitrator toensure that the nitric acid present is consumed to the maximum possible

    extent. The reaction mixture flows from the nitrator into a separator or a

    centrifuge where the organic phase is separated from the aqueous phase.

    This aqueous phase or spent acid is drawn from the bottom andconcentrated and recycled to the nitrator, where it is mixed with nitric acid

    and sulphuric acid immediately prior to being fed into the nitrator.

    Crude nitro chlorobenzene is obtained at this stage which is mainly amixture of isomers. Further, purification is needed to obtain para nitro

    chlorobenzene from the mixture of isomers which also contains small

    quantities of chlorobenzene and sulphuric acid.

    The crude nitro chlorobenzene flows through a couple of washer-separators where residual acid is removed by washing with dilute base

    followed by final washing with water.

    The product then is distilled to remove chlorobenzene from themixture of isomers. The bottom product which is a mixture of isomers

    contains about 34 weight percent ortho nitro chlorobenzene, 65 weight

    percent para nitro chlorobenzene and 1weight percent meta nitro

    chlorobenzene.

    The mixture is cooled to a temperature slightly above its freezingpoint and a large portion of para isomer slowly crystallizes and is

    separated from the mother liquor. Thus para nitro chlorobenzene is

    obtained in the form of crystals with very less impurities.

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    The reaction time takes about 10-30 minutes and theoretical yield isabout 96-99 %.

    2.1.1 Equipment Description

    NITRATOR

    The reaction vessels are acid resistant, glass-lined steel vesselsequipped with efficient agitators.

    Optimum mass transfer of reactants is maintained by vigorousagitation. The reactors contain internal cooling coil which control the

    temperature of the highly exothermic reaction.

    CRYSTALLISER

    The crystallizer used in this process is SWENSON- WALKERcrystallizer.

    It consists of a open trough with a semi- cylindrical bottom, a waterjacket welded to the outside of the trough and a slow speed long pitch,

    spiral agitator running at about 7 rpm and set as close to the bottom of the

    trough as possible.

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    Nitrator Acid

    separator

    Spent acid

    reconcentration

    Washtower(1)

    Washtower(2)

    Di

    c

    W aste water

    treatment

    Nitro c

    (I

    Salt + water

    Cr

    paranitro

    Fresh

    Sulphuric acid

    Nitrating

    Ac id

    Chlorobenzene

    Reaction mixture

    Crude

    Nitrochlorobenzene

    Dilute baseNaOH Water

    Spent

    Ac id

    FreshNitric acid

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    2.2 MATERIAL BALANCE

    NITRATOR

    BASIS: 1000 kg/hr of nitrating acid.

    The reaction given below takes place in the reactor.

    C6H5Cl + HNO3 )C6H4ClNO2+ H2O

    Composition of Nitrating Acid

    Components Weight(kg) Molecular

    weight(kg/kmole)

    No. of moles

    (in kmole)

    HNO3 355 63 5.635

    H2SO4 525 98 5.357

    H20 120 18 6.667

    Amount of chlorobenzene to be taken ( 20% excess) = 1.2 x 5.635

    =6.762 kmoles

    Products from Nitrator

    H2SO4 = 5.357 kmoles

    H2O = 6.667+(0.98 x 5.635) =12.98 kmoles

    C6H4ClNO2= 0.98 x 5.635 = 5.522 kmoles

    HNO3= 0.02 x 5.635 = 0.113 kmolesC6H5Cl = (0.02 x 5.635) + (0.2 x 5.635) =1.24 kmoles

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    ii

    WASHING

    Input to wash tower 1

    Crude Nitrochlorobenzene

    C6H4ClNO2 = 869.7 kg

    H2SO4= 26.25 kgH20 = 10.27 kg

    C6H5Cl = 139.5 kg

    Dilute base required to neutralize H2SO4completely

    2NaOH + H2SO4 " Na2SO4+ 2H20

    NaOH required = 2 x 0.2679 = 0.536 kmoles = 21.44 kg

    Total input = 1760.72kgTotal output = 1760.72kg

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    iii

    Input to wash tower 2

    C6H4ClNO2: 869.7 kg

    Na2SO4:38.042 kg

    H2O: 20.62 kg

    C6H5Cl: 139.5 kg

    Amount of water required to dissolve Na2SO4completely =96.48 kg

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    iv

    D = F ( x F x B ) / ( x D x B)

