AP Physics B - Impulse and Momentum

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    AP Physics B

    Impulse and Momentum

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    Impulse = MomentumConsider Newtons 2nd Law and

    the definition of acceleration

    Units of Impulse:

    Units of Momentum:

    Momentum is defined as Inertia in Motion

    Ns

    Kg x m/s

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    ExampleA 100 g ball is dropped from a height of h = 2.00 m above the floor. It

    rebounds vertically to a height of h'= 1.50 m after colliding with the

    floor. (a) Find the momentum of the ball immediately before it collideswith the floor and immediately after it rebounds, (b) Determine the

    average force exerted by the floor on the ball. Assume that the time

    interval of the collision is 0.01 seconds.

    smghv

    mvmgh

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    EE

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    o

    o

    AB

    /26.62*8.9*22

    21 2

    ===

    =

    =

    =

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    UKEE

    o

    AB

    /4.55.1*8.9*22 ===

    =

    =

    smkgp

    smkgp

    vmp

    after

    before

    /*54.0)4.5(100.0

    /*626.0)26.6(100.0

    ==

    ==

    = rr

    NF

    F

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    6.116

    ))26.6(4.5(100.0)01.0(

    )(

    =

    =

    ==

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    Impulse is the AreaSince J=Ft, Impulse is the AREA of a Force vs. Time graph.

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    How about a collision?Consider 2 objects speeding toward

    each other. When they collide......

    Due to Newtons 3rd Law the FORCEthey exert on each other areEQUAL and OPPOSITE.

    The TIMES of impact are also equal.

    Therefore, the IMPULSES of the 2

    objects colliding are also EQUAL

    21

    21

    2121

    )()(

    JJ

    FtFt

    ttFF

    =

    =

    ==

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    How about a collision?If the Impulses are equal then

    the MOMENTUMS are

    also equal!

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    222111

    2211

    21

    21

    )()(

    oo

    oo

    vmvmvmvm

    vvmvvm

    vmvmpp

    JJ

    +=

    =

    ==

    =

    22112211 vmvmvmvm

    pp

    oo

    afterbefore

    +=+

    =

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    Momentum is conserved!The Law of Conservation of Momentum: In the absence of

    an external force (gravity, friction), the totalmomentum before the collision is equal to the totalmomentum after the collision.

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    total

    car

    truck

    totalo

    caro

    otrucko

    /*3300/*18005.4*400

    /*15003*500

    /*3300

    /*800)2)(400(

    /*2500)5)(500(

    )(

    )(

    )(

    ===

    ==

    =

    ==

    ===

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    Several Types of collisionsSometimes objects stick together or blow apart. In this case,

    momentum is ALWAYS conserved.

    2211)(

    022011

    2211022011

    vmvmvm

    vmvmvm

    vmvmvmvm

    pp

    totalototal

    totaltotal

    afterbefore

    +=

    =+

    +=+

    = When 2 objects collide and DONT stick

    When 2 objects collide and stick together

    When 1 object breaks into 2 objects

    Elastic Collision = Kinetic Energy is Conserved

    Inelastic Collision = Kinetic Energy is NOT Conserved

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    Example A bird perched on an 8.00 cm tall swing has a mass of 52.0g, and the base of the swing has a mass of 153 g. Assumethat the swing and bird are originally at rest and that thebird takes off horizontally at 2.00 m/s. If the base canswing freely (without friction) around the pivot, how high

    will the base of the swing rise above its original level?

    How many objects due to have BEFORE the action?

    How many objects do you have AFTER the action?

    1

    2

    =

    +=

    +=

    =

    swing

    swing

    ToT

    AB

    v

    vvmvmvm

    pp

    )2)(052.0()153.0()0)(205.0( )(1

    2211

    -0.680 m/s

    ===

    =

    =

    =

    6.19

    )68.0(

    2

    21

    22

    2

    )(

    h

    g

    v

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    swingswingo

    AB

    0.024 m

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    Example Granny (m=80 kg) whizzesaround the rink with a velocityof 6 m/s. She suddenly collideswith Ambrose (m=40 kg) who

    is at rest directly in her path.Rather than knock him over,she picks him up and continuesin motion without "braking."Determine the velocity of

    Granny and Ambrose.How many objects do I have before the collision?

    How many objects do I have after the collision?

    2

    1

    =

    =+

    =+

    =

    T

    T

    TToo

    ab

    v

    v

    vmvmvm

    pp

    120)0)(40()6)(80(2211

    4 m/s

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    Collisions in 2 DimensionsThe figure to the left shows a

    collision between two pucks

    on an air hockey table. Puck Ahas a mass of 0.025-kg and ismoving along the x-axis with avelocity of +5.5 m/s. It makesa collision with puck B, whichhas a mass of 0.050-kg and isinitially at rest. The collision isNOT head on. After thecollision, the two pucks flyapart with angles shown in thedrawing. Calculate the speedsof the pucks after the collision.

    vA

    vB

    vA

    cos

    vAsin

    vBcosvBsin

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    Collisions in 2 dimensions

    vA

    vB

    vAcos

    vAsin

    vBcosvBsin

    )37cos)(050(.)65cos)(025(.0)5.5)(025.0( BA

    xBBxAAoxBBoxAA

    xox

    vv

    vmvmvmvm

    pp

    +=+

    +=+

    =

    BA vv 040.00106.01375.0 +=

    AB

    AB

    BA

    yBByAA

    yoy

    vv

    vv

    vv

    vmvm

    pp

    757.0

    0227.00300.0

    )37sin)(050.0()65sin)(025.0(0

    0

    =

    =

    +=

    +=

    =

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    Collisions in 2 dimensions

    AB vv 757.0=

    smv

    v

    vv

    vv

    A

    A

    AA

    AA

    /84.2

    04845.01375.0

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    )757.0)(050.0(0106.01375.0

    =

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    +=

    +=

    BA vv 040.00106.01375.0 +=

    smvB /15.2)84.2(757.0 ==