Analysis Converter Boost
Transcript of Analysis Converter Boost
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Boost Converter
3-2-1 Circuit diagram and key waveforms
C
Vg
D
+
Vo
-
Vg
+ VL -
(b)
+ VL -
R
L
(a)
+
Vo
-
L
C
(c)
L
Vg
R
RC
IRF150
+
Vo
-
+ VL -
iDiL
io
vL
C
A
B
iL,min
iL,maxiD
t
t
vo
vo
t
(1-D)TDT
iL,min
iL,maxiL
-Vo/R
iL
t
Vg
Vg
- Vo
(d)
ic
t
Figure 3-2 (a) Boost converter (b) switch on for a time durationDT(c) switch off for a timeduration (1-D)T(d) key waveforms.
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3-2-2 Circuit description and operation
Circuit description. The three basic dc-dc converters use a pair of switches, usually one
controlled (eg. MOSFET) and one uncontrolled (ie. diode), to achieve unidirectional power
flow from input to output. The converters also use one capacitor and one inductor to store
and transfer energy from input to output. They also filter or smooth voltage and current.
The dc-dc coverters can have two distinct modes of operation: Continuous
conduction mode (CCM) and discontinuous conduction mode (DCM). In practice, a
converter may operate in both modes, which have significantly different characteristics.
Therefore, a converter and its control should be designed based on both modes of operation.
However, for this course we only consider the dc-dc converters operated in CCM.
Circuit Operation. When the switch is on for a time duration DT, the switch conducts theinductor current and the diode becomes reverse biased. This results in a positive voltage vL =
Vg across the inductor. This voltage causes a linear increase in the inductor current iL. When
the switch is turned off, because of the inductive energy storage, iLcontinues to flow. Thiscurrent now flows through the diode, and vL = Vg-Vo for a time duration (1-D)T until the
switch is turned on again.
3-2-3 Analytical expressions forg
o
V
V, iL, and vo
Assumptions made about the operation of the converter are as follows:
The circuit is operating in the steady state The circuit is operating in the CCM
The capacitor is large enough to assume a constant output voltage The component are ideal.
Equating the integral of the inductor voltage over one time period to zero yields
0)1()(
0000
=+
=+= TDVVDTV
dtvdtvdtv
ogg
t
L
t
L
T
L
offon
go VD
V= 11
or
DV
V
g
o
=
1
1
Assuming a lossless circuit,Pg=Po,
Therefore
oogg IVIV =
And
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DV
V
I
I
o
g
g
o == 1
For a boost converter, it is obvious that
Lg II =
]A)(AreawaveformunderareaShaded[1
1
0
L
DT
LL
vL
dtvL
i
=
=
DTVL
g=1
From iL we can obtain iL,min and iL, max
2min,
LLL
iIi
=
2max,
LLL
iIi
+=
To obtain the average inductor current, we can use the relationship
LoD IDII )1( ==
Therefore
RD
V
D
II ooL
)1()1( =
=
The peak-peak output voltage ripple, vo. From the information of the capacitorcurrent, ic we can obtain vo.
DTR
V
C
iL
dtiC
vv
o
c
cco
=
=
==
1
]waveformunderareaShaded[1
1
therefore
DTR
V
Cv oo =
1
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3-2-4 CCM/DCM boundary condition
Being at the boundary between the continuous and the discontinuous mode, by definition, the
inductor current iLgoes to zero at the end of the off period. At this boundary, the averageinductor current is
2
LL
iI =
the minimum inductor current, iL, min = 0 and the maximum inductor curren iL, max= iL.
(1-D)TDT
iL
vL
t
Vg
Vg- Vo
We know that for buck convertersR
VII ooD == and TDVV
LDTV
Li oggL )1)((
11== .
Equation at the CCM/DCM boundary,2
LL
iI
= , can be used to determine the combination
ofL, fandR that will result in CCM. The minimum load current required for CCM operation
is:
TDDVL
TDDVL
I
DTVL
i
D
I
IDI
DTVL
iI
o
go
g
Lo
Lo
g
LL
2
min,
)1(2
1
)1(2
1
21
21
)1(but
2
1
2
=
=
=
=
=
=
=
If the desired switching frequency f and load resistance R are established, the minimum
inductor current required for CCM is:
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f
RDD
RTDDL
DTDVL
DTVLDR
V
iI
ogo
LL
2
)1(
2)1(
)1(2
1
2
1
)1(
2
2
2
min
=
=
==
=
If the desired value of the inductorL and the load resistanceR are established, the minimum
switching frequency required for CCM is
L
RDDf
2
)1( 2
min
=
If the desired switching frequency and the value of the inductor L are established, the
minimum load resistance required for CCM is
2min )1(
2
DD
fLR
=
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