Algebra II, Module 2โ‚ฌยฆย ยท Lesson 13: Properties of Similarity Transformations Exit Ticket A...

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10 9 8 7 6 5 4 3 2 1 Eureka Math โ„ข Algebra II, Module 2 Student_B Contains Sprint and Fluency, Exit Ticket, and Assessment Materials Published by the non-pro๏ฌt Great Minds. Copyright ยฉ 2015 Great Minds. All rights reserved. No part of this work may be reproduced or used in any form or by any means โ€” graphic, electronic, or mechanical, including photocopying or information storage and retrieval systems โ€” without written permission from the copyright holder. โ€œGreat Mindsโ€ and โ€œEureka Mathโ€ are registered trademarks of Great Minds. Printed in the U.S.A. This book may be purchased from the publisher at eureka-math.org A Story of Functions ยฎ

Transcript of Algebra II, Module 2โ‚ฌยฆย ยท Lesson 13: Properties of Similarity Transformations Exit Ticket A...

Page 1: Algebra II, Module 2โ‚ฌยฆย ยท Lesson 13: Properties of Similarity Transformations Exit Ticket A similarity transformation consists of a translation along the vector ๐น๐น ๐บ๐บ

10 9 8 7 6 5 4 3 2 1

Eureka Mathโ„ข

Algebra II, Module 2

Student_BContains Sprint and Fluency, Exit Ticket,

and Assessment Materials

Published by the non-profit Great Minds.

Copyright ยฉ 2015 Great Minds. All rights reserved. No part of this work may be reproduced or used in any form or by any means โ€” graphic, electronic, or mechanical, including photocopying or information storage and retrieval systems โ€” without written permission from the copyright holder. โ€œGreat Mindsโ€ and โ€œEureka Mathโ€ are registered trademarks of Great Minds.

Printed in the U.S.A. This book may be purchased from the publisher at eureka-math.org

A Story of Functionsยฎ

Page 2: Algebra II, Module 2โ‚ฌยฆย ยท Lesson 13: Properties of Similarity Transformations Exit Ticket A similarity transformation consists of a translation along the vector ๐น๐น ๐บ๐บ

Exit Ticket Packet

Page 3: Algebra II, Module 2โ‚ฌยฆย ยท Lesson 13: Properties of Similarity Transformations Exit Ticket A similarity transformation consists of a translation along the vector ๐น๐น ๐บ๐บ

M2 Lesson 1 GEOMETRY

Lesson 1: Scale Drawings

Name Date

Lesson 1: Scale Drawings

Exit Ticket

Triangle ๐ด๐ด๐ด๐ด๐ด๐ด is provided below, and one side of scale drawing โ–ณ ๐ด๐ดโ€ฒ๐ด๐ดโ€ฒ๐ด๐ดโ€ฒ is also provided. Use construction tools to complete the scale drawing and determine the scale factor. What properties do the scale drawing and the original figure share? Explain how you know.

A STORY OF FUNCTIONS

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Page 4: Algebra II, Module 2โ‚ฌยฆย ยท Lesson 13: Properties of Similarity Transformations Exit Ticket A similarity transformation consists of a translation along the vector ๐น๐น ๐บ๐บ

M2 Lesson 2 GEOMETRY

Lesson 2: Making Scale Drawings Using the Ratio Method

Name Date

Lesson 2: Making Scale Drawings Using the Ratio Method

Exit Ticket

One of the following images shows a well-scaled drawing of โ–ณ ๐ด๐ด๐ต๐ต๐ถ๐ถ done by the ratio method; the other image is not a well-scaled drawing. Use your ruler and protractor to make the necessary measurements and show the calculations that determine which is a scale drawing and which is not.

Figure 1

Figure 2

A STORY OF FUNCTIONS

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Page 5: Algebra II, Module 2โ‚ฌยฆย ยท Lesson 13: Properties of Similarity Transformations Exit Ticket A similarity transformation consists of a translation along the vector ๐น๐น ๐บ๐บ

M2 Lesson 3 GEOMETRY

Lesson 3: Making Scale Drawings Using the Parallel Method

Name Date

Lesson 3: Making Scale Drawings Using the Parallel Method

Exit Ticket

With a ruler and setsquare, use the parallel method to create a scale drawing of quadrilateral ๐ด๐ด๐ต๐ต๐ถ๐ถ๐ด๐ด about center ๐‘‚๐‘‚ with

scale factor ๐‘Ÿ๐‘Ÿ = 34. Verify that the resulting figure is in fact a scale drawing by showing that corresponding side lengths

are in constant proportion and that the corresponding angles are equal in measurement.

What kind of error in the parallel method might prevent us from having parallel, corresponding sides?

A STORY OF FUNCTIONS

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Page 6: Algebra II, Module 2โ‚ฌยฆย ยท Lesson 13: Properties of Similarity Transformations Exit Ticket A similarity transformation consists of a translation along the vector ๐น๐น ๐บ๐บ

M2 Lesson 4 GEOMETRY

Lesson 4: Comparing the Ratio Method with the Parallel Method

Name Date

Lesson 4: Comparing the Ratio Method with the Parallel Method

Exit Ticket

In the diagram, ๐‘‹๐‘‹๐‘‹๐‘‹๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ โˆฅ ๐ด๐ด๐ด๐ด๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ. Use the diagram to answer the following:

1. If ๐ต๐ต๐‘‹๐‘‹ = 4, ๐ต๐ต๐ด๐ด = 5, and ๐ต๐ต๐‘‹๐‘‹ = 6, what is ๐ต๐ต๐ด๐ด?

2. If ๐ต๐ต๐‘‹๐‘‹ = 9, ๐ต๐ต๐ด๐ด = 15, and ๐ต๐ต๐‘‹๐‘‹ = 15, what is ๐‘‹๐‘‹๐ด๐ด?

Not drawn to scale

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Page 7: Algebra II, Module 2โ‚ฌยฆย ยท Lesson 13: Properties of Similarity Transformations Exit Ticket A similarity transformation consists of a translation along the vector ๐น๐น ๐บ๐บ

M2 Lesson 5 GEOMETRY

Lesson 5: Scale Factors

Name Date

Lesson 5: Scale Factors

Exit Ticket

1. Two different points ๐‘…๐‘… and ๐‘Œ๐‘Œ are dilated from ๐‘†๐‘† with a scale factor of 34

, and ๐‘…๐‘…๐‘Œ๐‘Œ = 15. Use the dilation theorem to

describe two facts that are known about ๐‘…๐‘…โ€ฒ๐‘Œ๐‘Œโ€ฒ๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ.

2. Which diagram(s) below represents the information given in Problem 1? Explain your answer(s).a.

b.

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Page 8: Algebra II, Module 2โ‚ฌยฆย ยท Lesson 13: Properties of Similarity Transformations Exit Ticket A similarity transformation consists of a translation along the vector ๐น๐น ๐บ๐บ

M2 Lesson 6 GEOMETRY

Name Date

Lesson 6: Dilations as Transformations of the Plane

Exit Ticket

1. Which transformations of the plane are distance-preserving transformations? Provide an example of what thisproperty means.

