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Transcript of BBaassiicc aanndd AApppplliieedd ... Data/Thermodynamics/Study/Chapter 10- Gas... · T-s diagram,...
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In This Chapter We Cover the Following Topics
Art. Content Page
10.1 The Stirling Cycle 3
10.2 The Ericsson Cycle 4
10.3 Air Standard Otto Cycle 5
10.4 Air Standard Diesel Cycle 8
10.5 Air Standard Dual Cycle 11
10.6 Comparison of the Otto, Diesel and Dual Cycles 13
10.7 The Lenoir Cycle 14
10.8 The Atkinson Cycle 15
10.9 Air Standard Brayton Cycle 16
References:
1. M. J. Moran and H. N. Shapiro, Fundamentals of Engineering Thermodynamics, 6e,
John Wiley & Sons, Inc., New York, 2008.
2. G. J. Van Wylen, R. E. Sonntag, C. Borgnakke, Fundamentals of Thermodynamics,
John Wiley & Sons, Inc., New York, 1994.
3. J. P. Holman, Thermodynamics, 4e, McGraw-Hill, New York, 1988.
4. F. W. Sears, G. L. Salinger, Thermodynamics, Kinetic theory, and Statistical
Thermodynamics, 3e, Narosa Publishing House, New Delhi, 1998.
5. Y. A. Cengel and M. A. Boles, Thermodynamics: An Engineering Approach, 2e,
McGraw-Hill, New York, 1994.
6. E. Rathakrishnan, Fundamentals of Engineering Thermodynamics, 2e, PHI Learning
Private Limited, New Delhi, 2008.
7. P. K. Nag, Basic and Applied Thermodynamics, 1e, McGraw-Hill, New Delhi, 2010.
8. V Ganesan, Gas Turbine, 2e, Tata McGraw-Hill, New Delhi, 2003.
9. V Ganesan, I. C. Engine, 2e, Tata McGraw-Hill, New Delhi, 2003.
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2 Chapter 10: Gas Power Cycles
10. Y. V. C. Rao, An Introduction to Thermodynamics, 1e, New Age International (P)
Limited, Publishers, New Delhi, 1998.
Please welcome for any correction or misprint in the entire manuscript and your
valuable suggestions kindly mail us [email protected].
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3 Basic and Applied Thermodynamics By Brij Bhooshan
The operating cycle of an internal combustion engine can be broken down into a
sequence of separate processes viz., intake, compression, combustion, expansion and
exhaust. The internal combustion engine does not operate on a thermodynamic cycle as
it involves an open system i.e., the working fluid enters the system at one set of
conditions and leaves at another. However, it is often possible to analyze the open cycle
as though it were a closed one by imagining one or more processes that would bring the
working fluid at the exit conditions back to the condition of the starting point. The
accurate analysis of internal combustion engine processes is very complicated. In order
to understand them it is advantageous to analyze the performance of an idealized closed
cycle that closely approximates the real cycle. One such approach is the air-standard
cycle, which is based on the following assumptions:
(i) The working medium is assumed to be a perfect gas and follows the relation pV =
mRT or p = ρRT.
(ii) There is no change in the mass of the working medium.
(iii) All the processes that constitute the cycle are reversible.
(iv) Heat is assumed to be supplied from a constant high temperature source and not
from chemical reactions during the cycle.
(v) Some heat is assumed to be rejected to a constant low temperature sink during
the cycle.
(vi) It is assumed that there are no heat lasses from the system to the surroundings.
(vii) The working medium has constant specific heats throughout the cycle.
(viii) The physical constants viz., Cp, Cv, γ and M of working medium are the same as
those of air at standard atmospheric conditions.
Due to these assumptions, the analysis becomes over-simplified and the results do not
agree with those of the actual engine. Work output, peak pressure, peak temperature
and thermal efficiency based on air-standard cycles will be the maximum that can be
attained and will differ considerably from those of the actual engine. It is often used,
mainly because of the simplicity in getting approximate answers to the complicated
processes in internal combustion engines.
For the purpose of thermodynamic analysis of the internal combustion engines, the
following approximations are made:
a) The engine is assumed to operate on a closed cycle with a fixed mass of air which
does not undergo any chemical change.
b) The combustion process is replaced by an equivalent energy addition process from
an external source.
c) The exhaust process is replaced by an equivalent energy rejection process to
external surroundings by means of which the working fluid is restored to the
initial state.
d) The air is assumed to behave like an ideal gas with constant specific heat. These
cycles are usually referred to as air standard cycle.
