Bellringer. Chapter 6: Section 2 Slope-Intercept Form.

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Bellringer

Transcript of Bellringer. Chapter 6: Section 2 Slope-Intercept Form.

Page 1: Bellringer. Chapter 6: Section 2 Slope-Intercept Form.

Bellringer

Page 2: Bellringer. Chapter 6: Section 2 Slope-Intercept Form.

Chapter 6: Section 2

Slope-Intercept Form

Page 3: Bellringer. Chapter 6: Section 2 Slope-Intercept Form.

Linear Equation

Any equation whose graph is a line– Since a function rule can form a line, a function

can be linear– f(x) = 2x + 5

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Y-Intercept

Represented by the variable b The y-coordinate of the point where the line

crosses the y-axis Graph y = 2x + 5 to see where is crosses the y-

axis. What is its slope?

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Slope-Intercept Form

y = mx + b m = slope b = y-intercept

Page 6: Bellringer. Chapter 6: Section 2 Slope-Intercept Form.

Find the slope and y-intercept

1. y = 3x – 5

2. y = x + 1

3. y = (2/3)x – 3

4. y = -2x

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Write an equation of the line from the given slope and y-intercept.

1. m = 2/9 b = 3

2. m = 0 b = 1

3. m = -1/4 b = -2

4. m = 3 b = 0

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Write the slope-intercept form from the graph of the equation

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Use the slope and the y-intercept to graph the equation

1. y = ½ x +4

2. y = 2x +5

3. y = -3/2 x

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Assignment

Page 294– Numbers 3-39 multiples of 3– Number 40