Assay of Paracetamol Tablet _ Pharmacy Education
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Transcript of Assay of Paracetamol Tablet _ Pharmacy Education
4/3/2014 Assay of paracetamol tablet | Pharmacy Education
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Assay of paracetamol tablet
Apparatus:
Pistol and mortar, beaker, stirrer, volumetric flask, pipette, paracetamol tablets
Standard solutions:
0.1N NaOH solution (4g/100ml of water)
Stated potency:
500mg tablet
Official limits:
95-105%
Extinction value: 715 at 257nm
Procedure:
For assay of paracetamol. Take 20 tablets and weigh it. Grind the tablets and weight the amount of powder
that contain 150mg of active ingredient and transfer it to 100ml volumetric flask. Now add 40-50ml of the
NaOH 0.1N. Now add distilled water and shake it in a volumetric flask. This is the first dilution. Take 10ml of
it and add in another volumetric flask. Add few drops of the NaOH solution and dilute to 100 ml. similarly
prepare the third dilution. Adjust the wavelength of spectrophotometer at 257nm. Fill the solution in the cell
from 3rd dilution and measure absorbance at 257nm. Calculate percentage absorbance by following formula
Percentage purity= (Absorbance × Dilution factor) ×100/E1%1cm
Dilution factor: Solution in E1%1cm /solution in final dilution
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Compare it with official limits. If range fall in official limits, the batch is passed and if not the batch is failed.
Observations and Calculations:
Paracetamol tablet have active ingredient= 500mg
Weight of 20 tablets= 10.1g
Weight of 1 tablet= 505mg
500mg of active ingredient is in =505mg
1mg active ingredient will be in = 505/500
150mg active ingredient will be in = (505/500)×150 = 151.5 mg
First dilution:
100ml of the solution will contain = 150mg
10ml of the solution will contain = 15mg
Second dilution:
100ml of the solution will contain = 15mg
10ml of the solution will contain = 1.5mg
Third dilution:
In 10ml of the solution, add few drops of the NaOH solution. This is third dilution.
Dilution factor: Solution in E1%1cm /solution in final dilution
DF= (100mg/100ml)÷(1.5mg/100ml)
= 666.7
Percentage purity= (Absorbance × Dilution factor) ×100/E1%1cm
Percentage purity= 1.03×666.7×100/715
=96.04%
Result:
The batch is passed because the percentage purity fall in official limits.
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