Bracket Design Competition

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    ME240 Bracket Design

    Eric Grossman

    Jim Lovsin

    Mike Worth

    Spring 2003, Northwestern University

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    Background

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    Setup and Rules To Note

    Adhesives allowed

    Bracket does not have to be 1

    piece

    Can touch ground until point D

    B doesnt have to be used.

    Allowed 30mm clearance

    instead of 20mm

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    Performance Index

    mc

    PI

    *

    =

    2

    1

    3

    Priority:

    1. Load

    2. Mass

    3. Cost

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    Material Selection

    1018 Steel, and 3 grades of Al.

    1018 steel is our choice.

    Considering cost and strength

    advantage. highest yield stress,

    (smaller deformation).

    Costs significantly less than allAl alloys.

    Only candidate that can be

    welded together (rivets or bolts

    arent as strong and heavier).

    Much heavier, but we can

    minimize mass in design, not

    material.

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    Design Directions

    Maximize moment of inertia in an easily manufacturableshape

    Use welding Get bracket as close to edge as possible

    No need for mount at B

    Start with thickest steel then shave weight

    Not welding all connections/interchangeability

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    Preliminary Designs

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    Jims Design

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    Jims FEM

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    Erics Design

    S-shape: bringcompression column asclose as possible toload (reduce moment)

    Square cross-section:

    high moment of inertia Reinforced joints

    Only mounted at A

    Simple 3-tube design

    Notch to preventslipping of appliedload

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    Erics FEM

    High deformation

    Hard to manufacture

    Needed tension component

    Finite Element Analysis:

    1. Stress concentrated near

    applied load.

    2. Large displacement of top

    beam.

    3. No buckling in column

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    Mikes Design

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    Mikes FEM

    Finite Element Analysis:

    1. Blah.

    2. Add your comments

    3. here

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    Iterations

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    Iteration 1

    1.5mm steel

    Duct tape and spotwelding

    Reinforced lip

    U beam cantilever

    600N failure ofcantilever

    Tensile and columnnot deformed

    Weight: ~250 g Load: 600N

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    It.1: Interchangeable beams

    Cantilevers to interchange, none tested.

    Alignment problems

    Edges not crisp, contributed to misalignment

    Thinner steel used,not likely tosupport load

    Shapes that didnt

    require weldingtried. Shear forces

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    Iteration 2

    Slightly taller 3 u shaped

    members not

    welded

    Forming square

    shape

    Much heavier

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    Iteration 2

    Finite Element Analysis:

    1. Deformation confined to cantilever but high displacement

    2. Little displacement of tensile member

    3. No buckling in column

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    Iteration 3

    T-beam shape (manuf.)

    Reinforcing top plate

    Column grips cantilever to top Tensile width decreased

    Filler added to make columnwide enough

    Corners cut to reduce massand add clearance

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    Iteration 3

    Finite Element Analysis:

    1. Deformation still concentrated at front of column

    2. Strange behavior in tensile member

    3. No buckling in column

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    Iteration 3

    Thinner steel incolumn

    Tensile weld

    narrow tensile

    Tensile andcolumn notdeformed

    Crease at column

    Weight: 240 g Load: 1780N

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    Final Design

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    Final Dimensions

    All dimensions in mm.

    Mounting (no B)

    A

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    FEM

    Finite Element Analysis:

    1. Strange tensile behavior not observed in testing

    2. Less displacement of cantilever tip

    3. No buckling in column

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    The Bracket

    Thin steel incolumn (1.5mm)

    Tensile weld

    Free column

    Change inphilosophy abouthow to proportionleaving distance to

    displace vs. tallercantilever Weight: 190g Load: 2000N

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    Clearance/Thickness Tradeoff

    Al 2024 and Al 7075

    0

    10000

    20000

    30000

    40000

    50000

    60000

    70000

    80000

    90000

    0 0.05 0.1 0.15 0.2 0.25 0.3

    Strain (in/in)

    Stress

    (psi)

    AL 2024

    AL 7075

    .1% offset

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    Conclusions

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    Performance Index

    Reduce weight in cantilever holes T-beam

    Use thinner column

    In the problem statement, the performance index is given as I = P / (c*m).

    Our final bracket yields an index of:

    I = (2000 N) / (($0.195/kg)*(.19 kg)) = 54.0 kN/$

    Future Improvements

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    Thank youQuestions