2. Which transformations of the plane preserve angle measure? Provide one example of what this property means.

3. Which transformation is not considered a rigid motion and why?

Lesson 6: Dilations as Transformations of the Plane

A STORY OF FUNCTIONS

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Page 9: Algebra II, Module 2โ‚ฌยฆย ยท Lesson 13: Properties of Similarity Transformations Exit Ticket A similarity transformation consists of a translation along the vector ๐น๐น ๐บ๐บ

M2 Lesson 7 GEOMETRY

Name Date

Lesson 7: How Do Dilations Map Segments?

Exit Ticket

1. Given the dilation ๐ท๐ท๐‘‚๐‘‚,32, a line segment ๐‘ƒ๐‘ƒ๐‘ƒ๐‘ƒ, and that ๐‘‚๐‘‚ is not on ๐‘ƒ๐‘ƒ๐‘ƒ๐‘ƒ๏ฟฝโƒ–๏ฟฝ๏ฟฝ๏ฟฝโƒ— , what can we conclude about the image of ๐‘ƒ๐‘ƒ๐‘ƒ๐‘ƒ๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ?

2. Given figures A and B below, ๐ด๐ด๐ด๐ด๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ โˆฅ ๐ท๐ท๐ท๐ท๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ, ๐‘ˆ๐‘ˆ๐‘ˆ๐‘ˆ๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ โˆฅ ๐‘‹๐‘‹๐‘‹๐‘‹๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ, and ๐‘ˆ๐‘ˆ๐‘ˆ๐‘ˆ๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ โ‰… ๐‘‹๐‘‹๐‘‹๐‘‹๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ, determine which figure has a dilation mapping theparallel line segments, and locate the center of dilation ๐‘‚๐‘‚. For one of the figures, a dilation does not exist. Explainwhy.

Figure A

Figure B

Lesson 7: How Do Dilations Map Segments?

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Page 10: Algebra II, Module 2โ‚ฌยฆย ยท Lesson 13: Properties of Similarity Transformations Exit Ticket A similarity transformation consists of a translation along the vector ๐น๐น ๐บ๐บ

M2 Lesson 8 GEOMETRY

Name Date

Lesson 8: How Do Dilations Map Lines, Rays, and Circles?

Exit Ticket

Given points ๐‘‚๐‘‚, ๐‘†๐‘†, and ๐‘‡๐‘‡ below, complete parts (a)โ€“(e):

a. Draw rays ๐‘†๐‘†๐‘‡๐‘‡๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝโƒ— and ๐‘‡๐‘‡๐‘†๐‘†๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝโƒ— . What is the union of these rays?

b. Dilate ๐‘†๐‘†๐‘‡๐‘‡๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝโƒ— from ๐‘‚๐‘‚ using scale factor ๐‘Ÿ๐‘Ÿ = 2. Describe the image of ๐‘†๐‘†๐‘‡๐‘‡.๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝโƒ—

c. Dilate ๐‘‡๐‘‡๐‘†๐‘†๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝโƒ— from ๐‘‚๐‘‚ using scale factor ๐‘Ÿ๐‘Ÿ = 2. Describe the image of ๐‘‡๐‘‡๐‘†๐‘†๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝโƒ— .

d. What does the dilation of the rays in parts (b) and (c) yield?

e. Dilate circle ๐ถ๐ถ with radius ๐‘‡๐‘‡๐‘†๐‘† from ๐‘‚๐‘‚ using scale factor ๐‘Ÿ๐‘Ÿ = 2.

Lesson 8: How Do Dilations Map Lines, Rays, and Circles?

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Page 11: Algebra II, Module 2โ‚ฌยฆย ยท Lesson 13: Properties of Similarity Transformations Exit Ticket A similarity transformation consists of a translation along the vector ๐น๐น ๐บ๐บ

M2 Lesson 9 GEOMETRY

Name Date

Lesson 9: How Do Dilations Map Angles?

Exit Ticket

1. Dilate parallelogram ๐‘†๐‘†๐‘‡๐‘‡๐‘†๐‘†๐‘†๐‘† from center ๐‘‚๐‘‚ using a scale factor of ๐‘Ÿ๐‘Ÿ = 34.

2. How does ๐‘š๐‘šโˆ ๐‘‡๐‘‡โ€ฒ compare to ๐‘š๐‘šโˆ ๐‘‡๐‘‡?

3. Using your diagram, prove your claim from Problem 2.

Lesson 9: How Do Dilations Map Angles?

A STORY OF FUNCTIONS

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Page 12: Algebra II, Module 2โ‚ฌยฆย ยท Lesson 13: Properties of Similarity Transformations Exit Ticket A similarity transformation consists of a translation along the vector ๐น๐น ๐บ๐บ

M2 Lesson 10 GEOMETRY

Name Date

Lesson 10: Dividing the Kingโ€™s Foot into 12 Equal Pieces

Exit Ticket

1. Use the side splitter method to divide ๐‘€๐‘€๐‘€๐‘€๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ into 7 equal-sized pieces.

2. Use the dilation method to divide ๐‘ƒ๐‘ƒ๐‘ƒ๐‘ƒ๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ into 11 equal-sized pieces.

Lesson 10: Dividing the Kingโ€™s Foot into 12 Equal Pieces

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Page 13: Algebra II, Module 2โ‚ฌยฆย ยท Lesson 13: Properties of Similarity Transformations Exit Ticket A similarity transformation consists of a translation along the vector ๐น๐น ๐บ๐บ

M2 Lesson 10 GEOMETRY

3. If the segment below represents the interval from zero to one on the number line, locate and label 47

.

1 0

Lesson 10: Dividing the Kingโ€™s Foot into 12 Equal Pieces

A STORY OF FUNCTIONS

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Page 14: Algebra II, Module 2โ‚ฌยฆย ยท Lesson 13: Properties of Similarity Transformations Exit Ticket A similarity transformation consists of a translation along the vector ๐น๐น ๐บ๐บ

M2 Lesson 11 GEOMETRY

Name Date

Lesson 11: Dilations from Different Centers

Exit Ticket

Marcos constructed the composition of dilations shown below. Drawing 2 is 38

the size of Drawing 1, and Drawing 3 is

twice the size of Drawing 2.

1. Determine the scale factor from Drawing 1 to Drawing 3.

2. Find the center of dilation mapping Drawing 1 to Drawing 3.

Lesson 11: Dilations from Different Centers

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Page 15: Algebra II, Module 2โ‚ฌยฆย ยท Lesson 13: Properties of Similarity Transformations Exit Ticket A similarity transformation consists of a translation along the vector ๐น๐น ๐บ๐บ

M2 Lesson 12 GEOMETRY

Name Date

Lesson 12: What Are Similarity Transformations, and Why Do We

Need Them?

Exit Ticket

1. Figure A' is similar to Figure A. Which transformations compose the similarity transformation that maps Figure Aonto Figure A'?

2. Is there a sequence of dilations and basic rigid motions that takes the small figure to the large figure? Takemeasurements as needed.