    Input to Distillation Column

    Feed contains: C6H5Cl = 139.5 kg

    C6H4ClNO2= 869.7 kg

    Total = 1009.2 kg

    In mass fraction:

    x F = 0.14 ; x D= 0.98 ; x B= 0.03

    D= 116.85kg B= 892.35kg

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    v

    Crystallizer

    Solubility of para C6H4ClNO2at 80oC is

    kg para C6H4ClNO20.085

    kg ortho C6H4ClNO2

    Feed Mother liquor =328.25kgorthoC6H4ClNO2 orthoC6H4ClNO2=302.65kg=302.95kg para C6H4ClNO2=25.6kgpara C6H4ClNO2=562.93kg para C6H4ClNO2

    crystals = 537.33kgTotal = 865.58kg Total = 865.58kg

    ENERGY BALANCE

    Crystallizer

    Total =1009.2kgTotal =1009.2kg

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    vi

    *Hreaction = +(mcp*T)products+*Ho

    reaction +(mcp*T)reactants

    +(mcp*T)products = (mcp*T) C6H4ClNO2 - +(mcp*T)H2SO4+

    (mcp*T)HNO3+(mcp*T)H2O+(mcp*T)C6H5Cl

    = [(869.7 x 1.589) + (52.5 x 2.425) +

    (7.12 x 2.941) + (219.4 x 4.186) +

    (139.5 x 1.2104)] x (70.25)

    = 1,69,347.5 KJ

    *Horeaction = *Hf-products- *Hf reactant

    *Hf product = [(-309.46 x 869.7) + (454.13 x 139.5)

    + (-8273.3 x 525) + (2747.47 x 7.12) +

    (-68.3174 x 219.4)]

    = 45,44,695.6 kJ

    *Hf reactants = (454.13 x 760.72) + (-8273.3 x 525)

    + (2747.47 x 355) + (-68.3174 x 120)

    = 30,30,862.9 kJ

    *Horeaction = -45,44,695.6 (-30,30,862.9)

    = -15,13,832.7 kJ

    +(mcp*T)reactants = (mcp*T)C6H5Cl+ (mcp*T)H2SO4 + (mcp*T)HNO3

    + (mcp*T)H2O

    = [(760.07 x 1.2104) + (525 x 2.425)

    + (355 x 2.941) + (120 x 4.186)] x (40-25)= 56104.13 kJ

    *Hreaction = 169347.5 -1513832.7-56104.13

    = - 1400589.3 kJ

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    Mass of cooling water required.

    Heat to be removed = 1400589.3 kJ

    (mcp*T)water = 1400589.3*T = 40

    m (4.186)(40) = 1400589.3

    m = 8364.7 kg.

    Distillation column

    Condenser Hot fluid: distillate

    Cold fluid: water

    Distillate = 116.85 kg. = 1.03 kmoles

    Latent heat of distillate = 36564.65 kJ/kmol = 322.44 kJ/kmol

    (m,)hot fluid = (mcp*T)cold fluid

    116.85 x 322.44 = m x 4.186 x 20

    mass of water required = 450 kg.

    Reboiler

    -,= ms,s

    - = V- F(1-q))

    q = 1

    -= v = D(R+1) = 1.03(5.75+1) = 6.953 kmoles

    -=6.953 kmoles = 788.5 Kg.

    ,avg.= 36885.88 kJ/kmol = 236.2 kJ/kg.

    -,= ms,

    788.5 x 236.2 = ms x2259.83

    mass of steam required = 82.42 kg.

    Crystallizer

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    Design summary:

    Diameter of reactor = 0.56m

    Length of reactor = 2.8 m

    Heat from the crystallizer:

    Q = Fcp*T + C,

    = (865.58 x 1.589 * (245-80)) + (537.33*234.3)= 352838.5 kJ

    cooling water requirement

    Q = (mcp*T)cooling water

    m = 352838.5/ 4.186 X (353-288)

    = 1296.7 kg.