10.1 THE STIRLING CYCLE
The Carnot cycle has a low mean effective pressure because of its very low work output.
Hence, one of the modified forms of the cycle to produce higher mean effective pressure
whilst theoretically achieving full Carnot cycle efficiency is the Stirling cycle. It consists
of two isothermal and two constant volume processes. The heat rejection and addition
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take place at constant temperature. The p-V and T-s diagrams for the Stirling cycle are
shown in Diagrams 10.1(a) and 10.1(b) respectively. It is clear from Diagram 10.1(b)
that the amount of heat addition and rejection during constant volume processes is
same.
Diagram 10.1 The Stirling Cycle
Heat transfer in process 1-2 is
Heat transfer in process 2-3 is
Heat transfer in process 3-4 is
Heat transfer in process 4-1 is
Now according to cycle Q2-3 = Q4-1.
Hence, the efficiency of the cycle is given as
10.2 THE ERICSSON CYCLE
The Ericsson cycle consists of two isothermal and two constant pressure processes. The
heat addition and rejection take place at constant pressure as well as isothermal
processes [Diagram 10.2]. Since the process 2-3 and 3-4 are parallel to each other on the
T-s diagram, the net effect is that the heat need be added only at constant temperature
T3 = T4 and rejected at the constant temperature T1 = T2.
The cycle is shown on p-V and T-s diagrams in Diagram 10.2(a) and 10.2(b) respectively.
The advantage of the Ericsson cycle over the Carnot and Stirling cycles is its smaller
pressure ratio for a given ratio of maximum to minimum specific volume with higher
mean effective pressure.
Diagram 10.2 The Ericsson Cycle
(a) P-V diagram (b) T-s diagram
2 1
4 3
3
T = C T = C
4
2
1
(a) p-V diagram (b) T-s diagram
4
1
2
3
Heat rejection to the sink
Heat added from/ heat added to the regenerator
Heat addition from the source
4 3
2 1
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For 1 kg of ideal gas
Heat transfer in process 1-2 is
Heat transfer in process 2-3 is
Heat transfer in process 3-4 is
Heat transfer in process 4-1 is
Hence, the efficiency of the cycle is given as
The Ericsson cycle does not find practical application in piston engines but is
approached by a gas turbine employing a large number of stages with heat exchangers,
insulators and reheaters.
10.3 AIR STANDARD OTTO CYCLE
The main drawback of the Carnot cycle is its impracticability due to high pressure and
high volume ratios employed with comparatively low mean effective pressure. Nikolaus
A. Otto. (1876) proposed a constant-volume heat addition cycle which forms the basis for
the working of today's spark-ignition engines. One very common type of internal
combustion engines is the Spark Ignition (S.I.) engine used in automobiles.
Diagram 10.3 Air Standard Otto Cycle
Diagrams 10.3(a), and (b) illustrate the working principles of an Otto cycle. The Otto
cycle consists of the following processes.
0-1: Constant pressure suction during which a mixture of fuel vapour and air is drawn
into the cylinder as the piston executes an outward stroke.
1-2: The mixture is compressed isentropically due to the inward motion of the piston.
Because of the isentropic compression, the temperature of the gas increases.
2-3: The hot fuel vapour-air mixture is ignited by means of an electric spark. Since the
combustion is instantaneous, there is not enough time for the piston o move
outward. This process is approximated as a constant volume energy addition
process.
(a) Otto Cycle (b) P-V diagram
Combustion product
Inlet valve
Exhaust valve
Spark
Fuel air mixture
0
2
3
4
1
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3-4: The hot combustion products undergo isentropic expansion and the piston executes
an outward motion.
4-1: The exhaust port opens and the combustion products are exhausted into the
atmosphere. The process is conveniently approximated as a constant-volume energy
rejection process.
1-0: The remaining combustion products are exhausted by an inward motion of the
piston at constant pressure.
Diagram 10.4 Air Standard Otto Cycle
Effectively there are four strokes in the cycle. These are suction, compression,
expression, and exhaust strokes, respectively. From the P-V diagram [Diagram 10.3] it
can be observed that the work done during the process 0-1 is exactly balanced by the
work done during 1-0. Hence for the purpose of thermodynamic analysis we need to
consider only the cycle 1-2-3-4, which is air-standard Otto Cycle [Diagram 10.4].
Suppose m be the fixed mass of air undergoing the cycle of operation as described above.
1-2: It is reversible adiabatic compression process. The air is compressed reversibly and
adiabatically from T1 to T2. In this process no heat addition or rejection by the air,
(–ve work, Wc).
