AL-10
4
PH0101 UNIT 2 LECTURE 2 30 (Integral form of Maxwell’s third equation) (5) (6) s ds B dt d dt d e . emf ds dt B d dl E s l . .
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Transcript of AL-10
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PH0101 UNIT 2 LECTURE 2 30
s dsBdtd
dt
de .emf
sds
dt
Bd=
ds.dt
Bddl.E
s
(Integral form of Maxwells third equation)
(5)
(6)
s dsBdtd
dt
de .emf
dsdt
BddlE
sl..
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PH0101 UNIT 2 LECTURE 2 31
(Using Stokes theorem )
Hence,
t
B)E(
Maxwells third equation in differential form
s s
ds.dt
Bdds).E(
dl.E (7)
(8)
= s
ds).E(
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PH0101 UNIT 2 LECTURE 2 32
Maxwells Fourth Equation
By Amperes circuital law, l
idlB 0.
We know,H
B0 (or) B = 0 H
l
idlH .
(1)
(2)
(3)Using (1) and (2)
s
ds.JWe know i = (4)
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PH0101 UNIT 2 LECTURE 2 33
t
DEJ
ss
ds.t
Dds.Edl.H
(6)
We Know that
(7)
(Maxwells fourth equation in integral form)
ds.Jdl.H
s
ds.Jdl.H
s
t
DEJ
Using (3) and (4) (5) l s
dsJdlH ..
t
DEJ
l ss
dst
DdsEdlH ...
We Know that
(6)
(7)
