HSC Assessment Policy 2018/19 · hsc assessment policy 2 15 timing of assessment tasks..... 11
Assessment 15
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Transcript of Assessment 15
Mechanical Behavior 1: Calculation Solutions
(70 points)
1. (10 pts) A specimen of aluminum having a rectangular cross section 10 mm 12.7 mm (0.4 in. 0.5 in.) is pulled in tension with 35,500 N (8000 lbf) force, producing only elastic deformation. Calculate the resulting strain. A. 4.1x10^-5
B. 4.1 x10^-3
C. 3.6 x10^-3
D. 3.8 x 10^-5
2. (5 pts) Your co-worker has applied a stress of +300 MPa to a steel rod. Did he load the sample in
tension or compression?
a. Tension
b. Compression
3. (5 pts) Toughness represents:
a. The energy required to break (i.e., fracture) a material
b. The energy required to stretch a material.
c. The area of the test specimen
d. The length of the test specimen
4. (10 pts) A steel bar 100 mm (4.0 in.) long and having a square cross section 20 mm (0.8 in.) on an edge is pulled in tension with a load of 89,000 N (20,000 lbf), and experiences an elongation
of 0.10 mm (4.0 10-3 in.). Assuming that the deformation is entirely elastic, calculate the elastic modulus of the steel.
A. 225 MPa
B. 201 GPa
C. 223 GPa
D. 198 MPa
5. (10 pts) For a bronze alloy, the stress at which plastic deformation begins is 275 MPa (40,000
psi), and the modulus of elasticity is 115 GPa (16.7 106 psi). What is the maximum load that may be applied to a specimen with a cross-sectional area of 325 mm2 (0.5 in.2) without plastic deformation?
A. 89.4 kN
B. 95.6 kN
C. 78.8 kN
D. 100.1 kN
6. (10 pts) For a bronze alloy that is 115 mm in length, what is the maximum length the bronze alloy can be pulled to before plastic deformation initiates? Note that the stress at which plastic
deformation begins is 275 MPa (40,000 psi) and the modulus of elasticity is 115 GPa (16.7 106 psi).? A. 115.28 mm
B. 116.11 mm
C. 115.05 mm
D. 116.08 mm
7. (20 pts) A specimen of ductile cast iron having a rectangular cross section of dimensions 4.8
mm 15.9 mm (3/16 in. 5/8 in.) and is deformed in tension. Using the load-elongation data shown in the following table, complete parts (a) through (d). You will need to plot this data as engineering stress versus engineering strain to complete this problem.
Load Length
N lbf mm in.
0 0 75.000 2.953
4,740 1,065 75.025 2.954
9,140 2,055 75.050 2.955
12,920 2,900 75.075 2.956
16,540 3,720 75.113 2.957
18,300 4,110 75.150 2.959
20,170 4,530 75.225 2.962
22,900 5,145 75.375 2.968
25,070 5,635 75.525 2.973
26,800 6,025 75.750 2.982
28,640 6,440 76.500 3.012
30,240 6,800 78.000 3.071
31,100 7,000 79.500 3.130
31,280 7,030 81.000 3.189
30,820 6,930 82.500 3.248
29,180 6,560 84.000 3.307
27,190 6,110 85.500 3.366
24,140 5,430 87.000 3.425
18,970 4,265 88.725 3.493
Fracture
(a) Compute the modulus of elasticity (5 pts).
A. 207 GPa
B. 197 GPa
C. 200 GPa
D. 212 GPa
(b) Determine the yield strength at a strain offset of 0.002. (5 pts)
A. 167 MPa
B. 280 MPa
C. 325 MPa
D. 235 MPa
(c) Determine the tensile strength of this alloy. (5 pts)
A. 410 MPa
B. 359 MPa
C. 485 MPa
D. 520 MPa
(d) What is the ductility, in percent elongation? (5 pts)
A. 24.2%
B. 18.4%
C. 14.6 %
D. 12.8 %