Analysis Converter Boost

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    Boost Converter

    3-2-1 Circuit diagram and key waveforms

    C

    Vg

    D

    +

    Vo

    -

    Vg

    + VL -

    (b)

    + VL -

    R

    L

    (a)

    +

    Vo

    -

    L

    C

    (c)

    L

    Vg

    R

    RC

    IRF150

    +

    Vo

    -

    + VL -

    iDiL

    io

    vL

    C

    A

    B

    iL,min

    iL,maxiD

    t

    t

    vo

    vo

    t

    (1-D)TDT

    iL,min

    iL,maxiL

    -Vo/R

    iL

    t

    Vg

    Vg

    - Vo

    (d)

    ic

    t

    Figure 3-2 (a) Boost converter (b) switch on for a time durationDT(c) switch off for a timeduration (1-D)T(d) key waveforms.

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    3-2-2 Circuit description and operation

    Circuit description. The three basic dc-dc converters use a pair of switches, usually one

    controlled (eg. MOSFET) and one uncontrolled (ie. diode), to achieve unidirectional power

    flow from input to output. The converters also use one capacitor and one inductor to store

    and transfer energy from input to output. They also filter or smooth voltage and current.

    The dc-dc coverters can have two distinct modes of operation: Continuous

    conduction mode (CCM) and discontinuous conduction mode (DCM). In practice, a

    converter may operate in both modes, which have significantly different characteristics.

    Therefore, a converter and its control should be designed based on both modes of operation.

    However, for this course we only consider the dc-dc converters operated in CCM.

    Circuit Operation. When the switch is on for a time duration DT, the switch conducts theinductor current and the diode becomes reverse biased. This results in a positive voltage vL =

    Vg across the inductor. This voltage causes a linear increase in the inductor current iL. When

    the switch is turned off, because of the inductive energy storage, iLcontinues to flow. Thiscurrent now flows through the diode, and vL = Vg-Vo for a time duration (1-D)T until the

    switch is turned on again.

    3-2-3 Analytical expressions forg

    o

    V

    V, iL, and vo

    Assumptions made about the operation of the converter are as follows:

    The circuit is operating in the steady state The circuit is operating in the CCM

    The capacitor is large enough to assume a constant output voltage The component are ideal.

    Equating the integral of the inductor voltage over one time period to zero yields

    0)1()(

    0000

    =+

    =+= TDVVDTV

    dtvdtvdtv

    ogg

    t

    L

    t

    L

    T

    L

    offon

    go VD

    V= 11

    or

    DV

    V

    g

    o

    =

    1

    1

    Assuming a lossless circuit,Pg=Po,

    Therefore

    oogg IVIV =

    And

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    DV

    V

    I

    I

    o

    g

    g

    o == 1

    For a boost converter, it is obvious that

    Lg II =

    ]A)(AreawaveformunderareaShaded[1

    1

    0

    L

    DT

    LL

    vL

    dtvL

    i

    =

    =

    DTVL

    g=1

    From iL we can obtain iL,min and iL, max

    2min,

    LLL

    iIi

    =

    2max,

    LLL

    iIi

    +=

    To obtain the average inductor current, we can use the relationship

    LoD IDII )1( ==

    Therefore

    RD

    V

    D

    II ooL

    )1()1( =

    =

    The peak-peak output voltage ripple, vo. From the information of the capacitorcurrent, ic we can obtain vo.

    DTR

    V

    C

    iL

    dtiC

    vv

    o

    c

    cco

    =

    =

    ==

    1

    ]waveformunderareaShaded[1

    1

    therefore

    DTR

    V

    Cv oo =

    1

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    3-2-4 CCM/DCM boundary condition

    Being at the boundary between the continuous and the discontinuous mode, by definition, the

    inductor current iLgoes to zero at the end of the off period. At this boundary, the averageinductor current is

    2

    LL

    iI =

    the minimum inductor current, iL, min = 0 and the maximum inductor curren iL, max= iL.

    (1-D)TDT

    iL

    vL

    t

    Vg

    Vg- Vo

    We know that for buck convertersR

    VII ooD == and TDVV

    LDTV

    Li oggL )1)((

    11== .

    Equation at the CCM/DCM boundary,2

    LL

    iI

    = , can be used to determine the combination

    ofL, fandR that will result in CCM. The minimum load current required for CCM operation

    is:

    TDDVL

    TDDVL

    I

    DTVL

    i

    D

    I

    IDI

    DTVL

    iI

    o

    go

    g

    Lo

    Lo

    g

    LL

    2

    min,

    )1(2

    1

    )1(2

    1

    21

    21

    )1(but

    2

    1

    2

    =

    =

    =

    =

    =

    =

    =

    If the desired switching frequency f and load resistance R are established, the minimum

    inductor current required for CCM is:

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    f

    RDD

    RTDDL

    DTDVL

    DTVLDR

    V

    iI

    ogo

    LL

    2

    )1(

    2)1(

    )1(2

    1

    2

    1

    )1(

    2

    2

    2

    min

    =

    =

    ==

    =

    If the desired value of the inductorL and the load resistanceR are established, the minimum

    switching frequency required for CCM is

    L

    RDDf

    2

    )1( 2

    min

    =

    If the desired switching frequency and the value of the inductor L are established, the

    minimum load resistance required for CCM is

    2min )1(

    2

    DD

    fLR

    =

    -tammat-