    DESIGN

    REACTOR DESIGN

    Space time = %= 20 minutes

    %= V / VO

    VO = mo/!

    = (760.72/1128) + (1000/1447.33)= 1.365m3/hr

    V = 0.683 m3

    Assumption: L/D = 5

    (.D2 / 4)x L = O.683m3

    D = 0.56 m

    L = 2 .8 m

    DISTILLATION COLUMN

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    Design Summary:

    No of theoretical stages = 6

    Column diameter = 0.72m

    Column height = 5.85m

    x 0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1

    y 0 0.28 0.46 0.6 0.7 0.77 0.84 0.89 0.93 0.97 1

    Where y = $x /1+($-1 )xLet $= 3.5

    /= D(R+1)

    D = 1.03 kmoles/hr

    R = 5.75

    /= 6.953 kmoles/hr

    At the top

    No. of moles of vapour = 6.953 kmoles/hr

    Assuming ideal gas behaviour, VO= nRT / P = (6.953 x 0.082 x 405) /1

    = 230.91m3/hr

    Assumption: vapour velocity = 0.2 m/s

    Cross sectional area = 230.91/ (3600 x 0.2) = 0.321m2

    Column diameter = 0.64 m

    At the bottom

    No.of moles of vapour = 6.953 kmoles/hr

    Vapour flow rate = (6.953 x 0.082 x 518 )/1 = 295.33 kmoles/hr

    Cross sectional area = 0.41 m2

    Column diameter = 0.72m

    COLUMN HEIGHT

    Assumption: plate efficiency = 50%

    Plate spacing = 0.45m

    No.of actual plates = (7-1)/ 0.45 = 12

    Column height= ((12-1)+ 2) x 0.45 = 5.85 m

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    Design Summary:

    Area of the crystallizer =13.15m2

    No of the sections = 6

    CRYSTALLIZER DESIGN

    Surface area required

    Q =U A *Tlm

    Where U = 250 kJ/hr m2K

    *Tlm= (*T2 -*T1)/ln (*T2/*T1)= (165-65)/ln (165/65)

    = 107.34

    Area = 352838.35/(250 x 107.34)

    = 13.15m2

    Number of sections = total area / area of one section

    Maximum length of 1 section is 5ft = 1.524m.

    Assumption 1.5m2

    of cooling surface per m length of crystallizer is available.Area of one section =1.5 x 1.524 =2.286m2

    No of sections =13.15/2.286

    =5.8

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    PROCESS CONTROL AND INSTRUMENTATION

    The primary objectives of the designer when specifying instrumentation and

    control schemes are:

    1. Safe Plant Operation

    a.To keep the process variables within known safe operating limitsb.To detect dangerous situations as they develop and to

    provide alarms and automatic shut-down systems.

    c.To provide interlocks and alarms to prevent dangerousoperation procedures.

    2. Production rate

    To achieve the designed output.

    3. Product quality

    To maintain the product composition within specified quality standards.

    4. Cost

    To operate at the lowest production cost, commensurate with the other

    objectives.

    REACTOR CONTROL

    The schemes used for reactor control depend on the process and the type of

    reactor. If a reliable on-line analyzer is available, and the reactor dynamics are suitable,

    the product composition can be monitored continuously and the rector conditions and

    feed flows controlled automatically to maintain the desired product composition and

    yield. More often, the operator is the final link in the control loop, adjusting the

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    controller set points to maintain the product within specification, based on periodic

    laboratory analysis.

    Reactor temperature will normally be controlled by regulating the flow ofcooling medium. Pressure is usually held constant. Material balance control will be

    necessary to maintain the correct flow of reactants to the reactor and flow of products

    and unreacted, materials from the reactor.

    INSTRUMENTATION

    TEMPERATURE MEASUREMENT

    The temperature measuring element in a control system for jacketed tank is

    generally a thermocouple. The five most commonly used thermocouples are copper

    constantan, iron constantan, chromel alumel, platinum platinum 13% rhodium,

    platinum platinum 10% rhodium.