2-3: Constant volume heating the air is now heated at constant volume from
temperature T2 to T3. Now heat absorb (+ve heat, Qg) is,
3-4: It is reversible adiabatically expansion process. The air is expended reversibly and
adiabatically from T3 to T4. In this process no heat addition or rejection by the air,
(+ve work, We).
4-1: It is constant volume cooling. The air is cooled at constant volume from temperature
T4 to T1. Heat rejection process (–ve heat, Qr).
Therefore, efficiency of the Otto cycle is
Now process 1-2 and 3-4 are isentropic processes for which T = Const.
Therefore,
where rk (=V1/V2) is the compression ratio.
(a) P-V diagram (b) T-s diagram
2
3
4
1
2
3
4
1
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and,
where re (=V3/V4) is the expansion ratio.
But, V1 = V4, and V2 = V3, then we have
So,
Now from equation (10.3), we get
Since rk > 1, the efficiency of the Otto cycle increases with increasing compression ratio.
However, in an actual engine, the compression ratio cannot be increased indefinitely
since higher compression ratios give higher values of T2 and this leads to spontaneous
and uncontrolled combustion of the gasoline-air mixture in the cylinder. Such a
condition is usually called knocking.
Diagram 10.5
Work Output
Performance of an engine is evaluated in terms of the efficiency (see Diagram 10.5).
However, sometime it is convenient to describe the performance in terms of mean
effective pressure, an imaginary pressure obtained by equating the cycle work to the
work evaluated by the following the relation
Now process 1-2 and 3-4 are isentropic processes for which p = Const.
Therefore,
where rp is the pressure ratio.
γ = 1.2
γ = 1.4
3 4 5 6 7 8 9 10
0.8
0.6 0.4
0.2
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Mean Effective Pressure
The mean effective pressure is defined as the net work divided by the displacement
volume.
That is
Now swept volume is
Thus, it can be seen that the work output is directly proportional to pressure ratio, rp.
The mean effective pressure which is an indication of the internal work output increases
with a pressure ratio at a fixed value of compression ratio and ratio of specific heats. For
an Otto cycle, an increase in the compression ratio leads to an increase in the mean
effective pressure as well as the thermal efficiency.
10.4 AIR STANDARD DIESEL CYCLE
The Diesel cycle was developed by Rudolf Diesel in Germany. In actual spark-ignition
engines, the upper limit of compression ratio is limited by the self-ignition temperature
of the fuel. This limitation on the compression ratio can be circumvented if air and fuel
are compressed separately and brought together at the time of combustion. In such an
arrangement fuel can be injected into the cylinder which contains compressed air at a
higher temperature than the self-ignition temperature of the fuel. Hence the fuel ignites
on its own accord and requires no special device like an ignition system in a spark-
ignition engine. Such engines work on heavy liquid fuels. These engines are called
compression-ignition engines and they work on a ideal cycle known as Diesel cycle. The
difference between Otto and Diesel cycles is in the process of heat addition. In Otto cycle
the heat addition takes place at constant volume whereas in the Diesel cycle it is at
constant pressure. For this reason, the Diesel cycle is often referred to as the constant-
pressure cycle. It is better to avoid this term as it creates confusion with Joules cycle.
Diagram 10.6 Air Standard Diesel Cycle
(a) Diesel Cycle (b) P-V diagram
Combustion product
Inlet valve
Exhaust valve
Fuel
Air
0
2 3
4
1
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Diagrams 10.6(a), and (b) explain the working principle of an Air Standard Diesel cycle.
The following are the processes.
0-1: Constant pressure suction during which fresh air is drawn into the cylinder as the
piston executes the outward motion.
1-2: The air is compressed isentropically. Usually the compression ratio in the Diesel
cycle is much higher them that of Otto cycle. Because of the high compression ratio,
the temperature of the gas at the end of isentropic compression is so high that when
fuel is injected, it gets ignited immediately.
2-3: The fuel (Diesel oil) is injected into the hot compressed air at state 2 and the fuel
undergoes a chemical reaction. The combustion of Diesel oil in air is not as
spontaneous as the combustion of gasoline and the combustion is relatively slow.
Hence the piston starts moving outward as combustion take place. The combustion
processes is conveniently approximated as a constant pressure energy addition
process.
3-4: The combustion products undergo isentropic expansion and the piston executes an
outward motion.
4-1: The combustion products are exhausted at constant volume when the discharge port
opens. This is replaced by a constant-volume energy rejection process.
1-0: The remaining combustion products are exhausted at constant pressure by the
inward motion of the piston.