Figure A

Figure A'

Figure A Figure B

Lesson 12: What Are Similarity Transformations, and Why Do We Need Them?

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Page 16: Algebra II, Module 2โ‚ฌยฆย ยท Lesson 13: Properties of Similarity Transformations Exit Ticket A similarity transformation consists of a translation along the vector ๐น๐น ๐บ๐บ

M2 Lesson 13 GEOMETRY

Name Date

Lesson 13: Properties of Similarity Transformations

Exit Ticket

A similarity transformation consists of a translation along the vector ๐น๐น๐บ๐บ๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝโƒ— , followed by a dilation from point ๐‘ƒ๐‘ƒ with a scale factor of ๐‘Ÿ๐‘Ÿ = 2, and finally a reflection over line ๐‘š๐‘š. Use construction tools to find ๐ด๐ดโ€ฒโ€ฒโ€ฒ๐ถ๐ถโ€ฒโ€ฒโ€ฒ๐ท๐ทโ€ฒโ€ฒโ€ฒ๐ธ๐ธโ€ฒโ€ฒโ€ฒ.

Lesson 13: Properties of Similarity Transformations

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Page 17: Algebra II, Module 2โ‚ฌยฆย ยท Lesson 13: Properties of Similarity Transformations Exit Ticket A similarity transformation consists of a translation along the vector ๐น๐น ๐บ๐บ

M2 Lesson 14 GEOMETRY

Name Date

Lesson 14: Similarity

Exit Ticket

1. In the diagram, โ–ณ ๐ด๐ด๐ต๐ต๐ถ๐ถ~ โ–ณ ๐ท๐ท๐ท๐ท๐ท๐ท by the dilation with center ๐‘‚๐‘‚ and a scale factor of ๐‘Ÿ๐‘Ÿ. Explain why โ–ณ ๐ท๐ท๐ท๐ท๐ท๐ท~ โ–ณ ๐ด๐ด๐ต๐ต๐ถ๐ถ.

2. Radii ๐ถ๐ถ๐ด๐ด๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ and ๐‘‡๐‘‡๐‘‡๐‘‡๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ are parallel. Is circle ๐ถ๐ถ๐ต๐ต,๐ต๐ต๐ด๐ด similar to circle ๐ถ๐ถ๐‘‡๐‘‡,๐‘‡๐‘‡๐‘‡๐‘‡? Explain.

3. Two triangles, โ–ณ ๐ด๐ด๐ต๐ต๐ถ๐ถ and โ–ณ ๐ท๐ท๐ท๐ท๐ท๐ท, are in the plane so that ๐‘š๐‘šโˆ ๐ด๐ด = ๐‘š๐‘šโˆ ๐ท๐ท, ๐‘š๐‘šโˆ ๐ต๐ต = ๐‘š๐‘šโˆ ๐ท๐ท, ๐‘š๐‘šโˆ ๐ถ๐ถ = ๐‘š๐‘šโˆ ๐ท๐ท, and๐ท๐ท๐ท๐ท๐ด๐ด๐ด๐ด

=๐ท๐ท๐ธ๐ธ๐ด๐ด๐ต๐ต

=๐ท๐ท๐ธ๐ธ๐ด๐ด๐ต๐ต

. Summarize the argument that proves that the triangles must be similar.

Lesson 14: Similarity

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Page 18: Algebra II, Module 2โ‚ฌยฆย ยท Lesson 13: Properties of Similarity Transformations Exit Ticket A similarity transformation consists of a translation along the vector ๐น๐น ๐บ๐บ

M2 Lesson 15 GEOMETRY

Name Date

Lesson 15: The Angle-Angle (AA) Criterion for Two Triangles to Be

Similar

Exit Ticket

1. Given the diagram to the right, ๐‘ˆ๐‘ˆ๐‘ˆ๐‘ˆ๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ โŠฅ ๐‘‰๐‘‰๐‘‰๐‘‰๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ, and ๐‘‰๐‘‰๐‘Š๐‘Š๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ โŠฅ ๐‘ˆ๐‘ˆ๐‘‰๐‘‰๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ. Show that โ–ณ ๐‘ˆ๐‘ˆ๐‘ˆ๐‘ˆ๐‘‰๐‘‰~ โ–ณ๐‘‰๐‘‰๐‘Š๐‘Š๐‘‰๐‘‰.

2. Given the diagram to the right and ๐ท๐ท๐ท๐ท๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ โˆฅ ๐พ๐พ๐พ๐พ๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ, find ๐ท๐ท๐ท๐ทand ๐ท๐ท๐พ๐พ.

Lesson 15: The Angle-Angle (AA) Criterion for Two Triangles to Be Similar

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Page 19: Algebra II, Module 2โ‚ฌยฆย ยท Lesson 13: Properties of Similarity Transformations Exit Ticket A similarity transformation consists of a translation along the vector ๐น๐น ๐บ๐บ

M2 Lesson 16 GEOMETRY

Name Date

Lesson 16: Between-Figure and Within-Figure Ratios

Exit Ticket

Dennis needs to fix a leaky roof on his house but does not own a ladder. He thinks that a 25 ft. ladder will be long enough to reach the roof, but he needs to be sure before he spends the money to buy one. He chooses a point ๐‘ƒ๐‘ƒ on the ground where he can visually align the roof of his car with the edge of the house roof. Help Dennis determine if a 25 ft. ladder will be long enough for him to safely reach his roof.

Lesson 16: Between-Figure and Within-Figure Ratios

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Page 20: Algebra II, Module 2โ‚ฌยฆย ยท Lesson 13: Properties of Similarity Transformations Exit Ticket A similarity transformation consists of a translation along the vector ๐น๐น ๐บ๐บ

M2 Lesson 17 GEOMETRY

Name Date

Lesson 17: The Side-Angle-Side (SAS) and Side-Side-Side (SSS)

Criteria for Two Triangles to Be Similar

Exit Ticket

1. Given โ–ณ ๐ด๐ด๐ต๐ต๐ต๐ต and โ–ณ๐‘€๐‘€๐‘€๐‘€๐‘€๐‘€ in the diagram below and โˆ ๐ต๐ต โ‰… โˆ ๐‘€๐‘€, determine if the triangles are similar. If so, write asimilarity statement, and state the criterion used to support your claim.

2. Given โ–ณ ๐ท๐ท๐ท๐ท๐ท๐ท and โ–ณ ๐ท๐ท๐ธ๐ธ๐ท๐ท in the diagram below, determine if the triangles are similar. If so, write a similaritystatement, and state the criterion used to support your claim.

Lesson 17: The Side-Angle-Side (SAS) and Side-Side-Side (SSS) Criteria for Two Triangles to be Similar

A STORY OF FUNCTIONS

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Page 21: Algebra II, Module 2โ‚ฌยฆย ยท Lesson 13: Properties of Similarity Transformations Exit Ticket A similarity transformation consists of a translation along the vector ๐น๐น ๐บ๐บ

M2 Lesson 18 GEOMETRY

Name Date

Lesson 18: Similarity and the Angle Bisector Theorem

Exit Ticket

1. The sides of a triangle have lengths of 12, 16, and 21. An angle bisector meets the side of length 21. Find thelengths ๐‘ฅ๐‘ฅ and ๐‘ฆ๐‘ฆ.