    LEVEL MESUREMENT

    The float- shaft type is employed either in open vessels. This method is suitable

    for a wide range of liquids and semi-liquids. Difficulties are sometimes encountered

    when the liquid deposits on the float and when the liquid level is foaming or turbulent.

    FLOW RATE MEASURING

    The industrial devices for flow rate estimation are common orifice meter,

    venturimeter, pilot tube and the Rota meter. The piping system must be made ofspecial corrosion resistant material when corrosive fluids are used.

    pH MEASUREMENT

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    In this process we use the digital pH meters, these pH meters can measure the

    pH of the solution accurately for two decimal places. These pH meters can be used

    over wide range temperatures. These pH meters dont require additional current for the

    working once they are dipped in the solution they measure the pH of the solution onthe display.

    PLANT LAYOUT

    Administrative

    Block

    Hospital

    Canteen

    P

    A

    RK

    I

    N

    G

    S

    E

    C

    UR

    I

    T

    Y

    check

    post

    Transformer

    Fire

    Station

    Training Academy

    Health Club

    Work shop

    Water

    Treatment

    Area

    Store

    House

    Quality Prod and control limit

    Lab and testing area

    Processing

    Area

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    PLANT LOCATION AND SITE LAYOUT

    The location of the plant can have a crucial effect on the profitability of a

    project, and the scope for the future expansion. There are many factors must beconsidered while selecting a suitable site. Some of the principal factors while selecting a

    suitable site. Some of the principal factors which must be considered for the selection

    of chemical process site are:

    1. Area of development favored by the government and the incentives, whichare available.

    2. The likelihood of finding suitable employees in the area and of wagesubsides.

    3. The peculiarities of climate.4. Sources of electricity gas and water.5. Area of atleast 100 acres of level ground on good boulder clay free from

    any danger of flooding.

    6. Not sensitive environmental area.7. Besides fresh water, adequate water must be available for cooling purposes.8. Readily linked railway system.9. Besides readily linked road system.10.Near a responsible population centre.11.Local community considerations.12.Environmental impact and effluent disposal.13.Political and strategic considerations.14.Climate.15.Expansion possibilities.

    SITE LAYOUT

    The process units and ancillary building should be laid out to give the most

    economical flow of materials and personal around site. Hazardous process must be

    located at a safe distance from other buildings.

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    Considerations must also be given to future expansion of the site. The ancillary

    buildings and services required on site, in addition to the main processing

    units(buildings),will include :

    1. Storages for raw material and products : Tank farms andWare house

    2. Maintenance workshops.3. Store for maintenance and operating supplies.4. Laboratories for process control.5. Fire stations and other emergency services.6. Utilities : steam boilers , compressed air , power generation ,

    Transformer station.7. Effluent disposal plant.8. Offices for general administration.9. Canteens and other amenity buildings, such as medical centers.10. Regulatory laws.11. Taxes.12. Car parks.

    RAW MATERIALS SOURCES

    Careful considerations should be given to the sources of raw materials to be

    used, method of delivery and storage facilities of raw materials.

    WASTE PRODUCT DISPOSAL

    Another aspect, which is gaining importance these days, is the environmental

    considerations. Careful attention should be given to the nature of products to be

    wasted, their quantity, available methods of disposal and the legislations governing the

    disposal.

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    Location can be an important factor for cost. If the bearing quality of the land

    is low, considerable amount may be spent in piling support for heavy equipments or

    multi-storied buildings. If the land is uneven and the site needs even level, the cost of

    leveling may be considerable. Sometimes advantage can be taken of uneven levels so asto use gravity as a means of transportation of materials.

    When planning the preliminary site layout, the process units will normally be

    sited first and arranged to give a smooth flow of materials through various processing

    steps, from raw material to final product storage. Process units are normally spaced at

    least 30 meters apart. Administration offices and laboratories, in which a relatively large

    number people will be working, should be located well away from potentially hazardous

    process control rooms. The siting of the main process units will determine the layout ofthe plant roads, pipes, alleys and drains. Access roads will also be constructed for

    operation and maintenance purpose. Utility building should be sited to give the most

    economical run of the processing units. The main storage areas should be placed

    between the loading and unloading facilities and the process units they serve. Storage

    tanks containing hazardous materials should be sited at least 70 meter from site

    boundary.

