Associativity of operators
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Transcript of Associativity of operators
For more : http://comsciguide.blogspot.com/2015/06/associativity-of-operators.html
Associativity of operators :
In general, expressions are the combination of operands and operators.
An operator is a symbol that tells the compiler to perform specific
mathematical or logical manipulations. We have different types of
operators which have some priority. According to priority, the
expressions are simplified.
For example :
a*b+c;
Here, operands are a,b,c and operators are *, +
From the table, we see that * have high priority than +. So the
expression is equal to ((a*b) +c).This tells that the * operator is
executed first and + next.
Suppose if an expression contains two or more equal priority operators,
then we have to use the Associativity of operators.
For example :
a * b + c / d - e
operands are a,b,c,d,e operators are * , + , / , -
For more : http://comsciguide.blogspot.com/2015/06/associativity-of-operators.html
From the priority table we get * and / have equal priority and also +
and – have equal priority.
We get the expression as (a * b) + ( c / d) - e
Now the problem arises which one in the bracket should first executed.
(a * b) or (c / d) and ((a * b) + (c / d)) or ((c / d) - e) i.e.
either + or - .
Associativity indicates in which order two operators of same
precedence (priority) executes first.
For example :
Suppose if we consider the expression a == b != c ,
Operands are a,b,c and operators are == , != .These two have same
priority. The associativity of both == and != is left to right i.e. the
expression in left is executed first and execution takes place towards
right. Thus a == b != c is equal to ((a == b) != c).
For more : http://comsciguide.blogspot.com/2015/06/associativity-of-operators.html
Now if we consider the above expression , As arithmetic operators
have left to right precedence, expression which is on the left is solved
first i.e. ((a * b) + (c / d)) and final expression is (((a * b ) + ( c / d )) - e)