2. The perimeter of โ–ณ ๐‘ˆ๐‘ˆ๐‘ˆ๐‘ˆ๐‘ˆ๐‘ˆ is 22 12. ๐‘ˆ๐‘ˆ๐‘Š๐‘Š๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝโƒ— bisects โˆ ๐‘ˆ๐‘ˆ๐‘ˆ๐‘ˆ๐‘ˆ๐‘ˆ, ๐‘ˆ๐‘ˆ๐‘Š๐‘Š = 2, and ๐‘ˆ๐‘ˆ๐‘Š๐‘Š = 2 1

2. Find ๐‘ˆ๐‘ˆ๐‘ˆ๐‘ˆ and ๐‘ˆ๐‘ˆ๐‘ˆ๐‘ˆ.

Lesson 18: Similarity and the Angle Bisector Theorem

A STORY OF FUNCTIONS

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Page 22: Algebra II, Module 2โ‚ฌยฆย ยท Lesson 13: Properties of Similarity Transformations Exit Ticket A similarity transformation consists of a translation along the vector ๐น๐น ๐บ๐บ

M2 Lesson 19 GEOMETRY

Name Date

Lesson 19: Families of Parallel Lines and the Circumference of the

Earth

Exit Ticket

1. Given the diagram shown, ๐‘‚๐‘‚๐ด๐ด๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ โˆฅ ๐‘‚๐‘‚๐ต๐ต๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ โˆฅ ๐ถ๐ถ๐ถ๐ถ๏ฟฝ๏ฟฝ๏ฟฝ, ๐‘‚๐‘‚๐‘‚๐‘‚ = 6.5 cm, ๐ด๐ด๐ต๐ต = 7.5 cm, and ๐ต๐ต๐ถ๐ถ = 18 cm. Find ๐‘‚๐‘‚๐ถ๐ถ.

Lesson 19: Families of Parallel Lines and the Circumference of the Earth

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Page 23: Algebra II, Module 2โ‚ฌยฆย ยท Lesson 13: Properties of Similarity Transformations Exit Ticket A similarity transformation consists of a translation along the vector ๐น๐น ๐บ๐บ

M2 Lesson 19 GEOMETRY

2. Martin the Martian lives on Planet Mart. Martin wants to know the circumference of Planet Mart, but it is too largeto measure directly. He uses the same method as Eratosthenes by measuring the angle of the sunโ€™s rays in twolocations. The sun shines on a flagpole in Martinsburg, but there is no shadow. At the same time, the sun shines ona flagpole in Martville, and a shadow forms a 10ยฐ angle with the pole. The distance from Martville to Martinsburg is294 miles. What is the circumference of Planet Mart?

Lesson 19: Families of Parallel Lines and the Circumference of the Earth

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Page 24: Algebra II, Module 2โ‚ฌยฆย ยท Lesson 13: Properties of Similarity Transformations Exit Ticket A similarity transformation consists of a translation along the vector ๐น๐น ๐บ๐บ

M2 Lesson 20 GEOMETRY

Name Date

Lesson 20: How Far Away Is the Moon?

Exit Ticket

1. On Planet A, a 14

-inch diameter ball must be held at a height of 72 inches to just block the sun. If a moon orbiting

Planet A just blocks the sun during an eclipse, approximately how many moon diameters is the moon from theplanet?

2. Planet A has a circumference of 93,480 miles. Its moon has a diameter that is approximated to be 18

that of Planet

A. Find the approximate distance of the moon from Planet A.

Lesson 20: How Far Away Is the Moon?

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Page 25: Algebra II, Module 2โ‚ฌยฆย ยท Lesson 13: Properties of Similarity Transformations Exit Ticket A similarity transformation consists of a translation along the vector ๐น๐น ๐บ๐บ

M2 Lesson 21 GEOMETRY

Name Date

Lesson 21: Special Relationships Within Right Trianglesโ€”Dividing

into Two Similar Sub-Triangles

Exit Ticket

Given โ–ณ ๐‘…๐‘…๐‘…๐‘…๐‘…๐‘…, with altitude ๐‘…๐‘…๐‘†๐‘†๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ drawn to its hypotenuse, ๐‘…๐‘…๐‘…๐‘… = 15, ๐‘…๐‘…๐‘…๐‘… = 36, and ๐‘…๐‘…๐‘…๐‘… = 39, answer the questions below.

1. Complete the similarity statement relating the three triangles in the diagram.

โ–ณ ๐‘…๐‘…๐‘…๐‘…๐‘…๐‘… ~ โ–ณ ~ โ–ณ

2. Complete the table of ratios specified below.

shorter leg: hypotenuse longer leg: hypotenuse shorter leg: longer leg

โ–ณ ๐‘น๐‘น๐‘น๐‘น๐‘น๐‘น

โ–ณ ๐‘น๐‘น๐‘น๐‘น๐‘น๐‘น

โ–ณ ๐‘น๐‘น๐‘น๐‘น๐‘น๐‘น

3. Use the values of the ratios you calculated to find the length of ๐‘…๐‘…๐‘†๐‘†๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ.

Lesson 21: Special Relationships Within Right Trianglesโ€”Dividing into Two Similar Sub-Triangles

A STORY OF FUNCTIONS

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Page 26: Algebra II, Module 2โ‚ฌยฆย ยท Lesson 13: Properties of Similarity Transformations Exit Ticket A similarity transformation consists of a translation along the vector ๐น๐น ๐บ๐บ

M2 Lesson 22 GEOMETRY

Name Date

Lesson 22: Multiplying and Dividing Expressions with Radicals

Exit Ticket

Write each expression in its simplest radical form.

1. โˆš243 =

2. ๏ฟฝ75

=

3. Teja missed class today. Explain to her how to write the length of the hypotenuse in simplest radical form.

Lesson 22: Multiplying and Dividing Expressions with Radicals

A STORY OF FUNCTIONS

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Page 27: Algebra II, Module 2โ‚ฌยฆย ยท Lesson 13: Properties of Similarity Transformations Exit Ticket A similarity transformation consists of a translation along the vector ๐น๐น ๐บ๐บ

M2 Lesson 23 GEOMETRY

Name Date

Lesson 23: Adding and Subtracting Expressions with Radicals

Exit Ticket

1. Simplify 5โˆš11 โˆ’ 17โˆš11.

2. Simplify โˆš8 + 5โˆš2.

3. Write a radical addition or subtraction problem that cannot be simplified, and explain why it cannot be simplified.

Lesson 23: Adding and Subtracting Expressions with Radicals

A STORY OF FUNCTIONS

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Page 28: Algebra II, Module 2โ‚ฌยฆย ยท Lesson 13: Properties of Similarity Transformations Exit Ticket A similarity transformation consists of a translation along the vector ๐น๐น ๐บ๐บ

M2 Lesson 24 GEOMETRY

Name Date

Lesson 24: Prove the Pythagorean Theorem Using Similarity

Exit Ticket

A right triangle has a leg with a length of 18 and a hypotenuse with a length of 36. Bernie notices that the hypotenuse is twice the length of the given leg, which means it is a 30โ€“60โ€“90 triangle. If Bernie is right, what should the length of the remaining leg be? Explain your answer. Confirm your answer using the Pythagorean theorem.