    PLANT LAYOUT

    The economic construction and efficient operation of a process unit will

    depend on how well the plant and equipment specified on the process flow sheet is laid

    out. The major principal factor that has to be considered while designing a plant layout

    is as follows:

    1. Economic considerations : Constructions and operating cost2. Damage to person and property an case of fire , explosion and3. toxic release4. The process requirements5. Convenience of maintenance.6. Safety7. Future expansion.

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    8. Modular constructions.

    It is also advisable to check up the insurance regulations from the view of

    getting the best coverage at minimum cost for plant building and inventory. Adjacent tofermentors a separate house can be provided for pumps, compressors, molasses

    weighing system etc.

    STORE AND WAREHOUSES

    The engineer must decide whether the warehouses must be at ground level or

    dock level.

    The latter facilitates loading trains and trucks, but costs 15-20% more than one

    placed on the ground. It is usually difficult to justify the added expenses of a dock-high

    warehouse.

    To size the amount of space needed, it must be determined how much is to be

    stored in what size containers. The container sizes that will be used are obtained from

    the scope. Liquids are generally stored in bulk containers. No more than a weeks

    supply of liquid stored in drums should be planned. Solids, on the other hand, arefrequently stored in smaller containers or in a pile on the ground.

    COST ESTIMATION

    ESTIMATION OF THE TOTAL CAPITAL INVESTMENT

    The total capital investment I involves the following:

    A. The fixed capital investment in the process area, IF.

    B. The capital investment in the auxiliary services, IA.C. The capital investment as working capital, IW.

    i.e., I = IF + IA + IW

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    A. FIXED CAPITAL INVESTMENT IN THE PROCESS AREA, IF.

    This is the investment in all processing equipment within the processing area.

    Fixed capital investment in the process area, IF = Direct plant cost + Indirect

    plant cost

    The approximate delivered cost of major equipments used in the proposed P-

    nitrochlorobenzene manufacturing plant are furnished below:

    S.No. Equipment Units Cost in

    lakhs/unit

    Cost in lakhs

    1 Crystallizer 1 350 350

    2 Reactor 1 250 250

    3 Condenser 1 308 308

    5 Distillation column 1 420 420

    6 Pump 4 0.5 2

    7 Storage tank sealed 2 100 200

    8 Miscellaneous 2600

    TOTAL 4130 lakhs

    Direct Cost Factor

    S.No Items Direct cost factor

    1 Delivered cost of major equipments 100

    2 Equipment installation 15

    3 Insulation 15

    4 Instrumentation 15

    5 Piping 75

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    6 Land & building 30

    7 Foundation 10

    8 Electrical 15

    9 Clean up 5

    Total direct cost factor 280

    Direct plant cost = (Delivered cost of major equipments)

    (Total direct factor) / 100

    Direct plant cost = (4130 x 280) / 100

    = 11564 lakhs

    Indirect Cost Factor

    S.No. Item Indirect cost factor

    1 Overhead contractor etc. 30

    2 Engineering fee 13

    3 Contingency 13

    Total indirect cost factor 56

    Indirect plant cost = (Direct plant cost)

    (Total indirect cost factor)/ 100

    = (115664 x 56) / 100

    = 6475.84 lakhs

    Fixed capital investment in the process area, IF = Direct plant cost + Indirect

    plant cost

    = 1156 + 6475.84

    = 18039.84 lakh

    B. THE CAPITAL INVESTMENT IN THE AUXILLARY SERVICES, IA.

    Such items as steam generators, fuel stations and fire protection facilities are

    commonly stationed outside the process area and serve the system under consideration.

