Atoms RPI - ERTH 2330 The Basis of All Materials.
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Transcript of Atoms RPI - ERTH 2330 The Basis of All Materials.
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Atoms
RPI - ERTH 2330
The Basis of All Materials
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• Neutron - neutral particle• Proton - positively charged particle• Electron - negatively charged particle
E.B. Watson
The Atom
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Visible light – part of the EM spectrum
Longer
v = f, and v = 299,792,458 m / s (~3 E 8) in a vacuumis length of a cycle in m, f is Hz (cycles per second)
Higher f
Our story begins with light…
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FREQUENCY (f) number of cycles per unit time [units = Hertz (Hz)]
1 Hz = 1 cycle/sT = 1/f; f = 1/T; T f = 1
Wave Terms
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Dispersion
High f – more “bending” in prism
Refraction – producing constituent wavelengths
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RefractionWaves are bent as the move through materials with different wave propagating properties
E.B. Watson
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The spectrum of the hydrogen atom
E.B. Watson
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Violet 1 7.3E14 HzViolet 2 6.9E14 HzGreen 6.2E14 HzRed 4.6E14 Hz
What are the wavelengths (v=c)?
= v / f
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Ph
oto
-Ele
ctri
c E
ffec
tP
ho
to-E
lect
ric
Eff
ect
Incident light causes movement of charge. Electrons move from the surface of the negatively-charged metal plate
The intensity of the light determines how many electrons are produced, but not their kinetic energy. Wavelength changes kinetic energy
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Small packets, or quanta, possessing specific amounts of energy.
An incident photon is either totally absorbed by "target" matter or not absorbed at all*
The energy of the photons in a monochromatic beam of light
E = h f
h is (Planck’s constant 6.626 E -34 Js)
*Quantization of photons is like counting children - you can’t have a partial child
PHOTONS
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Ephoton = EH - EL = h f
Energy transitions in Hydrogen
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€
1
λ= R
1
22 −1
n2
⎡ ⎣ ⎢
⎤ ⎦ ⎥
Line n
Violet 6
Violet 5
Blue-green 4
Red 3
Balmer relationshipsBalmer relationships
Any hot gas at low pressure will produce a line spectrum, although the spectra of other gases are more complex than that of hydrogen.
Hydrogen spectra
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Bohr model - a "solar-system" model. assumptions:
•an electron is in specific "allowed" orbits•the allowed orbits are described by
m v r = n h / 2
Angular momentum Planck’s const.
F = m v2 / r and F = k q1 q2 / r2
Bohr saw this as charged particles on circular path set the forces equal
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Bohr specific radii for electrons
j
kl
E.B. Watson
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It requires energy to remove electrons
Energy increases with orbital distance.
Lowest energy configuration – ground state
2n
EE Ln =
Quantum number
Energy level at quantum number
Energy level at ground state
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2n
EE Ln =
You can use this to determine changes in the amount of energy
12GL
n
E
n
EE −=Δ
Describes the change in energy of an electron moved from 1st orbital (the ground state in H) to the n orbital
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E.B. Watson
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Electrons are attracted to the protons in the nucleus. Great, how big is the nucleus?
E.B. Watson
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E.B. Watson
E.B. Watson
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Elements differ from one another by the number of protons they contain (Z)
Hydrogen (H) – 1 proton
Helium (He) – 2 protons
Sodium (Na) – 11 protons
Francium (Fr) – 87 protons
A neutralneutral atom will have as many electrons as protons.
Many atoms for each element will have the same number of neutrons as protons
Elements of the same Z that differ in the number of neutrons are isotopesisotopes.
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AtomsAtoms
ElectronElectron
NeutronsNeutrons
ProtonProton
MassMass
9.109 E -31 kg9.109 E -31 kg
1.673 E -27 kg1.673 E -27 kg
1.673 E -27 kg1.673 E -27 kg
ChargeCharge
(-1) 1.602 E -19 coul.(-1) 1.602 E -19 coul.
(0) None(0) None
(+1) 1.602 E -19 coul.(+1) 1.602 E -19 coul.
Z = number of protons
N = number of neutrons
A = atomic mass number (N + Z)
Element = unique Z
Isotope = unique Z, different N
What happens to A? 14C
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IsotopeSame Z, different N
Carbon (C ) Z = 6
Carbon-12 12C 6 protons, 6 neutrons 98.89%Carbon-13 13C 6 protons, 7 neutrons 1.11%Carbon-14 14C 6 protons, 8 neutrons trace
Atomic mass units (u)
Every isotope is scaled to 12C (12.000 u)
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The total mass (“atomic weight”) of any element is the sum of the weighted mass of its isotopes.
For example, Oxygen has three isotopes
mass (rel 12C) Abundance
16O 15.99491 99.759%
17O 16.99914 0.037%
18O 17.00016 0.204%
(15.994191 x 0.99759) + (16.99914 x 0.00037) + (17.00016 x 0.00204) = 15.9994 u
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•The interactions of electromagnetic radiation and electrons reveal the energy structure of the atoms
•The interaction of charged nuclei reveal the size of atomic nuclei
•The number of protons(+) determines the element’s identity
•It also determines the number of electrons (-)
•The number of electrons controls the behavior of the atom
•The number of neutrons may vary - isotopes
•Atomic mass is normalized to 12C
•Atomic mass for an element is a function of isotope abundance and mass.