From the P-V diagram it can be observed that the work done during the process 0-1 and
1-0 is zero. Hence, they can be ignored for the purpose of thermodynamic analysis we
need to consider only the cycle 1-2-3-4, which is air-standard Diesel Cycle. The cycle is
composed two reversible adiabatics and one reversible isobars, and one reversible
isochoric [Diagram 10.7].
Diagram 10.7 Air Standard Diesel Cycle
Suppose m be the fixed mass of air undergoing the cycle of operation as described above.
1-2: The air is compressed reversibly and adiabatically from T1 to T2. In this process no
heat addition or rejection by the air.
2-3: The air is now heated at constant volume from temperature T2 to T3. Now heat
absorb is,
3-4: The air is expended reversibly and adiabatically from T3 to T4. In this process no
heat addition or rejection by the air.
4-1: The air is cooled at constant volume from temperature T4 to T1. Heat rejection is
Therefore, efficiency of the Diesel cycle is
(a) P-V diagram (b) T-s diagram
2
3
4
1
2 3
4
1
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10 Chapter 10: Gas Power Cycles
The efficiency of the cycle can be expressed in terms of the following ratios
Compression ratio, rk = V1/V2,
Expansion ratio, re = V4/V3,
Cut-off ratio, rc = V3/V2.
It is seen, as before that
The cut-off ratio is defined as the ratio of the volume at the end of constant-pressure
energy addition process to the volume at the beginning of the energy addition process.
Process 3-4 is Isentropic, then
Process 2-3 is Constant pressure, then
Process 1−2 is isentropic process, then
Substituting the values of T1, T2, and T4 in equations in (10.7), then
As rc > 1,
is also greater than unity. Therefore, the efficiency of the Diesel cycle
is less than that of the Otto cycle for the same compression ratio.
It may be noted that the efficiency of the Diesel cycle is different from that of the Otto
cycle only in the bracketed factor. This factor is always greater than unity. Hence for a
given compression ratio, the Otto cycle is more efficient. In diesel engines the fuel cut -off
ratio, rc, depends on output, being maximum for maximum output. Therefore, unlike the
Otto cycle the air-standard efficiency of the Diesel cycle depends on output. The higher
efficiency of the Otto cycle as compared to the Diesel cycle for the same compression
ratio is of no practical importance. In practice the operating compression ratios of diesel
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engines are much higher compared to spark-ignition engines working on Otto cycle. The
normal range of compression ratio for diesel engine is 16 to 20 whereas for spark-
ignition engines it is 6 to 10. Due to the higher compression ratios used in diesel engines
the efficiency of a diesel engine is more than that of the gasoline engine.
Work Output
The net work output for a Diesel cycle is given by
Mean Effective Pressure
The expression for mean effective pressure can be shown to be
10.5 AIR STANDARD DUAL CYCLE
The air standard Diesel cycle does not simulate exactly the pressure-volume variation in
an actual compression ignition engine, where the fuel injection is started before the end
of compression stroke. A closer approximation is the limited pressure cycle in which
some part of heat is added to air at constant volume, and the remainder at constant
pressure. Dual cycle is also termed as limited pressure cycle or Mixed cycle.
Diagram 10.8 Air Standard Dual Cycle
(a) P-V diagram (b) T-s diagram
2
3 4
5
1
5
2
3
4
1
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12 Chapter 10: Gas Power Cycles
Diagrams 10.7(a) and (b) shows the working principles of a Dual cycle. In the dual cycle,
the energy addition is accomplished in two stages: Part of the energy is added at
constant volume and part of the energy is added at constant pressure. The remaining
processes are similar to those of the Otto cycle and the Diesel cycle. The efficiency of the
cycle can be estimated in the following way
Heat is added reversibly, partly at constant volume (2-3) and partly at constant pressure
(3-4).
Heat supplied
Heat rejected
Efficiency
Process 3-4
Process 2-3
Process 1−2
Process 4−5
Substituting the values of T1, T2, T3, and T5 in equations in (10.12), then
It can be seen from the above equation that a value of rp > 1 results in an increased
efficiency for a given value of rc and γ. Thus the efficiency of Dual cycle lies between that
of the Otto cycle and the Diesel cycle having same compression ratio. With rc = 1, it
becomes an Otto cycle, and with rp = 1, it becomes a Diesel cycle.