Lesson 24: Prove the Pythagorean Theorem Using Similarity

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Page 29: Algebra II, Module 2โ‚ฌยฆย ยท Lesson 13: Properties of Similarity Transformations Exit Ticket A similarity transformation consists of a translation along the vector ๐น๐น ๐บ๐บ

M2 Lesson 25 GEOMETRY

Name Date

Lesson 25: Incredibly Useful Ratios

Exit Ticket

1. Use the chart from the Exploratory Challenge to approximate the unknown lengths ๐‘ฆ๐‘ฆ and ๐‘ง๐‘ง to one decimal place.

2. Why can we use the chart from the Exploratory Challenge to approximate the unknown lengths?

ยฐ

Lesson 25: Incredibly Useful Ratios

A STORY OF FUNCTIONS

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Page 30: Algebra II, Module 2โ‚ฌยฆย ยท Lesson 13: Properties of Similarity Transformations Exit Ticket A similarity transformation consists of a translation along the vector ๐น๐น ๐บ๐บ

M2 Lesson 26 GEOMETRY

Name Date

Lesson 26: The Definition of Sine, Cosine, and Tangent

Exit Ticket

1. Given the diagram of the triangle, complete the following table.

Angle Measure ๐ฌ๐ฌ๐ฌ๐ฌ๐ฌ๐ฌ ๐œฝ๐œฝ ๐œ๐œ๐จ๐จ๐ฌ๐ฌ ๐œฝ๐œฝ ๐ญ๐ญ๐š๐š๐ฌ๐ฌ ๐œฝ๐œฝ

๐’”๐’”

๐’•๐’•

a. Which values are equal?

b. How are tan ๐‘๐‘ and tan ๐‘ก๐‘ก related?

2. If ๐‘ข๐‘ข and ๐‘ฃ๐‘ฃ are the measures of complementary angles such that sin๐‘ข๐‘ข = 25 and tan ๐‘ฃ๐‘ฃ =

๏ฟฝ212 , label the sides and

angles of the right triangle in the diagram below with possible side lengths.

Lesson 26: The Definition of Sine, Cosine, and Tangent

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Page 31: Algebra II, Module 2โ‚ฌยฆย ยท Lesson 13: Properties of Similarity Transformations Exit Ticket A similarity transformation consists of a translation along the vector ๐น๐น ๐บ๐บ

M2 Lesson 27 GEOMETRY

Name Date

Lesson 27: Sine and Cosine of Complementary Angles and Special

Angles

Exit Ticket

1. Find the values for ๐œƒ๐œƒ that make each statement true.a. sin๐œƒ๐œƒ = cos 32

b. cos ๐œƒ๐œƒ = sin(๐œƒ๐œƒ + 20)

2. โ–ณ ๐ฟ๐ฟ๐ฟ๐ฟ๐ฟ๐ฟ is a 30โ€“60โ€“90 right triangle. Find the unknown lengths ๐‘ฅ๐‘ฅ and ๐‘ฆ๐‘ฆ.

Lesson 27: Sine and Cosine of Complementary Angles and Special Angles

A STORY OF FUNCTIONS

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Page 32: Algebra II, Module 2โ‚ฌยฆย ยท Lesson 13: Properties of Similarity Transformations Exit Ticket A similarity transformation consists of a translation along the vector ๐น๐น ๐บ๐บ

M2 Lesson 28 GEOMETRY

Name Date

Lesson 28: Solving Problems Using Sine and Cosine

Exit Ticket

1. Given right triangle ๐ด๐ด๐ด๐ด๐ด๐ด with hypotenuse ๐ด๐ด๐ด๐ด = 8.5 and ๐‘š๐‘šโˆ ๐ด๐ด = 55ยฐ, find ๐ด๐ด๐ด๐ด and ๐ด๐ด๐ด๐ด to the nearest hundredth.

2. Given triangle ๐ท๐ท๐ท๐ท๐ท๐ท, ๐‘š๐‘šโˆ ๐ท๐ท = 22ยฐ, ๐‘š๐‘šโˆ ๐ท๐ท = 91ยฐ, ๐ท๐ท๐ท๐ท = 16.55, and ๐ท๐ท๐ท๐ท = 6.74, find ๐ท๐ท๐ท๐ท to the nearest hundredth.

Lesson 28: Solving Problems Using Sine and Cosine

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Page 33: Algebra II, Module 2โ‚ฌยฆย ยท Lesson 13: Properties of Similarity Transformations Exit Ticket A similarity transformation consists of a translation along the vector ๐น๐น ๐บ๐บ

M2 Lesson 29 GEOMETRY

Name Date

Lesson 29: Applying Tangents

Exit Ticket

1. The line on the coordinate plane makes an angle of depression of 24ยฐ. Find the slope of the line correct to fourdecimal places.

2. Samuel is at the top of a tower and will ride a trolley down a zip line to a lower tower. The total vertical drop of thezip line is 40 ft. The zip lineโ€™s angle of elevation from the lower tower is 11.5ยฐ. What is the horizontal distancebetween the towers?

Lesson 29: Applying Tangents

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Page 34: Algebra II, Module 2โ‚ฌยฆย ยท Lesson 13: Properties of Similarity Transformations Exit Ticket A similarity transformation consists of a translation along the vector ๐น๐น ๐บ๐บ

M2 Lesson 30 GEOMETRY

Name Date

Lesson 30: Trigonometry and the Pythagorean Theorem

Exit Ticket

1. If sin๐›ฝ๐›ฝ = 4๏ฟฝ2929 , use trigonometric identities to find cos๐›ฝ๐›ฝ and tan๐›ฝ๐›ฝ.

2. Find the missing side lengths of the following triangle using sine, cosine, and/or tangent. Round your answer to fourdecimal places.

Lesson 30: Trigonometry and the Pythagorean Theorem

A STORY OF FUNCTIONS

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Page 35: Algebra II, Module 2โ‚ฌยฆย ยท Lesson 13: Properties of Similarity Transformations Exit Ticket A similarity transformation consists of a translation along the vector ๐น๐น ๐บ๐บ

M2 Lesson 31 GEOMETRY

Name Date

Lesson 31: Using Trigonometry to Determine Area

Exit Ticket

1. Given two sides of the triangle shown, having lengths of 3 and 7 and their included angle of 49ยฐ, find the area of thetriangle to the nearest tenth.

2. In isosceles triangle ๐‘ƒ๐‘ƒ๐‘ƒ๐‘ƒ๐‘ƒ๐‘ƒ, the base ๐‘ƒ๐‘ƒ๐‘ƒ๐‘ƒ = 11, and the base angles have measures of 71.45ยฐ. Find the area of โ–ณ ๐‘ƒ๐‘ƒ๐‘ƒ๐‘ƒ๐‘ƒ๐‘ƒto the nearest tenth.