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    S.No. Items Auxiliary services cost factor

    1 Auxiliary buildings 5

    2 Water supply 23 Electric Main Sub station 1.5

    4 Process waste system 1

    5 Raw material storage 1

    6 Fire protection system 0.7

    7 Roads 0.5

    8 Sanitary and waste disposal 0.2

    9 Communication 0.2

    10 Yard and fence lighting 0.2

    Total 12.3Capital investment in the auxillary services = (Fixed capital investment in the

    process area) (Auxiliary services cost factor) / 100

    = (18039.84 x 12.3) / 100

    = 2218.9 lakhs

    Installed cost = Fixed capital investment in the process area + Capital

    investment in the auxiliary services

    = 18039.84 + 2218.9

    = 20258.74 lakhs

    C. THE CAPITAL INVESTMENT AS WORKING CAPITAL, IW.

    This is the capital invested in the form of cash to meet day-to-day operational

    expenses, inventories of raw materials and products. The working capital may be

    assumed as 15% of the total capital investment made in the plant (I).

    Capital investment as working capital, IW

    = ((18039.84 + 2218.9) x 15) / 85

    = (20258.74 x 15) / 85

    = 3575.071 lakhs

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    Total capital investment, I = IF+ IA+ IW

    = 18039.84 + 2218.9+ 3575.07

    = 23833.81 lakhs

    ESTIMATION OF MANUFACTURING COST

    The manufacturing cost may be divided into three items, as follows:

    A. Cost Proportional to total investment

    B. Cost proportional to production rate

    C. Cost proportional to labour requirement

    A. COST PROPORTIONAL TO TOTAL INVESTMENT

    This includes the factors, which are independent of production rate and

    proportional to the fixed investment such as

    - Maintenance-labour and material- Property taxes- Insurance- Safety expenses- Protection, security and first aid- General services, laboratory, roads, etc.- Administrative services

    For this purpose we shall charge 15% of the installed cost of the plant

    = (Installed cost x 15) / 100

    = (20258.74 x 15) / 100

    = 3038.811 lakhs

    B. COST PROPORTIONAL TO PRODUCTION RATE

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    The factors proportional to production rate are

    - Raw material costs- Utilities cost power, fuel, water. Steam, etc.- Maintenance cost- Chemical, warehouse, shipping expenses

    Assuming that the cost proportional to production rate is nearly 60% of total

    capital investment.

    Cost proportional to production rate

    = (Total capital investment x 60) / 100

    = (23833.81 x 0.6)

    = 14300.286 lakhs

    C. COST PROPORTIONAL TO LABOUR REQUIREMENT

    The cost proportional to labour requirement might amount to 10% of total

    manufacturing cost.

    Cost proportional to labour requirement

    = (3038.811 + 14300.286)(0.1) / (0.9)

    = 1926.566 lakhs

    Therefore, manufacturing cost

    = (3038.811 + 14300.286 + 1926.566)

    = 19265.657 lakhs

    SALES PRICE OF PRODUCT

    Market price of Paranitrochlorobenzene = Rs.18/kg

    Production rate =1.5x105TPA

    Total sales income = 18x1.5x105 x1000

    = 27000 lakhs

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    PROFITABILITY ANALYSIS

    A. DEPRECIATION

    According to sinking fund method:

    R = (V-VS) I / (1+ I)n

    R = Uniform annual payments made at the end of each year

    V = Installed cost of the plant

    VS = Salvage value of the plant after n years

    N = life period (assumed to be 15 years)I = Annual interest rate (taken as 15%)

    R = (20258.74 x 0.15) / (1+0.15)15-1

    = 425.779 lakhs

    B. GROSS PROFIT

    Gross profit = Total sales income - manufacturing cost

    = 27000 19265.657= 7734.343 lakhs

    C. NET PROFIT

    It is defined as the annual return on the investment made after deducting

    depreciation and taxes. Tax rate is assumed to be 40%.

    Net profit = Gross profit-Depreciation-(Gross profit*Tax rate)= 7734.434-425.779-7734.434*0.4)

    = 4214.8268 lakhs

    D. ANNUAL RATE OF RETURN

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    Rate of return = (100*Net profit/Installed cost)

    = (100*4214.8268) / 20258.74 = 20.8%

    E. PAYOUT PERIOD

    Payout period = Depreciable fixed investment / ((profit)+(depreciation))

    = 20258.74 / (4214.826 + 425.779)

    = 4.365 years

    PROCESS SAFETY

    In recent years there has been an increased emphasis on process safety as aresult of number of serious accidents. This is due in part to the worldwide attention to

    issues in the chemical industry brought on by several dramatic accidents involving gas

    releases, major explosions and several environmental

    Accidents: Public awareness of these and other accidents has provided a driving

    force for industry to improve its safety record. Local and national governments are

    taking a hard look at safety in the industry as a whole and the chemical industry in

    particular. There has been an increasing amount of government regulations.

