Bekah Sean Griffen Kohta 5 th period 60 Degrease Bekah Tan x= Opposite/adjacent Tan 60= x feet / 14...
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Transcript of Bekah Sean Griffen Kohta 5 th period 60 Degrease Bekah Tan x= Opposite/adjacent Tan 60= x feet / 14...
How Tall Is IT? BekahSean
Griffen Kohta
5th period
60 DegreaseBekah Tan x=
Opposite/adjacent
Tan 60= x feet / 14 feet14(tan 60)= X24.249 feet+ 14 feet5.125 feet+ 24.249 feet =
29.374 feet
Long leg= square root of 3 x short leg
X = square root of 3 x 14 feet
X= 14 x square root of 3/ 3
X= 24.25 feet60 degrees
14 feet 5 feet
45 Degrees Kohta 60 inches (eye height) 28 feet base
Tan x = opposite adjacentTan (45)= x feet 28 feet28 (tan 45)= x
28 feet = x28 feet + 60 inches
28 feet + 5 feet = 33 feet
45-45-90
Side=Side
28=28
Side+Height=Pole Height
28+5=33feet
5 Feet
28 feet
30 Degrees Sean
Tan x = opposite / adjacent
Tan30 = x / 38ft
38(Tan30) = x
X ≈21.94 + 5.75
X≈27.69 ft
38 ft5.75
Long leg =√3 ×short leg
38 = √3 × s. leg
s. Leg = 38√3 / 3
s. Leg ≈ 21.94 + 5.75
X ≈ 27.69 ft.
30 degrees
X
24 Degrees Griffin
24 Degrees
67 Feet
5.75 Feet
Tan x ≈ opposite Adjacent
Tan (24) ≈ X Feet 67 Feet
67 [Tan (24)] ≈ X Feet
X ≈ 29.83 Feet
29.83 Feet + 5.75 Feet ≈ 35.58 Feet
So………What Did We Learn Again?We noted that as the measure of the angle increased, the
closer we got to the object. This made the angle sharper, and obviously decreased the distance from us to the light pole.
The height of the light pole stayed the same We also noted that our light pole was crooked, so the
measurements were most likely inaccurate. Also, one can not get an accurate measurement by simply taking steps.