Lesson 31: Using Trigonometry to Determine Area

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Page 36: Algebra II, Module 2โ‚ฌยฆย ยท Lesson 13: Properties of Similarity Transformations Exit Ticket A similarity transformation consists of a translation along the vector ๐น๐น ๐บ๐บ

M2 Lesson 32 GEOMETRY

Name Date

Lesson 32: Using Trigonometry to Find Side Lengths of an Acute

Triangle

1. Use the law of sines to find lengths ๐‘๐‘ and ๐‘๐‘ in the triangle below. Round answers to the nearest tenth as necessary.

2. Given โ–ณ ๐ท๐ท๐ท๐ท๐ท๐ท, use the law of cosines to find the length of the side marked ๐‘‘๐‘‘ to the nearest tenth.

Lesson 32: Using Trigonometry to Find Side Lengths of an Acute Triangle

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Page 37: Algebra II, Module 2โ‚ฌยฆย ยท Lesson 13: Properties of Similarity Transformations Exit Ticket A similarity transformation consists of a translation along the vector ๐น๐น ๐บ๐บ

M2 Lesson 33 GEOMETRY

Name Date

Lesson 33: Applying the Laws of Sines and Cosines

Exit Ticket

1. Given triangle ๐‘€๐‘€๐‘€๐‘€๐‘€๐‘€, ๐‘€๐‘€๐‘€๐‘€ = 8, ๐‘€๐‘€๐‘€๐‘€ = 7, and ๐‘š๐‘šโˆ ๐‘€๐‘€ = 75ยฐ, find the length of the unknown side to the nearest tenth.Justify your method.

2. Given triangle ๐ด๐ด๐ด๐ด๐ถ๐ถ, ๐‘š๐‘šโˆ ๐ด๐ด = 36ยฐ, ๐‘š๐‘šโˆ ๐ด๐ด = 79ยฐ, and ๐ด๐ด๐ถ๐ถ = 9, find the lengths of the unknown sides to the nearesttenth.

Lesson 33: Applying the Laws of Sines and Cosines

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Page 38: Algebra II, Module 2โ‚ฌยฆย ยท Lesson 13: Properties of Similarity Transformations Exit Ticket A similarity transformation consists of a translation along the vector ๐น๐น ๐บ๐บ

M2 Lesson 34 GEOMETRY

๐‘๐‘ยฐ

Brace

Wall

Name Date

Lesson 34: Unknown Angles

Exit Ticket

1. Explain the meaning of the statement โ€œarcsin ๏ฟฝ12๏ฟฝ = 30ยฐ.โ€ Draw a diagram to support your explanation.

2. Gwen has built and raised a wall of her new house. To keep the wall standing upright while she builds the next wall,she supports the wall with a brace, as shown in the diagram below. What is the value of ๐‘๐‘, themeasure of the angle formed by the brace and the wall?

Lesson 34: Unknown Angles

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Page 39: Algebra II, Module 2โ‚ฌยฆย ยท Lesson 13: Properties of Similarity Transformations Exit Ticket A similarity transformation consists of a translation along the vector ๐น๐น ๐บ๐บ

Assessment Packet

Page 40: Algebra II, Module 2โ‚ฌยฆย ยท Lesson 13: Properties of Similarity Transformations Exit Ticket A similarity transformation consists of a translation along the vector ๐น๐น ๐บ๐บ

M2 Mid-Module Assessment Task GEOMETRY

Name Date

1. The coordinates of โ–ณ ๐ด๐ด๐ด๐ด๐ด๐ด are shown on the coordinate plane below. โ–ณ ๐ด๐ด๐ด๐ด๐ด๐ด is dilated from the origin byscale factor ๐‘Ÿ๐‘Ÿ = 2.

a. Identify the coordinates of the dilated โ–ณ ๐ด๐ดโ€ฒ๐ด๐ดโ€ฒ๐ด๐ดโ€ฒ.

b. Is โ–ณ ๐ด๐ดโ€ฒ๐ด๐ดโ€ฒ๐ด๐ดโ€ฒ~ โ–ณ ๐ด๐ด๐ด๐ด๐ด๐ด? Explain.

Module 2: Similarity, Proof, and Trigonometry

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1

Page 41: Algebra II, Module 2โ‚ฌยฆย ยท Lesson 13: Properties of Similarity Transformations Exit Ticket A similarity transformation consists of a translation along the vector ๐น๐น ๐บ๐บ

M2 Mid-Module Assessment Task GEOMETRY

2. Points ๐ด๐ด, ๐ด๐ด, and ๐ด๐ด are not collinear, forming โˆ ๐ด๐ด๐ด๐ด๐ด๐ด. Extend ๐ด๐ด๐ด๐ด๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝโƒ— to point ๐‘ƒ๐‘ƒ. Line โ„“ passes through ๐‘ƒ๐‘ƒ andis parallel to segment ๐ด๐ด๐ด๐ด. It meets ๐ด๐ด๐ด๐ด๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝโƒ— at point ๐‘„๐‘„.

a. Draw a diagram to represent the situation described.

b. Is ๐‘ƒ๐‘ƒ๐‘„๐‘„๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ longer or shorter than ๐ด๐ด๐ด๐ด๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ?

c. Prove that โ–ณ ๐ด๐ด๐ด๐ด๐ด๐ด ~ โ–ณ ๐ด๐ด๐‘ƒ๐‘ƒ๐‘„๐‘„.

d. What other pairs of segments in this figure have the same ratio of lengths that ๐‘ƒ๐‘ƒ๐‘„๐‘„๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ has to ๐ด๐ด๐ด๐ด๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ?

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M2 Mid-Module Assessment Task GEOMETRY

3. There is a triangular floor space โ–ณ ๐ด๐ด๐ด๐ด๐ด๐ด in a restaurant. Currently, a square portion ๐ท๐ท๐ท๐ท๐ท๐ท๐ท๐ท is covered withtile. The owner wants to remove the existing tile and then tile the largest square possible within โ–ณ ๐ด๐ด๐ด๐ด๐ด๐ด,keeping one edge of the square on ๐ด๐ด๐ด๐ด๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ.

a. Describe a construction that uses a dilation with center ๐ด๐ด that can be used to determine themaximum square ๐ท๐ทโ€ฒ๐ท๐ทโ€ฒ๐ท๐ทโ€ฒ๐ท๐ทโ€ฒ within โ–ณ ๐ด๐ด๐ด๐ด๐ด๐ด with one edge on ๐ด๐ด๐ด๐ด๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ.

b. What is the scale factor of ๐ท๐ท๐ท๐ท๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ to ๐ท๐ทโ€ฒ๐ท๐ทโ€ฒ๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ in terms of the distances ๐ด๐ด๐ท๐ท๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ and ๐ด๐ด๐ท๐ทโ€ฒ๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ?

