Applications of the Definite Integrals Dr. Faud Almuhannadi Math 119 - Section(4)
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Transcript of Applications of the Definite Integrals Dr. Faud Almuhannadi Math 119 - Section(4)
Applications of the Definite Integrals
Dr. Faud AlmuhannadiMath 119 - Section(4)
Done by:
Hanen Marwa Najla Noof Wala
In this part, we are going to explain the
different types of applications related to
the “ Definite Integrals “.
Which includes talking about :
1. Area under a curve
2. Area between two curves
3. Volume of Revolution
Definition :
In calculus, the integral of a function
extends the concept of an ordinary
sum. While an ordinary sum is taken
over a discrete set of values,
integration extends this concept to
sums over continuous domains
The simplest case, the integral of a real-
valued function f of one real variable x on
the interval [a, b], is denoted:
The ∫ sign represents integration; a and b
are the lower limit and upper limit of
integration, defining the domain of
integration; f(x) is the integrand; and dx is
a notation for the variable of integration
Computing integrals
The most basic technique for
computing integrals of one real
variable is based on the fundamental
theorem of calculus. It proceeds like
this:
Choose a function f(x) and an interval [a, b].
Find an antiderivative of f, that is, a function F such that F' = f.
By the fundamental theorem of calculus, provided the integrand and integral have no singularities on the path of integration,
Therefore the value of the integral is F(b) − F(a).
Case ..1..
Area Under a Curve
Example ..1..
The graph below shows the curve and is shaded in the region
The area is found by integrating
Example ..2..
Case ..2..
Area between two curves
Say you have 2 curves y = f(x) and y = g(x)
Area under f(x)=
Area under g(x)=
Superimposing the two graphs:
Area bounded by f(x) and g(x)
Example ..3..
Find the area between the curves y = 0 and y = 3(x3 - x)
1 2 3 4-1-2-3-4
x
1
2
3
4
-1
-2
-3
-4
y
Example ..4.. Find the area bounded by the curves
y = x2 - 4x – 5
and
y = x + 1
Solving the equations simultaneously,
x + 1 = x2 - 4x - 5
x = -1 or x = 6
Required Area =
Volume Of A Revolution
A solid of revolution is formed when a region bounded by part of a curve is rotated about a straight line.
Rotation about x-axis:
Rotation about y-axis:
Example ..5..
The volume that we are looking for is shown in the diagram below
To find the volume, we integrate
Thank u 4 listening