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Work Output
The net work output for a Dual cycle is given by
Mean Effective Pressure
The expression for mean effective pressure can be shown to be
10.6 COMPARISON OF THE OTTO, DIESEL AND DUAL CYCLES
The important variable factors which are used as the basis for comparison of the cycles
are compression ratio, peak pressure, heat addition, heat rejection and the net work. In
order to compare the performance of the Otto, Diesel and Dual combustion cycles some
of the variable factors must be fixed. In this section, a comparison of these three cycles is
made for the same compression ratio, same heat addition, constant maximum pressure
and temperature, same heat rejection and net work output. This analysis will show
which cycle is more efficient for a given set of operating conditions.
Diagrams 10.8
For same compression ratio and heat rejection (Diagrams 10.8(a) and (b))
1-6-4-5: Otto Cycle;
1-7-4-5: Diesel Cycle;
1-2-3-4-5: Duel Cycle
For the same Qr, the higher the Qg, the higher is the cycle efficiency
(a) P-V diagram (b) T-s diagram
P
P = C
P = C
4
7
6
3
2
5
1
T
V = C
P = C
V = C 3
6
4
7
5
2
1
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14 Chapter 10: Gas Power Cycles
Diagrams 10.9
For the same maximum pressure and temperature (Diagrams 10.9(a) and (b))
1-6-4-5: Otto Cycle
1-7-4-5: Diesel Cycle
1-2-3-4-5: Duel Cycle
Qg is represented by:
area under 6-4 for Otto cycle
area under 7-4 for Diesel cycle and
area under 2-3-4 for Dual cycle and Qg is same for all the cycles
The actual cycles are modifications on the Air Standard cycles in the following manner:
10.7 THE LENOIR CYCLE
The Lenoir cycle consists of the following processes [see Diagram 10.10(a)]. Constant
volume heat addition (1-2); isentropic expansion (2-3); constant pressure heat rejection
(3-1). The Lenoir cycle is used for pulse jet engines.
Diagrams 10.10 The Lenoir Cycle
Heat given in process 1-2 is
Heat rejected in process 1-3 is
Efficiency
(a) P-V diagram (b) T-s diagram
2
3 1
2
3
1
Air Standard cycle
Actual cycles
Actual properties of working medium and their variation with temperature
Time loss factor, Heat loss factor, Exhaust blow loss factor
(a) P-V diagram (b) T-s diagram
P
6
2
7 3 4
5
1
T 3
7
2
6
1
5
4
5
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The efficiency of the cycle can be expressed in terms of the following ratios
Pressure ratio, rp = p2/p1,
Process 1−2
Process 3-2
Substituting the values of T1, and T3 in equations in (10.17), then
Thus the efficiency of the Lenoir cycle depends upon the pressure ratio as well as the
ratio of specific heats, viz., γ.
10.8 THE ATKINSON CYCLE
Atkinson cycle is an ideal cycle for Otto engine exhausting to a gas turbine. In this cycle
the isentropic expansion (3-4) of an Otto cycle (1234) is further allowed to proceed to the
lowest cycle pressure (3-5) so as to increase the work output. With this modification the
cycle is known as Atkinson cycle. The cycle is shown on p-V and T-s diagrams in
Diagrams 10.11(a) and (b) respectively.
Diagrams 10.11 The Atkinson Cycle
Heat given in process 2-3 is
Heat rejected in process 5-1 is
(a) P-V diagram (b) T-s diagram
5
4
3
2
1
5
2
3
4
1
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16 Chapter 10: Gas Power Cycles
Efficiency
The efficiency of the cycle can be expressed in terms of the following ratios
Compression ratio, rk = V1/V2,
Expansion ratio, re = V5/V3,
Process 1−2
Process 3-2
Now,
Process 5-3
Substituting the values of T2, T3, and T5 in equations in (10.19), then
10.9 AIR STANDARD BRAYTON CYCLE
Gas turbines function based on Brayton cycles. Air is first compressed adiabatically in
process 1-2, it then enters the combustion chamber where fuel is injected and burned
essentially at constant pressure in process 2-3, and then the products of combustion
expanded in the turbine to the ambient pressure in process 3-4, and are thrownout to
the surroundings. The cycle is open.
Diagram 10.12(a), (b) and (c) explain working of a Brayton cycle.
The air-standard Brayton cycle consists of
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1-2: Isentropic compression of air
2-3: Constant pressure energy addition
3-4: Isentropic expansion
4-1: Constant Pressure energy rejection.
Diagram 10.12 Brayton cycles
Work input compression Wc
Heat supplied
Work output turbine WT
Heat rejection
Efficiency
Pressure ratio, rp = p2/p1,
and,
(a) Brayton cycle (b) P-V diagram (c) T-s diagram
T
P = C
P = C
2
1
5
3
4 P = C
P = C
P 2 3
1 4
B
C T