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M2 Mid-Module Assessment Task GEOMETRY

c. The owner uses the construction in part (a) to mark off where the square would be located. Hemeasures ๐ด๐ด๐ท๐ท to be 15 feet and ๐ท๐ท๐ท๐ทโ€ฒ to be 5 feet. If the original square is 144 square feet, how manysquare feet of tile does he need for ๐ท๐ทโ€ฒ๐ท๐ทโ€ฒ๐ท๐ทโ€ฒ๐ท๐ทโ€ฒ?

4. ๐ด๐ด๐ด๐ด๐ด๐ด๐ท๐ท is a parallelogram, with the vertices listed counterclockwise around the figure. Points ๐‘€๐‘€, ๐‘๐‘, ๐‘‚๐‘‚,and ๐‘ƒ๐‘ƒ are the midpoints of sides ๐ด๐ด๐ด๐ด๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ, ๐ด๐ด๐ด๐ด๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ, ๐ด๐ด๐ท๐ท๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ, and ๐ท๐ท๐ด๐ด๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ, respectively. The segments ๐‘€๐‘€๐‘‚๐‘‚ and ๐‘๐‘๐‘ƒ๐‘ƒ cut theparallelogram into four smaller parallelograms, with the point ๐‘Š๐‘Š in the center of ๐ด๐ด๐ด๐ด๐ด๐ด๐ท๐ท as a commonvertex.

a. Exhibit a sequence of similarity transformations that takes โ–ณ ๐ด๐ด๐‘€๐‘€๐‘Š๐‘Š to โ–ณ ๐ด๐ด๐ท๐ท๐ด๐ด. Be specific indescribing the parameter of each transformation; for example, if describing a reflection, state theline of reflection.

b. Given the correspondence in โ–ณ ๐ด๐ด๐‘€๐‘€๐‘Š๐‘Š similar to โ–ณ ๐ด๐ด๐ท๐ท๐ด๐ด, list all corresponding pairs of angles andcorresponding pairs of sides. What is the ratio of the corresponding pairs of angles? What is theratio of the corresponding pairs of sides?

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Page 44: Algebra II, Module 2โ‚ฌยฆย ยท Lesson 13: Properties of Similarity Transformations Exit Ticket A similarity transformation consists of a translation along the vector ๐น๐น ๐บ๐บ

M2 Mid-Module Assessment Task GEOMETRY

5. Given two triangles, โ–ณ ๐ด๐ด๐ด๐ด๐ด๐ด and โ–ณ ๐ท๐ท๐ท๐ท๐ท๐ท, ๐‘š๐‘šโˆ ๐ด๐ด๐ด๐ด๐ด๐ด = ๐‘š๐‘šโˆ ๐ท๐ท๐ท๐ท๐ท๐ท, and ๐‘š๐‘šโˆ ๐ด๐ด๐ด๐ด๐ด๐ด = ๐‘š๐‘šโˆ ๐ท๐ท๐ท๐ท๐ท๐ท. Points ๐ด๐ด, ๐ด๐ด, ๐ท๐ท,and ๐ท๐ท lie on line ๐‘™๐‘™ as shown. Describe a sequence of rigid motions and/or dilations to show thatโ–ณ ๐ด๐ด๐ด๐ด๐ด๐ด ~ โ–ณ ๐ท๐ท๐ท๐ท๐ท๐ท, and sketch an image of the triangles after each transformation.

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Page 45: Algebra II, Module 2โ‚ฌยฆย ยท Lesson 13: Properties of Similarity Transformations Exit Ticket A similarity transformation consists of a translation along the vector ๐น๐น ๐บ๐บ

M2 Mid-Module Assessment Task GEOMETRY

6. โ–ณ ๐ฝ๐ฝ๐ฝ๐ฝ๐ฝ๐ฝ is a right triangle; ๐‘๐‘๐‘ƒ๐‘ƒ๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ โŠฅ ๐ฝ๐ฝ๐ฝ๐ฝ๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ, ๐‘๐‘๐‘‚๐‘‚๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ โŠฅ ๐ฝ๐ฝ๐ฝ๐ฝ๏ฟฝ๏ฟฝ๏ฟฝ, ๐‘€๐‘€๐‘๐‘๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ โˆฅ ๐‘‚๐‘‚๐‘ƒ๐‘ƒ๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ.

a. List all sets of similar triangles. Explain how you know.

b. Select any two similar triangles, and show why they are similar.

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M2 Mid-Module Assessment Task GEOMETRY

7.

a. The line ๐‘ƒ๐‘ƒ๐‘„๐‘„ contains point ๐‘‚๐‘‚. What happens to ๐‘ƒ๐‘ƒ๐‘„๐‘„๏ฟฝโƒ–๏ฟฝ๏ฟฝ๏ฟฝโƒ— with a dilation about ๐‘‚๐‘‚ and scale factor of๐‘Ÿ๐‘Ÿ = 2? Explain your answer.

b. The line ๐‘ƒ๐‘ƒ๐‘„๐‘„ does not contain point ๐‘‚๐‘‚. What happens to ๐‘ƒ๐‘ƒ๐‘„๐‘„๏ฟฝโƒ–๏ฟฝ๏ฟฝ๏ฟฝโƒ— with a dilation about ๐‘‚๐‘‚ and scale factorof ๐‘Ÿ๐‘Ÿ = 2?

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M2 Mid-Module Assessment Task GEOMETRY

8. Use the diagram below to answer the following questions.

a. State the pair of similar triangles. Which similarity criterion guarantees their similarity?

b. Calculate ๐ท๐ท๐ท๐ท to the hundredths place.

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M2 Mid-Module Assessment Task GEOMETRY

9. In โ–ณ ๐ด๐ด๐ด๐ด๐ด๐ด, ๐‘š๐‘šโˆ ๐ด๐ด is 40ยฐ, ๐‘š๐‘šโˆ ๐ด๐ด is 60ยฐ, and ๐‘š๐‘šโˆ ๐ด๐ด is 80ยฐ. The triangle is dilated by a factor of 2 about point ๐‘ƒ๐‘ƒto form โ–ณ ๐ด๐ดโ€ฒ๐ด๐ดโ€ฒ๐ด๐ดโ€ฒ. It is also dilated by a factor of 3 about point ๐‘„๐‘„ to form โ–ณ ๐ด๐ดโ€ฒโ€ฒ๐ด๐ดโ€ฒโ€ฒ๐ด๐ดโ€ฒโ€ฒ. What is themeasure of the angle formed by line ๐ด๐ดโ€ฒ๐ด๐ดโ€ฒ and line ๐ด๐ดโ€ฒโ€ฒ๐ด๐ดโ€ฒโ€ฒ? Explain how you know.

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M2 Mid-Module Assessment Task GEOMETRY

10. In the diagram below, |๐ด๐ด๐ด๐ด| = |๐ด๐ด๐ท๐ท| = |๐ท๐ท๐ท๐ท|, and โˆ ๐ด๐ด๐ด๐ด๐ด๐ด, โˆ ๐ท๐ท๐ด๐ด๐ท๐ท, and โˆ ๐ท๐ท๐ท๐ท๐ท๐ท are right. The two lines meetat a point to the right. Are the triangles similar? Why or why not?