    For many reasons, the public often associates chemical industry with

    environmental and safety problems. It is vital for the future of the chemical industry

    that process safety has a higher priority in the design and operation of chemical process

    facilities.

    Industrial accidents

    An accident has been defined as an unplanned or unexpected event, whichcauses or is likely to cause an injury.

    An accident occurs as a result of unsafe action or exposure to an unsafe

    environment.

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    Unsafe actions or unsafe mechanical or physical conditions exist only because

    of faults of a particular person.

    Faults of persons are inherited from the environment and reasons for the faultsare:

    Improper attitude Lack of knowledge or skill Physical unsuitability Improper mechanical or physical environment

    Accident prevention

    From the foregoing, it will be seen that the occurrence of an injury is the

    culmination of a series of events circumstances that invariably occur in a fused and

    logical order.

    Knowledge of the factors in the accident sequence guides and assists in

    selecting the point of attack in prevention work. It permits simplification without

    sacrifice of effectiveness. The most important point is that unsafe condition or actions

    are the immediate cause of accidents. The supervisions and management can control

    the action of employed persons and so prevent unsafe acts and also guard or remove

    unsafe conditions, even though previous events or circumstances in the sequence are

    unfavorable.

    The four factors that converge to cause accidents are:

    Personal factor Hazard factor Unsafe factor Proximate casual factor

    The solution under the four factors would also lead to the steps. These are

    planning and organizing to

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    1. Prevent unsafe mechanical or physical conditions.2. Prevent unsafe action being committed.

    Unsafe condition examples:

    Operating without securing, warning etc. Operating or working at unsafe speed. Making safety devices inoperative. Using unsafe equipment. Unsafe loading, placing, mixing etc. Taking unsafe position or posture. Working on moving or dangerous equipment. Unsafe mechanical and physical conditions. Inadequately guarded. Unguarded. Defective condition ( rough, delayed etc ). Unsafe design or construction. Hazardous arrangement or process. Inadequate or improperly distributed ventilation. Unsafe dress or apparel. Unsafe method, process, planning etc.

    The most important means of accident prevention are:

    Engineering revision. Instruction. Persuasion. Personal adjustment. Discipline.

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    Industrial ventilation and lighting

    The main functions of ventilation in an industry are:

    To prevent harmful concentration of aerosols. To maintain reasonable condition of comfort for operators at

    workplace.

    It maintains the body heat balance and to provide reasonableconditions of comfort.

    Ventilation should aim at

    Keeping the air temperature of the workroom low enough to enablebody heat to be dissipated by convection

    Preventing excessive humidity so as to assist body heat loss byevaporation.

    regulating the rate of air movement so that loss of body heat byconvection is facilitated.

    The amount of ventilation generally depends on the following factors:

    Size and type of room or building and its usage. Duration and type of occupants and their activities. heat gains from sun , hot manufacturing. Temperature conditions. The operators of the ventilating system.

    Types of ventilation

    1. Natural ventilation2. Mechanical ventilation

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    Natural ventilation

    Forces, which operate to induce natural ventilation in building, arc due to :

    Pressure exerted by outside wind. The temperature differences of the air within and withoutthe building.

    Mechanical ventilation

    It is brought out by their one or both of the following two methods:

    Ventilation through windows or other openings owing to thesuction created by the exhaust of air.

    Positive ventilation by means of a fan or blower.

    Personal protective devices

    Protective devices are required by regulation; the employers are required to

    provide it free of cost and also should be responsible to ensure its usage maintenance

    and renewal. Once it is decided to use personal protective devices, we must select the

    proper type of devices. Make sure that the employees use and maintain these correctly.

