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I will attempt to describe the process and logic behind completing the Week 3 / Week 4

Homework.

First, the question:

1. Your company has decided to add a new line of bikes. These will be beach cruisers. Youwill need to update /insert information the following tables:select * from Production.Product

select * from Production.ProductCategory

select * from Production.ProductSubcategory

select * from Production.ProductModel

The beach cruisers come in two sizes: 44 and 48 inch, and each size has three color choices (you

can decide on these colors).

Before I start with an insert I always try to build a query that shows the relationships between

the tables. It helps to know which columns are important.

SELECT*From Production.Product

innerjoin Production.ProductModel

on ProductModel.ProductModelID = Product.ProductModelID

innerjoin Production.ProductSubcategory

on ProductSubcategory.ProductSubcategoryID = Product.ProductSubcategoryID

innerjoin Production.ProductCategoryon ProductCategory.ProductCategoryID = ProductSubcategory.ProductCategoryID

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At this point, I like to see everything in Query Designer:

Although you dont have to with this exercise, it is a good idea to build inserts inwards toensure that the Primary Keys are populated before the Foreign Keys are created.

The ProductCategory is already available, so there is nothing to insert in

Production.ProductCategory (but I make a note of the ProductCategoryID:

The two ProductModels need to be created in Production.ProductModel. Because the

ProductModelID is a PK, with an IDENTITY constraint, I dont have to worry about creating a

ProductModelID number. Two of the columns allow nulls and two have default constraints

which makes populating the table easy:

INSERTINTO Production.ProductModel(Name, CatalogDescription, Instructions)

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VALUES ('Beach Cruiser 44',NULL,NULL);

INSERTINTO Production.ProductModel(Name, CatalogDescription, Instructions)VALUES ('Beach Cruiser 48',NULL,NULL);

Which produces the following:

Next I have to populate the ProductSubCategory table with a new value. This is an IDENTITY as

well, so all I have to describe is the ProductCategoryID to use as a Foreign Key, and the Name:

SELECT*FROM Production.ProductSubcategory;INSERTINTO Production.ProductSubcategory

(ProductCategoryID, Name)

VALUES ('1','Beach Cruisers')

The result shows the inserted line:

I now have all of the necessary values to populate the Product Table. To summarize:

ProductSubcategoryID = 38

ProductModelID = 129, 130

These values have to be part of the INSERT, or otherwise the joins will not work after the insert.

It is important to note the nonclemature of fields like MakeFlag to retain consistency.

INSERT INTO Production.Product (

Name

,ProductNumber

,MakeFlag

,FinishedGoodsFlag

,Color

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,SafetyStockLevel

,ReorderPoint

,StandardCost

,ListPrice

,DaysToManufacture

,ProductSubcategoryID

,ProductModelID

,SellStartDate

,ModifiedDate

)

VALUES (

Beach Cruiser 440 Red, 44

, BC-R50R 44

, 1

, 1

, Red

, 100

, 75

, 486.71

, 782.99

, 4

, 38

, 129

, GETDATE()

, GETDATE()

)

The most important step then is to use my original query to see if the row I added created the

correct PK/FK values:

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SELECTProductID

, Product.Name, ProductModel.Name

, ProductCategory.Name, ProductNumber

, Color, Product.ProductSubcategoryID, ProductSubcategory.ProductSubcategoryID

, ProductSubCategory.ProductCategoryID, ProductCategory.ProductCategoryID, Product.ProductModelID, ProductModel.ProductModelID

From Production.Product

innerjoin Production.ProductModelon ProductModel.ProductModelID = Product.ProductModelID

innerjoin Production.ProductSubcategoryon ProductSubcategory.ProductSubcategoryID =

Product.ProductSubcategoryID

innerjoin Production.ProductCategoryon ProductCategory.ProductCategoryID =

ProductSubcategory.ProductCategoryID

where Product.ProductID >'1000'

I then check the results to ensure all of my joins produce the same results. This may seem like apointless step, but if you are creating joins with rowguids or complex ID fields it is a necessity.

ProductID 1005

Name Beach Cruiser 440 Red, 44

Name Beach Cruiser 44

Name Bikes

ProductNumber BC-R50R 44

Color Red

ProductSubcategoryID 38

ProductSubcategoryID 38

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ProductCategoryID 1

ProductCategoryID 1

ProductModelID 129

ProductModelID 129

Once this step is completed correctly, I can then modify the INSERT statement to insert the

other products.