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M2 Mid-Module Assessment Task GEOMETRY

11. The side lengths of the following right triangle are 16, 30, and 34. An altitude of a right triangle from theright angle splits the hypotenuse into line segments of length ๐‘ฅ๐‘ฅ and ๐‘ฆ๐‘ฆ.

a. What is the relationship between the large triangle and the two sub-triangles? Why?

b. Solve for โ„Ž, ๐‘ฅ๐‘ฅ, and ๐‘ฆ๐‘ฆ.

c. Extension: Find an expression that gives โ„Ž in terms of ๐‘ฅ๐‘ฅ and ๐‘ฆ๐‘ฆ.

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M2 Mid-Module Assessment Task GEOMETRY

12. The sentence below, as shown, is being printed on a large banner for a birthday party. The height of thebanner is 18 inches. There must be a minimum 1-inch margin on all sides of the banner. Use thedimensions in the image below to answer each question.

a. Describe a reasonable figure in the plane to model the printed image.

b. Find the scale factor that maximizes the size of the characters within the given constraints.

c. What is the total length of the banner based on your answer to part (a)?

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GEOMETRY

Module 2: Similarity, Proof, and Trigonometry

M2 End-of-Module Assessment Task

Name Date

1. In the figure below, rotate โ–ณ ๐ธ๐ธ๐ธ๐ธ๐ธ๐ธ about ๐ธ๐ธ by 180ยฐ to get โ–ณ ๐ธ๐ธ๐ธ๐ธโ€ฒ๐ธ๐ธโ€ฒ. If ๐ธ๐ธโ€ฒ๐ธ๐ธโ€ฒ๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ โˆฅ ๐ถ๐ถ๐ถ๐ถ๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ, prove thatโ–ณ ๐ธ๐ธ๐ธ๐ธ๐ธ๐ธ ~ โ–ณ ๐ธ๐ธ๐ถ๐ถ๐ถ๐ถ.

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GEOMETRY

Module 2: Similarity, Proof, and Trigonometry

M2 End-of-Module Assessment Task

2. Answer the following questions based on the diagram below.

a. Find the sine and cosine values of angles ๐‘Ÿ๐‘Ÿ and ๐‘ ๐‘ . Leave the answers as fractions.

sin ๐‘Ÿ๐‘Ÿยฐ = sin ๐‘ ๐‘ ยฐ =

cos ๐‘Ÿ๐‘Ÿยฐ = cos ๐‘ ๐‘ ยฐ =

tan ๐‘Ÿ๐‘Ÿยฐ = tan ๐‘ ๐‘ ยฐ =

b. Why is the sine of an acute angle the same value as the cosine of its complement?

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GEOMETRY

Module 2: Similarity, Proof, and Trigonometry

M2 End-of-Module Assessment Task

c. Determine the measures of the angles to the nearest tenth of a degree in the right triangles below.

i. Determine the measure of โˆ ๐‘Ž๐‘Ž.

ii. Determine the measure of โˆ ๐‘๐‘.

iii. Explain how you were able to determine the measure of the unknown angle in part (i) orpart (ii).

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Module 2: Similarity, Proof, and Trigonometry

M2 End-of-Module Assessment Task

d. A ball is dropped from the top of a 45 ft. building. Once the ball is released, a strong gust of windblew the ball off course, and it dropped 4 ft. from the base of the building.

i. Sketch a diagram of the situation.

ii. By approximately how many degrees was the ball blown off course? Round your answer to thenearest whole degree.

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GEOMETRY

Module 2: Similarity, Proof, and Trigonometry

M2 End-of-Module Assessment Task

3. A radio tower is anchored by long cables called guy wires, such as ๐ธ๐ธ๐ธ๐ธ๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ in the figure below. Point ๐ธ๐ธ is250 m from the base of the tower, and ๐‘š๐‘šโˆ ๐ธ๐ธ๐ธ๐ธ๐ถ๐ถ = 59ยฐ.

a. How long is the guy wire? Round to the nearest tenth.

b. How far above the ground is it fastened to the tower?

c. How tall is the tower, ๐ถ๐ถ๐ถ๐ถ๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ, if ๐‘š๐‘šโˆ ๐ถ๐ถ๐ธ๐ธ๐ถ๐ถ = 71หš?

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Module 2: Similarity, Proof, and Trigonometry

M2 End-of-Module Assessment Task

4. The following problem is modeled after a surveying question developed by a Chinese mathematicianduring the Tang dynasty in the seventh century C.E.

A building sits on the edge of a river. A man views the building from the opposite side of the river. Hemeasures the angle of elevation with a handheld tool and finds the angle measure to be 45ยฐ. He moves50 feet away from the river and remeasures the angle of elevation to be 30ยฐ.

What is the height of the building? From his original location, how far away is the viewer from the top ofthe building? Round to the nearest whole foot.

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Module 2: Similarity, Proof, and Trigonometry

M2 End-of-Module Assessment Task

5. Prove the Pythagorean theorem using similar triangles. Provide a well-labeled diagram to support yourjustification.

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GEOMETRY

Module 2: Similarity, Proof, and Trigonometry

M2 End-of-Module Assessment Task

6. In right triangle ๐ธ๐ธ๐ธ๐ธ๐ถ๐ถ with โˆ ๐ธ๐ธ a right angle, a line segment ๐ธ๐ธโ€ฒ๐ถ๐ถโ€ฒ connects side ๐ธ๐ธ๐ธ๐ธ๏ฟฝ๏ฟฝ๏ฟฝ๏ฟฝ with the hypotenuse sothat โˆ ๐ธ๐ธ๐ธ๐ธโ€ฒ๐ถ๐ถโ€ฒ is a right angle as shown. Use facts about similar triangles to show why cos ๐ถ๐ถโ€ฒ = cos ๐ถ๐ถ .

A STORY OF FUNCTIONS

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Page 60: Algebra II, Module 2โ‚ฌยฆย ยท Lesson 13: Properties of Similarity Transformations Exit Ticket A similarity transformation consists of a translation along the vector ๐น๐น ๐บ๐บ

GEOMETRY

Module 2: Similarity, Proof, and Trigonometry

M2 End-of-Module Assessment Task

7. Terry said, โ€œI will define the zine of an angle ๐‘ฅ๐‘ฅ as follows. Build an isosceles triangle in which the sides ofequal length meet at angle ๐‘ฅ๐‘ฅ. The zine of ๐‘ฅ๐‘ฅ will be the ratio of the length of the base of that triangle tothe length of one of the equal sides.โ€ Molly said, โ€œWonโ€™t the zine of ๐‘ฅ๐‘ฅ depend on how you build theisosceles triangle?โ€

a. What can Terry say to convince Molly that she need not worry about this? Explain your answer.

b. Describe a relationship between zine and sin.

A STORY OF FUNCTIONS

This work is derived from Eureka Math โ„ข and licensed by Great Minds. ยฉ2015 Great Minds. eureka- math.orgGEO-M2-AP-1.3.0-05.2015

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