    For selection of device, two criteria should be used:

    1. The degree of protection.

    2. The ease with which it may be used.

    Protective devices are divided into two groups:

    1. Respiratory devices

    2. Non-respiratory devices

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    Safety appliances

    Helmets

    Every employee inside the factory should always wear the safety helmet to

    avoid head injuries. No worker will be allowed to enter any plant without a helmet.

    Safety goggles

    The goggles must be worn while entering the process areas. Special geoggles

    must be worn for gas and grinding operations.

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    Safety shoes

    All the employees working inside a factory should wear safety shoes and

    gumboots should be used while handling acids and alkalis.

    Hand gloves

    While operating any valve or equipment and also while executing any

    maintenance work including electrical maintenance work, the employees should wear

    appropriate type of safety gloves.

    Dust mask

    While working in a dusty atmosphere, the employees must wear dust masks to

    prevent dust and fumes entering the sensitive respiratory organs, which can cause a lot

    of irritation and in the long run painful and incurable diseases.

    Plastic aprons

    This along with the hood gives protection to the operation and maintenance

    staff while handling dangerous acids and other hazardous chemicals particularly whenthere is possible leakage.

    In spite of safety appliances, the companys medical center is equipped to meet

    any emergency and any employee coming in contact with acids or any hazardous

    chemicals must be treated at the medical center immediately.

    Health and Safety Factors

    The mononitrochlorobenzenes are toxic substances which may be absorbed

    through the skin and lungs giving rise to methemoglobin. their toxicity is about the

    same as or greater than that of nitrobenzene. The para isomer is less toxic than the

    ortho isomer, and the maximum allowable concentration that has been adopted for p-

    nitrochlorobenzene is 1mg/m3(0.1ppm). The mononitrochlorobenzenes are moderate

    fire hazards when exposed to heat or flame.

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    LIMITATIONS

    This compound is a derivative of nitrobenzene and information regarding the

    various processes available for the manufacture of p-nitrochlorobenzene was not

    available.

    Thus, the short comings and advantages of this process of manufacture of p-

    nitrochlorobenzene has not been discussed.

    CONCLUSION

    Para nitro chlorobenzene is an important compound used in theprocess of manufacture of intermediate for azo and sulphur dyes and also

    industrial chemicals.

    This project has dealt with material balance and energy balancerequired for production of para nitro chlorobenzene.

    Also, the design aspects, process instrumentation, project feasibilityand health and safety factors have been discussed.

    APPENDIX -1

    AICHE-

    DIPPR

    American Instiute of Chemical Engineers-Design Institute for Physical

    Property Data

    ASME Americal Society of Mechanical Engineers

    BLEVE Boiling Liquid Expanding Vapor Explosion

    CCPS Center for Chemical Process Safety

    CONSEQ Consequence Analysis Computer Software (Technica, Inc.)

    CPI Chemical Process Industry

    FMEA Failure Modes and Effects Analysis

    FN Frequency Number

    FTA Fault Tree Analysis

    HAZOP Hazard and operability

    OSHA Organization Safety and Heath administration

    PERD Process Equiment Reliability Data

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    PHA Preliminary Hazard Analysis

    P&ID Piping and Instrumention Diagram

    ROD Average Rate of Death

    ROF Average Rate of FailureSYREL Systems Relibility Service Data Base

    TCPA Toxic Catastrophe prevention Act

    THERP Technique of Human Error Rate prediction

    TNT Trinitrotoluene

    TLV Threshold Limit Values

    TNO Netherlands Organization for Applied Scientific Reserarch

    TXDS Toxicity Dispersion

    UCL Upper confidece LimitUFL Upper FlammableLimt

    UVCE Union Nations Industrial Development Organization

    VSP Vent Sizing Package

    appendix 2Glossary

    Aerosol fraction : The fraction of liquid phase which, when flashed to the

    atmosphere, remains suspended asan aerosol.

    Atmospheric dispersion : the low momentum mixing of a gas or vapor with air

    the mixing is the result of turbulent energy exchange, which is a function of wind

    (mechanical eddy formation ) and atmospherc